Regular Expressions from C++ to Java

Does anyone know if it is possible to use the same regular expressions used in C++ with in Java? Here it is a regular expression used in a C++ program:
^[[:digit:]]{4}$"I did a test, but it does not work. It always evaluate to false.
Thanks,
Sid

Does anyone know if it is possible to use the same
regular expressions used in C++ with in Java? C++ doesn't have regexes, so presumably you are using a library (and noting that might help.)

Similar Messages

Migrating Regular Expression from apache to Java1.4

Did any one out there migrate from apache regular expressions to the new Java regular expressions? Are the two compatible? How much work is it to do this? What are the pitfalls? Are there any resources on this topic?
Thanks,

I did migrate some Jakarta regexp to java 1.4's. If ur old codes just used match() method to see if a string matches the pattern, then search/replace using any decent text edit could quickly migrate all of them. However, if you used lots of the Apache regexp's APIs, the fastest way is to write a wrap class for each class you used in the regexp pacakage, and use the new regexp package to implement all the Apach regexp APIs, then, the only thing you need to do is to replace the import statement to import those wrapper classes. I personally think this is the best and common way to migrate from an old API package to a new one.

Mining for regular expressions from text

Hi all
I have a situation where I need to develop a set of regular expressions from lists.
I have lists of files uploaded and downloaded, and when the event happened. I need to analyze these and boil them down to a set of regular expressions.
The regular expressions will be used in the future to check the logs for activities. For example:
foo*.zip is downloaded every night. Has it been downloaded tonight.
I am looking for help in analyzing the lists of files and deriving regular expressions to describe them.
Any ideas?
Thanks all

check the url http://java.sun.com/developer/technicalArticles/releases/1.4regex/index.html

Remove regular expression from a string

Hello,
I have a string like this
@1test;'"{input+
Please help me to remove special characters from the string.

A: remove regular expression from a string

Hi Krishna,
DATA : str TYPE STRING VALUE '@1test;"{}]input+',
            char,
            length TYPE i,
            index TYPE i.
length = STRLEN( str ).
WHILE length > index.
char = str+index(1).
WRITE char.
if char CA '+-*/!`@#$%^&()_=[]{};'.               " Add/Remove here to include numbers
    REPLACE ALL OCCURRENCES OF char in str WITH ''.
    REPLACE ALL OCCURRENCES OF '"' in str WITH ''. " characters "{}[] are not comparable
    REPLACE ALL OCCURRENCES OF '{' in str WITH ''.
    REPLACE ALL OCCURRENCES OF '}' in str WITH ''.
    REPLACE ALL OCCURRENCES OF '[' in str WITH ''.
    REPLACE ALL OCCURRENCES OF ']' in str WITH ''.
    length = STRLEN( str ).
    ENDIF.
add 1 to index.
ENDWHILE.
WRITE str.
Add or remove special char from '+-*/!`@#$%^&()_=[]{};' in if part as per your requirement.
Hope it meets your requirement.
Do not forget to mark helpful/correct if ma answer is useful .
Thanks,
Karthik

Validation for regular expressions special characters in java

Hi,
I need to validate an user name field to an application while creating that. It has to contain only alpha numerics. can you give me the regular expression and also how to implement that.
thanks,
VJ

Do your own work. Look up the documentation on Pattern and make an attempt at validating a String yourself. Then worry about implementing a GUI on top of that.

Replace a string using regular expression from powershell

I want to replace the following:
'browserName': 'firefox'
with :
'browserName': 'chrome'
then I tried this:
(get-content $conffile) -replace "^('browserName': ')\S+","browserName': 'chrome' |set-content $conffile
But nothing happened.
Could someboby tell me how to write the regular expression here? Thanks a lot.

