Outer join with effective date in peoplesoft query

Hi,
I'm trying to join two tables using outer join. Both tables are effective dated:
Dept_Tbl: dept_id, status, effdt
Tips_Tbl: dept_id, tips_id, effdt
Not all records in Dept_Tbl are in Tips_Tbl. I need to get all active depts and their most recent tips_id if they have one.
select a.dept_id, b.tips_id
from dept_tbl a, tips_tbl b
where a.status = 'Active'
and a.effdt =
(select max(a_ed.effdt) from dept_tbl a_ed
where a.dept_id = a_ed.dept_id
and a_ed.effdt <= SYSDATE)
and b.dept_id(+) = a.dept_id
and b.effdt =
(select max(b_ed.effdt) from tips_tbl b_ed
where b.dept_id = b_ed.dept_id
and b.tips_id = b_ed.tips_id
and b_ed.effdt <= SYSDATE)
The query only returns records that are in both tables.
Is there a way for outer join to work with effective dates?
Thanks in advance,
Reg

Here is an example of one solution. Note the use of NVL on both sides of the equal sign since both sides could be NULL in the case of the outer join
with dept_tbl as (select 1 dept_id, SYSDATE effdt FROM DUAL),
     tips_tbl as (select 1 dept_id, NULL effdt FROM DUAL)
select a.effdt
  from dept_tbl a,
       tips_tbl b
where b.dept_id(+) = a.dept_id
   and NVL(b.effdt, SYSDATE) = NVL((select max(b_ed.effdt)
                                      from tips_tbl b_ed
                                     where b.dept_id = b_ed.dept_id
                                       and b_ed.effdt <= SYSDATE), SYSDATE);
EFFDT
5/7/2007 3:25:00 PM

Similar Messages

  • Maximum number of tables that can be outer joined with one table in a query

    Hi All,
    Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
    Thanks,
    Srini

    srinu2 wrote:
    Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
    There is no limit to the number of tables you can outer join as long as you join them correctly.
    SQL> with a as
      2      (
      3      select 1 id, 2 b_key, 3 c_key from dual union all
      4      select 2 id, 1 b_key, 4 c_key from dual union all
      5      select 3 id, 3 b_key, 1 c_key from dual union all
      6      select 4 id, 4 b_key, 2 c_key from dual
      7      ),
      8      b as
      9      (
    10      select 1 id, 1 c_key2 from dual union all
    11      select 2 id, 5 c_key2 from dual union all
    12      select 3 id, 3 c_key2 from dual union all
    13      select 4 id, 2 c_key2 from dual
    14      ),
    15      c as
    16      (
    17      select 1 key1, 1 key2, '1-1' dta from dual union all
    18      select 1 key1, 2 key2, '1-2' dta from dual union all
    19      select 1 key1, 3 key2, '1-3' dta from dual union all
    20      select 1 key1, 4 key2, '1-4' dta from dual union all
    21      select 2 key1, 1 key2, '2-1' dta from dual union all
    22      select 2 key1, 2 key2, '2-2' dta from dual union all
    23      select 2 key1, 3 key2, '2-3' dta from dual union all
    24      select 2 key1, 4 key2, '2-4' dta from dual union all
    25      select 3 key1, 1 key2, '3-1' dta from dual union all
    26      select 3 key1, 2 key2, '3-2' dta from dual union all
    27      select 3 key1, 3 key2, '3-3' dta from dual union all
    28      select 3 key1, 4 key2, '3-4' dta from dual union all
    29      select 4 key1, 1 key2, '4-1' dta from dual union all
    30      select 4 key1, 2 key2, '4-2' dta from dual union all
    31      select 4 key1, 3 key2, '4-3' dta from dual union all
    32      select 4 key1, 4 key2, '4-4' dta from dual
    33      )
    34  select d.a_id, d.b_id, c.key1 as c_key1, c.key2 as c_key3, c.dta
    35  from
    36      c,
    37      (
    38      select
    39          a.id as a_id, b.id as b_id, a.c_key, b.c_key2
    40      from a, b
    41      where a.b_key = b.id
    42      ) d
    43  where d.c_key = c.key1 (+)
    44  and   d.c_key2 = c.key2 (+);
          A_ID       B_ID     C_KEY1     C_KEY3 DTA
             3          3          1          3 1-3
             4          4          2          2 2-2
             2          1          4          1 4-1
             1          2
    SQL>

