Parent Child hierarchy Scenario
Hi friends,
Im just working on the parent child hierarchy using the following link with the sample data.
http://www.oracle.com/webfolder/technetwork/tutorials/obe/fmw/bi/bi11115/biadmin11g_02/biadmin11g.htm_
I tried to implement the same hierarchy using my local data instead of referring to the sample data.
I have a below query which returns the employee with manager along with the employee position
select distinct papf.person_id, papf.full_name "Employee Name", supf.person_id "Manager Id", supf.full_name "Manager Name", pj.name "Position Name"
from per_all_people_f papf, per_all_assignments_f paaf, per_all_people_f supf, per_jobs pj
where papf.person_id = paaf.person_id and supf.person_id = paaf.supervisor_id and paaf.job_id = pj.job_id
and trunc(sysdate) between paaf.effective_start_date and paaf.effective_end_date and
trunc(sysdate) between papf.effective_start_date and papf.effective_end_date
Im looking forward to implement the same result in my BI with a parent-child hierarchy.
Since i have imported three tables to my physical layer
per_all_people_f------------Dimension
per_all_assignments_f-----Fact
per_jobs---------------------DimensionFor creating parent-child in BI, we need to have a separate Parent child table which consist of four columns like ancestorkey, memberkey, distance, leaf.
From the above column i can understand the meaning like
For Ancestorkey-->Managerid
Memberkey------->Employeeid
But i couldnt get with the meaning for distance column as the meaning suggest like a distance b/w the two and leaf column as the meaning suggest like a leaf member. which leaf member does it refer.
I also referred the below link then too couldnt get the meaning for it
http://www.rittmanmead.com/2010/08/oracle-bi-ee-11g-parent-child-hierarchies-differing-aggregations/+
How i can form the parent child table for the BI from my above three tables of HRMS.
Thanks
Regards,
Saro
Hi friends,
I think i found a link of doing it
http://prasadmadhasi.com/2011/11/15/hierarchies-parent-child-hierarchy-in-obiee-11g/
Let me try this and will update accordingly.
Thanks for your views.
Regards,
Saro
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Hi All,
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http://www.rittmanmead.com/2010/07/obiee-11gr1-enhancements-to-essbase-support/
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===============================
(EmpKey|Name|Position| loginId| level| MgrKey)
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============================
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Elvis Long
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Z B
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notes **
the level of hierarchy is dynamic
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Didier
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Z.employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
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A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
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A.employee_id_5,
A.full_name_5,
A.supervisor_id_6,
A.employee_id_6,
A.full_name_6,
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Z.employee_id AS employee_id_7,
Z.full_name AS full_name_7
FROM employee Z,
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Z.full_name AS full_name_6
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SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
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A.supervisor_id_2,
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A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
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Z.employee_id AS employee_id_2,
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) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
WHERE A.employee_id_5 = Z.supervisor_id
) A
WHERE A.employee_id_6 = Z.supervisor_id
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SELECT DISTINCT
A.employee_id_6 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
A.supervisor_id_6,
A.employee_id_6,
A.full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
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Z.supervisor_id AS supervisor_id_6,
Z.employee_id AS employee_id_6,
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A.supervisor_id_1,
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A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
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A.supervisor_id_4,
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Z.full_name AS full_name_5
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A.employee_id_2,
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A.employee_id_1,
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A.supervisor_id_2,
A.employee_id_2,
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Z.supervisor_id AS supervisor_id_3,
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A.supervisor_id_1,
A.employee_id_1,
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Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
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SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
WHERE A.employee_id_5 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_5 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
A.supervisor_id_5,
A.employee_id_5,
A.full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
Z.supervisor_id AS supervisor_id_5,
Z.employee_id AS employee_id_5,
Z.full_name AS full_name_5
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
) A
WHERE A.employee_id_4 = Z.supervisor_id
) A
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A.employee_id_4 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
A.supervisor_id_4,
A.employee_id_4,
A.full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
Z.supervisor_id AS supervisor_id_4,
Z.employee_id AS employee_id_4,
Z.full_name AS full_name_4
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
