Please Help with range of uncertainty in java program

Question

I really need help with this, I've been searching for an answer all day and have found nothing.
This is the original program and I'm trying to make it so instead of stoppingDistance having to be equal to tailgateDistance for it to print minor wreck, it will allow a range of 40 feet. Like a range of uncertainty of plus or minus 20 feet, and I need to use a named constant that is: RANGE = 40.0
import java.util.Scanner;
public class StoppingA
public static void main(String[] args)
Scanner stdIn = new Scanner(System.in);
double speed; // speed car is traveling;
double tailgateDistance; // distance from other car;
double stoppingDistance; // calculated distance
System.out.print ("Enter your speed (in mph): ");
speed = stdIn.nextDouble();
System.out.print ("Enter your tailgate distance (in feet): ");
tailgateDistance = stdIn.nextDouble();
stoppingDistance=speed*(2.25+speed/21);
if (stoppingDistance < tailgateDistance)
System.out.println("No problem.");
else if (stoppingDistance == tailgateDistance)
System.out.println("Minor wreck.");
else if (stoppingDistance > tailgateDistance)
System.out.println("Major wreck!");
} // end main
} // end class StoppingA
Edited by: Ensanvoration on Feb 23, 2010 3:31 PM

Answer 1

Encephalopathic wrote:
Ensanvoration wrote:
Thanks, but I already tried that exact thing and it didn't work either. It's ridiculousIf you don't show us how you tried it, then we can only guess why it's not working.
... but if you wait around long enough, I bet you'll see JosAH post a recursive solution! :)Where is JosAH. Is he on vacation? Since I've been back, I haven't seen him.
Well, let's raise a bottle of Grolsch to him anyway. More for us.
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