Retrieve values where multiple types exist.

Question

I have an Order Table and an order distribution
I will have one order yet could have could have multiple distributions against an order.
I am want to be able to select only Orders  have only the one Distribution Type .
 Example - I could have an X distribution  or S distribution or both
If I have and S and an X I do not want to include the order
If I have an S only I do want to include the order.

Answer 1

Are you looking for something like below:
DECLARE @Orders TABLE (OrderID INT, OrderDate DATE)
INSERT INTO @Orders
SELECT 1, '01/01/2014' UNION ALL
SELECT 2, '01/01/2015'
DECLARE @OrderDistribution TABLE(OrderID INT, DistributionType CHAR(1))
INSERT INTO @OrderDistribution
SELECT 1, 'S' UNION ALL
SELECT 2, 'S' UNION ALL
SELECT 2, 'X'
SELECT *
FROM
@OrderDistribution As MainQry
INNER Join @Orders O On MainQry.OrderID = O.OrderID
WHERE
EXISTS (SELECT 1 FROM @OrderDistribution AS SubQry Where SubQry.OrderID = MainQry.OrderID Group By SubQry.OrderID Having Count(*) = 1)
Output
OrderID | DistributionType | OrderID | OrderDate
1 | S | 1 | 2014-01-01
Best Wishes, Arbi; Please vote if you find this posting was helpful or Mark it as answered.