Pushdown with outer joins
I'm implementing ALDSP 2.1 using the BEA best practice with 4 layers (physical, canonical, logical and application). The result of the logical layer is comparable with the example at http://e-docs.bea.com/aldsp/docs21/xquery/sql_pushdown.html#1131036
In the application layer I have defined a function findCustomerByOrderId($p_id as xs:string), searching on $c_order/ORDER_ID. I would have expected that the argument OrderId is pushed down to the final database query, but it is not. Can anyone tell me, if possible, how I get the argument pushed down and get the required result?
Looks like I outsmarted myself with the optimization on RX_Addresses.
Looking at the query plan, I see a 'where' operator - drill into it and you will eventually find $fxxx eq $fparam0 (the $postalCode). So the engine decided it would be more effective to get all the Addresses from the database (and put them in our variable), and then look if any of them have a matching postalCode.
Since all the addresses (even those with a postalCode that do not match) when at least one postalCode matches, DSP does the selection in memory. If you go directly to the database table for the postalCode (instead of using the addresses in the variable), the selection does get pushed.
Strictly speaking, I don't think it is impossible for the optimizer to figure out what we just figured out. But the format of your output hides this inference somewhat from the optimizer.
declare function tns:getCompanyProfiles() as element(ns0:company)* {
for $RXS_Org in (ns1:RXS_OrganizationObject())
let $RXS_AddressList := for $RXS_Addresses in ns2:RXS_Addresses()
where $RXS_Addresses/g_id eq $RXS_Org/g_org_id
return $RXS_Addresses
where $RXS_Org/u_relation_type eq "B"
return
<ns0:company>
<ns0:companySpecific? source?="{xs:string("REEDXS")}" reliability?="" registrationState?="" recordDate?="" changeDate?="" validationDate?="">
<ns0:companyIdentifier?>{fn:data($RXS_Org/g_org_id)}</ns0:companyIdentifier>
<ns0:companyName?>{fn:data($RXS_Org/u_Name)}</ns0:companyName>
<ns0:vatNumber?>{fn:data($RXS_Org/u_btw_number)}</ns0:vatNumber>
<ns0:employementClass?>{fn:data($RXS_Org/u_company_size)}</ns0:employementClass>
{ if (fn:string-length(xs:string($RXS_Org/i_branch))>0) then
<ns0:brancheCode?>{xs:string($RXS_Org/i_branch)}</ns0:brancheCode>
else
<ns0:brancheCode?>{xs:string($RXS_Org/i_branch_group)}</ns0:brancheCode>
</ns0:companySpecific>
<ns0:communication?>
{ for $RXS_Addresses in ns2:RXS_Addresses()
where $RXS_Addresses/g_id eq $RXS_Org/g_org_id
return
<ns0:address>
<ns0:country>{fn:data($RXS_Addresses/u_country_name)}</ns0:country>
{ if ($RXS_Addresses/u_address_line1/text() eq "Postbus") then
<ns0:poBox>{fn:data($RXS_Addresses/u_address_line2)}</ns0:poBox>
else ()
{ if ($RXS_Addresses/u_address_line1/text() != "Postbus") then
<ns0:houseNumber>{fn:data($RXS_Addresses/u_address_line2)}</ns0:houseNumber>
else ()
<ns0:postalCode?>{fn:data($RXS_Addresses/u_postal_code)}</ns0:postalCode>
<ns0:street>{fn:data($RXS_Addresses/u_address_line1)}</ns0:street>
<ns0:city>{fn:data($RXS_Addresses/u_city)}</ns0:city>
<ns0:addressIdentifier>{fn:data($RXS_Addresses/g_address_id)}</ns0:addressIdentifier>
<ns0:addressCategory>{"B"}</ns0:addressCategory>
</ns0:address>
{ for $RXS_Addresses in $RXS_AddressList
return
<ns0:phoneNumber?>