  • Case statement resulting into Left outer join with other tables

    Hi All ,
    I am facing a stuation where a Case statement on one of the logical columns in Answers is resulting into a left outer join with a table in the query.
    If we remove the case stmt, the table is not being acessed.
    The case stmt is a simple one and no other logical column is being accessed in the case stmt.
    Please advice .
    Thanks.

    Hi Sai,
    No ..we dont have any left outer join ...its just that I am selecting measure from F1 which has a confimred dimension D1 with F2.Now when I dont have case stmt on measure from F1(Case stmt is something like : CASE WHEN "- P table"."P Column" = 'Y' THEN 'Right' ELSE 'Wrong' END), then it doesnt query F2.
    However as soon as I introduce the case stmt ,the query creates a left outer join with F2.
    Thanks.

  • Outer Join with the query

    I have written the below query, our requirement is, Some employees have "Transport Allowance" but not "Project Allowance". For this, I tried to use OUTER JOIN with this query. But this query takes long time and failed. The following query works fine if the employee has both "Transport Allowance" and "Project Allowance" (without outer join) Now, I also need to retrieve the employees who have "Transport Allowance" but not "Project Allowance". How can I retrieve it?
    SELECT DISTINCT papf.employee_number
    , peev.screen_entry_value Transport_Allowance
    ,peev1.screen_entry_value Project_Allowance
    FROM apps.per_all_people_f papf
    ,apps.per_all_assignments_f paaf
    ,apps.pay_element_types_x petf
    ,apps.pay_element_types_x petf1
    ,apps.pay_element_types_x petf2
    ,apps.pay_element_entries_f peef
    ,apps.pay_element_entries_f peef1
    ,apps.pay_element_entries_f peef2
    ,apps.pay_element_entry_values_x peev
    ,apps.pay_element_entry_values_x peev1
    ,apps.pay_element_entry_values_x peev2
    ,apps.pay_input_values_x pivf
    ,apps.pay_input_values_x pivf1
    ,apps.pay_input_values_x pivf2
    WHERE
    papf.person_id = paaf.person_id
    AND paaf.assignment_id = peef.assignment_id
    AND paaf.assignment_id = peef1.assignment_id
    AND paaf.business_group_id = papf.business_group_id
    --Transport Allowance
    AND peef.element_entry_id = peev.element_entry_id
    AND petf.element_Name = 'Transport Allowance'
    AND pivf.element_type_id =petf.element_type_id
    AND pivf.name = 'Allowance'
    AND peev.input_value_id= pivf.input_value_id
    --Project Allowance
    AND peef1.element_entry_id = peev1.element_entry_id
    AND petf1.element_Name = "Project Allowance'
    AND pivf1.element_type_id = petf1.element_type_id
    AND pivf1.name = 'Allowance'
    AND peev1.input_value_id = pivf1.input_value_id
    AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
    AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
    AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
    ORDER BY papf.employee_number
    Thanks in advance.

    I am using sames tables with alias to retrieve the columns values from the same table.
    Here is my query.
    SELECT DISTINCT papf.employee_number
    , peev.screen_entry_value Transport_Allowance
    ,peev1.screen_entry_value Project_Allowance
    FROM apps.per_all_people_f papf
    ,apps.per_all_assignments_f paaf
    ,apps.pay_element_types_x petf
    ,apps.pay_element_types_x petf1
    ,apps.pay_element_entries_f peef
    ,apps.pay_element_entries_f peef1
    ,apps.pay_element_entry_values_x peev
    ,apps.pay_element_entry_values_x peev1
    ,apps.pay_input_values_x pivf
    ,apps.pay_input_values_x pivf1
    WHERE
    papf.person_id = paaf.person_id
    AND paaf.assignment_id = peef.assignment_id
    AND paaf.assignment_id = peef1.assignment_id
    AND paaf.business_group_id = papf.business_group_id
    --Transport Allowance
    AND peef.element_entry_id = peev.element_entry_id
    AND petf.element_Name = 'Transport Allowance'
    AND pivf.element_type_id =petf.element_type_id
    AND pivf.name = 'Allowance'
    AND peev.input_value_id= pivf.input_value_id
    --Project Allowance
    AND peef1.element_entry_id = peev1.element_entry_id
    AND petf1.element_Name = "Project Allowance'
    AND pivf1.element_type_id = petf1.element_type_id
    AND pivf1.name = 'Allowance'
    AND peev1.input_value_id = pivf1.input_value_id
    AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
    AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
    AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
    ORDER BY papf.employee_number
    Thanks in advance.

