Sharepoint Workflow : how to get document full path + file name into variable?

Hi,
Anybody knows how to get document full path + file name into a variable in Sharepoint 2010 workflow?
Example http://sp1:80/InvoiceQueue/Shared Documents/123.pdf
I am using List Workflow which links to a document library.

Hi SAMSUNG,
According to your description, my understanding is that you want to get the full path of a document in a list workflow.
You can set the variable to the Enconded Absolute URL of the document. The screenshot is my testing. In my testing (in the red area), when the title of a document was equal to the tile of the current item, set a variable to the Enconded Absolute URL of the
document. I used ‘Log to history list’ to check the value of the variable in Workflow History .
I hope this helps.
Thanks,
Wendy
Wendy Li
TechNet Community Support

Similar Messages

How to get the full path or name of the Layer to which Filter is applied?

Hi All,
I have created a layer using some background image as source. How to get the name or ful path of the background image?
I checked the documentation and found GetPathNameProc(SPPlatformFileSpecification*) function, but I couldn't get the parameter SPPlatformFileSpecification*.
Is there any other way to get the file path of background layer in my custom filter?
Thanks,
Dheeraj

If this is a client side application then I'd say look into drag-n-drop tutorials.
i.e. drag file to your application, action listener fires, create File object giving you full name and path of users action.
If this is a web application then look into the "multipart/form-data" content type specifications on how to upload files.
i.e. user specifies file from <input type='file' ... /> type, submits, servlet receives data and recreates file locally on application server side.
If you are thinking that all you need to send a file to a program is the full path and name in a textbox its a little bit more complicated then that.
Good luck, hope that helps!

How to get the full path instead of just the file name, in �FileChooser� ?

In the FileChooserDemo example :
In the statement : log.append("Saving: " + file.getName() + "." + newline);
�file.getName()� returns the �file name�.
My question is : How to get the full path instead of just the file name,
e.g. C:/xdirectory/ydirectory/abc.gif instead of just abc.gif
import java.io.*;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.filechooser.*;
public class FileChooserDemo extends JFrame {
static private final String newline = "\n";
public FileChooserDemo() {
super("FileChooserDemo");
//Create the log first, because the action listeners
//need to refer to it.
final JTextArea log = new JTextArea(5,20);
log.setMargin(new Insets(5,5,5,5));
log.setEditable(false);
JScrollPane logScrollPane = new JScrollPane(log);
//Create a file chooser
final JFileChooser fc = new JFileChooser();
//Create the open button
ImageIcon openIcon = new ImageIcon("images/open.gif");
JButton openButton = new JButton("Open a File...", openIcon);
openButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
int returnVal = fc.showOpenDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//this is where a real application would open the file.
log.append("Opening: " + file.getName() + "." + newline);
} else {
log.append("Open command cancelled by user." + newline);
//Create the save button
ImageIcon saveIcon = new ImageIcon("images/save.gif");
JButton saveButton = new JButton("Save a File...", saveIcon);
saveButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
int returnVal = fc.showSaveDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//this is where a real application would save the file.
log.append("Saving: " + file.getName() + "." + newline);
} else {
log.append("Save command cancelled by user." + newline);
//For layout purposes, put the buttons in a separate panel
JPanel buttonPanel = new JPanel();
buttonPanel.add(openButton);
buttonPanel.add(saveButton);
//Explicitly set the focus sequence.
openButton.setNextFocusableComponent(saveButton);
saveButton.setNextFocusableComponent(openButton);
//Add the buttons and the log to the frame
Container contentPane = getContentPane();
contentPane.add(buttonPanel, BorderLayout.NORTH);
contentPane.add(logScrollPane, BorderLayout.CENTER);
public static void main(String[] args) {
JFrame frame = new FileChooserDemo();
frame.addWindowListener(new WindowAdapter() {
public void windowClosing(WindowEvent e) {
System.exit(0);
frame.pack();
frame.setVisible(true);

simply use file.getPath()
That should do it!Thank you !
It takes care of the problem !!

How to get the full path of the fmx's directory.