{ if (fn:string-length($RXS_Addresses/u_tel_number) > 0) then
( <ns0:phoneNumberCategory>{"V"}</ns0:phoneNumberCategory>
, <ns0:phoneNumberContent?>{fn:data($RXS_Addresses/u_tel_number)}</ns0:phoneNumberContent>
else ()
</ns0:phoneNumber>
{ for $RXS_Addresses in $RXS_AddressList
return
<ns0:phoneNumber?>
{ if (fn:string-length($RXS_Addresses/u_fax_number) > 0) then
( <ns0:phoneNumberCategory>{"F"}</ns0:phoneNumberCategory>
, <ns0:phoneNumberContent?>{fn:data($RXS_Addresses/u_fax_number)}</ns0:phoneNumberContent>
else ()
</ns0:phoneNumber>
{ for $RXS_Addresses in $RXS_AddressList
return
<ns0:phoneNumber?>
{ if (fn:string-length($RXS_Addresses/u_mobile_tel_number) > 0) then
( <ns0:phoneNumberCategory>{"M"}</ns0:phoneNumberCategory>
, <ns0:phoneNumberContent?>{fn:data($RXS_Addresses/u_mobile_tel_number)}</ns0:phoneNumberContent>
else ()
</ns0:phoneNumber>
<ns0:webAddress?>{fn:data($RXS_Org/u_internet_url)}</ns0:webAddress>
</ns0:communication>
</ns0:company>
Similar Messages
-
How to poll a blob using db adapter, with outer joins condition
Hi All,
We are trying to poll tables which contain column types as long and blob, we are using relationships in adapter and kept outer joins. by this we got select distinct t1.document .....etc
distinct keyword cannot be used for blobs.
is there any way to poll these tables having blob column types with outer joins.
thanks a lot in advance,
RRHi,
Procedure will be an explicit Invoke not Polling. If you can alter you design such that your BPEL process instead of polling gets triggered by some external entity (Java, PL/SQL, Scheduler, another BPEL etc.), you can put the data fetching logic in the procedure and call this procedure from your BPEL process to get the data. And your BPEL process is called periodically at an interval by an external entity.
Also see if you can restrict the duplicate records at the database level itself. Polling, AFAIK, is limited in terms of customization and wouldn't be easy to customize. However, would like to learn a way if someone has.
Regards,
Neeraj Sehgal -
Help requried with outer joins
Hi All,
I neeed a query help can any one please help me getting this done,
for the below query
select trunc(assumed_time_sql) AS date1,sum(rp.rebate_due)as sum1 from mn_date_dim dd ,mn_rebate_payment rp,mn_prc_program prc,mn_structured_doc sd
where trunc(assumed_time_sql) in (TO_DATE('01-JUL-10','dd-mon-yy'),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-3),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-6),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-9))----input parameter
AND trunc(dd.assumed_time_sql)=TRUNC(rp.start_date)
AND prc.prc_program_id=rp.tiered_rebate_id
AND sd.struct_doc_id=prc.struct_doc_id
AND sd.struct_doc_id_num='M0000763'----input parameter
group by trunc(assumed_time_sql);
I am getting output as
date1 sum1
01-JAN-10 10
01-APR-10 15
01-JUL-10 20
But i want my output to be as
date1 sum1
01-JAN-10 10
01-APR-10 15
01-JUL-10 20
01-OCT-09 NULL
I have tried with outer joins but this didn't help me
Can any one please give me help in getting this done
ThanksHi,
As SB pointed out, you'd better provide tables and data in order to be helped more efficiently.
Anyway, you may want to investigate the use of NVL and/or DECODE so that you can translate NULL into valid values so they are returned to your select statement.