  • Problem with outer join with filter on join column

    Hi,
    In physical layer I have one dimension and two facts, and there's an outer join between the facts.
    dim_DATE ,
    fact_1 ,
    fact_2
    Joins:
    dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
    fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
    When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
    select fact1.X, fact2.Y
    from
    Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
    where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
    and  Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
    The filter on Fact_2.DATE effectively replaces outer join with inner.
    Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
    Thanks in advance,
    Alex
    Edited by: AM_1 on Aug 11, 2009 8:20 AM

    If you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
    * create in your physical layer for each fact table the joins with the dimension
    * create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
    In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
    Cheers
    Nico

  • Need to specify LEFT OUTER JOIN while using data from logical database BRM?

    I'm trying to extract data for external processing using SQVI. The fields required are in tables BKPF (Document Header) and BSEG (document detail) so I'm using logical database BRM. Note: required fields include the SPGR* (blocking reasons) which don't appear to be in BSIS/BSAS/BSID/BSAD/BSIK/BSAK, hence I can't just use a Table Join on any of these but have to use BSEG, hence BRM.
    If the document type is an invoice, I also need to include the PO number from table EKKO (PO header), if present, hence I'd like to add this to the list. However, if I do this, it seems that some records are no longer display, e.g. AB documents.
    The interesting thing is that not all records are suppressed, so it's not a simple case of the logical database using an effective INNER JOIN, but the effect is similar.
    In any event, is there a way to specify that the link to table EKKO should be treated as an effective LEFT OUTER JOIN, i.e. records from BKPF/BSEG should be included irrespective of whether any records from EKKO/EKPO exist or not?
    Alternatively, is there some other way to get the SPGR* fields (for example) from BSEG and still join the BKPF? Of course, one solution is to use multiple queries, but I was hoping to avoid this.

    Thanks for everyone's responses, I know how to work around the problem with sql, I am wanting to see if there is a way to make the outer joins filter go in the join clause instead of the where clause with Crystal Reports standard functionality. 
    We have some Crystal Reports users that are not sql users, i.e. benefit specialists, payroll specialists and compensation analysts who have Crystal Reports.  I was hoping this functionality was available for them.  I just made my example a simple one, but often reports have multiple outer joins with maybe 2 or three of the outer joins needing a filter on them that won't make them into an inner join. 
    Such as
    Select person information
    outer join address record
    outer join email record
    outer join tax record (filter for active state record & filter for code = STATE )
    outer join pay rates record
    outer join phone#s  (filter for home phone#)
    I thought maybe the functionality may be available, that I just don't know how or where to use it.  Maybe it is just not available.
    If it is not available, I will probably need to setup some standard views for them to query, rather than expecting them to pull the tables together themselves.

