Multi-line String - Match Regular Expression

I am trying to figure out the format of a regular expression in order to pull select lines out of a multi-line string and populate those lines as individual elements of a string array while using Match Regular Expression. The overall length of the multi-line string can vary as well as the text contained within the string. The string can contain letters, numbers, and special characters. I have attached an example VI. Within the example VI I only want to return the lines beginning with "Device #" into the array. The number of lines beginning with "Device #" can vary but I want to capture them all.
Or is there a better function to use instead of Match Regular Expression that will give me the desired outcome?
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Attachments:
MultiLine Regular Expression.vi ‏22 KB

aaronb wrote:
I am trying to figure out the format of a regular expression in order to pull select lines out of a multi-line string and populate those lines as individual elements of a string array while using Match Regular Expression. The overall length of the multi-line string can vary as well as the text contained within the string. The string can contain letters, numbers, and special characters. I have attached an example VI. Within the example VI I only want to return the lines beginning with "Device #" into the array. The number of lines beginning with "Device #" can vary but I want to capture them all.
Or is there a better function to use instead of Match Regular Expression that will give me the desired outcome?
Match Regular Expression works well for this.
Ben64

Similar Messages

How to Capture Multiple Line String using Regular Expression?

Hi,
I have a simple program like this:
What I want to accomplish is to capture everything between >>start and >>end using a single Match Regular Expression node. It seems that setting multiple? to True or False does not help.
I am using LabVIEW 2012.
If it is impossible to capture it using a single node, that is fine. But I want to make sure that I can make full use of this node without combining serveral others.
Thank you!
TailOfGon
Certified LabVIEW Architect 2013
Solved!
Go to Solution.

Thank you for the fast response! Your solution worked in the example case
After I saw your post, I was finally able to step forward. But I still wanted to make use of dot notation due to the limitation of characters that match with \w.
I made some more modification to your regular expression then now it seems working for all characters:
>>start((?:\s|.)*)>>end
Thanks!
TailOfGon
Certified LabVIEW Architect 2013

Not understanding the String matches (regular Expression)

Everytime I search I do not find any examples of java String's matches function.
I am reading an input file and just want to print if it matches the pattern
/thisdirectory/source_code/*.cc
I even tried to test by doing
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System.out.println("IT MATCHES");
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I totally understand what you are going through, maybe someone could shed some light on my problem as well.
In my code the getText() method is pulling the text from a form being filled out. I am checking for validation of fields: But the problem is that my code wont compile with matches method inside these lines of code.:
else if ( !firstTextField.getText().matches( "[A-Z][a-zA-Z]*" ) )
          JOptionPane.showMessageDialog(this, "Invalid First Name");
          else if(!lastTextField.getText().matches("[A-Z][a-zA-Z]*" ) )
                    JOptionPane.showMessageDialog(this, "Invalid Last Name");
          else if(!addressTextField.getText().matches("\\d+\\s+([a-zA-Z]+\\s[a-zA-Z]+") )
                    JOptionPane.showMessageDialog(this, "Invalid Address");
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                    JOptionPane.showMessageDialog(this, "Invalid City");
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The error I am receiving is:
The method matches(String) is undefined for the type String.
What gives?

Match Regular Expression Function input string format

Hi,
I am new to labview and was having some difficulties using the Match Regular Experssion Function.
I am using labview to communicate with a sensor. I have installed the NI device driver to do so. The output of my sensor is in the format,
X20
R40 P20 A123. The numbers in this case are arbitrary. I am trying to use Match Regular Expression Function to display and perform mathematical operations on the numbers. I am having difficulties formatting the input string on the Match Regular Expression Function. Could you please give me some tips on how to format the example I provided.
Thank

MoAgha wrote:
Hi,
I am new to labview and was having some difficulties using the Match Regular Experssion Function.
I am using labview to communicate with a sensor. I have installed the NI device driver to do so. The output of my sensor is in the format,
X20
R40 P20 A123. The numbers in this case are arbitrary. I am trying to use Match Regular Expression Function to display and perform mathematical operations on the numbers. I am having difficulties formatting the input string on the Match Regular Expression Function. Could you please give me some tips on how to format the example I provided.
Thank
Here is a way to do it if the format is constant (X R P A followed by a positive integer number).
Ben64

