Query to get the data of all the columns in a table except any one column

Question

Can anyone please tell how to write a query to get the data of all the columns in a table except one particular column..
For Example:
Let us consider the EMP table.,
From this table except the column comm all the remaining columns of the table should be listed
For this we can write a query like this..
Select empno, ename, job, mgr, sal, hiredate, deptno from emp;
Just to avoid only one column, I mentioned all the remaining ( 7 ) columns of the table in the query..
As the EMP table consists only 8 columns, it doesn't seem much difficult to mention all the columns in the query,
but if a table have 100 columns in the table, then do we have to mention all the columns in the query..?
Is there any other way of writing the query to get the required result..?
Thanks..

Answer 1

Your best best it to just list all the columns. Any other method will just cause more headaches and complicated code.
If you really need to list all the columns for a table because you don't want to type them, just use something like...
SQL> ed
Wrote file afiedt.buf
  1  select trim(',' from sys_connect_by_path(column_name,',')) as columns
  2  from (select column_name, row_number() over (order by column_id) as column_id
  3        from user_tab_cols
  4        where column_name not in ('COMM')
  5        and   table_name = 'EMP'
  6       )
  7  where connect_by_isleaf = 1
  8  connect by column_id = prior column_id + 1
  9* start with column_id = 1
SQL> /
COLUMNS
EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,DEPTNO
SQL>