  • GL Trial Balance Report with Effective Dates as Parameters

    We have a requirement to show the GL Trial Balance report with Effective dates as Parameters.
    Current Analysis:
    The Journals get updated with corresponding CCID in GL_BALANCES table when the Journal is posted. GL_BALANCE is SOB specific, if the SOB has month as period then the balances in GL_BALANCES would get updated against the month(period).
    To overcome the period problem, we explored the option of using a View based on GL_JE_HEADERS and GL_JE_LINES for 'Posted' Journal Batches of a SOB. We are checking whether the GL_JE_HEADERS.default_effective_date lies between the :p_from_date and :p_to_date which is sent to the Report as a parameter. The above idea does not return expected data when the custom Trial Balance Report is run.
    Following is the Query being used:
    SELECT cc.segment4 ACCOUNT, bal.code_combination_id,
    bal.begin_balance_dr
    + SUM (NVL (gljel.accounted_dr, 0)) opening_bal_dr,
    bal.begin_balance_cr
    + SUM (NVL (gljel.accounted_cr, 0)) opening_bal_cr,
    ffv.description,
    (SELECT SUM (NVL (gljel.accounted_dr, 0))
    FROM gl_je_headers gljeh,
    gl_je_lines gljel,
    gl_code_combinations gcc
    WHERE gljeh.default_effective_date BETWEEN :p_from_date
    AND :p_to_date
    AND gljeh.je_header_id = gljel.je_header_id
    AND gljel.code_combination_id = gcc.code_combination_id
    AND gljel.period_name = gljeh.period_name
    AND gljel.set_of_books_id = :p_set_of_books_id
    AND gljeh.status = 'P'
    AND gljel.status = 'P'
    AND gljeh.actual_flag = 'A'
    --AND gljel.code_combination_id =
    -- bal.code_combination_id
    AND gcc.segment4 = cc.segment4
    GROUP BY gcc.segment4) c_dr,
    (SELECT SUM (NVL (gljel.accounted_cr, 0))
    FROM gl_je_headers gljeh,
    gl_je_lines gljel,
    gl_code_combinations gcc
    WHERE gljeh.default_effective_date BETWEEN :p_from_date
    AND :p_to_date
    AND gljeh.je_header_id = gljel.je_header_id
    AND gljel.period_name = gljeh.period_name
    AND gljel.code_combination_id = gcc.code_combination_id
    AND gljel.set_of_books_id = :p_set_of_books_id
    AND gljeh.status = 'P'
    AND gljel.status = 'P'
    AND gljeh.actual_flag = 'A'
    AND gcc.segment4 = cc.segment4
    GROUP BY gcc.segment4) c_cr
    FROM gl_period_statuses per,
    gl_code_combinations cc,
    gl_balances bal,
    gl_je_headers gljeh,
    gl_je_lines gljel,
    fnd_flex_values_vl ffv,
    fnd_flex_value_sets ffvs
    WHERE cc.chart_of_accounts_id = :p_chart_of_accts_id
    AND bal.currency_code = :p_currency
    AND bal.actual_flag = 'A'
    AND bal.period_name = per.period_name
    AND cc.template_id IS NULL
    AND cc.code_combination_id = bal.code_combination_id
    AND per.set_of_books_id = :p_set_of_books_id
    AND per.application_id = 101
    AND :p_from_date BETWEEN per.start_date AND per.end_date
    AND gljeh.period_name = per.period_name
    AND gljeh.default_effective_date <= :p_from_date
    AND gljeh.je_header_id = gljel.je_header_id
    AND gljel.period_name = gljeh.period_name
    AND gljel.set_of_books_id = :p_set_of_books_id
    AND ffv.flex_value_set_id = ffvs.flex_value_set_id
    AND ffvs.flex_value_set_name = 'JSWEL_ACCOUNT'
    AND gljeh.status = 'P'
    AND gljel.status = 'P'
    AND cc.summary_flag = ffv.summary_flag
    AND cc.segment4 = ffv.flex_value
    AND gljeh.actual_flag = 'A'
    AND gljel.code_combination_id = bal.code_combination_id
    GROUP BY bal.begin_balance_dr,
    bal.begin_balance_cr,
    cc.segment4,
    ffv.description,
    bal.code_combination_id
    Kindly suggest if I am missing anything. I am sure that the great guns here can help me out.
    Thanks
    Sumit

    suggest to create customize TB report.