Second person today with the same question.
get-content $conffile |%{$_ -replace "'browserName':\s+'firefox'","'browserName': 'chrome'" | set-content $conffile
\_(ツ)_/

ALC-FUT-001-007: Syntax error in the regular expression *. from File Utilities - Find in ES2

Has anyone encountered the above error when trying to use the Foundation - File Utilities service Find?
This is occuring in ES2, and I have tried using an asterisk, as well as the exact file name I know exists.
I have tried literals in the Process Properties, as well as passing it in via string variables.
Any help is appreciated.
Thanks
Mark

Thanks for your response.
Here is what we have learned:
We should not put the regular expression value in single quotes - eliminates the error.
The problem is, the Find operation always returns an empty list no matter what criteria we enter - even C:\ with criteria = *.*
ES 2 is running on a Windows 2003 machine.
Thanks Again
Mark

Getting the regular expression from the given text

Hi
I need to develope an application which can convert the given text into the regular expression. I need that when i enter any text in textarea that should be translated into regular expression in another panel. but i could not find the method or technique which can do so. plz help me to resolve this issue.
Thanks Imran khan.

well, there are an infinite number of regular expressions for an arbitrary piece of text, so you will have to qualify in your mind what the purpose of the regular expression is.
For instance, it is trivial to create a regex for a string just by copying the input text, and inserting \ before any special characters. But this pattern would probably be quite silly.

Java regular expression for CSV?

I found several regular expressions in the internet to parse/split csv data lines. Howeverm, they all don't work with the Java regular expression API. Is there a regular expression to tokenize CSV fields for the Java regexp API?

If the licensing of the above solution is too restrictive for you...I'm sure there are other types of parsers out there that do that type of thing.
In the meantime, here is some code I cooked up (no GPL...use it freely) that might get you started.
Don't know that it handles everything, but I never said it would...
Please READ and let me know what changes could be made. I'm always looking for improvements in my understanding of regular expressions...
import java.util.regex.*;
import java.util.*;
import java.util.List;
public class Example
   final static Pattern CSV_PATTERN;
   final static Pattern DOUBLE_QUOTE;
   static
      String regex = "(?: ([^q;]+) | (?: q ((?: (?:[^q]+) | (?:qq) )+ ) q) );?";
      //                       1          2          a           b       3    4
      // So, pretend your quote character is q
      // (you can change it to \" later when you understand what's going on.)
      // This regex (when applied iteravely) matches a token that:
      // 1) contains NO QUOTE MARKS whatsoever (;'s) (in group 1)
      //                       or
      // 2) starts with a QUOTE, then contains either
      //    a) no quotes at all inside or
      //    b) double quotes (to escape a quote)
      // 3) and ends with a QUOTE.
      // 4) and is followed by a separator (optional for the last value)
      // Note that (a) and (b) are captured in group 2 of the regex.
      CSV_PATTERN = Pattern.compile(regex, Pattern.COMMENTS);
      DOUBLE_QUOTE = Pattern.compile("qq");
    * Attempts to parse Excel CSV stuff...
    * @param text the CSV text.
    * @return a list of tokens.
   public static List parseCsv(String text)
      Matcher csvMatcher = CSV_PATTERN.matcher(text);
      Matcher doubleQuotes = DOUBLE_QUOTE.matcher("");
      List list = new ArrayList();
      while (csvMatcher.find())
         if (csvMatcher.group(1) != null)
            // The first one matched.
            list.add(csvMatcher.group(1));
         else
            doubleQuotes.reset(csvMatcher.group(2));
            list.add(doubleQuotes.replaceAll("q"));
      return list;
}

Problem with email regular expression

I found the following regular expression from this website : http://www.regular-expressions.info/email.html
\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}\bor
^[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}$I am using the following website to check its success, as well as my java app. : http://www.regexplanet.com/simple/index.html
of course java has a problem with the illegal escape character so i add another "/".
In both of my testing scenarios the regex value seems to fail. Am I missing something here?
If anyone could also test this regex and verify or correct my problem I would be very grateful.
Edited by: rico16135 on Jun 5, 2010 4:01 PM
Edited by: rico16135 on Jun 5, 2010 4:02 PM

rico16135 wrote:
of course java has a problem with the illegal escape character so i add another "/".I seem to be missing the distinction between a forward slash / which is not an escape character, and a backslash \ which is.
Also, if you show your actual Java code (in code tags, of course), and describe clearly and precisely what's going wrong--pasting in the exact, complete error message and indicating clearly which line caused it, if there is one--people will be in a better position to help you.

