Quarterly results in query

hi gurus
i am preparing a report on the revenues. now i am getting the revenue for the entire year. i want to get the quarterly results.
i mean i want the results to be displayed in the 1st, 2nd, 3rd and fourth quarter.
what are the steps i need to get the results in this way
thanks in advance
vijaykumar

Vikay Kumar,
http://help.sap.com/saphelp_nw04/helpdata/en/0f/80bf39137e9817e10000000a11402f/frameset.htm
this explains how to get quarters using posting period...
Hope it helps.
The page is for something to do with cost controlling or something but I guess the logic indicated should work.
Arun
P.S Rewarding points is a way of saying thank you in SDN
Message was edited by: Arun Varadarajan

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Inconsistent SDO_RELATE results when querying 2.5D data

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I'm getting inconsistent results from SDO_RELATE results when querying 2.5D data. Some geometries I expect to be OVERLAPBDYDISJOINT, are not always being returned by SDO_RELATE when using the OVERLAPBDYDISJOINT mask. It seems that the order of the tables makes a difference to the result.
Here's a table with one 2.5D geometry and a 2D index:
CREATE TABLE TEST1 (
ID                NUMBER PRIMARY KEY,
GEOMETRY     SDO_GEOMETRY);
INSERT INTO TEST1 (id, geometry) VALUES (
1,
SDO_GEOMETRY(3002, 2157, NULL, SDO_ELEM_INFO_ARRAY(1, 2, 1), SDO_ORDINATE_ARRAY(561695.935, 834005.726, 25.865,
561696.229, 834005.955, 25.867, 561686.278, 834015.727, 26.088, 561685.179, 834019.771, 26.226, 561680.716, 834022.389, 26.226,
561674.434, 834025.125, 26.171, 561671.963, 834032.137, 25.667, 561670.832, 834037.185, 25.619, 561667.946, 834042.976, 25.84,
561666.717, 834047.218, 26.171, 561664.229, 834051.781, 26.778, 561660.041, 834055.935, 26.64, 561657.514, 834061.742, 26.53,
561658.59, 834067.116, 27.882, 561657.67, 834070.739, 28.821, 561653.028, 834073.777, 29.042, 561653.234, 834078.769, 28.379,
561658.336, 834080.105, 29.511, 561664.582, 834079.468, 31.94, 561669.257, 834075.821, 33.707, 561672.716, 834074.456, 33.707,
561676.875, 834077.262, 33.735, 561675.868, 834081.55, 33.707, 561673.131, 834087.641, 33.679, 561672.208, 834093.502, 33.238,
561668.578, 834100.894, 33.735, 561666.013, 834106.399, 33.679, 561661.408, 834111.23, 33.514, 561654.854, 834117.181, 33.486,
561651.695, 834122.292, 33.569, 561649.112, 834128.847, 33.431, 561645.982, 834134.786, 33.293, 561642.485, 834141.235, 33.072,
561642.138, 834150.085, 33.293, 561646.072, 834159.721, 36.578, 561647.274, 834165.532, 37.02, 561646.359, 834170.867, 37.02,
561645.42, 834175.485, 36.799, 561642.44, 834180.977, 36.826, 561638.677, 834185.419, 36.771, 561636.693, 834194.824, 37.158,
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561625.79, 834226.697, 39.532, 561620.561, 834236.494, 39.891, 561619.265, 834249.687, 39.697, 561619.883, 834260.02, 41.326,
561620.977, 834264.399, 43.093, 561622.557, 834270.723, 43.452, 561622.172, 834276.978, 43.452, 561621.347, 834285.541, 43.479,
561622.214, 834292.055, 43.645, 561619.718, 834302.583, 43.755, 561616.762, 834316.47, 43.755, 561608.842, 834328.241, 43.7,
561606.346, 834334.93, 43.7, 561605.27, 834341.929, 43.7, 561603.925, 834350.648, 43.728, 561602.462, 834358.405, 43.838,
561599.552, 834366.629, 44.031, 561594.551, 834374.291, 43.396, 561590.644, 834383.986, 43.065, 561588.48, 834392.21, 44.942,
561586.923, 834397.32, 46.737, 561584.608, 834402.898, 49.299, 561581.389, 834410.194, 50.077, 561580.437, 834419.49, 51.907,