HTH,
Thierry
Handle: p78
Status Level: Newbie (10)
Registered: Mar 9, 2009
Total Posts: 60
Total Questions: 35 (30 unresolved) Be kind to share your helpful / correct threads with other with marking them as ANSWERED
Edited by: Urgent-IT on Feb 13, 2011 11:00 AM -
Generate a where clause with outer join criteria condition: (+)=
Hi,
In my search page, I use Auto Customization Criteria mode, and I build where clause by using get Criteria():
public void initSrpQuery(Dictionary[] dic, String userName) {
int dicSize = dic.length;
StringBuffer whereClause = new StringBuffer(100);
Vector parameters = new Vector(5);
int clauseCount = 0;
int bindCount = 1;
for(int i=0; i < dicSize; i++){
String itemName = (String)(dic.get(OAViewObject.CRITERIA_ITEM_NAME));
Object value = dic[i].get(OAViewObject.CRITERIA_VALUE);
String joinCondition = (String)dic[i].get(OAViewObject.CRITERIA_JOIN_CONDITION);
String criteriaCondition = (String)dic[i].get(OAViewObject.CRITERIA_CONDITION);
String criteriaDataType = (String)dic[i].get(OAViewObject.CRITERIA_DATATYPE);
String viewAttributename = (String)dic[i].get(OAViewObject.CRITERIA_VIEW_ATTRIBUTE_NAME);
String columnName = findAttributeDef(viewAttributename).getColumnNameForQuery();
if((value != null) /*&& (!("".equals((String).trim())))*/){
if(clauseCount > 0){
whereClause.append(" AND ");
whereClause.append(columnName + " " + criteriaCondition + " :");
whereClause.append(++bindCount);
parameters.addElement(value);
clauseCount++;
If I want to generate following where clause:
select
,emp.name
,emp.email
,emp.salesrep_number
,comp.name
,gs.srp_goal_header_id
,gs.status_code
,gs.start_date
,gs.end_date
from g2c_goal_shr_emp_assignments_v emp
,jtf_rs_salesreps rs
,xxg2c_srp_goal_headers_all gs
,cn_comp_plans_all comp
where 1 = 1
and rs.salesrep_id = gs.salesrep_id (+)
and gs.comp_plan_id = comp.comp_plan_id (+)
and gs.period_year (+) = :1 -- :1 p_fiscal_year
How can I generate a where clause with outer join : gs.period_year (+) = :1 ? Will I get '(+)=' from get(OAViewObject.CRITERIA_CONDITION)?
thanks
LeiIf you are using SQL-Plus or Reports you can use lexical parameters like:
SELECT * FROM emp &condition;
When you run the query it will ask for value of condition and you can enter what every you want. Here is a really fun query:
SELECT &columns FROM &tables &condition;
But if you are using Forms. Then you have to change the condition by SET_BLOCK_PROPERTY.
Best of luck! -
Group by sum doesn't work with outer join. Can anyone please help me to get it right?
I've posted some sample data and queries below:
CREATE TABLE COMPLAINT
CNO NUMBER,
REASON VARCHAR2(15 BYTE),
TOTAL NUMBER
Insert into COMPLAINT
(CNO, REASON, TOTAL)
Values
(1, 'edge', 250);
Insert into COMPLAINT
(CNO, REASON, TOTAL)
Values
(2, 'edge', 250);
Insert into COMPLAINT
(CNO, REASON, TOTAL)
Values
(3, 'brst', 300);
Insert into COMPLAINT
(CNO, REASON, TOTAL)
Values
(4, 'crea', 400);
COMMIT;
CREATE TABLE SCOTT.COMPLAINTROLL
CNO NUMBER,
ROLL VARCHAR2(15 BYTE)
SET DEFINE OFF;
Insert into COMPLAINTROLL
(CNO, ROLL)
Values
(2, 'roll22');
Insert into COMPLAINTROLL
(CNO, ROLL)
Values
(1, 'roll4');
Insert into COMPLAINTROLL
(CNO, ROLL)
Values
(1, 'roll3');
Insert into COMPLAINTROLL
(CNO, ROLL)
Values
(1, 'roll2');
Insert into COMPLAINTROLL
(CNO, ROLL)
Values
(1, 'roll1');
COMMIT;
select * from complaint
CNO REASON TOTAL
1 edge 250
2 edge 250
3 brst 300
4 crea 400
select * from complaintroll
CNO ROLL
1 roll1
1 roll2
1 roll3
1 roll4
2 roll22
-- total of reason code edge is 500
select reason,sum(total)
from complaint c
group by reason
REASON SUM(TOTAL)
brst 300
crea 400
edge 500
-- total of reason code edge after outer join is 1250
select reason,sum(total)
from complaint c,complaintroll cr
where c.cno=cr.cno(+)
group by reason
REASON SUM(TOTAL)
brst 300
crea 400
edge 1250
{\code}
Thanks for reading this post.The problem that you described is simple. The outer join duplicates all the rows from the parent table (complaint). If you want to sum a column from the parent table, then this sum includes all the duplicated rows.