  • How to achieve an outer join with existsNode() function

    I have a requirement to do an outer join with existsNode() function in my where clause. At present my where clause for join is like below
    WHERE A.SOME_ID= “XYZ”
    AND existsNode (B.SOMEXML_FEILD , …. ) = 1
    AND existsNode (C.SOMEOTHERXML_FEILD , …. ) = 1
    In this case if the existsNode fails on B or C, I still want data from A to be selected. How to rewrite this query to achieve that? I kinda want to achieve an outer join

    Hi,
    is this what you are looking for:
    SQL> with t as(select 1 id1,'A' name from dual union all
      2            select 2 ,'B' name from dual union all
      3            select 3,'C' from dual)
      4      ,x as(select 1 id2,xmltype('<a>a</a>') xcol from dual union all
      5            select 2 ,xmltype('<b>b</b>') xcol from dual)
      6  select *
      7  from t,x
      8  where t.id1=x.id2(+)
      9    and (existsNode(x.xcol,'/a')=1 or x.xcol is null);
           ID1 N        ID2 XCOL                                                   
             1 A          1 <a>a</a>                                               
             3 C                                                                   
    SQL> spool off;

  • Outer Join with Where Clause in LTS

    HI all,
    I have a requirement like this in ANSI SQL:
    select p1.product_id, p1.product_name, p2.product_group
    from product p1 left outer join product_group p2 on p1.product_id = p2.product_id
    and p2.product_group = 'NEW'
    In Regular SQL:
    select p1.product_id, p1.product_name, p2.product_group
    from product p1, product_group p2
    WHERE p1.product_id *= p2.product_id and p2.product_group = 'NEW'
    In OBIEE, I am using a left outer join between these two in Logical table Source, and also, Gave
    p2.product_group = 'NEW' in WHERE clause of LTS.
    This doesn't seem to solve purpose.
    Do you have any idea how to convert WHERE clause in physical query that OBIEE is generating to something like
    product p1 left outer join product_group p2 on p1.product_id = p2.product_id AND p2.product_group = 'NEW'
    I am using Version 10.1.3.4.1
    Creating an Opaque view would be my last option though.

    Hello
    I have read your post and the responses as well. and I understand that you have issues with the Outer Join with where Clause in LTS.
    Try this solution which worked for me (using your example ) -
    1. In the Physical Layer created a Complex join between PRODUCT and PRODUCT_GROUP tables and use this join relationship :
    PRODUCT.PROD_ID = PRODUCT_GROUP.PROD_ID  AND  PRODUCT_GROUP.GROUP_NAME = 'MECHANICAL' 
    2. In the General Tab of PRODUCT table LTS add PRODUCT_GROUP  table and select Join Type as Left Outer Join.
    3. Check Consistency and make sure there are no errors .
    when you run a request you should see the following query generated -
    select distinct T26908.PROD_ID as c1,
         T26908.PROD_NAME as c2,
         T26912.GROUP_NAME as c3
    from
         PRODUCT T26908 left outer join PRODUCT_GROUP T26912 On T26908.PROD_ID = T26912.PROD_ID and T26912.GROUP_NAME = 'MECHANICAL'
    order by c1, c2, c3
    Hope this works for you. If it does please mark this response as 'Correct' .
    Good Luck.

  • Outer join With a constant value

    Hi all,
    In one of query i have found out that the outer join with a constant value like
    to_currency(+)='USD'
    to_currency is a column name in a table.can any one please explain this outer join condtn.
    Thanks in advance
    Senthil