Introduction to regular expressions ... last part.

Continued from Introduction to regular expressions ... continued., here's the third and final part of my introduction to regular expressions. As always, if you find mistakes or have examples that you think could be solved through regular expressions, please post them.
Having fun with regular expressions - Part 3
In some cases, I may have to search for different values in the same column. If the searched values are fixed, I can use the logical OR operator or the IN clause, like in this example (using my brute force data generator from part 2):
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE data IN ('abc', 'xyz', '012');There are of course some workarounds as presented in this asktom thread but for a quick solution, there's of course an alternative approach available. Remember the "|" pipe symbol as OR operator inside regular expressions? Take a look at this:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)$')
;I can even use strings composed of values like 'abc, xyz , 012' by simply using another regular expression to replace "," and spaces with the "|" pipe symbol. After reading part 1 and 2 that shouldn't be too hard, right? Here's my "thinking in regular expression": Replace every "," and 0 or more leading/trailing spaces.
Ready to try your own solution?
Does it look like this?
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(' || REGEXP_REPLACE('abc, xyz , 012', ' *, *', '|') || ')$')
;If I wouldn't use the "^" and "$" metacharacter, this SELECT would search for any occurence inside the data column, which could be useful if I wanted to combine LIKE and IN clause. Take a look at this example where I'm looking for 'abc%', 'xyz%' or '012%' and adding a case insensitive match parameter to it:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)', 'i')
; An equivalent non regular expression solution would have to look like this, not mentioning other options with adding an extra "," and using the INSTR function:
SELECT data
FROM (SELECT data, LOWER(DATA) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search LIKE 'abc%'
    OR search LIKE 'xyz%'
    OR search LIKE '012%'
SELECT data
FROM (SELECT data, SUBSTR(LOWER(DATA), 1, 3) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search IN ('abc', 'xyz', '012')
; I'll leave it to your imagination how a complete non regular example with 'abc, xyz , 012' as search condition would look like.
As mentioned in the first part, regular expressions are not very good at formatting, except for some selected examples, such as phone numbers, which in my demonstration, have different formats. Using regular expressions, I can change them to a uniform representation:
WITH t AS (SELECT '123-4567' phone
             FROM dual
            UNION
           SELECT '01 345678'
             FROM dual
            UNION
           SELECT '7 87 8787'
             FROM dual
SELECT t.phone, REGEXP_REPLACE(REGEXP_REPLACE(phone, '[^0-9]'), '(.{3})(.*)', '(\1)-\2')
FROM t
;First, all non digit characters are beeing filtered, afterwards the remaining string is put into a "(xxx)-xxxx" format, but not cutting off any phone numbers that have more than 7 digits. Using such a conversion could also be used to check the validity of entered data, and updating the value with a uniform format afterwards.
Thinking about it, why not use regular expressions to check other values about their formats? How about an IP4 address? I'll do this step by step, using 127.0.0.1 as the final test case.
First I want to make sure, that each of the 4 parts of an IP address remains in the range between 0-255. Regular expressions are good at string matching but they don't allow any numeric comparisons. What valid strings do I have to take into consideration?
Single digit values: 0-9
Double digit values: 00-99
Triple digit values: 000-199, 200-255 (this one will be the trickiest part)
So far, I will have to use the "|" pipe operator to match all of the allowed combinations. I'll use my brute force generator to check if my solution works for a single value:
SELECT data
FROM TABLE(regex_utils.gen_data('0123456789', 3))
WHERE REGEXP_LIKE(data, '^(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$')
; More than 255 records? Leading zeros are allowed, but checking on all the records, there's no value above 255. First step accomplished. The second part is to make sure, that there are 4 such values, delimited by a "." dot. So I have to check for 0-255 plus a dot 3 times and then check for another 0-255 value. Doesn't sound to complicated, does it?
Using first my brute force generator, I'll check if I've missed any possible combination:
SELECT data
FROM TABLE(regex_utils.gen_data('03.', 15))
WHERE REGEXP_LIKE(data,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; Looks good to me. Let's check on some sample data:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
            UNION
           SELECT '256.128.64.32'
             FROM dual
SELECT t.ip
FROM t WHERE REGEXP_LIKE(t.ip,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; No surprises here. I can take this example a bit further and try to format valid addresses to a uniform representation, as shown in the phone number example. My goal is to display every ip address in the "xxx.xxx.xxx.xxx" format, using leading zeros for 2 and 1 digit values.