There are several solutions for this problem.
A) One had been shown already by Cenutil. Instead of doing an outer join, you can do a subquery in the select clause that delivers the additional information from the detail table.
SQL> select reason,
sum(total),
sum((select count(*) from complaintroll cr where c.cno=cr.cno)) cnt_rolls
from complaint c
group by c.reason;
REASON SUM(TOTAL) CNT_ROLLS
crea 400 0
brst 300 0
edge 500 5b) sum in two steps. First sum and count including the join criteria, then use this information to calculate the correct total sum.
SQL> select reason, sum(stotal), sum(stotal/scount), sum(scount), sum(cnt_rolls)
2 from (select reason, sum(total) stotal, count(*) scount, count(cr.cno) cnt_rolls
3 from complaint c
4 left join complaintroll cr on c.cno=cr.cno
5 group by reason, c.cno
6 )
7 group by reason;
REASON SUM(STOTAL) SUM(STOTAL/SCOUNT) SUM(SCOUNT) SUM(CNT_ROLLS)
crea 400 400 1 0
brst 300 300 1 0
edge 1250 500 5 5
sql> c) another option is to do the left join, but do the aggregation only one time for the parent table. Analytic functions are helpful for that. However since analytic fuinctions can't be used inside an aggregation function, we would again need an inline view.
SQL> select reason, sum(case when rn = 1 then total end) sum_total, count(*), count(crcno)
2 from (select row_number() over (partition by c.reason order by c.cno) rn,
3 c.*, cr.cno crcno
4 from complaint c
5 left join complaintroll cr on c.cno=cr.cno
6 )
7 group by reason;
REASON SUM_TOTAL COUNT(*) COUNT(CRCNO)
brst 300 1 0
crea 400 1 0
edge 250 5 5
SQL> Edited by: Sven W. on Feb 10, 2011 1:00 PM - formatting + column added to 2nd option -
Update with Outer Join, round 2
Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
However, here is a new version of my problem:
I have three tables.
Table_1 has a column that needs to be updated based on values in Table_2 and Table_3.
Both Table_1 and Table_2 have values used to determine which Table_3 row to use.
However, not every Table_1 row has a corresponding Table_3 row, in which case the Table_3 value to use is assumed to be 1.
The tables and corresponding columns are:
TABLE_1
value_1 - the value to be updated
key_2 - a pointer to TABLE_2
key_3a - a pointer to TABLE_3, or a dummy value if there is no corresponding TABLE_3 record
TABLE_2
key_2 - the primary key
key_3b - a secondary pointer to TABLE_3
value_2 - a value to be used in calculating TABLE_1.value_1
TABLE_3
key_3a - the first part of the unique key
ley_3b - the second part of the unique key
value_3 - a value to be used in calculating TABLE_1.value_1
If there is a row in table_3 that matches the table_1.key_3a and table_2.key_3b values (where table_2.key_2 = table_1.key_2):
set table_1.value_1 = table_2.value_2 * table_3.value_3
If there is no such row in table_3:
set table_1.value_1 = table_2.value_2
I want to do something like this:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_2 t2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
WHERE t2.key_2 = t1.key_2
However, Oracle does not allow t1 to be referenced in the ON clause of the outer join.
(Assume that every key_2 value in table_1 is in table_2 as well - it is only the key_3 value that can be a dummy.)
If I move "t3.key_3 = t1.key_3" to the WHERE clause, then t1.value_1 is null for rows without the corresponding table_3 value.
I can do it with a clone of table_1 using ROWIDs:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_1 t1a
JOIN table_2 t2
ON t2.key_2 = t1a.key_2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1a.key_3a)
WHERE t1a.row_id = t1.row_id
However, is there an easier way to do this using ANSI joins (i.e. without (+) syntax)?