    Hallo,
    if you write var (+) = constant
    var can be equal constant, and also can be null
    Compare these 2 queries
    select e.* from scott.emp e, scott.dept d
    where e.deptno = d.deptno(+)
    and d.deptno(+) = 10EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    7369     SMITH      CLERK      7902     17-Dez-1980     800          20
    7499     ALLEN      SALESMAN      7698     20-Feb-1981     1600     300     30
    7521     WARD      SALESMAN      7698     22-Feb-1981     1250     500     30
    7566     JONES      MANAGER      7839     2-Apr-1981     2975          20
    7654     MARTIN      SALESMAN      7698     28-Sep-1981     1250     1400     30
    7698     BLAKE      MANAGER      7839     1-Mai-1981     2850          30
    7782     CLARK      MANAGER      7839     9-Jun-1981     2450          10
    7788     SCOTT      ANALYST      7566     19-Apr-1987     3000          20
    7839     KING      PRESIDENT           17-Nov-1981     5000          10
    7844     TURNER      SALESMAN      7698     8-Sep-1981     1500     0     30
    7876     ADAMS      CLERK      7788     23-Mai-1987     1100          20
    7900     JAMES      CLERK      7698     3-Dez-1981     950          30
    7902     FORD      ANALYST      7566     3-Dez-1981     3000          20
    7934     MILLER      CLERK      7782     23-Jan-1982     1300          10
    select e.* from scott.emp e, scott.dept d
    where e.deptno = d.deptno(+)
    and d.deptno = 10 EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    7782     CLARK      MANAGER      7839     9-Jun-1981     2450          10
    7839     KING      PRESIDENT           17-Nov-1981     5000          10
    7934     MILLER      CLERK      7782     23-Jan-1982     1300          10
    As you can see, this (+) is very important
    Regards
    Dmytro

  • Outer Join with an 'OR'

    I have a very complicated query to construct that requires the use of 'AND', 'OR', and Outer Joins. Oracle's 9i documentation says you can't use an outer join with an 'OR'.
    Can you suggest how I may return the correct records under the following conditions. There are 3 tables to join. Table A, Table B, and Table C. Tables A & B join with an = to common fields. The problem is with Table C.
    The way the application was designed, it has to track a parent and child relationship. As such, the field to relate may exist in 1 of 2 fields. Let's see if I can draw it out for you.
    Table A - Record 1
    (ID = 1)
    Table B - Record 1
    (ID =1 [this relates to Table A.ID]
    PID = 12345
    CID = 67899
    Site = A)
    Table C - Record 1
    (PID = 12345 [this relates to Table B.PID]
    CID = 67899
    Site = A)
    Table C - Record 2
    (PID = 67899 [This relates to Table B.CID]
    CID = 12345
    Site = A)
    Now, I need to relate Table A to Table B where A.ID = B.ID AND
    ((B.PID = C.PID AND B.CID = C.CID)
    OR
    (B.CID = C.PID AND B.PID = C.CID))
    AND
    B.SITE = C.SITE
    There may or may NOT be related records in Table C. That's the problem. This is where I need the outer join to get the all the records of the 1st two joins and only those that apply from the last join.
    Your help will be greatly appreciated.

    I'd create two queries, a join from b to c in each of those manners and then UNION ALL the results together.
    drop table junk_a;
    create table junk_a (
      id number );
    drop table junk_b;
    create table junk_b (
      id number,
      pid number,
      cid number,
      site varchar2(80) );
    drop table junk_c;
    create table junk_c (
      pid  number,
      cid  number,
      site  varchar2(80) );
    insert into junk_a values (1);
    insert into junk_b values (1, 12345, 67899, 'A');
    insert into junk_c values (12345, 67899, 'A');
    insert into junk_c values (67899, 12345, 'A');
    commit;
    SELECT b.*,
           c.site AS site_c
      FROM junk_b b,
           junk_c c
    WHERE c.pid(+) = b.pid
       AND c.cid(+) = b.cid
    UNION ALL
    SELECT b.*,
           c.site AS site_c
      FROM junk_b b,
           junk_c c
    WHERE c.cid(+) = b.pid
       AND c.pid(+) = b.cid;
    SELECT a.id,
           bc.pid,
           bc.cid,
           bc.site,
           bc.site_c
      FROM junk_a  a,
    SELECT b.*,
           c.site AS site_c
      FROM junk_b b,
           junk_c c
    WHERE c.pid(+) = b.pid
       AND c.cid(+) = b.cid
    UNION ALL
    SELECT b.*,
           c.site AS site_c
      FROM junk_b b,
           junk_c c
    WHERE c.cid(+) = b.pid
       AND c.pid(+) = b.cid
           )  bc
    WHERE bc.id(+) = a.id;