561580.438, 834427.63, 53.127, 561582.245, 834433.389, 55.791, 561586.664, 834433.397, 57.503, 561593.88, 834433.608, 57.475,
561596.305,834439.653, 57.42, 561591.804, 834445.862, 57.309, 561589.097, 834447.689, 57.014)));
SELECT sdo_geom.validate_geometry_with_context(geometry, 0.0005) FROM TEST1;
DELETE FROM user_sdo_geom_metadata WHERE table_name = 'TEST1' AND column_name = 'GEOMETRY';
INSERT INTO user_sdo_geom_metadata VALUES ('TEST1','GEOMETRY',
     MDSYS.SDO_DIM_ARRAY(
     MDSYS.SDO_DIM_ELEMENT('X',400000,750000,0.0005),
     MDSYS.SDO_DIM_ELEMENT('Y',500000,1000000,0.0005),
     MDSYS.SDO_DIM_ELEMENT('Z',-10000,10000,0.0005)
), 2157);
DROP INDEX TEST1_SPIND;
CREATE INDEX TEST1_SPIND ON TEST1(GEOMETRY) INDEXTYPE IS MDSYS.SPATIAL_INDEX PARAMETERS ('layer_gtype=line sdo_indx_dims=2');And here's another table with a 2D geometry and a 2D index:
CREATE TABLE TEST2 (
ID                NUMBER PRIMARY KEY,
GEOMETRY     SDO_GEOMETRY);
INSERT INTO TEST2 (id, geometry) VALUES (
1,
SDO_GEOMETRY(2002, 2157, NULL, SDO_ELEM_INFO_ARRAY(1, 2, 1), SDO_ORDINATE_ARRAY(561816.516, 834055.581, 561819.504, 834057.173,
561817.942, 834060.818, 561810.044, 834078.997, 561805.576, 834087.634, 561801.572, 834094.299, 561798.558, 834100.467,
561796.254, 834107.637, 561793.754, 834115.605, 561794.049, 834123.694, 561793.698, 834130.518, 561792.905, 834138.883,
561787.867, 834145.772, 561782.544, 834150.548, 561777.707, 834156.53, 561773.945, 834161.32, 561771.061, 834166.957,
561768.155, 834173.131, 561764.735, 834178.744, 561759.603, 834187.782, 561756.146, 834195.493, 561753.416, 834198.821,
561754.141, 834205.691, 561756.768, 834209.681, 561757.217, 834216.701, 561753.086, 834232.46, 561744.371, 834254.589,
561740.936, 834263.001, 561737.198, 834272.208, 561732.231, 834284.915, 561730.52, 834297.01, 561728.339, 834310.053,
561727.825, 834328.069, 561730.461, 834342.992, 561729.808, 834367.948, 561730.216, 834396.988, 561732.273, 834419.047,
561732.783, 834424.668, 561731.647, 834432.212, 561731.872, 834439.436, 561731.39, 834449.269, 561732.041, 834462.813,
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561727.488, 834555.23, 561729.357, 834577.873, 561731.05, 834595.931, 561731.163, 834611.928, 561734.057, 834637.031,
561732.67, 834636.4, 561725.401, 834633.796, 561721.039, 834632.493, 561718.777, 834632.167, 561710.437, 834632.888,
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561608.718, 834624.94, 561599.935, 834619.684, 561596.67, 834613.843, 561594.27, 834607.774, 561592.513, 834601.752,
561591.349, 834593.899, 561597.265, 834584.888, 561595.956, 834571.479, 561595.075, 834556.196, 561593.997, 834539.68,
561594.316, 834528.071, 561595.261, 834516.44, 561595.538, 834504.804, 561597.227, 834497.417, 561599.3, 834490.416,
561601.265, 834482.61, 561605.126, 834475.502, 561599.232, 834473.683, 561593.076, 834471.379, 561599.154, 834451.112,
561589.097, 834447.689, 561591.804, 834445.862, 561596.305, 834439.653, 561593.88, 834433.608, 561582.245, 834433.389,
561580.438, 834427.63, 561580.437, 834419.49, 561581.389, 834410.194, 561584.608, 834402.898, 561586.923, 834397.32,
561588.48, 834392.21, 561590.644, 834383.986, 561594.551, 834374.291, 561599.552, 834366.629, 561602.462, 834358.405,
561603.925, 834350.648, 561605.27, 834341.929, 561606.346, 834334.93, 561608.842, 834328.241, 561616.762, 834316.47,
561619.718, 834302.583, 561622.214, 834292.055, 561621.347, 834285.541, 561622.172, 834276.978, 561622.557, 834270.723,