Hi all,
I will ship my project to a customer. So I must install forms runtime at the customer's machine.
I put all of the fmx files of my project into a certain directory at the customer's machine, and I create a desktop shortcut of the forms runtime. In the "start in" field of the shortcut property I put the full path of the directory where I put the fmx files. And in the target field of the shortcut property I put after the ifrun60.exe the name of the fmx file which to call first.
Now , in one of my forms file I want to get the full path of this directory because I must call Ora_Ffi.Load_Library. And the library which I want to load resides on that directory.
So how to get programatically the directory where the fmx files reside.
I know that there is the registry entry FORMS60_PATH, but we plan to ship many projects to that customer; so if I use the FORMS60_PATH variable then there will be an error because there will be many directories. And the customer can launch many of the projects at the same time.
So how to get it.
Thank you very much indeed.

If you are using the d2kwutil library, then you can use the win_api_environment.Get_Working_Directory() function.
If not, I doubt that there is anyway to get it since the get_application_property(current_form) does not return the full path of the form as it used to in prior versions of Oracle forms such as 4.5.

How to get the full path of a file

    If the user selects a file through a browse button, Is there a way, I can get the full path of the file. The file can be from his local hard drive as well.. Can someone advise

To upload multiple files (example is for 3), try something like this.
== Form section ==
There would be three(3) file form fields for the selection of a file/document to upload, which
each being uniquely named.
<div style="clear: both;">
<cfinput type="file" name="upload_01" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
<div style="clear: both;">
<cfinput type="file" name="upload_02" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
<div style="clear: both;">
<cfinput type="file" name="upload_03" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
== Processing section ==
Checks to see if any files / documents were selected for upload. If none were, then
displays an alert indicating as such. If at least one file/document was selected, then
the process would process the upload.
<cfif isdefined('form.upload_01') and trim(form.upload_01) eq "" and
isdefined('form.upload_02') and trim(form.upload_02) eq "" and
isdefined('form.upload_03') and trim(form.upload_03) eq ""
>
    <p>Did not select any files to upload</p>
<cfelse>
    <cfif isdefined('form.upload_01') and trim(form.upload_01) neq "">
        <cffile
            action="upload"
            destination="C:\path\to\upload\files\to"
            filefield="upload_01"
            nameconflict="overwrite"
            accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
            <cfcookie name="upload_01_doc" value="#cffile.serverfile#">
            <cfcookie name="upload_01_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cfif isdefined('form.upload_02') and trim(form.upload_02) neq "">
        <cffile
            action="upload"
            destination="C:\path\to\upload\files\to"
            filefield="upload_02"
            nameconflict="overwrite"
            accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
            <cfcookie name="upload_02_doc" value="#cffile.serverfile#">
            <cfcookie name="upload_02_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cfif isdefined('form.upload_03') and trim(form.upload_03) neq "">
    <cffile
        action="upload"
        destination="C:\path\to\upload\files\to"
        filefield="upload_03"
        nameconflict="overwrite"
        accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
        <cfcookie name="upload_03_doc" value="#cffile.serverfile#">
        <cfcookie name="upload_03_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cflocation url="completed.cfm" addtoken="no">
</cfif>
== Completed section ==
Can confirm to the person what files were actually uploaded, by displaying file name and file extension.
You can you use the file extension information to display a respective icon for the file type.
<cfoutput>
<cfif isdefined('cookie.upload_01_doc')>
01. #cookie.upload_01_doc# - #cookie.upload_01_doc_ext#<br /></cfif>
<cfif isdefined('cookie.upload_02_doc')>
02. #cookie.upload_02_doc# - #cookie.upload_02_doc_ext#<br /></cfif>
<cfif isdefined('cookie.upload_03_doc')>
03. #cookie.upload_03_doc# - #cookie.upload_03_doc_ext#<br /></cfif>
</cfoutput>
Leonard B

How to get the full path name of a file

Hey everybody, I'm new here and in Java.
so I will explain my question by giving an example:
I want to send file from the Desktop by the "Send to" on the popup menu to my program.
I want to know how can I read the full path name and the file name, and show it on my text box.
Thanx alot

If this is a client side application then I'd say look into drag-n-drop tutorials.
i.e. drag file to your application, action listener fires, create File object giving you full name and path of users action.
If this is a web application then look into the "multipart/form-data" content type specifications on how to upload files.
i.e. user specifies file from <input type='file' ... /> type, submits, servlet receives data and recreates file locally on application server side.
If you are thinking that all you need to send a file to a program is the full path and name in a textbox its a little bit more complicated then that.
Good luck, hope that helps!