  • Outer join with BETWEEN clause

    Hi All,
    I have 2 tables (A and B) which i need to join. I need all records from table A and matching records from the table B. below is the structure.
    TABLE A (total rows = 10)
    ROW_WID
    GL_DATE
    LOCATION_CODE
    TABLE B (total = 7)
    ROW_WID
    START_DATE
    END_DATE
    LOCATION_CODE
    Initially, we were asked to join based on location_code. In the table B, some of the LOCATION_CODE are missing, which is present in table A.
    We wrote below query
    SELECT A.*, B.START_DATE, B.END_DATE
    FROM A, B
    WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
    This gives 10 records, where 3 records have START_DATE and END_DATE NULL. because of outer join
    It gave all records from the A table. It worked fine. Now i need to add one more condition where A.GL_DATE between B.START_DATE and B.END_DATE
    If i write this
    SELECT A.*, B.START_DATE, B.END_DATE
    FROM A, B
    WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
    AND A.GL_DATE BETWEEN B.START_DATE and B.END_DATE
    This gives me only 7 records. IS IT POSSIBLE TO ADD OUTER JOIN with BETWEEN clause.

    Hi All,
    I'm in a similar situation,
    I have a complex query, everything is working fine, except this part (I will simplify everything, removing other stuffs because I need help only on the following condition)
    SELECT *
    from transaction t, card c
    where c.card_id = t.card_id (+)
    and t.trn_date between to_date ('01/01/2012','dd/mm/yy') and ('01/01/2013,'dd/mm/yy')
    How could i OUTER JOIN the between condition?
    I tried with
    and t.trn_date between to_date ('01/01/2012','dd/mm/yy') (+) and ('01/01/2013','dd/mm/yy') (+)
    but returns a "missing expression" error.
    Surely I'm missing some stupid thing about it, could you help me on this? (probably because I'm talking about parameters and I cannot put the outer join on a value)
    How can I rewrite the condition in order to satisfy what I'm trying to accomplish?
    Thanks in Advance,
    Alex
    Edited by: 981667 on 14-gen-2013 4.23
    Edited by: 981667 on 14-gen-2013 4.24

  • Join columns of outer join with table have no uniqueness cons

    Hi! I'm getting noizy error in alert log from time to time:
    Join columns of outer join with table <table_name> have no uniqueness constraints
    I've collected all the queries (v$sql, all_source) with montioned table, but non of them produces that error if executed.
    Any hints how to reproduce this error or where else to search that buggy sql join?
    Edited by: user545083 on 25.10.2010 6:21

    Hi
    I think this error is output via an materialized view refresh - check for mviews against the given table which fulfil the issue given in the error text.
    Thanks
    Paul

  • Inner join Vs Outer join with ABAP code...?

    Inner join Vs Outer join with ABAP code...?

    Inner Join means, it will not select that recor at all, unless there is a matching entry in the second table.
    suppose table VBAK INNER join table VBAP on VBAKVBELN = VBAPVBELN.
    In this case, if there are no entries in VBAP, the header entry also will not show up.
    But in case of OUTER JOIN, even if there is no items, it will show the header entry(VBAK) with blank columns for fields  from item table.(VBAP)
    here is one sample for inner join.
    SELECT   A~EBELN
               A~EKORG
               A~EKGRP
               A~BSART
               A~LPONR
               A~LOEKZ
               A~LIFNR
               A~RESWK
               B~AEDAT
               B~WERKS
               B~MATNR
               B~MENGE
               B~EBELP
               B~ELIKZ
               B~PLIFZ
               B~PSTYP
               B~KNTTP
               B~MATKL
               B~ZZD_PLANT
               FROM EKKO AS A INNER JOIN EKPO AS B
               ON
               AEBELN = BEBELN
               INTO CORRESPONDING FIELDS OF TABLE T_DATA
               FOR ALL ENTRIES IN T_EKET
               WHERE
               A~EBELN EQ T_EKET-EBELN AND
               A~BSART EQ C_UBSTO      AND
               A~EKORG IN S_EKORG      AND
               A~EKGRP IN S_EKGRP      AND
               A~BSTYP EQ C_BSTYP      AND
               A~LOEKZ EQ SPACE        AND " Order not deleted
               A~RESWK IN S_RESWK      AND
               B~EBELN EQ T_EKET-EBELN AND
               B~EBELP EQ T_EKET-EBELP AND
               B~WERKS IN S_WERKS      AND
               B~MATNR IN S_MATNR      AND
               B~MATKL IN S_MATKL      AND
               B~LOEKZ EQ SPACE.           " Line item not deleted

