Per-message signature or Encryption in iOS 6?

Can someone tell me if:
     1. There is a way to do per-message digital sigantures AND digital Encryption in iOS 6, AND
      2. There is a way to cause the default behavior to be to return an encrypted e-mail with an encrypted e-mail?  The default is to return an unencrypted e-mail (in iOS 5), and that's clearly the wrong thing to do.
Rob

Robert Cunningham wrote:
Can someone tell me if:
     1. There is a way to do per-message digital sigantures AND digital Encryption in iOS 6
Not until iOS 6 becomes available to the general public which happens later today.

Similar Messages

  • With per-message S/MIME enabled, the default action when replying to an encrypted message is to send that reply unencrypted.  Causes users to accidentally send originally encrypted content, back unencrypted.

    This seems counter-intuitive, are we doing something wrong or is this working as expected?
    When we have per-message S/MIME enabled on an iOS 8 device.  Everything works as expected and we have the ability to select when you are sending an email whether that email should be encrypted or not, but i've noticed that, when you receive an email encrypted with your S/MIME cert, read that email on your iOS8 device with per-message S/MIME enabled, and reply to, or forward, that message, the default action is to send that reply, or forward, unencrypted UNLESS you manually re-tap the little padlock button to re-encrypt the message.
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    Hi,
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    Yes, it seems you have installed all the updates for the Outlook.
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    SAP Network Blog: How to use Digital Certificates for Signing & Encrypting Messages in XI
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    SAP Network Blog: How XML Encryption can be done using web services security in SAP NetWeaver XI
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    https://www.sdn.sap.com/sdn/collaboration.sdn?contenttype=url&content=https%3A//forums.sdn.sap.com/thread.jspa%3FforumID%3D44%26threadID%3D37512
    Ensure the Confidentiality of Your SOAP Message Content: XML Encryption Using Web Services Security in SAP NetWeaver Exchange Infrastructure
    https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/f0650f56-7587-2910-7c99-e1b6ffbe4d50
    Digital Signatures in SAP Applications
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    Edited by: Swarup Sawant on Apr 4, 2008 2:02 PM

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  • Message signature for NTLMv2 Authentication message