"Match Regular Expression" and "Match Pattern" vi's behave differently

Hi,
I have a simple string matching need and by experimenting found that the "Match Regular Expression" and "Match Pattern" vi's behave somewhat differently. I'd assume that the regular expression inputs on both would behave the same. A difference I've discovered is that the "|" character (the "vertical bar" character, commonly used as an "or" operator) is recognized as such in the Match Regular Expression vi, but not in the Match Pattern vi (where it is taken literally). Furthermore, I cannot find any documentation in Help (on-line or in LabVIEW) about the "|" character usage in regular expressions. Is this documented anywhere?
For example, suppose I want to match any of the following 4 words: "The" or "quick" or "brown" or "fox". The regular expression "The|quick|brown|fox" (without the quotes) works for the Match Regular Expression vi but not the Match Pattern vi. Below is a picture of the block diagram and the front panel results:
The Help says that the Match Regular Expression vi performs somewhat slower than the Match Pattern vi, so I started with the latter. But since it doesn't work for me, I'll use the former. But does anyone have any idea of the speed difference? I'd assume it is negligible in such a simple example.
Thanks!
Solved!
Go to Solution.

Yep-
You hit a point that's frustrated me a time or two as well (and incidentally, caused some hair-pulling that I can ill afford)
The hint is in the help file:
for Match regular expression "The Match Regular Expression function gives you more options for matching
strings but performs more slowly than the Match Pattern function....Use regular
expressions in this function to refine searches....
Characters to Find
Regular Expression
VOLTS
VOLTS
A plus sign or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[^0-9]+
The word Level only if it
appears at the beginning of the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The first string within parentheses but not containing any
parentheses within it
$[^()]*$
A left bracket
A right bracket
cat, cag, cot, cog, dat, dag, dot, and dag
[cd][ao][tg]
cat or dog
cat|dog
dog, cat
dog, cat cat dog,cat
cat cat dog, and so on
((cat )*dog)
One or more of the letter a
followed by a space and the same number of the letter a, that is, a a, aa aa, aaa aaa, and so
on
(a+) \1
For Match Pattern "This function is similar to the Search and Replace
Pattern VI. The Match Pattern function gives you fewer options for matching
strings but performs more quickly than the Match Regular Expression
function. For example, the Match Pattern function does not support the
parenthesis or vertical bar (|) characters.
Characters to Find
Regular Expression
VOLTS
VOLTS
All uppercase and lowercase versions of volts, that is, VOLTS, Volts, volts, and so on
[Vv][Oo][Ll][Tt][Ss]
A space, a plus sign, or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[~0-9]+
The word Level only if it begins
at the offset position in the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The longest string within parentheses but not containing any
parentheses within it
([~()]*)
A left bracket
A right bracket
cat, dog, cot, dot, cog, and so on.
[cd][ao][tg]
Frustrating- but still managable.
Jeff

Matching Regular Expressions in OBPM 10GR3

Hi all,
How do I match Regular expressions like" Wait For Response" in Strings using OBPM?
Any idea?
Is there any exact syntax?
Because I tried doing this:-
for( int i=0; i < testGroup.length(); i++)
if(testGroup.reason.match(regexp : "Wait For Response"))
logMessage("--Test Group Matched--");
But it does not work..
Any idea?

String myVar = "has matching_char_set";
if ( myVar.match(regexp : '/matching_char_set/') ) {
logMessage("matched...yep");
Try like this ..should work.
Rgds,
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Match Regular Expression does not match what Match Pattern does

I have read through a lot of posts about how Match Pattern does not match what Match Regular Expression will due to not processing some characters.
However, I found a problem with the other way. A simple Reg-Ex that works in Match Pattern but not Match Regular Expression.
What I have here is just an example. I want to use Match Regular Expression so I can specify some sub-matches.
The reg-ex is for: one or more non-numeric characters, a space, one or more numeric characters. At the start of the string.
How can I get this working in Match Regular Expression? I am working in LabVIEW 2010f2 32 bit. Here is the code snippet and the results:
Rob
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Robert Cole wrote:
I think I prefer the ~ for negation since ^ is also used for beginning of the string. But we work with what we have.
Let me offer you a tip and perhaps defend the honor of the regex a little bit. One of my favorite features of regexes is the ability to specify character classes (and their negation). One of the reasons I have to think about the ~ versus ^ is that I rarely use ^ in a regex alternative.
Some examples:
[0-9] = \d (digit)
[^0-9] = \D (not a digit)
The equivalent regex for your case is: \D+ \d+

Match Regular Expression not returning submatches.

