SAX: How to create new XML file using SAX parser

Hi,
Please anybody help me to create a XML file using the Packages in the 5.0 pack of java. I have successfully created it reading the tag names and values from database using DOM but can i do this using SAX.
I am successful to read XML using SAX, now i want to create new XML file for some tags and its values using SAX.
How can i do this ?
Sachin Kulkarni

SAX is a parser, not a generator.Well,
you can use it to create an XML file too. And it will take care of proper encoding, thus being much superior to a normal textwriter:
See the following code snippet (out is a OutputStream):
PrintWriter pw = new PrintWriter(out);
      StreamResult streamResult = new StreamResult(pw);
      SAXTransformerFactory tf = (SAXTransformerFactory) TransformerFactory.newInstance();
      //      SAX2.0 ContentHandler.
      TransformerHandler hd = tf.newTransformerHandler();
      Transformer serializer = hd.getTransformer();
      serializer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");//
      serializer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"pdfBookmarks.xsd");
      serializer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"http://schema.inplus.de/pdf/1.0");
      serializer.setOutputProperty(OutputKeys.METHOD,"xml");
      serializer.setOutputProperty(OutputKeys.INDENT, "yes");
      hd.setResult(streamResult);
      hd.startDocument();
      //Get a processing instruction
      hd.processingInstruction("xml-stylesheet","type=\"text/xsl\" href=\"mystyle.xsl\"");
      AttributesImpl atts = new AttributesImpl();
      atts.addAttribute("", "", "someattribute", "CDATA", "test");
      atts.addAttribute("", "", "moreattributes", "CDATA", "test2");
       hd.startElement("", "", "MyTag", atts);
String curTitle = "Something inside a tag";
          hd.characters(curTitle.toCharArray(), 0, curTitle.length());
    hd.endElement("", "", "MyTag");
      hd.endDocument();
You are responsible for proper nesting. SAX takes care of encoding.
Hth
;-) stw

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import javax.xml.transform.TransformerConfigurationException;
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Cheers,
JavaImran

Sax.startDocument();
Sax.startValidation();
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Sax.startElement("", "basic-metadata", "basic-metadata", new AttributesImpl());
String xmp_str = new String(meta_data.getByteArray(),"UTF8");
char[] xmp_arr = xmp_str.toCharArray();
Sax.characters(xmp_arr, 0, xmp_arr.length);
</code><code>Sax.endElement("", "basic-metadata", "basic-metadata");</code>
<code class="jive-code jive-java">Sax.endElement("", "pdf", "pdf");
Sax.endValidation();
Sax.endDocument();
* I HAVE CHANGED MY AS PER YOUR SUGGESTION, NOW SAME RESULT HAS COMING.
* I AM NOT ABLE TO GET THE EXACT OUTPUT.,WHY THAT ?
Thanks,
JavaImran{code}

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Hi,
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</A>
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If possible, please post a code snippet for the same.
Thanks in advance..

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Hi,
when I look in the JDK1.4.2 specification I don't see any write method in the Document interface.
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Nitin

You should update your DOM document to represent the changes that you want made.
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Source source = new DOMSource(dom);
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How do I generate XML File Using JDeveloper 9.0.3

Hi All
I want to generate a XML file against the data in one of my Oracle table,,,, This is the first time I am doing this Task, so please let me know whether I am going through the correct path, or if not appreciate if you could put me to the correct system of doing this please��..
OK , Well I am working to a publishing company in Australia and we have Oracle 8i (Release 3 ) database and I have Oracle JDeveloper (9.0.3 -Preview ) version in my personal computer.
I have a Table(ONIXT4) with three Columns( ISBN,Author,Price) in Oracle as follows:
ISBN     Author     Price
2512456321     Peter     14.50
7445854127     Ray      21.75
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<ISBN>2512456321</ISBN>
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<Author>Peter</Author>
<Price>14.50</Price>
</ProductInfor>
<ISBN>7445854127</ISBN>
<ProductInfor>
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<?xml version = '1.0' encoding = 'windows-1252'?>

<page xmlns:xsql="urn:oracle-xsql" connection="Connection1">
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<?xml version="1.0" encoding="windows-1252" ?>
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<author>Peter</author>
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<author>Ray</author>
<price>21.75</price>
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How do I format the outcome to obtain the my requirement??
Welcome all comments of donig this ....