Regular expressions don't have any format models like for example the TO_CHAR function, so how could this be achieved? Thinking in regular expressions, I first have to find a way to make sure, that each single number is at least three digits wide. Using my example, this could look like this:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2')
FROM t
; Look at this: leading zeros. However, that first value "00127" doesn't look to good, does it? If you thought about using a second regular expression function to remove any excess zeros, you're absolutely right. Just take the past examples and think in regular expressions. Did you come up with something like this?
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2'),
                            '[0-9]*([0-9]{3})(\.?)', '\1\2'
FROM t
; Think about the possibilities: Now you can sort a table with unformatted IP addresses, if that is a requirement in your application or you find other values where you can use that "trick".
Since I'm on checking INET (internet) type of values, let's do some more, for example an e-mail address. I'll keep it simple and will only check on the
"[email protected]", "[email protected]" and "[email protected]" format, where x represents an alphanumeric character. If you want, you can look up the corresponding RFC definition and try to build your own regular expression for that one.
Now back to this one: At least one alphanumeric character followed by an "@" at sign which is followed by at least one alphanumeric character followed by a "." dot and exactly 3 more alphanumeric characters or 2 more characters followed by a "." dot and another 2 characters. This should be an easy one, right? Use some sample e-mail addresses and my brute force generator, you should be able to verify your solution.
Here's mine:
SELECT data
FROM TABLE(regex_utils.gen_data('a1@.', 9))
WHERE REGEXP_LIKE(data, '^[[:alnum:]]+@[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})$', 'i'); Checking on valid domains, in my opinion, should be done in a second function, to keep the checks by itself simple, but that's probably a discussion about readability and taste.
How about checking a valid URL? I can reuse some parts of the e-mail example and only have to decide what type of URLs I want, for example "http://", "https://" and "ftp://", any subdomain and a "/" after the domain. Using the case insensitive match parameter, this shouldn't take too long, and I can use this thread's URL as a test value. But take a minute to figure that one out for yourself.
Does it look like this?
WITH t AS (SELECT 'Introduction to regular expressions ... last part. URL
             FROM dual
            UNION
           SELECT 'http://x/'
             FROM dual
SELECT t.URL
FROM t
WHERE REGEXP_LIKE(t.URL, '^(https*|ftp)://(.+\.)*[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})/', 'i')
Update: Improvements in 10g2
All of you, who are using 10g2 or XE (which includes some of 10g2 features) may want to take a look at several improvements in this version. First of all, there are new, perl influenced meta characters.
Rewriting my example from the first lesson, the WHERE clause would look like this:
WHERE NOT REGEXP_LIKE(t.col1, '^\d+$')Or my example with searching decimal numbers:
'^(\.\d+|\d+(\.\d*)?)$'Saves some space, doesn't it? However, this will only work in 10g2 and future releases.
Some of those meta characters even include non matching lists, for example "\S" is equivalent to "[^ ]", so my example in the second part could be changed to:
SELECT NVL(LENGTH(REGEXP_REPLACE('Having fun with regular expressions', '\S')), 0)
FROM dual
;Other meta characters support search patterns in strings with newline characters. Just take a look at the link I've included.
Another interesting meta character is "?" non-greedy. In 10g2, "?" not only means 0 or 1 occurrence, it means also the first occurrence. Let me illustrate with a simple example:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +')
FROM dual
;This is old style, "greedy" search pattern, returning everything until the last space.
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +?')
FROM dual
;In 10g2, you'd get only "Having " because of the non-greedy search operation. Simulating that behavior in 10g1, I'd have to change the pattern to this:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^[^ ]+ +')
FROM dual
;Another new option is the "x" match parameter. It's purpose is to ignore whitespaces in the searched string. This would prove useful in ignoring trailing/leading spaces for example. Checking on unsigned integers with leading/trailing spaces would look like this:
SELECT REGEXP_SUBSTR(' 123 ', '^[0-9]+$', 1, 1, 'x')
FROM dual
;However, I've to be careful. "x" would also allow " 1 2 3 " to qualify as valid string.
I hope you enjoyed reading this introduction and hope you'll have some fun with using regular expressions.
C.
Fixed some typos ...
Message was edited by:
cd
Included 10g2 features
Message was edited by:
cd