561620.977, 834264.399, 561619.883, 834260.02, 561619.265, 834249.687, 561620.561, 834236.494, 561625.79, 834226.697,
561627.554, 834220.393, 561628.871, 834213.994, 561631.998, 834208.745, 561635.462, 834202.105, 561636.693, 834194.824,
561638.677, 834185.419, 561642.44, 834180.977, 561645.42, 834175.485, 561646.359, 834170.867, 561647.274, 834165.532,
561646.072, 834159.721, 561642.138, 834150.085, 561642.485, 834141.235, 561645.982, 834134.786, 561649.112, 834128.847,
561651.695, 834122.292, 561654.854, 834117.181, 561661.408, 834111.23, 561666.013, 834106.399, 561668.578, 834100.894,
561672.208, 834093.502,561673.131, 834087.641, 561675.868, 834081.55, 561676.875, 834077.262, 561672.716, 834074.456,
561669.257, 834075.821, 561664.582, 834079.468, 561658.336, 834080.105, 561653.234, 834078.769, 561653.028, 834073.777,
561657.67, 834070.739, 561658.59, 834067.116, 561657.514, 834061.742, 561660.041, 834055.935, 561664.229, 834051.781,
561666.717, 834047.218, 561667.946, 834042.976, 561670.832, 834037.185, 561671.963, 834032.137, 561674.434, 834025.125,
561680.716, 834022.389, 561685.179, 834019.771, 561686.278, 834015.727, 561696.229, 834005.955, 561695.935, 834005.726,
561677.805, 833994.91, 561683.163, 833985.817, 561703.01, 833949.434, 561725.891, 833961.856, 561744.35, 833971.197,
561768.396, 833983.86, 561777.842, 833988.883, 561798.333, 833999.743, 561797.243, 834005.725, 561783.574, 834040.515,
561798.127, 834046.391, 561807.001, 834050.509, 561816.516, 834055.581)));
SELECT sdo_geom.validate_geometry_with_context(geometry, 0.0005) FROM TEST2;
DELETE FROM user_sdo_geom_metadata WHERE table_name = 'TEST2' AND column_name = 'GEOMETRY';
INSERT INTO user_sdo_geom_metadata VALUES ('TEST2','GEOMETRY',
     MDSYS.SDO_DIM_ARRAY(
     MDSYS.SDO_DIM_ELEMENT('X',400000,750000,0.0005),
     MDSYS.SDO_DIM_ELEMENT('Y',500000,1000000,0.0005)
), 2157);
DROP INDEX TEST2_SPIND;
CREATE INDEX TEST2_SPIND ON TEST2(GEOMETRY) INDEXTYPE IS MDSYS.SPATIAL_INDEX PARAMETERS ('layer_gtype=line sdo_indx_dims=2');Now if I check how these two geometries relate to each other, the answer is OVERLAPBDYDISJOINT, which makes sense when inspecting the geometries.
SQL> SELECT
2 sdo_geom.relate(t1.geometry, 'determine', t2.geometry, 0.0005) relate_1_to_2,
3 sdo_geom.relate(t2.geometry, 'determine', t1.geometry, 0.0005) relate_2_to_1
4 FROM test2 t2, test1 t1
5 WHERE t1.id = t2.id;
RELATE_1_TO_2        RELATE_2_TO_1
OVERLAPBDYDISJOINT   OVERLAPBDYDISJOINT
1 row selected.So, I'd expect this query to return something...
SELECT /*+ ORDERED */ t1.id, t2.id, sdo_geom.relate(t1.geometry, 'determine', t2.geometry, 0.0005) relate
FROM test2 t2, test1 t1
WHERE sdo_relate(t1.geometry, t2.geometry, 'mask=overlapbdydisjoint') = 'TRUE'
AND t1.id = 1
AND t2.id = 1;Nada. And this...
SELECT /*+ ORDERED */ t1.id, t2.id, sdo_geom.relate(t1.geometry, 'determine', t2.geometry, 0.0005) relate
FROM test1 t1, test2 t2
WHERE sdo_relate(t2.geometry, t1.geometry, 'mask=overlapbdydisjoint') = 'TRUE'
AND t1.id = 1
AND t2.id = 1;Nada.
And this...
SQL> SELECT /*+ ORDERED */ t1.id, t2.id, sdo_geom.relate(t1.geometry, 'determine', t2.geometry, 0.0005) relate
2 FROM test2 t2, test1 t1
3 WHERE sdo_relate(t2.geometry, t1.geometry, 'mask=overlapbdydisjoint') = 'TRUE'
4 AND t1.id = 1
5 AND t2.id = 1;
        ID         ID RELATE
         1          1 OVERLAPBDYDISJOINT
1 row selected.This version gives the right answer.
Can anyone explain this?

