Restriction on length of the name given to a radio button in selection scr

Hi,
Is there any length restriction for the name given to a radio button in SELECTION SCREEN?
I need to display a 35 char name for a radio button.

It can be upto 8 characters long. But here is a solution to your problem:
selection-screen begin of line.
parameters: rb_opt1 radiobutton group mygrp.
selection-screen comment 5(35) text-s01 for field rb_opt1.
selection-screen end of line.
selection-screen begin of line.
parameters: rb_opt2 radiobutton group mygrp.
selection-screen comment 5(35) text-s02 for field rb_opt2.
selection-screen end of line.
and then just double click on the text objects to write your own texts.
Hope it helps.

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Hi Shikha,
Regarding your query, when you select a particular radio-button then the fields pertaining to that radio-button should get activated or get displayed, otherwise it should be hidden.
This can be done adding the addition to the Radiobutton 'USER-COMMAND' this will automatically enable-up
the functionality of the fields related to that radiobutton, while disabling the others.
If USER-COMMAND isn't given, then ENTER key serves the purpose.
DATA:
w_carrid LIKE sflight-carrid,
w_connid LIKE sflight-connid.
PARAMETERS:
p_carrid RADIOBUTTON GROUP airl USER-COMMAND airline,
p_connid RADIOBUTTON GROUP airl.
SELECT-OPTIONS:
s_carrid FOR w_carrid,
s_connid FOR w_connid.
INITIALIZATION.
p_carrid = 'X'.
Now enabling desired fields and disabling the others, can be done by the following snippet.
AT SELECTION-SCREEN OUTPUT.
LOOP AT SCREEN.
IF p_carrid EQ 'X'.
IF screen-name CS 'S_CONNID'.
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ELSEIF screen-name CS 'S_CARRID'.
screen-active = 1. " Enable the field S_CARRID
MODIFY SCREEN.
ENDIF.
ELSEIF p_connid EQ 'X'.
IF screen-name CS 'S_CARRID'.
screen-active = 0.
MODIFY SCREEN.
ELSEIF screen-name CS 'S_CONNID'.
screen-active = 1.
MODIFY SCREEN.
ENDIF.
ENDIF.
ENDLOOP.
Hope, this would help you solve your problem.
Thankyou,
Zahack.

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Restriction on length of the name given to a radio button in selection scr

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