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Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
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WHERE A.employee_id_2 = Z.supervisor_id
) A
WHERE A.employee_id_3 = Z.supervisor_id
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A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
A.supervisor_id_3,
A.employee_id_3,
A.full_name_3,
NULL AS supervisor_id_4,
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NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
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A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
Z.supervisor_id AS supervisor_id_3,
Z.employee_id AS employee_id_3,
Z.full_name AS full_name_3
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
WHERE A.employee_id_2 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_2 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
A.supervisor_id_2,
A.employee_id_2,
A.full_name_2,
NULL AS supervisor_id_3,
NULL AS employee_id_3,
NULL AS full_name_3,
NULL AS supervisor_id_4,
NULL AS employee_id_4,
NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
Z.supervisor_id AS supervisor_id_2,
Z.employee_id AS employee_id_2,
Z.full_name AS full_name_2
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A
WHERE A.employee_id_1 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
A.employee_id_1 AS employee_id,
A.supervisor_id_1,
A.employee_id_1,
A.full_name_1,
NULL AS supervisor_id_2,
NULL AS employee_id_2,
NULL AS full_name_2,
NULL AS supervisor_id_3,
NULL AS employee_id_3,
NULL AS full_name_3,
NULL AS supervisor_id_4,
NULL AS employee_id_4,
NULL AS full_name_4,
NULL AS supervisor_id_5,
NULL AS employee_id_5,
NULL AS full_name_5,
NULL AS supervisor_id_6,
NULL AS employee_id_6,
NULL AS full_name_6,
NULL AS supervisor_id_7,
NULL AS employee_id_7,
NULL AS full_name_7
FROM employee Z,
SELECT DISTINCT
supervisor_id AS supervisor_id_1,
employee_id AS employee_id_1,
full_name AS full_name_1
FROM employee
WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A -
Parent child hierarchy and measure using lookup
Hi,
I'm using OBIEE 11.1.1.5 and I have an issue with a parent child hierarchy, which is setup like case 4 in this example . When I create a simple analysis using the hierarchy and a simple measure, it works fine. But when I try to use a calculated measure using a lookup formula, I get the following error:
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 43119] Query Failed: [nQSError: 46036] Internal Assertion: Condition pTableRef->GetLeftTable() && pTableRef->GetLeftTable()->IsTableReference(), file server/Query/Optimizer/ServiceInterfaceMgr/Src/SQOIDriveJoinGenerator.cpp, line 568. (HY000)
Does anyone know how to get past this error?
Thanks,
MihaiHi,
I'm using OBIEE 11.1.1.5 and I have an issue with a parent child hierarchy, which is setup like case 4 in this example . When I create a simple analysis using the hierarchy and a simple measure, it works fine. But when I try to use a calculated measure using a lookup formula, I get the following error:
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 43119] Query Failed: [nQSError: 46036] Internal Assertion: Condition pTableRef->GetLeftTable() && pTableRef->GetLeftTable()->IsTableReference(), file server/Query/Optimizer/ServiceInterfaceMgr/Src/SQOIDriveJoinGenerator.cpp, line 568. (HY000)
Does anyone know how to get past this error?
Thanks,
Mihai -
Parent-Child Hierarchy Show No Data
Hi:
OBIEE 11.1.1.6.5
I created a parent-child hierarchy following multiple examples in books and on the web. I can pull the presentation hierarchy--by itself--into a view and drill up and down. But when I add a measurement from the fact table, I receive a no data found error. I copied the SQL into SQL*Developer and ran it, and it too returned no data. I've tried to read and debug the query in SQL*Developer, but I don't understand what it is doing.
The dimension table I am using for the parent-child hierarchy has a cost_Center_id and parent_cost_center_id. I used the Parent-Child dimension wizard to create and populate the new hierarchy table.
I can create a view by using the cost_center item and a fact table measurement without the presentation hierarchy, so it has something to do with the presentation hierarchy.
I've been at this for a few days now, and I've run out of ideas. Can anyone suggest what I may have done wrong?
Thanks.check if there is data in the fact table.. Next check also if the join condition between the dimension and fact is valid.
-
Parent Child Hierarchy for Type 2
I have read the articles on Parent Child hierarchy setup in OBIEE 11g, however, most are based on what seems to be a current snapshot of the Employee-Manager relationship. Has anyone tried to build out a Parent-Child hierarchy/table off a Type 2 dimension. Being able to navigate what the hierarchy may have been on a specific date.
I would welcome any feedback, thanks.Hi,
Thanks for the reply, I'm actually using snapshots. But even with the Type 2 Dim I don't think it will work.
When OBIEE generates the very first sql against the Parent-Child table the fact table is not included in the query. It seems to create 2 queries - one to find the top level parent (ancestor key is null) and then one to find all the leaf nodes.
It does not have any join to the fact table when it does this. So if you have multiple rows in the table (with date stamps) for a single row (person in this case) - it picks up both rows. Therefore, when you have a person who was, say, promoted to manager, and WAS a leaf node, and is now a manager, they show up in the leaf query and don't display in the hierarchy as a manager.
Once it has the leaf nodes and it joins to the fact table everything works (ie the surrogate key join).
I'm trying to figure out if there is any way to influence those initial queries against the parent-child table.
Hopefully that made sense.
Thanks,
Tori -
Parent-Child hierarchy based on two-column key
Hello
Is it possible to create a parent-child hierarchy, if the primary key of the table consists of two columns?