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Message was edited by:
Tomeo

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end;
END;page items to submit: P3_PO_REF_NUMBER
page items to return: P3_VALID
Eventually I thought that I'd create another hide/show DA based on the value of P3_VALID, but before I went much further, I wanted to check to see how this worked. It didn't. Error: exception thrown and not caught.
Any thoughts as to what I'm missing, or am I doing this completely wrong?
Thanks,
Joe

Ok, just for closure. I did get this working.
I ended up deleting the original P3_PO_REF_NUMBER item and recreated it, and everything began to work. As I was doing this, I noticed that it seemed like things would begin to go awry when I changed the item's name, even if I changed it back again. It was almost as if there was an associated between the DA that became corrupted once the item name was changed. If I took the item out of the page items to submit field, no error. Of course the DA wouldn't fire correctly then either because it wasn't getting any value changes, but when I added the item back into the page items to submit field, I go an error.
So:
When I created the second PO_REF_NUMBER item, I did not delete the original first, so the new one of course had to be named differently. Then I modified the DA to use the new item name (PO_REF_NUM). It worked! Cool. So, no wanting to get rid of the original yet, I rename it, and then renamed the second one to what the original was (I have other code using that item name). Then I changed the DA again...but now it failed - unless I blanked out the page items to submit field...
3rd time is a charm. So, this time, I made sure that no items were named "PO_REF_NUMBER", then I created the PO_REF_NUMBER again, naming it exactly as I needed it to be so I wouldn't have to change it later. Then I set out to tweak the field (size, etc), but did not touch the name. Now my DA is working nicely! It sets a hidden field's value, then another DA shows or hides an icon based on that hidden field's.
Hopefully someone will find this useful,
Joe