To format your XML to the requiered output you'll use a stylesheet and XSLT
As it says in your output:
- 
A nice tutorial on XSLT is available on the XML technology center in OTN:
See Transforming XML with XSLT
http://otn.oracle.com/tech/xml/learner.html

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import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
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DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("ENtemplate.xml");
doc.normalize();
NodeList rootNodes = doc.getElementsByTagName("templates");
Node rootNode = rootNodes.item(0);
Element rootElement = (Element) rootNode;
NodeList templateList = rootElement.getElementsByTagName("template");
for(int i=0; i < templateList.getLength(); i++) {
Node theTemplate = templateList.item(i);
Element templateElement = (Element) theTemplate;
System.out.println("Template" + ": " +templateElement.getAttribute("name")+ ".xml");
} catch (ParserConfigurationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
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Ive posted the new code but now I'm getting a FileAlreadyExistException error. How do I handle this exception error correctly in my code?
import java.io.IOException;
import java.nio.file.FileAlreadyExistsException;
import java.nio.file.Files;
import java.nio.file.Paths;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
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public static void main(String[] args) {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("ENtemplate.xml");
doc.normalize();
NodeList rootNodes = doc.getElementsByTagName("templates");
Node rootNode = rootNodes.item(0);
Element rootElement = (Element) rootNode;
NodeList templateList = rootElement.getElementsByTagName("template");
for(int i=0; i < templateList.getLength(); i++) {
Node theTemplate = templateList.item(i);
Element templateElement = (Element) theTemplate;
System.out.println(templateElement.getAttribute("name")+ ".xml");
for(int i=0; i < templateList.getLength(); i++) {
Node theTemplate = templateList.item(i);
Element templateElement = (Element) theTemplate;
String fileName = templateElement.getAttribute("name") + ".xml";
Files.createFile(Paths.get(fileName));
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} catch (ParserConfigurationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();

How to create an XML file from scratch ?

Hi all,
I'm afraid that I will seem dummy, but I think I really misunderstand something or I'm trying to do something that is not possible...
I would like to create a XML file containing the following:<?xml version="1.0" encoding="UTF-8"?>
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<!DOCTYPE playlist SYSTEM "pl.dtd">
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Thanks,
Karau

Could send me an example ?
For the moment I am using Transformer in that way:
     TransformerFactory tfactory = TransformerFactory.newInstance();
     try {
         Transformer transformer = tfactory.newTransformer();
         DOMSource source = new DOMSource(playlistDoc.getDocumentElement());
         StreamResult res = new StreamResult(new File(path));
         transformer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM, PL_DTD);
         transformer.setOutputProperty(OutputKeys.INDENT, "yes");
         transformer.transform(source, res);
     catch (TransformerConfigurationException tce) {
         throw tce;
     catch (TransformerException te) {
         throw te;
     }

How to create an XML File for Gantt?

Hi Everybody.
I need a Gantt in Web Dynpro ABAP. I need it for the boss to do a Forecast for Vacation. I Hope this is understanding.
Did Anyone know how can i create a XML File for the Gantt at runtime?
Thanks
MSi

Hi Marcus,
the following link is to the JNet/JGantt developer doco
[JNet/JGantt Developer Documentation|http://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/lw/uuid/f010ec31-9658-2910-3c83-c6e62904eceb]
included in this is the:
[Schema for XML|http://www.sdn.sap.com/irj/sdn/go/portal/prtroot/com.sap.km.cm.docs/lw/webdynpro/jnet_jgantt%20developer%20documentation/schema/xml-spy/jnet-schema.html]
You can use this to build XML to represent a gantt like chart.
I did this to build XML to represent employee avaliablity - although we fronted the gantt through WD Java not ABAP - the java applet called is the same (I believe).
Don't underestimate the work required to tweek your data into a decent layout. It took me days.
There may be tools/api to help generate the XML - I don't know of them - I'd look forward to seeing any other replies to this thread from people who have used/built any. An example of a class that generates JNet XML - CL_SPI_UI_JNET - but this does not seem to be a Gantt display.
Cheers,
Chris

How to create new .dat file and its contents?

Hi There
Can anybody let me know the procedure of how to create new .ctl or .dat file to load data to tables.
i working on 2day dba chapter 8. it shows me how to creat table and use .dat file to load data. but doesnot giv any clue how new .dat file and its contents can be created. please help.
thanks in advance.

Thanks for ur help
I ve created txt file in notepad and saved it as dat file. tried to load that data thru Enterprise manager. used load data from User files everything went well and job was showing suceeded but dont know why that data is not showing in the table. i ve tried it now for three four times. used right table and pathe but dont know. has anybody got idea why that ll be?
Thanks

How to Save a XML file using Document Object

Hai all,
I am new to XML and i created a application to insert a node in the XML file using org.w3c.dom.Document object. And want to know which method has to be used to store the Document object into a XML fille.

The standard way would be to use a transformer with no transformation where the destination is a StreamResult.
something like:
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer();
transformer.transform(new DOMSource(doc), new StreamResult("output.xml"));

SAX: How to create new XML file using SAX parser

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