Replace charcter from string in 46c

Question

Hi,
If you could send me code for below scanerio that will be great.
in 46c i have string '/ABCD/te_12' now i want to replace the '/' with '+'  and '_' with '|', can you tell me how to do this.
thanks,
john

Answer 1

hi check the replace statement... hit F1 on replace and make ur code..
Basic form
REPLACE f WITH g INTO h.
Addition
... LENGTH len (length specification for field f )
Effect
Replaces the first occurrence of the contents of field f in field h with the contents of field g . All fields are handled in their defined length; this means that closing blanks are not ignored.
The return code value indicates whether the string f was found in h and replaced by g :
SY-SUBRC = 0 String replaced.
SY_SUBRC = 4 String not replaced.
Example
    DATA FIELD(10).
    MOVE 'ABCB' TO FIELD.
    REPLACE 'B' WITH 'string' INTO FIELD.
returns:
FIELD = 'AstringCB', SY-SUBRC = 0
Note
The fields f and g in the REPLACE statement should not overlap. Otherwise, the result is undefined.
Addition
... LENGTH len ... (length specification for field f )
Effect
Searches for the string f in the field h not in its (full) field length, but in the length len .
Example
    DATA: PATTERN(5) VALUE 'ABC',
          LEN TYPE I,
          REPL_STRING(5) VALUE '12345',
          FIELD(12) VALUE 'abcdeABCDE'.
    REPLACE PATTERN WITH REPL_STRING
                    INTO FIELD.
does not change FIELD , since 'ABC ' does not occur in abcdeABCDE ' .
    LEN = STRLEN( PATTERN ).
    REPLACE PATTERN LENGTH LEN
                    WITH REPL_STRING
                    INTO FIELD.