My table looks like:
TRACE_ID | DIAG_ID | SUPER_DIAG_ID
with TRACE_ID and DIAG_ID as PK.
If I define only DIAG_ID as PK, I can add a logical dimension (PC-hierarchy) without problems.
However when I also add TRACE_ID to my PK, I cannot select a member key in the new logical dimension window and therefore not create a logical dimension.
Is this a limitation of OBIEE and I have to merge the two colums (which would be rather bad, as there are FK relations to DIAG_ID) or is there a solution?
Regards
MatthiasDear Gowtham ,
I am very well aware of the level based hierarchy available in BO .
The issue that i have raised is all about the Parent Child Hierarchy which creates the recursive query.
I.e Every Parent has a child and that child can be parent of some other . (See the original example for more illustration) -
I am new learner for using OBIEE 11g, when I try to create the Parent_Child_Hierarchy in the repository, BI answer in the web shows the errors:
"State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 38107] *Not all four columns are defined for closure table 'Parent_Chile_Table_Closure'*. (HY000)".
According to the help web "http://www.adivaconsulting.com/adiva-blog/item/22-obiee-11g-hierarchical-table.html", I have created the relational Parent-Child-Hierarchy table in the database that is imported into the physical layer, and finish every steps, but when I drag the hierarchy in the presentation layer into display scope, which shows the errors mentioned above.
If you known the method for solving it,please help me and share your idea, thanks!Hey,
I am also facing the same issue when i try to replicate this practice. (Create Logical Dimensions with Parent Child Hierarchies -- http://www.oracle.com/webfolder/technetwork/tutorials/obe/fmw/bi/bi11115/biadmin11g_02/biadmin11g.htm#t9s3)
Odbc driver returned an error (SQLExecDirectW).
Error Details
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 43119] Query Failed: [nQSError: 22056] To use hierarchical functions, you need to associate a Closure Table with Logical Table Source 'LTS1 Sales Rep'. (HY000)
SQL Issued: SET VARIABLE PREFERRED_CURRENCY='USD';SELECT 0 s_0, "Y - Sample Sales"."Sales Reps"."Sales Rep Name" s_1, CASE WHEN ISLEAF("Y - Sample Sales"."Sales Reps"."H5 Sales Rep DimHier") THEN 1 ELSE 0 END s_2, IDOF("Y - Sample Sales"."Sales Reps"."H5 Sales Rep DimHier") s_3, PARENT("Y - Sample Sales"."Sales Reps"."H5 Sales Rep DimHier") s_4 FROM "Y - Sample Sales" WHERE ISROOT("Y - Sample Sales"."Sales Reps"."H5 Sales Rep DimHier") -
OBIEE 11g Parent Child hierarchy
Hi,
I'm trying to setup a parent-child hierarchy dimension. I have setup a new hierarchy dimension using numeric keys but want to display another field in the hierarchical column on a report e.g. employee fullname & not the member_key based on a numeric value. Can this be done & how do you do it? All the examples I have seen use varchar2 type columns as the keys to do this.
Thanks in advance, Phil
My Setup
=============
Dimension - logical level
===============
member key = employee_id
parent-child table source
===============
member key = employee_id
parent key = supervisor_id
relationship distance = levels_removed
leaf node identifier = isleaf
Employee logical folder
==============
employee_id ( number)- primary key
full_name (varchar2) - unique key
supervisor_id ( number)
Closure table
=========
employee_id ( number)
supervisor_id ( number)
level ( number)
isleaf ( number)Thanks for the link Suresh but the aggregations are working correctly.
My problem is only at the display level. I need to create a dashboard that displays the complete hierarchy.
So for example if I have this hierarchy:
- Steven King
- Adam Frip
Alexis Bull
Anthony Cabrio
Alberto Erraruriz
Den Raphaely
I want the dashboard to display immediately that complete hierarchy. If someone adds a member to the hierarchy in the database, the dashboard should display this new member without having to manually modify the dashboard.
- Steven King
- Adam Frip
Alexis Bull
Anthony Cabrio
- Alberto Erraruriz
Mozhe Atkinson
Den Raphaely
Also, if I just manually open the hierarchy and save the dashboard, if "Steven King" is replaced by "Shanta Vollman", the dashboard doesn't like it and returns a result looking like:
- Adam Frip
Alexis Bull
Anthony Cabrio
- Alberto Erraruriz
Mozhe Atkinson
Den Raphaely
+ Shanta Vollman
So I'm looking for some option that will tell OBIEE to open the hierarchy without having to specify "Drill down on member "Steven King"", "Drill down on member "Adam Frip"...
I hope I'm explaining correctly...
Maybe you are looking for
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