OpenSQLException - The SQL statement "INSERT INTO "KMC_SUB_RCPT"...

Hallo,
We have the problem that subscriptions cannot be sent. In defaultTrace I have found following entry:
#1.5 #32B150008004002400001641000710B80004539FE52B4274#1217846116565#com.sapportals.wcm.repository.service.subscription.wcm.SubscriptionsOpenSQL#sap.com/irj#com.sapportals.wcm.repository.service.subscription.wcm.SubscriptionsOpenSQL#LI01736#118449##iscp63.isc.aok.de_LFP_399377450#LI01736#03186780621111ddb4c432b150008004#SAPEngine_Application_Thread[impl:3]_10##0#0#Fatal##Plain###Cannot unsubscribe user. Context: ResourceContext: user=LI01736, creationTime=1217846116420, locale=de. User: LI01736. ID: 50cdd784-51ac-2810-2393-ea9709f50de3. Recipient: com.sapportals.wcm.util.channels.wcm.Recipient@ce9b7f70. Step: Executing SQL INSERT. . Trying to rollback transaction.#
#1.5 #32B150008004002400001643000710B80004539FE52B989A#1217846116586#com.sap.sql.jdbc.common.StatementAnalyzerImpl#sap.com/irj#com.sap.sql.jdbc.common.StatementAnalyzerImpl#LI01736#118449##iscp63.isc.aok.de_LFP_399377450#LI01736#03186780621111ddb4c432b150008004#SAPEngine_Application_Thread[impl:3]_10##0#0#Error#1#/System/Database/sql/jdbc/common#Java#com.sap.sql_0019##Exception of type com.sap.sql.log.OpenSQLException caught: The SQL statement "INSERT INTO "KMC_SUB_RCPT" ("ID","RECIPIENT","RCPTTYPE","UNSUBSCRIBED") VALUES ('50cdd784-51ac-2810-2393-ea9709f50de3','LI01736','0','X')" contains the semantics error[s]: - 1:27 - the column >>ID<< is undefined in the current scope
[EXCEPTION]
#3#com.sap.sql.log.OpenSQLException#The SQL statement "INSERT INTO "KMC_SUB_RCPT" ("ID","RECIPIENT","RCPTTYPE","UNSUBSCRIBED") VALUES ('50cdd784-51ac-2810-2393-ea9709f50de3','LI01736','0','X')" contains the semantics error[s]: - 1:27 - the column >>ID<< is undefined in the current scope
#com.sap.sql.log.OpenSQLException: The SQL statement "INSERT INTO "KMC_SUB_RCPT" ("ID","RECIPIENT","RCPTTYPE","UNSUBSCRIBED") VALUES ('50cdd784-51ac-2810-2393-ea9709f50de3','LI01736','0','X')" contains the semantics error[s]: - 1:27 - the column >>ID<< is undefined in the current scope
     at com.sap.sql.jdbc.common.StatementAnalyzerImpl.check(StatementAnalyzerImpl.java:38)
     at com.sap.sql.jdbc.common.StatementAnalyzerImpl.preprepareStatement(StatementAnalyzerImpl.java:101)
     at com.sap.sql.jdbc.common.StatementAnalyzerImpl.preprepareStatement(StatementAnalyzerImpl.java:87)
     at com.sap.sql.jdbc.common.CommonStatementImpl.executeUpdate(CommonStatementImpl.java:159)
     at com.sap.engine.services.dbpool.wrappers.StatementWrapper.executeUpdate(StatementWrapper.java:162)
     at com.sapportals.wcm.repository.service.subscription.wcm.SubscriptionsOpenSQL$SqlCommand.executeUpdate(SubscriptionsOpenSQL.java:3834)
     at com.sapportals.wcm.repository.service.subscription.wcm.SubscriptionsOpenSQL.unsubscribe(SubscriptionsOpenSQL.java:2127)
     at com.sapportals.wcm.repository.service.subscription.wcm.SubscriptionManager.unsubscribe(SubscriptionManager.java:3226)
     at com.sapportals.wcm.repository.service.subscription.wcm.SubscriptionManager.unsubscribe(SubscriptionManager.java:3205)
     at com.sapportals.wcm.repository.service.subscription.wcm.ActionInboxItemProducer.executeItemAction(ActionInboxItemProducer.java:222)
     at com.sapportals.wcm.service.actioninbox.wcm.ActionInboxService.executeItemAction(ActionInboxService.java:610)
     at com.sapportals.wcm.service.actioninbox.wcm.ActionInboxService.executeItemActions(ActionInboxService.java:1221)
     at com.sapportals.wcm.control.actioninbox.ActionInboxDetailsControl.onClick(ActionInboxDetailsControl.java:396)
Any Idea?
Regards,
Gerhard

Statement statement = connection.createStatement();
//createing a statement object
String query= "INSERT INTO table......"
output.append("\nSending query:" + connection.nativeSQL(query));
int result = statement.executeUpdate(query);//updates database wit record
if (result==1)
output.append("\ninsertation successfull");
JOptionPane.showMessageDialog(null,"Insertation successfull ",
JOptionPane.INFORMATION_MESSAGE);
else
output.append("\ninsertation unsuccessfull");
JOptionPane.showMessageDialog(null,"Insertation unsuccessfull",
JOptionPane.WARNING_MESSAGE);
statement.close();
have left out the trys and catches and some other bits and pieces that i dont think ud need its the bare bones but it might help or at least give u an idea. have used this code before to do something similar.

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