ORACLE 10g PERFORMANCE ON SOLARIS 10

Hi all,
In sunfire v890 we have installed oracle 10g release 2 on solaris 10.
prstat -a command shows :
NPROC USERNAME SIZE RSS MEMORY TIME CPU
105 root 9268M 6324M 20% 1:21:57 0.4%
59 oracle 24G 22G 71% 0:04:33 0.1%
2 nobody4 84M 69M 0.2% 0:11:32 0.0%
2 esbuser 13M 9000K 0.0% 0:00:46 0.0%
1 smmsp 7560K 1944K 0.0% 0:00:00 0.0%
4 daemon 12M 7976K 0.0% 0:00:00 0.0%
and top utility shows :
last pid: 8639; load avg: 0.09, 0.09, 0.09; up 2+06:05:29 17:07:50
171 processes: 170 sleeping, 1 on cpu
CPU states: 98.7% idle, 0.7% user, 0.7% kernel, 0.0% iowait, 0.0% swap
Memory: 32G phys mem, 22G free mem, 31G swap, 31G free swap
therefore from prstat we come to know that memory used by oracle is 71%
where as top says 31.25% used.....
which one is true in this scenario.....
shall we go ahead in trusting top utility????
Advance thanks to you.

therefore from prstat we come to know that memory
used by oracle is 71%
where as top says 31.25% used.....
which one is true in this scenario.....
shall we go ahead in trusting top utility????In this case top is more accurate. prstat pretends all the memory used by each Oracle process is used only by that process. But lots of the memory used by Oracle is shared between several processes. prstat is counting that shared memory over and over for each process... resulting in the higher figure.
http://forum.java.sun.com/thread.jspa?threadID=5114263&tstart=105
Regards,
[email protected]
http://www.HalcyonInc.com

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    53 The rows from step 52 were inserted into using direct-load insert.
    54 Every row in the table SYS.SYS_TEMP_0FD9FC8FC_DC4EE804 is read.
    55 A view definition was processed, either from a stored view WEIJ. or as defined by steps 54.
    56 Rows were retrieved using the unique index Partitions determined by Key Values.
    57 Rows from table Partitions determined by Key Values were accessed using rowid got from a local (single-partition) index.
    58 PARTITION LIST SINGLE
    59 A range of partitions of steps 58 were accessed..
    60 For each row retrieved by step 55, the operation in step 59 was performed to find a matching row.
    61 Every row in the table SYS.SYS_TEMP_0FD9FC8FC_DC4EE804 is read.
    62 A view definition was processed, either from a stored view WEIJ. or as defined by steps 61.
    63 Return all rows from steps 60, 62 - including duplicate rows.
    64 TEMP TABLE TRANSFORMATION
    65 Rows were returned by the SELECT statement.

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