I have this feeling I am missing something reasonably obvious here.ddelgran wrote:
Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
I want to do something like this:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_2 t2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
WHERE t2.key_2 = t1.key_2
However, Oracle does not allow t1 to be referenced in the ON clause of the outer join.
(Assume that every key_2 value in table_1 is in table_2 as well - it is only the key_3 value that can be a dummy.)
If I move "t3.key_3 = t1.key_3" to the WHERE clause, then t1.value_1 is null for rows without the corresponding table_3 value.
I can do it with a clone of table_1 using ROWIDs:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_1 t1a
JOIN table_2 t2
ON t2.key_2 = t1a.key_2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1a.key_3a)
WHERE t1a.row_id = t1.row_id
However, is there an easier way to do this using ANSI joins (i.e. without (+) syntax)?
I have this feeling I am missing something reasonably obvious here.You might want to refer to my post in your original thread how to use join views in updates. You can use ANSI join syntax there, too:
Re: Update with Outer Join
You would end up with something like this (note: untested):
UPDATE
SELECT t1.value_1, t2.value_2 * NVL(t3.value_3, 1) as new_val
FROM table_1 t1
INNER JOIN table_2 t2 ON (t2.key_2 = t1.key_2)
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
SET value_1 = new_val;And again the same restrictions regarding key-preserved tables apply as described in the post referred to.
Regards,
Randolf
Oracle related stuff blog:
http://oracle-randolf.blogspot.com/
SQLTools++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676/
http://sourceforge.net/projects/sqlt-pp/ -
Getting an error called Invalid relational Operator
SELECT DISTINCT t1.recv_order_no, t2.reference_no
FROM receiving_order t1, receiver_num t2
WHERE TRIM(t2.reference_no) (+) = TRIM (t1.recv_order_no)
ORDER BY t2.reference_no ASC
What I am doing wrong here ?
Can I use trim fun with outer join ?
Thanks for help.
SriniHi Srini,
I have done this with emp and dept
Following is an example:
1 select a.deptno, b.ename
2 from dept a, emp b
3* where trim(a.deptno) = trim(b.deptno(+))
scott>/
DEPTNO ENAME
10 CLARK
10 KING
10 GHULAM
10 MILLER
20 SMITH
20 ADAMS
20 FORD
20 SCOTT
20 JONES
30 ALLEN
30 BLAKE
30 MARTIN
30 JAMES
30 TURNER
30 WARD
40Hope this helps
Ghulam -
How to use common object from two tables with out join.
HI,
I have two tables called A & B In A table i have the following objects
1.weekend
2.S1(measure)
3.S2(measure)
4.S3(measure)
5.S4(measure)
And In B table i have followning columns
1.week end
2.p1(measure)
3.p2(measure)
4.p3(measure)
5.p4(measure)
Now in universe i created all the measure objects i.e.s1,s2,s3,s4,p1,p2,p3,p4 A.weekend,B.weekend.
instead of using week end two times i wnt to use only once because this is common in both table.
if i use join between these tables i am getting values fine
But With out join is there any thing to do in universe level to create common objects to use from both the tables..I tried using aggregate awareness but while reporting it is taking as two SQL.which is not synchronized.
Please help me on this ...hi,
Although Weekend column is present in both tables, by creating a single Object in Universe, Universe can identify relationship with only table referenced in Object Creation.
So, there will be no identification of relationship with other table measures.
Obviously, you need to create 2 Weekend objects in Universe (in two classes).
Case 1: You need not join these two tables in Universe. When you create 2 Queries in WEBI, automatcially Weekend objects are synchronized (if both are of same datatype)
Case 2: If you join these two tables in Universe, Obviously,
your SQL may contain Weekend from Table1, measures from Table 2
or
your SQL may contain Weekend from Table2, measures from Table 1
Finally, You need to create 2 objects in Universe. But your query may contain a single Object based on Case 2.
Regards,
Vamsee -
Problem with outer join with filter on join column
Hi,
In physical layer I have one dimension and two facts, and there's an outer join between the facts.
dim_DATE ,
fact_1 ,
fact_2
Joins:
dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
select fact1.X, fact2.Y
from
Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
and Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
The filter on Fact_2.DATE effectively replaces outer join with inner.
Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
Thanks in advance,
Alex
Edited by: AM_1 on Aug 11, 2009 8:20 AMIf you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
* create in your physical layer for each fact table the joins with the dimension
* create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
Cheers
Nico -
SAP QUERY/INFOSET with OUTER JOIN
Hi,
I have created an infoset (SQ02) using two tables for SAP query.
Table: AGR_TEXTS. Fields: AGR_NAME, SPRAS, LINE, TEXT.
TABLE: AGR_FLAGS. Fields: AGR_NAME, FLAG_TYPE, FLAG_VALUE.
Joined these two tables using outer join. Defined the join condition as AGR_NAME = AGR_NAME. Saved and Generated the infoset.
Created SAP Query (SQ01) using the above created infoset.
In the basic list,
Marked AGR_NAME (AGR_TEXTS), TEXT, FLAG_VALUE as listed fields.
Marked AGR_NAME (AGR_TEXTS), SPRAS, LINE, FLAG_TYPE as selection fields.
Save the query. When execute the query provided the inputs for all the selection fields in the selection screen as given below:
AGR_NAME=Z*
SPRAS=E
LINE=00000
FLAG_TYPE=LICENSE_01
Executed the Query.
Got the results only the matched records as per the selection field FLAG_TYPE.
But I want all the records from table AGR_TEXTS and matched records from table AGR_FLAGS.
I want the report (output) as below,
_AGR_NAME TEXT FLAG_VALUE_
ZCA_BASIC_ACCESS_GLOBAL Non-critical basic access for all users. 53
ZCA_BASIC_ENDUSER_ACCESS UK:CA Basic Enduser Access
ZCA_BASIC_ENDUSER_ACCESS_UK UK:CA Basic Enduser Access UK 52
ZCA_BASIC_ENDUSER_SU52_UK UK:CA Basic Enduser Access to change Parameter ID's
But I got the report (output) as below,
_AGR_NAME TEXT FLAG_VALUE_
ZCA_BASIC_ACCESS_GLOBAL Non-critical basic access for all users. 53
ZCA_BASIC_ENDUSER_ACCESS_UK UK:CA Basic Enduser Access UK 52
Apprecited your help. Thanks.
Code Formatted by: Alvaro Tejada Galindo on Dec 30, 2009 2:20 PMIdentify a KF for which there are non-zero values for all accounts in the cube.
Create the query with Account (from MP coming from both IO and cube) and this KF. KF will have 0 values for accounts not existing in the cube. Create a condition to show only the 0 value for the KF. This should show you all the accounts in the IO which are not in the cube. -
Use of db link in subquery with outer join
I have a query where i am using db link to get data from another database.
I have an outer join where i am using a subquery using the same db link but it fails gives me the error:
ORA-00991: illegal use of LONG datatype.
But the same query with inner join is not giving me the error.
Is this a limitation of Oracle or am I doing something wrong.This is an example of what i am running. That last outer join does not work c.acad_plan(+).
select count(1)
from ( select a.* from cb001_tbl a where a.strm='1800' ) a ,
( select distinct emplid,national_id,strm, acad_plan, acad_career from ps_uhcb_001@SAPRD where institution='00730') b ,
( select * from ps_acad_plan_tbl@SAPRD a
where a.institution='00730'
and a.eff_status='A'
and a.effdt=(select max(b.effdt) from ps_acad_plan_tbl@SAPRD b
where a.institution=b.institution
and a.acad_plan=b.acad_plan
and b.effdt<=to_date(20100514,'yyyymmdd'))) c
where a.stdnt_id=b.national_id (+)
and a.strm=b.strm (+)
and b.acad_plan=c.acad_plan (+) -
Oracle.jbo.RowAlreadyDeletedException with outer join
Hi,
I have created a VO, based on an EO, with an outer join present.
The first time I query my data (search) everything goes well, but when I perform a search the second time, I receive the error message: "oracle.apps.fnd.framework.OAException: oracle.jbo.RowAlreadyDeletedException: JBO-25019: Entiteitsrij van sleutel oracle.jbo.Key[202 53162 ] not found in XxpostMmpParametersEO."
