Regular Expressions (java.util.regex)

I am developing using a product that must
use java 1.2.2_05a but I want to use regular
expressions, does anybody know where I can
get of the package java.util.regex without
having to download the whole java 1.4 release.
Or does someone know of an alternative that
I can use ?

There is another regex pack for java available from Apache Foundation Project. You can try it.
Take a look at http://jakarta.apache.org/

Similar Messages

Doubt in Regular Expressions : java.util.regex

I want to identify words starting with capital letters in a sentence and I want to replace the matched word with "#" added in front of it.... For example, if my input sentence is
"Christopher Williams asked Mike Muller a question"
my output should be,
"#Christopher #Williams asked #Mike #Muller a question"
How do I do that using java.util.regex ?
In perl we can can use *"back references"* in *"replacement string"* . Perl replacement accepts back references whereas java replacement method accepts only strings....
Please help me.....

Your replacement is swallowing the space before the uppercase character, and won't match at the beginning of the line.
Also, it's unnecesarily verbose. String has a replaceAll method (that calls the same methods of Pattern and Matcher under the covers)sentence = s.replaceAll("(^| )([A-Z])", "$1#$2");Disclaimer: I'm no prome, sabre or u/a :-) That can probably be simplified.
db

Using regular expresions (java.util.regex.*)?

Hello,
I have a couple of Strings I want to change.
If I make up a test String which looks like this </a><h1>h1<script><script><script><script></script></script>
and I want to make a space after each tag > but only if it contains a /
the result should look like this </a> __<h1>h1<script><script><script><script></script> __</script> __
I made this code but the while statement never becomes true
Pattern pattern = Pattern.compile("</*>");
Matcher matcher = pattern.matcher(+Test string+);
StringBuffer correctedStr = new StringBuffer(+Test string+);
while(matcher.find()){
correctedStr.insert(matcher.end(), " ");
}Edited by: Farmor on Jul 1, 2008 1:09 PM

Pattern pattern = Pattern.compile("(</[^>]*>)");and use Matcher.replaceAll("$1 ");instead of the loop.
Edited by: sabre150 on Jul 1, 2008 1:31 PM

Java.util.regex vs jarkata-oro on regular expression

hi, all
Both java utility (java.util.regex) and jarkata-oro (org.apache.oro.text.perl) provide supports of Perl5 compatible regular expressions. What are your opinions of which one do you choose?
I've searched in this forum and others online. I don't see this topic. Maybe I miss something...
Anyway, your opinions/experences are more than welcome.
thx
Tim

One big difference:
java.util.regex is JAVA 1.4+ only.
jarkata-oro is JAVA 1.2+

Regular expressions with java.util.regex

Hello Guys,
I wrote last time this
* Uses split to break up a string of input separated by
* commas and/or whitespace.
* See: http://developer.java.sun.com/developer/technicalArticles/releases/1.4regex/
* Change: I have slightly modified the source
import java.util.regex.*;
public class Splitter {
public static void main(String[] args) throws Exception {
// Create a pattern to match breaks
Pattern p = Pattern.compile("[<>\\s]+");
// Split input with the pattern
String[] result =
p.split("<element attributname1 = \"attributwert1\" attributname2 = \"attributwert2\">");
for (int i=0; i<result.length; i++)
if (result.equals(""))
System.out.println("EMPTY");
else
System.out.println(result[i]);
int res = result.length - 1;
System.out.println("\nStringlaenge: " + res);
I wonder, why I got an empty element in reult[0]. Have anyone an idea?
We'll come together next time
... �nhan Inay ([email protected])

