RMI IO Exception

Question

hi,
i am getting this error with my simple hello world program on the RMI tutorial:
java.io.IOException: Test IO Exception
at sun.rmi.transport.StreamRemoteCall.exceptionReceivedFromServer(Unknown Source)
at sun.rmi.transport.StreamRemoteCall.executeCall(Unknown Source)
at sun.rmi.server.UnicastRef.invoke(Unknown Source)
at HelloImp_Stub.sayHello(Unknown Source)
at HelloClient.main(HelloClient.java:20)
Any thoughts what this error points to. Its not a security problem since I have the policy file granting all permissions.
All feedback appreciated.
My hello world imp:
public class HelloImp extends UnicastRemoteObject implements Hello {
     public HelloImp() throws RemoteException {
          super();
     public String sayHello() throws IOException, RemoteException {
          if (true) {
               throw new IOException("Test IO Exception");
          return "Hello";
     public static void main(String[] args) {
          // Create and install a security manager
          if (System.getSecurityManager() == null) {
               System.setSecurityManager(new RMISecurityManager());
          try {
               HelloImp obj = new HelloImp();
               // Bind this object instance to the name "HelloServer"
               Naming.rebind("//localhost/HelloServer", obj);
               System.out.println("HelloServer bound in registry");
          } catch (Exception e) {
               System.out.println("HelloImpl err: " + e.getMessage());
               e.printStackTrace();
My client:
public class HelloClient {
     public static void main(String[] args) {
          String message = "blank";
          Hello obj = null;
          try {
               obj = (Hello)Naming.lookup("//localhost/HelloServer");
               message = obj.sayHello();
               System.out.println(message);
          } catch (IOException e) {
               e.printStackTrace();
          } catch (Exception e) {
               System.out.println("HelloApplet exception: " + e.getMessage());
               e.printStackTrace();

Answer 1

Your simple hello world program is throwing the exception, just the way you coded it.