Can I write this condition with only one reg expr in Oracle (regexp_substr in my example)?I meant to use only regexp_substr in select clause and without regexp_like in where clause.
but for better understanding what I'd like to get
next example:
a have strings of two blocks separated by space.
in the first block 5 symbols of [01] in the second block 3 symbols of [01].
In the first block it is optional to meet one (!), in the second block it is optional to meet one (>).
The idea is to find such strings with only one reg expr using regexp_substr in the select clause, so if the string does not satisfy requirments should be passed out null in the result set.
with t as (select '10(!)010 10(>)1' num from dual union all
select '1112(!)0 111' from dual union all --incorrect because of '2'
select '(!)10010 011' from dual union all
select '10010(!) 101' from dual union all
select '10010 100(>)' from dual union all
select '13001 110' from dual union all -- incorrect because of '3'
select '100!01 100' from dual union all --incorrect because of ! without (!)
select '100(!)1(!)1 101' from dual union all -- incorrect because of two occurencies of (!)
select '1001(!)10 101' from dual union all --incorrect because of length of block1=6
select '1001(!)10 1011' from dual union all) --incorrect because of length of block2=4
select '10110 1(>)11(>)0' from dual union all)--incorrect because of two occurencies of (>)
select '1001(>)1 11(!)0' from dual)--incorrect because (!) and (>) are met not in their blocks
--end of test data

Regular expressions in JavaScript for CP5?

I'm having trouble implementing a regular expression from within the JavaScript window. First of all, does CP 5 support regular expressions?

On slide 1 I have a Text Entry Box, (called TheTeb) with a Submit button. TheTeb has variable associated with it called TypedText.
In the box, the user may type anything.
On slide 2 there is a caption.
The caption must show the text that the user typed into TheTeb but filtered so that only the letters, numbers, and spaces can be shown.
For example,
if the user types:           123 & abc /DEF
the caption will show: 123 abc DEF
This requirement is represents the behavior of an application that I am simulating, so I don't want to change the interaction in any way.
My strategy is to use 2 different variables, one for the text entry box (TypedText), the other for the caption (FilteredText). I can add JavaScript to the On Enter event of slide 2. The script will Get the TypedText, pass the TypedText to FilteredText, and run a regular expression somewhere so the filtered text displays on slide 2.
Here's the script so far:
var objCP = document.Captivate;
var ScriptTypedText = objCP.cpEIGetValue('TypedText');
function ReturnValue(){
objCP.cpEISetValue('FilteredText', ScriptTypedText);
ReturnValue();
The script works as is. The user types text on slide 1 (as TypedText), presses Enter and the text shows up on slide 2 (as $$FilteredText$$). Obviously, the trouble is, I don't know where to add my regular expression into the JavaScript so the text actually gets filtered. Do I make a new function?
By the way, a sort of pseudocode syntax for the expression would be:
FilteredText = TypedText.replace(/ /g,"");

Regular expression - find if string does NOT contain text....