I am having an issue with Match Regular Expression not returning the appropriate number of submatches. My string is as follows:
DATAM 995000 1.75 0.007 -67.47 24.493 99.072
The spaces are tabs and the length is not fixed so simple string manipulation is out of the question. The regular expression I was trying is as follows:
(?<=\t)[0-9\.\-]*(?=(\t|$))
It successfully returns Whole Match as the first number but no submatches are returned. I've tried simpler expressions which work in Matlab and EditPad Pro such as [0-9.-]* but never got the same answer in Labview.
What is going on?

Here is an image of the VI. The top portion is the input from our Licor 7000. The bottom portion is the bit of code I'm having problems with.
Attachments:
matchregularexpression.jpg ‏336 KB

Question about match regular expression

Colleagues,
Very stupid question. I would like to get substring between "..." symbols. For example, string 02 July from Explosion occurred on "02 July", 2008.
How to do this with single Match Regular Expression?
For example such expression ".*" will give me "02 July":
But I would like to get it without " symbols!
I tried this "[~"]*" and this "[~"].*", then read this and this , and all without success... But I'm sure it should be possible. Can you help me?
Andrey.
PS
This regular expression should give exactly the same output as following construction:

I'm only using 7.0 now, but you can do this with Scan from String...
%[^"]"%[^"]"%[^"]
Message Edited by Phillip Brooks on 07-02-2008 02:47 PM
Now is the right time to use %^<%Y-%m-%dT%H:%M:%S%3uZ>T
If you don't hate time zones, you're not a real programmer.
"You are what you don't automate"
Inplaceness is synonymous with insidiousness
Attachments:
NotPCRE.png ‏20 KB

Parse Mac Address with match regular expression

Hi Everyone,
I have a problem with the Match Regular Expression function,
I am trying to parse the response two a arp -a 192.168.0.15 request in order to extract MAC address of this remote IP, I used the following RegEx: ^([0-9a-fA-F]{2}[:-]){5}([0-9a-fA-F]{2})$
I am wondering why do I need to do a string subset first to extract only the MAC Address part. Isn't Match Regular Expression function capable of recognizing the RegEx directly in the middle of a string?
I only works when I extract the right tring subset as in the picture bellow.
Thanks for your answers.
Solved!
Go to Solution.
Attachments:
Mac Address.JPG ‏40 KB

Get rid of the "^" in the beginning of your regular expression. You are instructing it to find the pattern at the beginning of the string.
Mark Yedinak
"Does anyone know where the love of God goes when the waves turn the minutes to hours?"
Wreck of the Edmund Fitzgerald - Gordon Lightfoot

Multi-line string - Array?

I was wondering if someone could tell me how to take a multi-line
string and dump it into an array. I'm assuming that I use the 'Pick
Line' function in a while loop? What do I check for to terminate the
loop?
Thanks...
-- N

"kevin" wrote in message news:...
> In article <[email protected]>, "Natalia"
> wrote:
>
> > I was wondering if someone could tell me how to take a multi-line string
> > and dump it into an array. I'm assuming that I use the 'Pick Line'
> > function in a while loop? What do I check for to terminate the loop?
> >
> > Thanks...
> >
> > -- N
>
> Natalia,
>
> Use the 'Spreadsheet String to Array' vi. Use the End of Line delimiter
> (or carriage return, depends on OS). Add a %s to the format string and
> POOF!, an instant text array. No loops required. Oh yeah, you also need
> to add an array string constant to the array type so the output comes ou
t
> as a string type instead of the default double.
>
> You can do it with you present method if you need the loops for other
> stuff. To terminate the loop just look for a -1 in the output of 'Pick
> Line' when searching for you CR or EOL. You just have to remember to dump
> the last value.
>
> good luck,
> - Kevin
Kevin -
Thank you. That did the trick.
-- Natalia

Pattern matching regular expressions

I'm attempting to determine if a string matches a pattern of containing less than 100 alphanumeric characters a-z or 0-9 case insensitive. So my regular expression string looks like:
"^[a-zA-Z0-9]{0,100}$"And I use something like...
Pattern pattern = Pattern.compile( regexString );I'd like to modify my regex string to include the email 'at' symbol "@". So that the at symbol will be allowed. But my understanding of regex is very limited. How do I include an "or at symbol" in my regex expression?
Thanks for your help.