What is wrong with this Pattern?
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
This time i used following Split:
p.split("<element attributname1=\"attributwert1\" attributname2=\"attributwert2\">");
I've got a compilation error:
U:\qms_neu\htdocs\inay\Source\myWork\Regex-Samples>javac Splitter.java
Splitter.java:14: illegal start of expression
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:14: illegal character: \92
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:14: illegal character: \92
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:14: unclosed string literal
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:17: ')' expected
p.split("<element attributname1=\"attributwert1\" attributname2
=\"attributwert2\">");
^
Splitter.java:14: unexpected type
required: variable
found : value
Pattern p = Pattern.compile("^<[a-zA-Z0-9_\\"=]+[\\s]*$>");
^
Splitter.java:18: cannot resolve symbol
symbol : variable result
location: class Splitter
for (int i=0; i<result.length; i++)
^
Splitter.java:19: cannot resolve symbol
symbol : variable result
location: class Splitter
if (result.equals("")){
^
Splitter.java:21: cannot resolve symbol
symbol : variable result
location: class Splitter
System.out.println(result[0]);
^
Splitter.java:24: cannot resolve symbol
symbol : variable result
location: class Splitter
System.out.println(result[i]);
^
Splitter.java:25: cannot resolve symbol
symbol : variable result
location: class Splitter
int res = result.length - 1;
^
11 errors

Java.util.regex error

Hello,
I checked JavaDoc multiple times but do not see what is wrong with
myString.replaceAll("D:\\web\\mars","")which results in
java.util.regex.PatternSyntaxException: Illegal/unsupported escape squence near index 7
D:\web\mars
       ^
     at java.util.regex.Pattern.error(Unknown Source)
     at java.util.regex.Pattern.escape(Unknown Source)
     at java.util.regex.Pattern.atom(Unknown Source)
     at java.util.regex.Pattern.sequence(Unknown Source)
     at java.util.regex.Pattern.expr(Unknown Source)
     at java.util.regex.Pattern.compile(Unknown Source)
     at java.util.regex.Pattern.<init>(Unknown Source)
     at java.util.regex.Pattern.compile(Unknown Source)
     at java.lang.String.replaceAll(Unknown Source)
     at ArticleImageImportProcessor.main(ArticleImageImportProcessor.java:40)
Exception in thread "main" please, every suggestion/hint is most appeciated

You have to "encode" backslash twice, first for String purpose and second time because of special meaning of '\' in regular expressions.
It should looks like
myString.replaceAll("D:\\\\web\\\\mars","")

RFC used for java.util.regex

Hi,
Does anyone know the RFC used for java.util.regex ??
Thanks & Regards,
Gurushant Hanchinal

Can you please give me the link to view to specifications for java.util.regex.. I have tried the link which is available in :
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html page with name " Java Language Specification"
on click of this link, i am getting page not found error..
Please give me any other alternate links to view the regular expression specifications..
Thanks,
Gurushant Hanchinal

Ignore word (Java.util.regex )

Hello All,
Can anyone help me to solve this probelm:
Probelm: I have a text file and i want to search a word or combination of words in that using java.util.regex
Example : in the sentence "things like the Forestry in the Commission (FC)." i want to search "Forestry Commission" while ignoring the word "in the". This ignoring criteria is specific i.e. search return true only if it ignore "in the" word not any other word.
Also how i ignore multiple words in ignore condition.
Thanks in advance.

Try out this line of code:
System.out.println("Forestry in the Commission".replaceAll("Forestry\\s(.*?\\s)?Commission", "Hello"));In EBNF, it looks like this:
match ::= "Forestry" <whitespace> [<character> <whitespace>] "Commission"
whitespace ::= <space> | \t | \n | \x0B | \f | \r
character ::= (any one character)
This, of course, is an ambiguous EBNF definition. The breakdown of the expression, however, reveals why this works. In the string, "\\s" refers to a character of whitespace. "(.*?\\s)?" is where the magic happens: it causes ".*?\\s" to happen either not at all or once. ".*?" will consume as few "." (any character) as possible to make the match, and the following "\\s" is to make sure that strings like "Forestry deCommission" don't match. The EBNF's ambiguity comes from EBNF's lack of ability to describe "reluctant qualifiers": qualifiers that indicate that as few of the given expression should be matched as possible.
Cheers!