    Hi,
    I'm implementing NTLMv2 support for SMBv2 and I have encountered some problems calculating the correct checksum for the authentication message. 
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    4E 54 4C 4D 53 53 50 00 03 00 00 00 18 00 18 00 AE 00 00 00 42 01 42 01 C6 00 00 00 1E 00 1E 00 58 00 00 00 1A 00 1A 00 76 00 00 00 1E 00 1E 00 90 00 00 00 10 00 10 00 08 02 00 00 15 82 88 E2 06 01 B1 1D 00 00 00 0F 57 7C 17 17 5E DF 25 D8 8C 06 8D E6 75 5F
    62 65 57 00 49 00 4E 00 2D 00 34 00 37 00 50 00 30 00 39 00 4E 00 51 00 42 00 4B 00 49 00 38 00 41 00 64 00 6D 00 69 00 6E 00 69 00 73 00 74 00 72 00 61 00 74 00 6F 00 72 00 57 00 49 00 4E 00 2D 00 51 00 32 00 33 00 49 00 36 00 4F 00 34 00 55 00 55 00 44 00
    53 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 67 E7 1D 8A 39 CC A0 52 A7 01 51 02 E9 5A DF 7B 01 01 00 00 00 00 00 00 7F D2 02 FD 80 6C D0 01 2A 01 01 16 D7 E9 11 F7 00 00 00 00 02 00 1E 00 57 00 49 00 4E 00 2D 00 34 00 37 00
    50 00 30 00 39 00 4E 00 51 00 42 00 4B 00 49 00 38 00 01 00 1E 00 57 00 49 00 4E 00 2D 00 34 00 37 00 50 00 30 00 39 00 4E 00 51 00 42 00 4B 00 49 00 38 00 04 00 1E 00 57 00 49 00 4E 00 2D 00 34 00 37 00 50 00 30 00 39 00 4E 00 51 00 42 00 4B 00 49 00 38 00
    03 00 1E 00 57 00 49 00 4E 00 2D 00 34 00 37 00 50 00 30 00 39 00 4E 00 51 00 42 00 4B 00 49 00 38 00 07 00 08 00 7F D2 02 FD 80 6C D0 01 06 00 04 00 02 00 00 00 08 00 30 00 30 00 00 00 00 00 00 00 00 00 00 00 00 30 00 00 20 28 45 5A F8 71 0C F9 CC 5A EB A1
    F5 FB C3 17 49 CE 76 FF 1B 32 31 4D 52 E7 0E D8 B0 BA C5 F9 0A 00 10 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 09 00 22 00 63 00 69 00 66 00 73 00 2F 00 31 00 39 00 32 00 2E 00 31 00 36 00 38 00 2E 00 31 00 2E 00 31 00 31 00 00 00 00 00 00 00 00 00
    00 00 00 00 03 AC 9B EA 78 DD DF 49 BB D8 2D 66 0C 4F 22 61 
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    ExportedSessionKey: 945d257f88b6be1a4b201748e3f134c5
    and from there calculate the correct MIC (based on the negotiation,challenge and authentication messages).
    But now when I am trying to calculate the checksum for the message signature I can't get this right.
    The SignKey equals to md5(concat(ExportedSessionKey,"session key to client-to-server signing key magic constant")):
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    The SealKey equals to md5(concat(ExportedSessionKey,"session key to client-to-server sealing key magic constant"))
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    and the sequence number is: 0
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    That's an incorrect checksum, the real checksum should have been: 524102bf5e86c109 (captured from the packet).
    These are the negotiation flags of this session that are set:
    NegotiateUnicode,RequestTarget,NegotiateSign,NegotiateNTLM,NegotiateAlwaysSign,NegotiateNTLM2,
    NegotiateTargetInfo,NegotiateVersion,Negotiate128,NegotiateKeyExch,Negotiate56
    The only thing I wasn't sure about is if I need to calculate the checksum from the message with Z(16) instead of the mic or with the real calculated mic. Nevertheless I don't get the checksum on both ways.
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    Thanks in advance!