* Code by sabre150
private static final Pattern emailMatcher;
    static
        // Build up the regular expression according to RFC821
        // http://www.ietf.org/rfc/rfc0821.txt
        // <x> ::= any one of the 128 ASCII characters (no exceptions)
        String x_ = "\u0000-\u007f";
        // <special> ::= "<" | ">" | "(" | ")" | "[" | "]" | "\" | "."
        //              | "," | ";" | ":" | "@" """ | the control
        //              characters (ASCII codes 0 through 31 inclusive and
        //              127)
        String special_ = "<>()\\[\\]\\\\\\.,;:@\"\u0000-\u001f\u007f";
        // <c> ::= any one of the 128 ASCII characters, but not any
        //             <special> or <SP>
        String c_ = "[" + x_ + "&&" + "[^" + special_ + "]&&[^ ]]";
        // <char> ::= <c> | "\" <x>
        String char_ = "(?:" + c_ + "|\\\\[" + x_ + "])";
        // <string> ::= <char> | <char> <string>
        String string_ = char_ + "+";
        // <dot-string> ::= <string> | <string> "." <dot-string>
        String dot_string_ = string_ + "(?:\\." + string_ + ")*";
        // <q> ::= any one of the 128 ASCII characters except <CR>,
        //               <LF>, quote ("), or backslash (\)
        String q_ = "["+x_+"$$[^\r\n\"\\\\]]";
        // <qtext> ::= "\" <x> | "\" <x> <qtext> | <q> | <q> <qtext>
        String qtext_ = "(?:\\\\[" + x_ + "]|" + q_ + ")+";
        // <quoted-string> ::= """ <qtext> """
        String quoted_string_ = "\"" + qtext_ + "\"";
        // <local-part> ::= <dot-string> | <quoted-string>
        String local_part_ = "(?:(?:" + dot_string_ + ")|(?:" + quoted_string_ + "))";
        // <a> ::= any one of the 52 alphabetic characters A through Z
        //              in upper case and a through z in lower case
        String a_ = "[a-zA-Z]";
        // <d> ::= any one of the ten digits 0 through 9
        String d_ = "[0-9]";
        // <let-dig> ::= <a> | <d>
        String let_dig_ = "[" + a_ + d_ + "]";
        // <let-dig-hyp> ::= <a> | <d> | "-"
        String let_dig_hyp_ = "[-" + a_ + d_ + "]";
        // <ldh-str> ::= <let-dig-hyp> | <let-dig-hyp> <ldh-str>
        // String ldh_str_ = let_dig_hyp_ + "+";
        // RFC821 looks wrong since the production "<name> ::= <a> <ldh-str> <let-dig>"
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        String ldh_str_ = let_dig_hyp_ + "*";
        // <name> ::= <a> <ldh-str> <let-dig>
        String name_ = "(?:" + a_ + ldh_str_ + let_dig_ + ")";
        // <number> ::= <d> | <d> <number>
        String number_ = d_ + "+";
        // <snum> ::= one, two, or three digits representing a decimal
        //              integer value in the range 0 through 255
        String snum_ = "(?:[01]?[0-9]{2}|2[0-4][0-9]|25[0-5])";
        // <dotnum> ::= <snum> "." <snum> "." <snum> "." <snum>
        String dotnum_ = snum_ + "(?:\\." + snum_ + "){3}"; // + Dotted quad
        // <element> ::= <name> | "#" <number> | "[" <dotnum> "]"
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        // <domain> ::= <element> | <element> "." <domain>
        String domain_ = element_ + "(?:\\." + element_ + ")*";
        // <mailbox> ::= <local-part> "@" <domain>
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        emailMatcher = Pattern.compile(mailbox_);
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    }Wow. Sheesh, sabre150 that's pretty impressive. I like it for two reasons. First it avoids some false negatives that I would have gotten using the regex I mentioned. Like, [email protected] is a valid email address which my regex pattern has rejected and yours accepts. It's unusual but it's valid. And second I like the way you have compartmentalized each rule so that changes, if any custom changes are desired, are easier to make. Like if I want to specifically aim for a particular domain for whatever reason. And you've commented it so that it is easier to read, for someone like myself who knows almost nothing about regex.
Thanks, Good stuff!