  • Peoplesoft Query Outer join with MAX EFFDT

    I have this criteria in my PS Query
    where A.emplid = B.emplid
    and B.effdt = (select max( B1.effdt ) from PS_TABLE_B B1 where B1.effdt <= SYSDATE )
    Need to do an OUTER JOIN for B.
    Ie. If no row found in B, then return blank so that row in A can be returned by query.
    It's OK for A.emplid = B.emplid(+)
    But how to approach for and B.effdt = (select max ... ?
    Please advise

    If I remember it right, if you write outer joins using ( + ), there shouldn't be any other non-outer join criteria in your SQL, otherwise it will negate its being an 'outer join'.
    so for your (1) this highlighted SQL block negates your 'outer join' condition
    AND A.EMPLID =  C.EMPLID(+)
    AND ( C.EFFDT = (SELECT MAX( D.EFFDT)
                             FROM PS_D D
                            WHERE D.EMPLID = C.EMPLID
                              AND D.ACTION_REASON = 'MAT'
                              AND ( D.RETURN_DT IS NULL OR D.RETURN_DT > SYSDATE))
                OR C.EFFDT IS NULL) )
    you should see more from here http://docs.oracle.com/cd/B28359_01/server.111/b28286/queries006.htm#SQLRF52336
    From that article, it says.. "If A and B are joined by multiple join conditions, then you must use the operator in all of these conditions. If you do not, then Oracle Database will return only the rows resulting from a simple join, but without a warning or error to advise you that you do not have the results of an outer join."
    What I suggest, create a SQL view to replace C that retrieves exactly what C has to retrieve.. probably something like this
    SELECT D.*
    FROM PS_D D
    WHERE D.ACTION_REASON = 'MAT'
      AND( D.RETURN_DT IS NULL OR D.RETURN_DT > SYSDATE )
      AND D.EFFDT = (SELECT MAX(EFFDT) ... )
    and reference that new SQL view for C.. so that in your query, it should only look something like
    AND A.EMPLID = C.EMPLID(+)
      AND( C.EFFDT =
      (SELECT MAX( D.EFFDT )
         FROM PS_D D
        WHERE D.EMPLID = C.EMPLID
        AND D.ACTION_REASON = 'MAT'
        AND( D.RETURN_DT IS NULL
        OR D.RETURN_DT > SYSDATE )
      OR C.EFFDT IS NULL ) )
    Hope this helps

Maybe you are looking for

  • Universe Design Suggestion for a Report

    Hi Guys, I am building a trend report from a fact table that was newly built in SQL server 2012. Prior to this table there was a manual process of data importing into SQL Server and then bringing into BO universe for reports. With the new change the

  • Need Help with Advanced Filters

    I hope someone can please help A.S.A.P. my current project depends on getting the searches to function correctly I have found the Multiple Filters very useful all it needs is a little tweaking, I have tried but failed 1st Main Problem The problem wit

  • Why is the iPad so slow on the net?

    Internet (and phone etc) all on cable with nominal download speed of 60Mb (reduces a bit when going to computer via router). Have added wireless access point (rated 300Mb) so I can connect the iPad (bought last Friday). Connections all fine, but the

  • Help needed: Search function for custom Repository Manager

    Hi there, i'm writing my own Repository Manager for EP 6.0 SP2 PL4. I've serious problems getting the search function running. I'm using the 'new', Netweaver-based API. I think, there are some general questions to answer: - My Repository Manager expo

  • Mv confirmation (URGENT)

    hi all, someone moved critical files on a server by mistake to another directory with the mv command. i need to do something that whenever any user enters the rm or mv command, it should ALWAYS ask for confirmation. I have used alias rm="rm -i" for t