Problem in finding the Duplicate as well as Non-Duplicate count

Question

Hi,
I have a scenario where I have a table TABLEA which has 3 values
10 ABC
10 ABC
20 DEF
I want to pick up the duplicate count as wel as non duplicate count:
I have used the following query:
SELECT COUNT(*) FROM TABLEA A WHERE A.ROWID > ANY (
SELECT B.ROWID FROM TABLEA B WHERE
A.CODE=B.CODE)
But I am finding problem in getting the non-duplicate count .
Any help will be needful for me
Edited by: user598986 on Sep 23, 2009 11:32 PM

Answer 1

user598986 wrote:
Hi,
I have a scenario where I have a table TABLEA which has 3 values
10 ABC
10 ABC
20 DEF
I want to pick up the duplicate count as wel as non duplicate count:
I have used the following query:
SELECT COUNT(*) FROM TABLEA A WHERE A.ROWID > ANY (
SELECT B.ROWID FROM TABLEA B WHERE
A.CODE=B.CODE)
But I am finding problem in getting the non-duplicate count .
Any help will be needful for me
Edited by: user598986 on Sep 23, 2009 11:32 PMHi,
perhaps this query makes your job:
HR: XE > select * from test_;
NAME           SALARY HIRE_DATE START_DAT END_DATE
                      15-SEP-09 15-SEP-09
                      15-SEP-09 01-DEC-09
john                  27-AUG-09 16-SEP-09 16-SEP-10
                      28-FEB-09 20-SEP-09
Dave                2 17-JUN-08 16-SEP-09 02-JUL-11
                 1000 21-AUG-82 08-MAY-10
6 rows selected.
HR: XE > select count(hire_date), hire_date from test_
  2  group by hire_date;
COUNT(HIRE_DATE) HIRE_DATE
               1 27-AUG-09
               1 21-AUG-82
               2 15-SEP-09
               1 28-FEB-09
               1 17-JUN-08
HR: XE > select count(id), id from
  2  (
  3  select hire_date, 'simple' id from test_
  4  minus
  5  select test_.hire_date, 'simple' id
  6  from test_
  7  where test_.hire_date In (Select hire_date FROM test_  GROUP BY hire_date HAVING Count(*)>1 )
  8  union all
  9  select test_.hire_date, 'double' id
10  from test_
11  where test_.hire_date In (Select hire_date FROM test_  GROUP BY hire_date HAVING Count(*)>1 )
12  )
13  group by id;
COUNT(ID) ID
         2 double
         4 simple
HR: XE > Regards,
Ion