How to get the full path of the plug-in on Mac

I use SDK function "GetPluginFileSpecification" to get the full path of the plug-in .On Windows,I success(for example I get "C:\Adobe\plugin.aip"), On Mac , I only get the plug-in's name(for example"plugin.aip").If I want to get the full path of the plug-in on Mac,is there other function I can use ?

Thank you for the answer.
Unfortunately i'm working on Photoshop plugin, not illustrator.
i was looking for solution on google and i found this post.
I hope you can help me becouse this plug-in is very simple, it must execute a file in the same directory where the plugin is installed.
If i execute system("./Appname.app/Contents/MacOS/AppName"); the plugin search in my home directory (on windows and on MacOS).
i try to write:
   SPPluginsSuite* sSPPlugins;
    SPPluginRef fPluginRef = message->d.self;
    SPPlatformFileSpecification filespec;
    sSPPlugins->GetPluginFileSpecification(message->d.self, &fileSpec);
    filespec.mReference
    ai::FilePath path(platformFileSpec);
    std::cout << path.GetFullPath().as_Platform() << std::endl;
but i have several errors.
Thank you

Tree control - How to get the full path of selected Item in tree control

I am Flex newbie. When the user clicks the particular item in
the tree control I just wanted to get it name along with it's full
parent.
Here is my XML
var dirXML:XML=<root basename="/home/tcegrid">
<Directories>
<Dir Name=".autosave" />
<Dir Name=".emacs.d" />
<Dir Name="AnsysDistributed">
<Dir Name="opt"/>
<Dir Name="root" />
</Dir>
<Dir Name="postgres"/>
<Dir Name="FineTurbo"/>
<Directories>
</root>
The above XML is data provider for Tree control. When the
user clicks the Dir Name called opt. I wanted it absolute path in
XML. say Directories.Dir.Dir.@Name is opt
Can any one tell me how to get this?

"Thamizhannal" <[email protected]> wrote in
message
news:gam9q8$4es$[email protected]..
>I am Flex newbie. When the user clicks the particular
item in the tree
>control
> I just wanted to get it name along with it's full
parent.
> Here is my XML
> var dirXML:XML=<root basename="/home/tcegrid">
> <Directories>
> <Dir Name=".autosave" />
> <Dir Name=".emacs.d" />
> <Dir Name="AnsysDistributed">
> <Dir Name="opt"/>
> <Dir Name="root" />
> </Dir>
> <Dir Name="postgres"/>
> <Dir Name="FineTurbo"/>
> <Directories>
> </root>
>
> The above XML is data provider for Tree control. When
the user clicks the
> Dir
> Name called opt. I wanted it absolute path in XML. say
> Directories.Dir.Dir.@Name is opt
> Can any one tell me how to get this?
loop until the parent() property of the XML node is empty.
HTH;
Amy

How to get the full path of a specific programe(flash media live encoder in my case) in air?

I need to call it in air,but first of all how can I figure out where it's installed programatically?

If you are using the d2kwutil library, then you can use the win_api_environment.Get_Working_Directory() function.
If not, I doubt that there is anyway to get it since the get_application_property(current_form) does not return the full path of the form as it used to in prior versions of Oracle forms such as 4.5.

How to get outbound ftp adapter file name

All,
I am writing an ftp adapter sending out files. The file name is defined as po_%yyyyMMDD%.xml format. However, I need to save the filename into a database after each file is sent out. How could I get the filename after invoking this service? It is on soa 10.1.3.3.
I tried to create a filename variable based on outbound message type and pass that long in the invoke header. But cannot get the name back. Any idea?