I have a string that I want to tokenize. The string can contain basically anything. I want to produce tokens for each "word" found, and for each "<=" or "," found. There does not need to be whitespace around a "<=" or a "," to consider it a token. So for example:
joe schmoe<=jack, jane
should become
joe
schmoe
<=
jack
jane
As a constraint, I do not want to use StringTokenizer at all, as "its use is discouraged in new code". http://java.sun.com/j2se/1.4.2/docs/api/java/util/StringTokenizer.html
Here's the code I plan on using for this:
    public String[] getWords(String input) {
        Matcher matcher = WORD_PATTERN.matcher(input);
        ArrayList<String> words = new ArrayList<String>();
        while (matcher.find()) {
            words.add(matcher.group());
        return (String[]) words.toArray(new String[0]);
    }The trick, though, is coming up with a working regular expression. The closest I've found yet is:
([^\s]|^(,)|^(<=))+|,|<=
but that produces the following:
joe
schmoe<=jack,
jane
I think what I need is to be able to find if a string does not contain the substring "<=" or "," using a regular expression. Anyone know how to do this, or another way to do this using regular expressions?

Try:
* Tokenizer.java
* version 1.0
* 01/06/2005
package samples;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
* @author notivago
public class StrangeTokenizer {
    public static void main(String[] args) {
        String text = "joe schmoe<=jack, jane";
        Pattern pattern = Pattern.compile( "((?:<=)|(?:,)|(?:\\w+))");
        Matcher matcher = pattern.matcher(text);
        while( matcher.find() ) {
            System.out.println( "Item: " + matcher.group(1) );
}May the code be with you.

Regular expression - Replace a part of an expression

Dear All,
This is not a business requirement, just trying to practice regexp.
Suppose we want to replace a part of a regular expression from a string. As an example, in the string 'THIS Number 124356 Is to Change.This Number 5 Also', I am trying to replace the last digit of each number with $ sign.
Output will be
'THIS Number 12435$ Is to Change.This Number $ Also'.
Will this be possible using a single regexp_replce?
Thanks in advance.

MichaelS wrote:
I am trying to achieve this using a SINGLE regexp_replace.Here we go:
SQL> with t as (
select 'ABC124556def568gh236klJ258' str from dual union all
select 'THIS Number 124356 Is to Change.This Number 5 Also' str from dual
select str, regexp_replace(str, '(\d{0,})\d{1}', '\1$') str2
from t
STR                                                     STR2
ABC124556def568gh236klJ258                              ABC12455$def56$gh23$klJ25$
THIS Number 124356 Is to Change.This Number 5 Also      THIS Number 12435$ Is to Change.This Number $ Also
2 rows selected.
Nice..
Learning for me ..
Never thought of usage like {0,} ... kepping the end value OPEN.
I was trying with \d+?\d, which was not working..

Tomahawk Regular expression Validator

Hi,
I am trying to use Tomahawk RegEx Validator in my application.
My questions are as follows.
1. I want to get the pattern of the regular expression from the bean or resource bundle. Is this possible?
2. If I use the pattern as in <t:validateRegExpr pattern='[a-zA-Z\s]+'/> it works perfectly fine. But when I change that to <t:validateRegExpr pattern='\\p{N}+'/> it doesn't work. I want to do this as there won't be any issues with internationalsation.
Please let me know how these issues can be addressed.
Thanks in Advance.
Regards,
Raja

manick_r wrote:
1. I want to get the pattern of the regular expression from the bean or resource bundle. Is this possible?Read the TLD documentation of the tag in question. If the 'pattern' attribute accepts a ValueExpression, then it is possible. I can't directly answer this as you're at a Sun JSF forum, not at an Apache Tomahawk mailinglist.
2. If I use the pattern as in <t:validateRegExpr pattern='[a-zA-Z\s]+'/> it works perfectly fine. But when I change that to <t:validateRegExpr pattern='\\p{N}+'/> it doesn't work. I want to do this as there won't be any issues with internationalsation.Please elaborate "it doesn't work". What did you expect it to do and what did it do unexpectedly instead? Does this pattern work when you just use it in String#matches()? Provide a SSCCE if you can.

Regular Expressions from C++ to Java

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