Who use sql-mapping with java.util.regex?

Hi everyone:
I use the IBatis SQL-Mapping and I think it is very good.Now I want to add the search function to my BBS forum.I also want to display the content high light like jive.I mean that if I want to find the string "ibatis",then the search result "ibatis" will be high light displayed.
So I must use the java.util.regex in jsdk1.4.But the problem is that what I get is a List if I use sql-mapping.For example:
          String resource="conf/XML/sql/lyo-sql-map.xml";
          Reader reader=Resources.getResourceAsReader(resource);
          sqlmap=XmlSqlMapBuilder.buildSqlMap(reader);
          List articlelist=sqlmap.executeQueryForList("selectSiteArticle","%"+icontent+"%");
The result I get is a List and I have no time to use regex.
I don't know whether I could do this:
Iterate the List,use the regex and later place all the object back to the List.
It's right?
How to use regex with sql-mapping?Thks

Any idea? :(

Parsing xhtml using java.util.regex

I am parsing an XHTML file using the java.util.regex package and I am perplexed at why the following doesn�t work.
The lines I wish to match are either like this:
<span class="someclass"><b>Some String.</b></span></td>
or
Some String.</td>
The code I use to try to achieve this is:
Pattern somePattern = Pattern.compile(".*(<span class=\"someclass\"><b>)?(.*)[.](</b></span>)?</td>.*");
String s = null;
while((s = br.readLine()) != null) {
if(somePattern.matcher(s).matches()) {
System.out.println("0:" + eventMatcher.group(0));
System.out.println("1:" + eventMatcher.group(1));
System.out.println("2:" + eventMatcher.group(2));
System.out.println("3:" + eventMatcher.group(3));
I expect to get as output
0:<span class="someclass"><b>Some String.</b></span></td> 1:<span class="someclass"><b>
2:Some String
3:</b></span>
or
0:Some String.</td>
1:null
2:Some String
3:null
depending on which lines provide the match as mentioned above. Instead I get:
0:<span class="someclass"><b>Some String.</b></span></td>
1:null
2:(empty string)
3:</b></span>
or
0:Some String.</td>
1:null
2:(empty string)
3:null
Any ideas? Thanks in advance.

Consider the terms of ".*(<span class=\"someclass\"><b>)?(.*)[.](</b></span>)?</td>.*"
.* - greedily collect characters
(<span class=\"someclass\"><b>)? - optionallly collect information taht will always be matched by the previous .* pattern so will be empty.
(.*) - greedily collect characters that will also have been swallowed by the first .* so will be empty
[.] - a single .
(</b></span>)? - optionally collection
</td> - must be there
.* - collect the rest of the charcters in the line.
Therefore in general groups 1 and 2 will be empty because the first .* will have collected the information you wanted to capture!
You could just make the first .* non-greedy by using .*? but this may fail for other reasons.
So, in general terms, what are you trying to extract?

WHERE to find [b]java.util.regex.*[\b] package?

Does anyone know where to obtain a copy of the java.util.regex.* package (separate package)? This is a new package included in version 1.4.0.

Does anyone know where to obtain a copy of the
java.util.regex.* package (separate package)?
This is a new package included in version 1.4.0.Simple:
Go to your java sdk directory
$ jar xvf src.jar
$ cd java/util/regex
$ javac ASCII.java
$ javac Matcher.java
$ javac Pattern.java
$ javac PatternSyntaxException.java
$ cd ../../..
$ jar cvf regex.jar java/util/regex/*.class
et voila; how difficult can that be ? There is no native, JVM depending stuff in there, although I did not check for dependencies on other new stuff inside the jdk.
I'm also unaware if this isn't illegal under the agreement with Sun.

