Plz help me on the hangman code

Question

Consider the venerable "hangman" game, in which a player attempts to guess a word one letter at a time. If you are unfamiliar with hangman, simply google it; you'll be playing in no time.
Consider the following abstract view of hangman. The input is an unknown word and a sequence of character guesses. There is also an implicit parameter, which is the number of incorrect guesses that may be made before losing the game. Even though you wouldn't implement an interactive hangman game this way, let's model this as:
static public int hangman (String puzzle, String guesses, int limit)
Requires: puzzle != null, guesses != null, limit >=0
Effects: returns the number of the guess that solves the
puzzle within the given limit on incorrect guesses.
If the puzzle is not solved within the limit, returns -1.
e.g.
hangman ("cat", "abct", 1) is 4 (solved)
hangman ("cat", "abct", 0) is -1 (hit the limit)
hangman ("cat", "abcd", 5) is -1 (gave up)
I wrote the following code but it gives me an error of array index out of bounds exception though it compiles correctly. If someone can help me in correcting the code or point out my mistake.
public class hangman
public static int hang(String puz,String gue,int lim)
     int i,j,flag=0,ret=0;
     char p[],g[];
     p=puz.toCharArray();
     g=gue.toCharArray();
     one:
          for(i=0;i<g.length;i++)
               two:
               for(j=0;j<p.length;j++)
                    if(g==p[j])
                         //take the element off the p array and resize p
                         if(p.length==1)
                         break one;
                         else
                         char b[]=new char[p.length];
                         for(int k=j+1;k<p.length;k++)
                              p[k-1]=p[k];
                              b=p;
                              p=new char[p.length-1];
                         for(int l=0;i<p.length;l++)
                         p[l]=b[l];
                         continue one;
                    else
                    if(j==p.length-1)
                         flag++;
                    else
                    continue two;
          if(flag>lim)
          return -1;
          else
          return 0;
public static void main(String args[])
int ret;
ret=hang("cat","abct",1);
System.out.println(ret);

Answer 1

I wrote the following code but it gives me an error
of array index out of bounds exception though it
compiles correctly.I just want to point out a fundamental misunderstanding that this statement suggests you have.
Compiling just converts your source code into equivalent bytecode. The only errors you'll get during compilation are if the syntax is bad (like you forgot a semicolon, misspelled a method name, have an extra closing brace, etc.) or if you're trying to ues a vairialbe that the copmiler can't be sure will have been initialized, etc.
Compilation does NOT execute your code, and it has no way to determine the logical problem with, for instance, int[] arr = new int[0];
int x = arr[999]; The fact that x has zero elements and you're trying to access element 999 only comes to light at execution time.
So "I get an error at runtime even though it compiles fine" is kind of meaningless.
Note that I'm not trying to pick on you here. I just want to shift your thinking away from this fundamental misconception you seem to have.