Removing File Name from Slideshow

Using CS4 I create a slideshow to embed in a webpage as a photo gallery. How do i Disable the display of a file name under each picture? I have tried to insert captions and everything I can see to try but the file name still appears and no captions show up??

Which Slideshow preset are you using?
h

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Can't remove file name from portfolio-9 Pro

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Try this...
In terminal type
defaults write com.apple.finder _FXShowPosixPathInTitle -bool NO
charlie

How do I remove files names from my contact sheets in bridge?

I'm creating a contact sheet in Bridge and I only want the pictures not the text file names on the final contact sheet. How do I do this?

I only want the pictures not the text file names on the final contact sheet.
In the output panel are several options to select or deselect. In your case go the 'Overlays' and inhere deselect 'filename' and ' extensions' for not showing this info on your final contact sheet. You can also create a template when your final lay out is ready so you can easily return to this lay out when needed.

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How can I stop the file path appearing as a title on my video?

Click on the Wrench symbol and from the drop down menu choose Overlays to toggle it off.
MtD

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Thanks for the answer, I will try this & post my results with this method. I have set the amount to zero, & it seems if I want to put back valid files into my list I first need to find them in another file in my pc, such as documents, open them in Adobe Reader, & then then they will reappear in the Adobe Reader list. Is this correct? Thank you!
This seems to be the case, you need to restore each file you want in your list one by one by accessing them elsewhere on your pc, & then you must open them with Adobe Reader to have files reappear in your Adobe Reader list. However, this seems to be a tedious process if you only want to delete one obsolete file from your list by first emptying the list & rebuilding it file by file. It works, but I'm wondering if there is a more sensible & efficient way to do this?

How can I assign image file name from Main() class

I am trying to create library class which will be accessed and used by different applications (with different image files to be assigned). So, what image file to call should be determined by and in the Main class.
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import org.me.lib.MyJNIWindowClass;
public class Main {
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mw.s = "clock.gif";
And here is the library class
package org.me.lib;
public class MyJNIWindowClass {
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ImageIcon image = new ImageIcon("C:/Documents and Settings/Administrator/Desktop/" + s);
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Your problem is one of timing. Consider this simple example.
public class Example {
    public String s;
    private String message = "Hello, " + s;
    public String toString() {
        return message;
    public static void main(String[] args) {
        Example ex = new Example();
        ex.s = "world";
        System.out.println(ex.toString());
}When this code is executed, the following happens in order:
1. new Example() is executed, causing an object to constructed. In particular:
2. field s is given value null (since no value is explicitly assigned.
3. field message is given value "Hello, null"
4. Back in method main, field s is now given value "world", but that
doesn't change message.
5. Finally, "Hello, null" is output.
The following fixes the above example:
public class Example {
    private String message;
    public Example(String name) {
        message = "Hello, " + name;
    public String toString() {
        return message;
    public static void main(String[] args) {
        Example ex = new Example("world");
        System.out.println(ex.toString());
}

How do I remove my name from an ipod prior to donating it to someone?

I would like to donate my ipod touch to someone as I just bought another one. How do I remove my name from the device prior to donating it? I was able to remove all of my apps, music and videos but not the name.

Go into your settings>general>reset, then select Erase All Content and Settings.

File name from a path

hi ,
there is a path "c:\abc\abc\abc\abc\abc.doc", i have to get file name from it.
but i had to write a dynamic code which can get the file name from any given path.

Smoke me a kipper, I'll be back before breakfast.
SQL> var extended_filepath varchar2(128)
SQL> exec :extended_filepath := '/this/is/a/path/to/a/file.txt'
PL/SQL procedure successfully completed.
SQL> select instr(:extended_filepath, '/', -1)
2 from dual
3 /
INSTR(:EXTENDED_FILEPATH,'/',-1)
21
SQL> select substr(:extended_filepath, instr(:extended_filepath, '/', -1) +1)
2 from dual
3 /
SUBSTR(:EXTENDED_FILEPATH,INSTR(:EXTENDED_FILEPATH,'/',-1)+1)
file.txt
SQL> Cheers, APC

Retreiving the file names from directory inside another directory from application server

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I had a problem in retreiving the file names from a directory inside another directory.
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But here I am getting only one directory details.
Actually my file is located a directory inside one more directory and one more directory and inside the files are located.
i.e total 3 directories inside the 3rd one my files are there.
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Hi Ram,
Following thread can be helpful for you, were it shows in the tables structure rsfillst a field RSFILLST-TYPE whether its a directory or file..........
http://scn.sap.com/thread/865272
thanks and regards,
narayan

How to get the target file name from an URL?

