Problem with String to Int conversion

Dear Friends,
Problem with String to Int conversion
I am having a column where most of the values are numeric. Only 4 values are non numeric.
I have replaces those non numeric values to numeric in order to maintain the data type.
CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END
This comes the result as down
Grade
_0_
_1_
_10_
_11_
_12_
_13_
_14_
_15_
_16_
_17_
_18_
_19_
_2_
_20_
_21_
_22_
_23_
_24_
_3_
_4_
_5_
_6_
_7_
_8_
_9_
Refresh
Now I want to convert this value to numeric and do some calculation
So I changed the formula as below
cast (CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END as INT)
Now I get the following error
View Display Error
_ Odbc driver returned an error (SQLExecDirectW)._
Error Details
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
_State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 17001] Oracle Error code: 1722, message: ORA-01722: invalid number at OCI call OCIStmtFetch. [nQSError: 17012] Bulk fetch failed. (HY000)_
SQL Issued: SELECT cast ( CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END as Int) saw0 FROM "Human Capital - Manpower Costing" WHERE LENGTH(CASE Grade.Grade WHEN 'E1' THEN '20' WHEN 'E2' THEN '21' WHEN 'E3' THEN '22' WHEN 'E4' THEN '23' ELSE Grade.Grade END) > 0 ORDER BY saw_0_
Refresh
Could anybody help me
Regards
Mustafa
Edited by: Musnet on Jun 29, 2010 5:42 AM
Edited by: Musnet on Jun 29, 2010 6:48 AM

Dear Kart,
This give me another hint, Yes you are right. There was one row which returns neither blank nor any value.
I have done the code like following and it works fine
Thanks again for your support
Regards
Code: cast (CASE (CASE WHEN Length(Grade.Grade)=0 THEN '--' ELSE Grade.Grade END) WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' when '--' then '-1' ELSE Grade.Grade END as Int)

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</HTML>
The error is:
org.apache.jasper.JasperException: For input string: ""
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:367)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:293)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:240)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
root cause
java.lang.NumberFormatException: For input string: ""
     java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
     java.lang.Integer.parseInt(Integer.java:489)
     java.lang.Integer.parseInt(Integer.java:518)
     org.apache.jsp.store_jsp._jspService(store_jsp.java:107)
     org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:293)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:240)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)

what are you trying to test with client [ i ] == "\0"
You sure you dont need to test against null ?

Problem with String to Int conversion

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