The reason why is because of the outer join there is no 1 to 1 relationship between the EO and the VO. However for the first time , it works fine.
Does someone have an idea how I can avoid the error for my second search action?
Thanks in advance!
br
GuyHi all,
the following article:
http://radio.weblogs.com/0123729/stories/2003/05/15/entityObjectOverTableWhosePrimaryKeyMayBeNull.html
suggest a possible workaround. It wok fine, but it is not generic! :((
By
Alessandro -
I have the following table structure,
Table - 1_
ID | Information
1 | abcadskasasa
2 | asdasdasdasd
3 | saeqdfdvsfcsc
Table - 2_
ID | PID
1 | 12
1 | 13
2 | 14
1 | 15
1 | 16
2 | 12
Table - 3_
ID | PARID
1 | 12
2 | 14
1 | 15
Now I want to select for each ID in table 1, the count of number of PID from table 2 and count of number of PARID from table 3.
Desired output:_
ID | COUNT_PID | COUNT_PARID
1 | 4 | 2
2 | 2 | 1
3 | 0 | 0
Could anyone please help me out with this. I am trying to make use of outer joins, but as I work mostly on the front end so, not able to come up with a proper solution for the above.
Thanks in advance,
TejasHi, Tejas,
You might have been doing the outer join correctly.
There's another problem here: joining table_1 to two other tables with which it has a one-to-many relationship.
If you were joining table_1 to just one other table, you could say:
SELECT t1.id
, COUNT (t2.pid) AS count_pid
FROM table_1 t1
LEFT OUTER JOIN table_2 t2 ON t1.id = t2.id
GROUP BY t1.id
ORDER BY t1.id;You could have done the exact same thing with table_3 instead of table_2.
But you can't do the same thing with both table_2 and table_3 at the same time: that would be like cross-joining table_2 and table_3. Instead of showing id=1 having count_pid=4 and count_parid=2, you would get cout_pid=8 and count_parid=8 (since 8 = 4 * 2).
You can do a separate GROUP BY on (at least) one of the tables.
This gets the right results. In the main query, there is only one one-to-many relationship.
WITH t3_summary AS
SELECT id
, COUNT (parid) AS count_parid
FROM table_3
GROUP BY id
SELECT t1.id
, COUNT (t2.pid) AS count_pid
, MAX (t3.count_parid) AS count_parid
FROM table_1 t1
LEFT OUTER JOIN table_2 t2 ON t1.id = t2.id
LEFT OUTER JOIN t3_summary t3 ON t1.id = t3.id
GROUP BY t1.id
ORDER BY t1.id; -
Tabular form from query with outer join destroys the universe!
Well, maybe just my app...
At any rate, what I have is a query that pulls RISKS for a project and does a reasonable outer join which joins the latest value from a RISK_HISTORY table. Values for RISK are updated and the value for RISK_HISTORY is changed and a new entry added to the RISK_HISTORY table.
At least that's how it's supposed to be.
I was able to do this with a report-with-a-form region by adding an extra update process to do a new insert into RISK_HISTORY but it seems that the tabular form is a bit more work.
Here's the query I'm using:
select * from(
select
r.RISK_SEQ RISK_SEQ_DISPLAY,
r.RISK_PRIORITY,
r.RISK_INFO,
r.RISK_MITIGATION,
r.ONGOING_FLAG,
r.RISK_DATE,
r.WEEK_GROUP_SEQ,
r.CREATED_ON,
r.CREATED_BY,
r.LAST_MODIFIED_ON,
r.LAST_MODIFIED_BY,
rh.STATUS,
row_number() over (partition by rh.risk_seq order by rh.last_modified_on desc) rn
from RISK r, WEEK_GROUP w, RISK_HISTORY rh
where w.PROJECT_SEQ=43
and r.week_group_seq= w.week_group_seq
and w.week_index=0
and rh.RISK_SEQ = r.RISK_SEQ
) where rn = 1
Clicking "Add Row" gets me this:
Error in mru internal routine: ORA-20001: no data found in tabular form
Running debug doesn't seem to expose much for me either. Is there a better tact for me to take here?