Hi there,
I am trying to download data from an URL and save the content in a file that have the same name as the file on the server. In some way, what I want to do is pretty similar to what you can do when you do a right click on a link in Internet Explorer (or any other web browser) and choose "save target as".
If the URL is a direct link to the file (for example: http://java.sun.com/images/e8_java_logo_red.jpg ), I do not have any problem:
URL url = new URL("http://java.sun.com/images/e8_java_logo_red.jpg");
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FileOutputStream fos=null;
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StringTokenizer st=new StringTokenizer(url.getFile(), "/");
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File localFile= new File(System.getProperty("user.dir"), fileName);
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try {
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However, if the URL is an indirect link to the file (for example: http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719 , which link to a file named JavaSetup6u18-rv.exe ), the similar code return AutoDL?BundleId=37719 as file name, when I would like to have JavaSetup6u18-rv.exe .
URL url = new URL("http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
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System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
    byte[] buf = new byte[1024];
    int i = 0;
    while ((i = is.read(buf)) != -1) {
        fos.write(buf, 0, i);
} catch (Throwable e) {
    e.printStackTrace();
} finally {
    if (is != null)
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    if (fos != null)
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Thanks for your help
// JB
Edited by: jb-from-sydney on Feb 9, 2010 10:37 PM

Thanks for your answer.
By following your idea, I found out that one of the header ( content-disposition ) can contain the name to be used if the file is downloaded. Here is the full code that allow you to download locally a file on the Internet:
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      * @param url - the url.
      * @param destinationFolder - The destination folder.
      * @return the file
      * @throws IOException Signals that an I/O exception has occurred.
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          URLConnection urlC = url.openConnection();
          InputStream is = urlC.getInputStream();
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          destinationFolder.mkdirs();
          File localFile = new File(destinationFolder, fileName);
          fos = new FileOutputStream(localFile);
          try {
               byte[] buf = new byte[1024];
               int i = 0;
               while ((i = is.read(buf)) != -1) {
                    fos.write(buf, 0, i);
          } finally {
               if (is != null)
                    is.close();
               if (fos != null)
                    fos.close();
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      * @param urlC - the url connection
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      * @throws IOException Signals that an I/O exception has occurred.
     private static final String getFileName(URLConnection urlC) throws IOException {
          String fileName = null;
          String contentDisposition = urlC.getHeaderField("content-disposition");
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          // if the file name cannot be extracted from the content-disposition
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          if (fileName == null) {
               StringTokenizer st = new StringTokenizer(urlC.getURL().getFile(), "/");
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                    fileName = st.nextToken();
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      * Extract the file name from the content disposition header.
      * <p>
      * See <a
      * href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec19.html">http:
      * //www.w3.org/Protocols/rfc2616/rfc2616-sec19.html</a> for detailled
      * information regarding the headers in HTML.
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               String contentDisposition) {
          String[] attributes = contentDisposition.split(";");
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                    // quotes.
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          // not found
          return null;
     }

Flat file name from Sender Side Dynamically into subject of Receiver Mail

Hi All,
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Thanks in Advance

Hi....
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DynamicConfiguration conf = (DynamicConfiguration) param.get(
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Hi My requirement is I am getting a CSV file from Trading partner, I am using oracle 10g b2b to translate the data.
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</sequence>
Can you help me to get the file name from Oracle b2b 10g ?
Thanks,
b2b user

Retrieve file name from full file path

I am trying to retrieve a file name from a path (ex. c:\temp\tes.txt) using the following code, but it is given me an error of "The method split(String) in the type String is not applicable for the arguments (char).
{code}
String filepath = item.getName();
String[] buf = filepath.split('/');
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{code}
I tried to use double quote instead of single quote, but it is not returning anything.
{code}
String[] buf = filepath.split("/");
{code}
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How is this related to JDBC?
Anyway, is the path separator actually a forward slash? Isn't it a backward slash?
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Thanks
Karthik

Hi,
>>>Is it possible to do using only Adapter Specific message properties?
yes
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Dear Experts,
Could you suggest the syntax for specifying the file name from a variable in the file receiver communication channel? I need to grab the file name from an ATTRIBUTE of an element of the payload.
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Example: Need to pass the attribute "descReceipt" of the element "promotionEvent" to the variable in the following payload:
<?xml version="1.0" encoding="UTF-8"?>
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The scenario is IDOC to FILE. I need to get the value of the receiving partner.
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<SAP:Record namespace="http://sap.com/xi/XI/System/IDoc" name="SNDPRT">LS</SAP:Record>
<SAP:Record namespace="http://sap.com/xi/XI/System/IDoc" name="RCVPRN">0000002104</SAP:Record>
<SAP:Record namespace="http://sap.com/xi/XI/System/IDoc" name="SNDPOR">SAPLCD</SAP:Record>
<SAP:Record namespace="http://sap.com/xi/XI/System/IDoc" name="SNDPRN">LCDCLNT220</SAP:Record>
<SAP:Record namespace="http://sap.com/xi/XI/System/IDoc" name="CIMTYP" />
<SAP:Record namespace="http://sap.com/xi/XI/System/IDoc" name="IDOCTYP">WPDBBY01</SAP:Record>
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<SAP:Record namespace="http://sap.com/xi/XI/System/IDoc" name="RCVPRT">KU</SAP:Record>
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Removing File Name from Slideshow

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