REGEXP_INSTR on a multi line string

Hello ,
I am trying to search through a string that is stored with multi line and trying to find the first occurrence of a character.
For example : The string is -
"This is a sample
text to test
from [first string] to [second string] "
When i try to search for the first occurrence of "[" and "]" regular instr function is returning the complete string
This is the query i used:
The above string is stored in a varchar2 column named - comments
select substr(comments,instr(comments,'['),instr(comments,']')) from my_table
This above query returns : [first string] to [second string]
i assume instr returns the first occurence of a letter in the given string. i was looking for [first string] but it returns me both. Can this be replaced with regexp_instr function?.
Any help on this would be much appreciated.
Thanks

user619203 wrote:
Hello ,
I am trying to search through a string that is stored with multi line and trying to find the first occurrence of a character.
For example : The string is -
"This is a sample
text to test
from [first string] to [second string] "
When i try to search for the first occurrence of "[" and "]" regular instr function is returning the complete string
This is the query i used:
The above string is stored in a varchar2 column named - comments
select substr(comments,instr(comments,'['),instr(comments,']')) from my_table
This above query returns : [first string] to [second string]
i assume instr returns the first occurence of a letter in the given string. i was looking for [first string] but it returns me both. Can this be replaced with regexp_instr function?.
Any help on this would be much appreciated.
Thankslike this?
SQL> ed
Wrote file afiedt.buf
1 with tmp as
2 (
3 select 'This is a sample
4 text to test
5 from [first string] to [second string]' txt from dual)
6 select substr(txt, instr(txt, '['), instr(txt, ']') - instr(txt, '[') + 1)
7* from tmp
SQL> /
SUBSTR(TXT,INS
[first string]Also questions of these types are better asked in {forum:id=75} forum.

Spliting a large string using regular expression which contain special char

I have huge sting(xml) containing normal character a-z,A-Z and 0-9 as well as special char( <,>,?,&,',",;,/ etc.)
I need to split this sting where it ends with </document>
for e.g.
Original String:
<document>
<item>sdf</item>
<item><text>sd</text</item>
</document>
<document>hi</document>
The above sting has to be splited in to two parts since it is having two document tag.
Can any body help me to resolve this issue. I can use StringTokenizer,String split method or Regular expression api too.

manas589 wrote:
I used DOM and sax parser and got few exception. Again i don't have right to change xml. so i thought to go with RegularExpression or some other way where i can do my job.If the file actually comes in lines like what you posted, you should just be able to compare the contents of each line to see if it contains "</document>" or whatever you're looking for. I wouldn't use regex unless I needed another problem.
I got excpetion like: Caused by: org.xml.sax.SAXParseException: The entity "nbsp" was referenced, but not declared.
     at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
     at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source)
     at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)So then it isn't even XML.
Edit: sorry, I just realized why you're considering all of these heavy-duty ideas. It's just that you don't know how to break the string into lines. You do it like this:
BufferedReader br = new BufferedReader(new StringReader(theNotXMLString));

Dumbfounded by Scanner processing String using regular expression

I was reading Bruce Eckel's book when I came across something interesting: extending Scanner with regular expressions. Unfortunately, I was confronted with an issue that doesn't make much sense to me: if the String that I am scanning contains a hyphen, the Scanner doesn't produce anything. As soon as I take it out, it all works like a charm. Here is my example:
import java.util.Scanner;
import java.util.regex.*;
public class StringScan {
public static void main (String [] args){
     String input = "there's one caveat when scanning with regular expressions";
     Scanner scanner = new Scanner (input);
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     while (scanner.hasNext(pattern)){
          scanner.next(pattern);
          MatchResult match = scanner.match();
          String output = match.group();
          System.out.println(output);
}What could be the reason? I imagined it could be because the hyphen for some reason gets given a special meaning but when I tried escaping it, it still didn't work.

Thanks for your prompt reply.
I have figured out what was wrong with my code, by the way. Since a single quote is not a word character, it does not match w+. And as the very first input token does not match, the scanner stops immediately. I rewrote my regex to "[a-z].*" and now it does work.

Multi-line String - Match Regular Expression

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