[bug]Jdev 11g:NullPointerException at java.util.regex.Matcher.getTextLength

Hi,
Jdev 11.1.1.0.31.51.56
If somebody of you get the following trace stack when running a jspx using ViewCriteriaRow.setOperator :
There is bug 7534359 and metalink note 747353.1 available.
java.lang.NullPointerException
at java.util.regex.Matcher.getTextLength(Matcher.java:1140)
at java.util.regex.Matcher.reset(Matcher.java:291)
at java.util.regex.Matcher.<init>(Matcher.java:211)
at java.util.regex.Pattern.matcher(Pattern.java:888)
at oracle.adfinternal.view.faces.model.binding.FacesCtrlSearchBinding._loadFilter
CriteriaValues(FacesCtrlSearchBinding.java:3695)
Truncated. see log file for complete stacktrace
Workaround:
If you use
        vcr.setAttribute("Job",job);
or
        vcr.setAttribute("Job","="+job);
than add following line of code:
        vcr.setOperator("Job","=");   regards
Peter

Hi,
useful to mention that this happens when setting the equal operator or LIKE operator
vcr.setAttribute("Job","= '"+job+"'");
or
vcr.setOperator("Job","=");
Frank

Patters for avoiding the '/' (in java.util.regex)

Hi all ,
i wanted to knw the pattern format (in java.util.regex) for avoiding the '/' at the begenning of a line ....... hope to get the best answers ....
thnx 'n cheers
max

first of thnx for the quick responses .... !
what i am really trying to do here is to avoid all lines which are starting with a comment ( '//' or '/*' ) .
-> I am checking for all lines and inserting a line of code just before a particular statement , the only thing is that statement which i am looking for should not be inside a comment ( '//' or '/*' ) .... hope u got the thing
thnx
max

About the error of java.util.regex in jdk1.4's docs

In java.util.regex,the class Pattern's document says:
Greedy quantifiers
X? X, once or not at all
X* X, zero or more times
X X, one or more times
X{n} X, exactly n times
X(n,} X, at least n times
X{n,m} X, at least n but not more than m times
Why don't metion �X+�?
I think that should be "X+ X, one or more times",right?

Agreed. I use Regex in many places (and used
Oromatcher before 1.4), and I've verified that I
use the + operator in several places-- it works.

Please help on java.util.regex.*

Hi all,
My RTF file looks like this:
Project Num\tab N/A
\par Project Name\tab Hook-up Installation and Service
\par
My intension is to read the file until the \tab and store Project Num as a string into a
variable. Similarly read until \par and store the value of Project Num into another variable.
So that i can use those variables further in my program.
I used java.util.regex.* package for this purpose. I could successfully split the sentence whenever it sees \tab and \par but don't know how to get the text before and after the delimeters and store them into variables.
The code which i wrote is:
import java.util.regex.*;
import java.io.*;
import java.nio.*;
import java.nio.charset.*;
import java.nio.channels.*;
public class RegexDemo{
public static void main(String[] args){
// Create a pattern to match breaks
Pattern p = Pattern.compile("\\\\.[a-z][a-z]",Pattern.DOTALL);
try{
File file = new File("sample.rtf");
FileInputStream fis = new FileInputStream(file);
FileChannel fc = fis.getChannel();
// Get a CharBuffer from the source file
ByteBuffer bb = fc.map(FileChannel.MapMode.READ_ONLY, 0, (int)fc.size());
Charset cs = Charset.forName("8859_1");
CharsetDecoder cd = cs.newDecoder();
CharBuffer cb = cd.decode(bb);
// Run some matches
Matcher m = p.matcher(cb);
while (m.find())
System.out.println("Found comment: "+m.group());
}catch(Exception e){
e.printStackTrace();
Please somebody help me in this regard. I have spent lot of time searching the forums but couldn't find any solution.
Thanks in advance
rnallu

Just put target inside parenthesis with delimiters at boundaries.
Example: "(\\w+)\\t(\\d)\\s" will match occurrences of a word followed with a tab char then a digit followed with a whitespace. If target string matches pattern then m.group(1) contains the word and m.group(2) contains the digit.

Regular Expressions (java.util.regex)

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