Measure the average read time of a single database block for hardware.

Question

Hi,
how to Measure the average read time of a single database block for hardware ?
Many thanks.

Answer 1

Hi,
A STATSPACK report has data file level I/O tunings, but they include buffered reads, so they are biased.
Try this in 9i:
http://www.dba-oracle.com/oracle_tips_cost_adj.htm
select
a.average_wait c1,
b.average_wait c2,
a.total_waits /(a.total_waits + b.total_waits)*100 c3,
b.total_waits /(a.total_waits + b.total_waits)*100 c4,
(b.average_wait / a.average_wait)*100 c5
from
v$system_event a,
v$system_event b
where
a.event = 'db file scattered read'
and
b.event = 'db file sequential read';
Or this, in 10g:
col c1 heading 'Average Waits for|Full Scan Read I/O' format 9999.999
col c2 heading 'Average Waits for|Index Read I/O' format 9999.999
col c3 heading 'Percent of| I/O Waits|for scattered|Full Scans' format 9.99
col c4 heading 'Percent of| I/O Waits|for sequential|Index Scans' format 9.99
col c5 heading 'Starting|Value|for|optimizer|index|cost|adj' format 999
select
sum(a.time_waited_micro)/sum(a.total_waits)/1000000 c1,
sum(b.time_waited_micro)/sum(b.total_waits)/1000000 c2,
sum(a.total_waits) /
sum(a.total_waits + b.total_waits)
) * 100 c3,
sum(b.total_waits) /
sum(a.total_waits + b.total_waits)
) * 100 c4,
sum(b.time_waited_micro) /
sum(b.total_waits)) /
(sum(a.time_waited_micro)/sum(a.total_waits)
) * 100 c5
from
dba_hist_system_event a,
dba_hist_system_event b
where
a.snap_id = b.snap_id
and
a.event_name = 'db file scattered read'
and
b.event_name = 'db file sequential read';