Too many results for query

Hello,
I'm using Oracle to teach my students database programming with VB.NET (ADO.NET). During my course, I introduce the DataAdapter Configuration wizard of Visual Studio for creating a connection and dataadapter. I'm using OleDb (from Microsoft) to connect to Oracle.
The problem is that this wizard asks Oracle for all the tables that can possibly be used for a user. When 20 students do this exercise at the same time, the Oracle DB (we use release 9, version 2 on Windows) responds extremely slow.
I used tracing to search for the query that this wizard generates (using trace files) and I found this one:
select * from (select null table_catalog, decode (o1.owner, 'PUBLIC', NULL, o1.owner) table_schema, o1.object_name table_name, decode(o1.owner,'SYS',decode(o1.object_type,'TABLE','SYSTEM TABLE','VIEW','SYSTEM VIEW',o1.object_type),'SYSTEM',decode(o1.object_type,'TABLE','SYSTEM TABLE','VIEW','SYSTEM VIEW',o1.object_type),o1.object_type) table_type, null table_guid, null description, null table_propid, null date_created, null date_modified from all_objects o1 where o1.object_type in ('TABLE','VIEW')union select null table_catalog, decode (o2.owner, 'PUBLIC', NULL, o2.owner) table_schema, o2.object_name table_name, o2.object_type table_type, null table_guid, null description, null table_propid, null date_created, null date_modified from all_objects o2, all_objects o3, all_synonyms s where o2.object_type = 'SYNONYM' and o3.object_type in ('TABLE','VIEW') and o2.owner = s.owner and o2.object_name = s.synonym_name and s.table_owner = o3.owner and s.table_name = o3.object_name) tables order by 4,2,3
Has anybody an idea how I can limit the results of this query? It's not an option to change the query itself, because its executed by Visual Studio, I was thinking to revoke some rights for my student accounts, but I'm no expert, so ...
PS: my student accounts have standard roles CONNECT and RESOURCE
thanks in advance,
Kris Hermans.
instructor
http://www.xios.be

I think you are on the right track with revoking rights. The query you listed refers to all_tables -- which is the list of all the tables that the person executing the query has access to.
But to accomplish your goal, you would have to know more about the users and roles that they are doing. The view all_tab_privs shows you a list of tables and the privilege level for each grantee. You would have to revoke their select (and other) privs in order to stop them from showing up in the all_tables view.
But be careful....

Overall result in Query designer displaying ' * ' for one kf when executing

Hello
I have a got a kf in which value ' * ' is getting displayed when i have done display overall results for one of my chars. Now what i am hoping is that this can be because there are too many records in the display and the total is too huge and that is the reason it is disaplying * in it. Please can somone guide me if there is some setting that can be done

Hi Tom,
This is because you have different unit or currency in the data record and you can not sum it if they are different unit/Currency therefore system is showing you *.
You can try NODIM(KF) and see if it is adding or try currency or unit conversion at query level so that all records in the query have same unit/currency.
Regards,
Kams

How to show the result of query in oracle forms 10g to Excel Sheet File

Dear All,
I have query and i want the result to be show in excel sheet file in oracle forms
for example if i have a form with search criteria and when pressed the button of ( export to excel ) the result is
excel file contains the result of the query .

The only method to achieve this is with the help of Webutil. Please go through documentation for more help.
Regards,
Manoj Chakravarthy

Insert result of query into a table with unique constraint

Hi,
I have a query result that I would like to store in a table. The target table has a unique constraint. In MySQL you can do
insert IGNORE into myResultTable <...select statement...>
The IGNORE clause means if inserting a row would violate a unique or primary key constraint, do not insert the row, but continue inserting the rest of the query. Leaving the IGNORE clause out would cause the insert to fail and an error to return.
I would like to do this in oracle... that is insert the results of a query that are not already in the target table. What is the best way to do this? One way is use a procedural language and loop through the first query, checking to see if each row is a duplicate before inserting it. I would think this would be slow if there are lots of records. Other options...
insert into myTargetTable
select value from mySourceTable where ... and not exists (select 'x' from myTargetTable where value = mySourceTable.value)
insert into myTargetTable
select mySourceTable.value
from myTargetTable RIGHT JOIN mySourceTable
ON myTargetTable.value = mySourceTable.value
where ...
and myTargetTable.value IS NULL
any other suggestions?
Thanks,
Simon

Try doing a MINUS instead of not exists., ie Source MINUS Target.
Disabling the constraint will not help you since this will allow the duplicate rows to be inserted into the table. I don't think you want this.
--kalpana

Quarterly results in query

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