OID And Java Hash Algorithm Output Differences?

Question

Hi,
Can anyone tell me why I am not able to recreate the OID ldap password hash algorithm? Or can anyone tell me why I get these subtle differences between my Java created message digest and the one that is read directly from the oracle ldap hint password field? They are both based on the same original word "test".
OID Hint Password from ldap ==> {SHA}zrFqbho8VPUOnVvtyUb4c+RWF+k=
Hash created based on input ==> {SHA}zrFqbho8VPUOP1vtyUb4c+RWF+k=
Here is a little background. I am working on developing a custom forgot password feature for my web site using OID 10g R2 and Java. I am able to retrieve the oracle hint password from OID using Java JNDI as the orcladmin. This ldap password is a SHA message digest, or hash, that is base 64 encoded. Since it is a one way algorithm I can not decrypt. So instead I take the clear text password string provided by the user and create a message digest(SHA) and then encode in base 64 using Java 1.4.2 like so;
MessageDigest md = MessageDigest.getInstance("SHA");
md.update(clearTextPassword.getBytes());
String userSuppliedPassword = new String(md.digest());
BASE64Encoder base64encoder = new BASE64Encoder();
String output = "{SHA}" + base64encoder.encode(userSuppliedPassword.getBytes());
By the way, I have been able to work around this issue by performing the compare using JNDI search but was curious why this was happening. Thanks!

Answer 1

Hi
I am having similar issue. I have to save passwords in encrypted form to LDAP. But not working. I am prepending the encrypted password {SHA} so OID should not convert further.
Any help is appreciated
Thanks