Moving multiple messages at once...HELP PLEASE!

I can't move multiple messages at once in Mail. Why not? When's it going to get fixed?

I can. So it's just your installation. If I were you, the first thing I would try to do is, if you have multiple user accounts on that same computer, see if it is afflicting the other user accounts as well.
If so, I would try reapplying 10.6.3 COMBO update, after running disk utility verify hard disk (and repair if necessary) and running disk utility repair disk permissions.
If not, I would try rebuilding all the mailbox folders. May want to run the two disk utility routines anyways before rebuilding.

Similar Messages

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    Hello,
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    //      ex.printStackTrace();
            removeClient(client); // something not right, kick this client
    }On the client, I think this is the culprit :
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    private SocketChannel  client; // the client SocketChannel
    protected synchronized void read() throws IOException {
      readBuffer.clear();    // clear previous buffer
      int bytesRead = client.read(readBuffer);  // THIS ONE READ THE SAME MESSAGES, I think this is the culprit
      if (bytesRead < 0) {
        throw new IOException("Reached end of stream");
      } else if (bytesRead == 0) {
        return;
      // write to storage (DataInputStream input field storage)
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      // in here the construction of the buffer to real message
    }How could the next client read not from the beginning of the received message but to its actual message (client.read(readBuffer)), i'm thinking to use SocketChannel.read(ByteBuffer[] dsts, , int offset, int length) but don't know the offset, the length, and what's that for :(
    Anyone networking gurus, please help...
    Thank you very much.

    Hello ejp, thanks for the reply.
    (1) You can't assume that each read delivers an entire message.Yep I know about this, like I'm saying everything is okay when all the clients send the message not in the same time, but when the server tries to read client message at the same time, for example there are 3 clients message arrive at the same time and the server tries to read it, the server construct all the message exactly like the first message arrived.
    This is the actual construction of the message, read the length of the packet first, then construct the message into DataInputStream, and read the message from it:
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    private DataInputStream input;
    private NewPipedOutputStream storage;
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    private int length;     
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      if (bytesRead < 0) {
        throw new IOException("Reached end of stream");
      } else if (bytesRead == 0) {
        return;
      // the bytes read is used to fill the byte buffer
      storage.write(readBuffer.array(), 0, bytesRead);
      // after read the packet
      // this is the message construction
      // write to byte buffer to input storage
      // (this will write into DataInputStream)
      storage.write(readBuffer.array(), 0, bytesRead);
      // unpack the packet
      while (input.available() > 0) {
        // unpack the byte length first
        if (waitingForLength) { // read the packet length first
          if (input.available() > 2) {
            length = input.readShort();
            waitingForLength = false;
          } else {
            // the length has not fully read
            break; // wait until the next read
        // construct the packet if the length already known
        } else {
          if (input.available() >= length) {
            // store the content to data
            byte[] data = new byte[length];
            input.readFully(data);
            // add to received packet
            addReceivedPacket(data);
         waitingForLength = true; // wait for another packet
          } else {
            // the content has not fully read
         break; // wait until next read
    (2) You're sharing the same ByteBuffer between all your clients
    so you're running some considerable risks if (1) doesn't happen.
    I recommend you run a ByteBuffer per client and have a good look
    at its API and the NIO examples.Yep, I already use one ByteBuffer per client, it's not shared among the clients, this is the class for each client:
    private SocketChannel client; // socket channel per client
    private ByteBuffer readBuffer; // byte buffer per client
    private Selector packetReader; // the selector that is shared among all clients
    private static final int BUFFER_SIZE = 10240; // default huge buffer size for reading
    private void init() throws IOException {
      storage; // the packet storage writer
      input; // the actual packet input
      readBuffer = ByteBuffer.allocate(BUFFER_SIZE); // the byte buffer is one per client
      readBuffer.order(ByteOrder.BIG_ENDIAN);
      client.configureBlocking(false);
      client.socket().setTcpNoDelay(true);
      // register packet reader
      // one packetReader used by all clients
      client.register(packetReader, SelectionKey.OP_READ, this);
    }Cos the ByteBuffer is not shared, I think it's impossible that it mixed up with other clients, what I think is the SocketChannel client.read(ByteBuffer) that fill the byte buffer with the same packet?
    So you're probably getting the data all mixed up - you'll probalby be seeing a new client message followed by whatever was there from the last time, or the time before.If the server not trying to read all the messages at the same time, it works fine, I think that if the client SocketChannel filled up with multiple client messages, the SocketChannel.read(...) only read the first client message.
    Or am I doing something wrong, I could fasten the server read by removing the Thread.sleep(100); but I think that's not the good solution, since in NIO there should be time where the server need to read client multiple messages at once.
    Any other thoughts?
    Thanks again.

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    I've had this same problem for a while now.
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    If it matters, I have two active sync acounts setup. I have noticed the problem though even if I remove one of the accounts.
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    Hi,
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