Need help with agent determination for release workflow

Hi,
I am trying to perform a release in the contract(FS-contract management) by using the framework for principle of dual control. When i create a contract, i get a message that says contract created, not yet released. But i am not able to get the work item in my inbox to release the contract. The SWI1 transaction shows 'no agent' for the triggered workflow. I am using the template WS50100021 as there is only one release step. By default there is a rule '50100017' given for the template. But in the customizing settings i have the section called 'assign rule to release steps'. Do i need to assign a rule here for agent determination. If so, what about the rule in the WS50100021 template? Which one should i use? I am able to execute the method 'release' of object BUSISB001 from SWO1 and release or reject the contract creation. But i am not able to get the workitem in my inbox in SBWP transaction

Hi Suhas,
The rule used in workflow template WS50100021 is a standard one. So try to find out that on what basis it is fetching the agents. It could be the case that the logic specified in the rule does not fulfill your requirement.
The other reason could be that you have not specified the task as general. Please check if the agents tab is activated(green) in the task or not. If it is not you need to set the task as general.
SOLUTION : if you want to get the workitem in your own SAP Inbox for testing purpose, you can set the WFINITIATOR as agent instead of that standard rule. This setting will send the workitem in your own SAP Inbox.
Regards,
Guddan

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    https://www.sdn.sap.com/irj/sdn/developerareas/xi?rid=/webcontent/uuid/a680445e-0501-0010-1c94-a8c4a60619f8
    1. SAP XI Certification - Important Topics
    2. Regarding XI Certification Material.
    3. Xi sample Certification questions
    XI certification passing used to be normally 65%. It may vary based on the runtime exam rules.
    There are marks as well as no of questions allocated for every section, so you may refer below link
    you can go to the following site and check the information.
    https://service.sap.com/%7Esapidp/011000358700005902252004E
    https://service.sap.com/~sapidp/011000358700003595762004E
    SAP XI Certification - Important Topics All about XI certification
    Thanks
    Swarup

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    This topic has been moved to MSI Notebook.
    https://forum-en.msi.com/index.php?topic=128552.0

    Mike,
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    try calling Apple suport

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    See sample data and what i expect.
    Thank you all for your help.
    We use Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
    Here the sample data tables:
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    (     "ORDER_NR"      VARCHAR2 (12)
    ,      "PRIORITY"      VARCHAR2 (2)
    ,      "WO_STEP"      VARCHAR2 (1)
    ,      "STEP_DATE"      DATE
    CREATE      TABLE      TABLE_1
    (     "ORDER_NR"           VARCHAR2     (12) PRIMARY KEY
    ,      "PRIORITY"           VARCHAR2      (2)
    ,      "CREATE_DATE"      DATE
    ,     "ACT_STEP"          VARCHAR2     (2)
    ,     "STEP_DATE"          DATE
    ,     "EMPLOYEE"          VARCHAR2     (5)
    ,     "DESCRIPTION"     VARCHAR2     (20)
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                        VALUES           ('1KKA1T205634',     '12',          TO_DATE('10-FEB-13 10:00:00','DD-MON-RR HH24:MI:SS'),     'U',          TO_DATE('28-FEB-13 12:00:00','DD-MON-RR HH24:MI:SS'),     'W0010',     'CLEAN HOUSE');
    INSERT      INTO      TABLE_1      (ORDER_NR,               PRIORITY,     CREATE_DATE,                                                        ACT_STEP,     STEP_DATE,                                                            EMPLOYEE,     DESCRIPTION)
                        VALUES           ('1KKA1Z300612',     '12',          TO_DATE('08-FEB-13 14:00:00','DD-MON-RR HH24:MI:SS'),     'F',          TO_DATE('20-FEB-13 16:00:00','DD-MON-RR HH24:MI:SS'),     'K0052',     'REPAIR CAR');
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'A',          TO_DATE('12-FEB-13 13:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          '5',          TO_DATE('13-FEB-13 09:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'K',          TO_DATE('13-FEB-13 10:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          '5',          TO_DATE('13-FEB-13 11:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'K',          TO_DATE('13-FEB-13 12:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          '5',          TO_DATE('13-FEB-13 16:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'C',          TO_DATE('14-FEB-13 08:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'B',          TO_DATE('14-FEB-13 10:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'E',          TO_DATE('18-FEB-13 13:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'F',          TO_DATE('20-FEB-13 16:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'S',          TO_DATE('21-FEB-13 08:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'R',          TO_DATE('21-FEB-13 09:00:00','DD-MON-RR HH24:MI:SS'));
    INSERT     INTO      TABLE_2      (ORDER_NR,               PRIORITY,     WO_STEP,     STEP_DATE)
                        VALUES           ('1KKA1T205634',     '12',          'U',          TO_DATE('28-FEB-13 12:00:00','DD-MON-RR HH24:MI:SS'));
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    COMMIT;And here is what i expect from my query:
    SYSDATE     28.Feb.13 14:00                                                                                     
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    1KKA1T205634     12     10.Feb.13 10:00     U     28.Feb.13 12:00     CLEAN HOUSE     18,083     8,833     2,125     0,833     4,125     0,083     0,750     0,208     2,125     0,666     0,042     7,125     
    1KKA1Z300612     12     08.Feb.13 14:00     F     20.Feb.13 16:00     REPAIR CAR     20,000     16,042     2,125     0,833     4,125     0,083     0,750     0,208     2,125     0,666          And now the explanation to the query result:
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    Thanks all for your help.
    Greets Reinhard W.

