Regarding unicode conversion

Question

HI ,
i have a
string a="0621 0622 0623";
each 4 characters represents unicode character,when iam outputing the string as in following program
for(int i=0;i<a.length();i+=4){
String sub=a.substring(i,i+4);
stringbuffer.append("\\u"+sub);
then iam getting output as "\u0621 \u0622 \u0623" ,actually i should get output represented by those unicode characters 'which is an arabic characters,.
after trying i used second method like ,
for(int i=0;i<a.length();i+=4){
isub=a.substring(i,i+4);
int k=Integer.parseInt(isub,16);
stringbuffer.append(char(k));
when iam outputting stringbuffer iam getting output ???? characters,
Is there any way to convert that hexa string a, to utf-8 format,so that it can be furher processed by other application,
kindly reply,
Thanks

Answer 1

    char c = (char) Integer.parseInt("0621", 16);
    System.out.println("The character is " + c);I get ? out too, but I think this an output problem and the char inside the Java program i correct.
"\\u" + "0621" is a string consisting of 6 chars: a backslash, a u and four digits. "\u0621" is a String consisting of one char, the one with unicode value 0621. There is no direct conversion between these two Strings.