    Hi Guy:
    The details for how to calculate a MechListMIC are described in RFC 4178 (http://www.rfc-editor.org/rfc/rfc4178.txt) section 5(a).
    Any details specific to Windows are described in MS-SPNG (https://msdn.microsoft.com/en-us/library/cc247021.aspx) documents.
    I will give you an example here how the client calculates MechListMIC in case of NTLM.
    For this example, I used an actual SMB2 session set up exchange. If you need the network trace that I used, please send an email to dochelp at microsoft dot com to my attention referencing this thread.
    server challenge: 0x91, 0xA7, 0xB5, 0xA0, 0x93, 0xD1, 0x28, 0x73
    Password: Password01!
    client's MechTypes from first session set up message : 30 0C 06 0A 2B 06 01 04 01 82 37 02 02 0A
    Security blob from the session set up command that contains the authenticate message:
    A1 82 01 CD 30 82 01 C9 A0 03 0A 01 01 A2 82 01
    AC 04 82 01 A8 4E 54 4C 4D 53 53 50 00 03 00 00
    00 18 00 18 00 86 00 00 00 FA 00 FA 00 9E 00 00
    00 0C 00 0C 00 58 00 00 00 06 00 06 00 64 00 00
    00 1C 00 1C 00 6A 00 00 00 10 00 10 00 98 01 00
    00 15 82 88 E2 06 03 80 25 00 00 00 0F 82 C4 C5
    F7 7B 08 49 FD A2 87 0E A3 05 EC 77 AB 66 00 6F
    00 72 00 4D 00 44 00 4D 00 61 00 62 00 63 00 4D
    00 49 00 4E 00 49 00 4E 00 54 00 2D 00 36 00 37
    00 31 00 30 00 38 00 46 00 4B 00 00 00 00 00 00
    00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
    00 00 00 30 0B A0 EF 0B 39 38 45 54 E6 ED 4F B4
    FD 6D B6 01 01 00 00 00 00 00 00 72 23 6C 58 68
    6D D0 01 B5 FF F2 9D 10 1B 35 60 00 00 00 00 02
    00 0C 00 46 00 4F 00 52 00 4D 00 44 00 4D 00 01
    00 0C 00 46 00 4F 00 52 00 4D 00 44 00 4D 00 04
    00 0C 00 66 00 6F 00 72 00 4D 00 44 00 4D 00 03
    00 0C 00 66 00 6F 00 72 00 4D 00 44 00 4D 00 07
    00 08 00 72 23 6C 58 68 6D D0 01 06 00 04 00 02
    00 00 00 08 00 30 00 30 00 00 00 00 00 00 00 01
    00 00 00 00 20 00 00 15 7C 95 BD E7 02 DE 3B C9
    8D F1 46 91 04 AC 4D 16 61 03 F1 BF 42 77 85 B2
    82 B7 83 2E CB 1E 3F 0A 00 10 00 00 00 00 00 00
    00 00 00 00 00 00 00 00 00 00 00 09 00 22 00 63
    00 69 00 66 00 73 00 2F 00 31 00 39 00 32 00 2E
    00 31 00 36 00 38 00 2E 00 31 00 2E 00 34 00 30
    00 00 00 00 00 00 00 00 00 00 00 00 00 8E 07 9F
    C9 F1 50 97 65 F3 BD A8 C1 32 8A 52 56 A3 12 04
    10 01 00 00 00 3B 1F D5 E0 2D 97 5F 97 00 00 00
    00
    My calculation are from servers perspective. Everything server needs to verify client's MechListMIC
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    The KeyExchangeKey is NTLMv2 session base whose calculation is described in MS-NLMP (https://msdn.microsoft.com/en-us/library/cc236621.aspx) section "3.3.2 NTLM v2 Authentication"
    KeyExchangeKey (NTLMv2 session base key)=ad6e6c75872afd2178533d2ebb8ad9ad
    Using KeyExchangeKey to RC4 decrypt the Encrypted Random Session key, we get
    Random Session Key: c7 9a 31 b6 8d b6 4e 3f 84 66 be a3 b2 22 3b c1
    Using Random session key above and description in MS-NLMP, we calculate the signing and sealing keys.
    Server Signing Key: 69 cb 53 69 d5 18 75 04 dc 7e 61 03 33 10 53 e9
    Server Seal Key: 35 4e c9 d1 86 2d 4f a5 98 25 87 c4 b5 35 f2 33
    Client Signing Key: a2 b2 1a ed a9 ec d3 f1 3d ff c3 3d e0 1b 59 30
    Client Seal Key: 1e bb c6 f3 65 5b dc 13 b3 5b e4 e2 24 eb 71 e2
    Now using the client signing and sealing keys, we proceed to calculate the NTLM signature of client's MechTypes as described in MS-NLMP section "3.4.4.2 With Extended Session Security":
    Message number is 00 00 00 00
    MechList with 0000 concatenated:
    00 00 00 00 30 0c 06 0a 2b 06 01 04 01 82 37 02 02 0a
    HMAC_MD5 of the above using client signing key (first 8 bytes): 28 d5 e1 57 a4 d4 58 24
    checksum (RC4 encrypting the above using Client Sealing key): 3b 1f d5 e0 2d 97 5f 97
    MechListMIC by appending version and sequence: 01 00 00 00 3b 1f d5 e0 2d 97 5f 97 00 00 00 00
    As you can see this matches with what client sent.
    Please let me know if it does not answer your question.
    Regards, Obaid Farooqi

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