Hi,
Go thro' the URL:
http://abhishek-soablog.blogspot.com
Cheers,
Abhi...

How to get the read input file name in bpel process using File Adapter.

Hi,
I am reading a .txt file from configured directory using File Adapter.
I had configured file adapter to read file with naming pattern “SalesOrder.*\.txt”.
Now I had requirement to access the actual file name in bpel process eg: “SalesOrder123.txt”
How can I get the file name in bpel process.
Any help is appreciated.
Vidya.

1) create a variable of message type. Click on Browse Message type. Here you select Message Type-->Project WSDL Files -->fileAdapterInboundHeader-->Message Types-->Inboundheader_msg. Then click OK
2)Next dbl Click on teh receive Activity which is receing your File from teh File Adapter. Go to the Adapter Tab. Click on Browse variable and select the variable that you had just created above.
This would get the File name in the variable declared

How to get Log and Output File Names for a concurrent request

Hi,
I am submitting a concurrent frm OAF with the following code in AM
try{
OADBTransaction tx = getOADBTransaction();
Connection conn = tx.getJdbcConnection();
ConcurrentRequest cr = new ConcurrentRequest(conn);
Vector parameters = new Vector();
parameters.addElement("10");
nRequestID= cr.submitRequest("CIE","DTFEMP","","",false,parameters);
tx.commit();
}catch(RequestSubmissionException e)
How do i get the handle to log and output files for the abvoe concurrent request ?
One more thing is there a way where we can evaluate the environment variables
like in the above example once i get a the request id
logfile = $APPLCSF/$APPLOUT/"l"+requestID+".log"
and
outputfile=$APPLCSF/$APPLOUT/"o"+requestID+".out"
is there a way i can get the values of $APPLCSF and $APPLOUT from the os ?
Thanks
Tom...
Thanks
Tom ...

You can query the Fnd_Concurrent_Requests table using Request_ID, which has the log & out file directory details.
Hth
Srini

How to get the full image directory when i upload the image to web page???

hai, how to get the full image directory when i upload the image to web page???
here is the example:
<form action="uploadfile.jsp" method="post">
image<input type="file" name="image" />
<input type="submit" value="submit"/>
<%
String s=request.getParameter("image");
%>
<%=s%>
</form>
i upload the image from C:\image\center.gif. i use request.getParameter just can get the image name like "center.gif". Can anybody help me how to get the full path name. Thanks a lot..

There is no need to get the path. It is also fairly pointless as the server cannot access the client's local file system.
Carefully read this article how you can upload files the right way: http://balusc.blogspot.com/2007/11/multipartfilter.html

How to get KD Folder path

Hi,
How to get the full path for a given folder ID in KD ?
I am using Java IDK 5.3
Looking for a method like this:
String fullPath = getFolderPath(200);
Thanks.

Besides, the HTML input type="file" lets the client choose a file to upload and it only sends the file contents along the request body from the client to the server. I have reread your question over three times, but I really, really don't see any relation between that HTML code line and your actual problem. Aren't you confusing the client-server relation and the concepts behind it?
At least I can tell you that you can't get the folder path in the server side (as asked in the topic subject), although some browsers (e.g. IE) will do this, but this is faulty and you shouldn't rely on this. Just obtain the file contents from the request body. There are parsers for this as well, such as Apache Commons FileUpload.

How do I get the full path and filename of the current document?

I'm writing a format plug-in. How do I obtain the full path and filename of the current image (document) from within my plug-in? Any help would be greatly appreciated!

I actually just figured this out. For anyone else who would like to know, check out the propetizer sample code in the photoshop sdk. It makes a "filter" plug-in that just spits out all the properties of the document you could ever want to know about. The function I used to get the full path and filename of the current document is PIGetDocumentName(). I hope this helps someone eventually...

Sharepoint Workflow : how to get document full path + file name into variable?

Similar Messages

Maybe you are looking for