Thanks,
JonHi Prazy,
using nvl also didn't solve my problem.Actually my problem is I am having a table a in which I have a column called satus, status has the values like A or I .I have one lookup called MTH_BUYSINESS_FUNCTION in which for lookup_code A I have menaing as Active and for lookup_code I meaning is Inactive.Now in table a for sttaus I have two values one A and one null Now I want to write sql which displayes the meaning for column staus.Result should be Active and null .If I am uisng 1 query which I gave u I am not able to get the 2nd row in my output.If I use 2nd query then I get duplicate rows.
Thanks ,
Amrit -
Help with outer joins in Oracle!!
so far this is what i've come up with and the code below does not work. Can anyone please help me on how the sytanx of left joins and how to use multiple left joins in a single query in oracle?
SELECT a.*, b.Position_CD, c.Skill_CD, d.Team_Name, d.Team_Country, d.Club, e.Structure_Name
FROM Roster a, Roster_position b, roster_skill c, Team d, Team_Structure e
where (a.Roster_ID = ((b.Roster_ID= c.Roster_Id(+)) b.roster_id(+)).......
I dont' know how to add more left joins!
Here is the query I'm trying to duplicate (which is a query from Ms Access databaase which works fine).
SELECT a.*, b.Position_CD, c.Skill_CD, d.Team_Name, d.Team_Country, d.Club, e.Structure_Name
from ((Roster a LEFT JOIN (Roster_Position b LEFT JOIN Roster_Skill c ON b.Roster_ID=c.Roster_ID) ON a.Roster_ID=b.Roster_ID) LEFT JOIN Team d ON a.Team_CD=d.Team_CD) LEFT JOIN Team_Structure e ON a.Team_Structure_CD=e.Team_Structure_CD
ORDER BY a.Roster_Id;
Any help or comments are greatly appreciatedFirst,
I am not one of the leading SQL brains here...but I'm taking a stab, nonetheless.
Second,
Here's my best guess - and it seems to me that it should work as there are not two outer joins between any two tables. I hope I decoded your joins correctly - quite a mess that Access syntax!
SELECT a.*, b.position_cd, c.skill_cd, d.team_name, d.team_country, d.club, e.structure_name
FROM ROSTER a, ROSTER_POSITION b, ROSTER_SKILL c, TEAM d, TEAM_STRUCTURE e
WHERE a.roster_id = b.roster_id(+)
AND b.roster_id = c.roster_id(+)
AND a.team_cd = d.team_cd(+)
AND a.team_structure = e.team_structure(+);Third,
As an architect-dude, it seems to me that you have a serious
modeling problem to need so many outer joins in such a basic
grab of data. In any scale other than minute, the performance
of this model will suffer dramatically. Specifically, why can't
ROSTER have an equijoin with TEAM and with TEAM_STRUCTURE - as they
appear to be lookup tables...
Good Luck
(I'm certain you'll get better SQL from the others),
Michael O'Neill
Publisher of the PigiWiki
clever-idea.com
Maybe you are looking for
-
How can we read the screen field values from the report selection screen wi
Hi expart, How can we read the screen field values from the report selection screen with out having an ENTER button pressed . Regards Razz
-
Won't boot up--frozen in time and space
My boyfriend tried installing Leopard or something on his iMac, and now it's completely messed up. It won't boot or anything. I realize that trying to install Leopard was a mistake, but it's done with now. Anyway, I'm pretty sure that he does not hav
-
Upload item long text in RFBIBL00
Hi All, is it posible to upload item long text(item text) in accounting document using RFBIBL00 program? If not there is any tool except creating new program? Hengky
-
Hai , Can Any body help me in creating a Pie Chart in Web dynpro ABAP , My requirement is I have an data in an internal table with company code and Amount , which need to be displayed in Pie chart , it could be helped if u send me the code . Regard
-
hi, i am working for vle integrated sol hyd. can any body send me some xi scenarios or documents for client demo with real(similar to) time business scenarios. or links in internet. thanks and regards. vijender