    Hi,
    i changed this query:
    with t2 as (
                select  t.*,
                        lead(step_date) over(partition by order_nr order by step_date) next_step_date
                  from  table_2 t
    select  t1.*,
            nvl(
                max(
                    case t2.wo_step
                      when 'U' then t2.step_date
                    end
               sysdate
              ) - t1.create_date age_1,
            nvl(
                max(
                    case t2.wo_step
                      when 'R' then t2.step_date
                    end
               sysdate
              ) - t1.create_date age_2,
            sum(
                case t2.wo_step
                  when 'B' then t2.next_step_date - t2.step_date
                end
               ) step_b
      from  table_1 t1,
            t2
      where t2.order_nr = t1.order_nr
      group by t1.order_nr,
               t1.priority,
               t1.create_date,
               t1.act_step,
               t1.step_date,
               t1.employee,
               t1.descriptionTo this:
    with t2 as (
                select  t.*,
                        lead(step_date) over(partition by order_nr order by step_date) next_step_date
                  from  table_2 t
    select  t1.order_nr,
            nvl(
                max(
                    case t2.wo_step
                      when 'U' then t2.step_date
                    end
               sysdate
              ) - t1.create_date age_1,
            nvl(
                max(
                    case t2.wo_step
                      when 'R' then t2.step_date
                    end
               sysdate
              ) - t1.create_date age_2,
            sum(
                case t2.wo_step
                  when 'B' then t2.next_step_date - t2.step_date
                end
               ) step_b
      from  table_1 t1,
            t2
      where t2.order_nr = t1.order_nr
      group by t1.order_nrthen i get the ORA-00979 Error.
    Whats wrong?
    I have another question.
    How can i handle i i want to group to or more 'STEP's in one Column.
    in Case of this i want that the column 'STEP_B' contains all days for STEP 'B' and STEP '5'.
    I tried already with a + Operation like this:
    with t2 as (
                select  t.*,
                        lead(step_date) over(partition by order_nr order by step_date) next_step_date
                  from  table_2 t
    select  t1.*,
            nvl(
                max(
                    case t2.wo_step
                      when 'U' then t2.step_date
                    end
               sysdate
              ) - t1.create_date age_1,
            nvl(
                max(
                    case t2.wo_step
                      when 'R' then t2.step_date
                    end
               sysdate
              ) - t1.create_date age_2,
            Round( sum(
                case t2.wo_step
                  when 'B' then t2.next_step_date - t2.step_date
                end
               ) +
            sum(
                case t2.wo_step
                  when '5' then t2.next_step_date - t2.step_date
                end
               ), 3 ) step_b
      from  table_1 t1,
            t2
      where t2.order_nr = t1.order_nr
      group by t1.order_nr,
               t1.priority,
               t1.create_date,
               t1.act_step,
               t1.step_date,
               t1.employee,
               t1.descriptionBut this does reply evertime a NULL.
    Thank You.

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    5) Export files in JPEG form into the same client folder.
    6) At the end of the year I save the catalog, make a new catalog for the new year. I delete the RAW files off of my hard drive after backing them up on 2TB external hard drive. I leave the jpegs and the client's folder on the computer hard drive.

    My guess is that you are not actually deleting the original raws from your internal hard drives and have lots and lots of crud around that you are not aware off so you should go through your internal drives with a fine-toothed comb. Don't forget to actually empty the trash when you delete! 1TB is more than enough disk space for storing the Lightroom catalog file, previews and some jpegs. 30.000 photos is really not that much. My main catalog  has >50.000 images in it with the raw files all stored on external hard drives. The catalog itself is on my internal 256 GB SSD HD that also houses the previews (so I can use it with the raw files offline) and the operating system as well as a lot of software (photoshop, office, iWorks, Aperture, etc.). It is more than enough space as it still has more than 150 GB free. I automatically back up everything, including the external HD that stores the raw images to separate external HDs stored in different places.

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