Show Column Data In One Row

Hello,
Tell Me how i can show a single column data in one row.
10
20
30
To
10,20,30

If you are OK with displaying comma separated list or column data you could:
SQL> select  ltrim(sys_connect_by_path(ename,','),',') ename_list
  2    from  (
  3           select  ename,
  4                   row_number() over(order by 1) rn,
  5                   count(*) over() cnt
  6             from  emp
  7          )
  8    where rn = cnt
  9    start with rn = 1
10    connect by rn = prior rn + 1
11  /
ENAME_LIST
SMITH,ALLEN,WARD,JONES,MARTIN,BLAKE,MILLER,SCOTT,KING,TURNER,ADAMS,JAMES,FORD,CLARK
SQL> To display as separate columns you would need to either know number of rows:
SQL> select  min(case rn when 1 then ename else null end) ename1,
  2          min(case rn when 2 then ename else null end) ename2,
  3          min(case rn when 3 then ename else null end) ename3,
  4          min(case rn when 4 then ename else null end) ename4,
  5          min(case rn when 5 then ename else null end) ename5,
  6          min(case rn when 6 then ename else null end) ename6,
  7          min(case rn when 7 then ename else null end) ename7,
  8          min(case rn when 8 then ename else null end) ename8,
  9          min(case rn when 9 then ename else null end) ename9,
10          min(case rn when 10 then ename else null end) ename10,
11          min(case rn when 11 then ename else null end) ename11,
12          min(case rn when 12 then ename else null end) ename12
13    from  (
14           select  ename,
15                   rownum rn
16             from  emp
17          )
18  /
ENAME1  ENAME2  ENAME3  ENAME4  ENAME5  ENAME6  ENAME7  ENAME8  ENAME9  ENAME10  ENAME11  ENAME12
SMITH   ALLEN   WARD    JONES   MARTIN  BLAKE   CLARK   SCOTT   KING    TURNER   ADAMS    JAMES
SQL> or use dynamic SQL.
SY.

Similar Messages

  • How to display Column data in one row

    Hello,
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    AUDITEFFECTIVEDATE_3
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    1/2/2007
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    Well that's a little tougher... For a solution to work, you're going to need to find a way to differentiate between the the specific hiring events.  Without seeing what data is available, I'd say start looking at the use of running totals... or in this case a running count.
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  • Need to split data from one row into a new row redux

    Hi folks,
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    Hi Tod,
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  • Display array data in one row

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  • Need a report column to hold data for one row only

    Hey Guys,
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  • Write to spreadsheet file.vi is storing data in one row only.

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    Certified LabVIEW Architect
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    "... after all, He's not a tame lion..."
    Be thinking ahead and mark your dance card for NI Week 2015 now: TS 6139 - Object Oriented First Steps

  • Two rows as one display the data in one row

    Hello All,
    I would like to have data of two rows put in one as:
    Lets say the data is like this:
    SELECT * FROM TEST;
          COL1       COL2       COL3 C
           1.5          3          1 M
                        2          1 C
           2.5                     2 C
                      3.5          2 M
                      4.5          3 M How do i get the output as :
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           1.5          3          1 M      2
           2.5                     2 C      3.5
                      4.5          3 M If there are two rows with same value in Col3, then col5(a new dummy column in select stmt) the second row's col2 should be disaplyed in Row 1.
    Can we do it in a Select Statement ?
    Regds,
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    A try :
    SQL> select * from Amkotz;
          COL1           COL2          COL3 C                                             
           1,5              3             1 M                                             
                            2             1 C                                             
           2,5                            2 C                                             
                          3,5             2 M                                             
                          4,5             3 M                                             
    SQL> select a.col1,
      2         a.col2,
      3         a.col3,
      4         a.col4,
      5         max(decode(a.rowid,b.rowid,null,b.col2)) keep (dense_rank last order by a.col1,a.col2) as col5
      6  from   (select Amkotz.*, row_number() over (partition by col3 order by col1,col2) rn from Amkotz) a, Amkotz b
      7  where  a.rn=1
      8  and    a.col3=b.col3
      9  group by a.col1,
    10         a.col2,
    11         a.col3,
    12         a.col4;
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          1,5          3        1 M 2         
          2,5                   2 C 3,5       
                     4,5        3 M            Nicolas.

  • Depicting multiple rows' data in one row

    Hi All,
    Pls. check the below query:
    select manager_id mg_id, employee_id emp_id, last_name name from employees
    where manager_id = '100'
    and DEPARTMENT_ID = '80'if i run the following query, then o/p comes row wise; like below:
           mg_id           emp_id            name
           100             145                     Russell
           100             146                     Partners
           100             147                     Errazuriz
           100             148                     Cambrault
           100             149                     Zlotkeybut if i want the o/p like below; i.e; under manager # 100, all employees' emp_id and name should come in only ONE row NOT in multiple rows:
    mg_id                   emp_id     name          emp_id       name       emp_id     name         emp_id     name                emp_id         name
    100                             145             Russell     146       Partners        147     Errazuriz       148              Cambrault        149        Zlotkeypls. help me to sort out the above sought o/p.
    kindly tell me if there is any posting guidelines (except "Plain Text Help" on the right side) in this forum. i tried a lot to post above two o/p in easily readable format, but couldn't do that.
    Edited by: Shariful on Sep 20, 2009 4:28 AM
    Edited by: Shariful on Sep 20, 2009 4:29 AM

    Hi,
    Shariful wrote:
    Hi All,
    Pls. check the below query:
    select manager_id mg_id, employee_id emp_id, last_name name from employees
    where manager_id = '100'
    and DEPARTMENT_ID = '80'
    if i run the following query, then o/p comes row wise; like below:
    mg_id           emp_id            name
    100     145     Russell
    100     146     Partners
    100     147     Errazuriz
    100     148     Cambrault
    100     149     Zlotkey
    but if i want the o/p like below; i.e; under manager # 100, all employees' emp_id and name should come in only ONE row NOT in multiple rows:
    mg_id                   emp_id     name          emp_id       name       emp_id     name         emp_id     name                emp_id         name
    100     145     Russell     146     Partners     147     Errazuriz     148     Cambrault     149     ZlotkeyIf you want all the emp_ids and names concatenated into one big VARCHAR2 column, that's called String Aggregation
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    You can format that one big column so that it looks like separate columns.
    If you want each emp_id and name in its own column, that's called Pivoting .
    Look up "pivot" for various techniques. If you do not know exactly how many rows were in the original query (and therefore how many columns you'll need in the output), then it will require Dynamic SQL , which can be complicated.
    Unfortunately, when you do search for "pivot", mlost of the hits will be things like "Search for pivot and you'll get lots of examples".
    Re: Help for a query to add columns is one that actually has some information. It was a question very much like yours.
    kindly tell me if there is any posting guidelines (except "Plain Text Help" on the right side) in this forum. i tried a lot to post above two o/p and query in easily readable format, but couldn't do that.Type these 6 characters:
    (small letters only, inside curly brackets) before and after formatted text, to preserve spacing.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                               

  • How to show three more than one row as single row

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    101 1
    101 2
    101 3
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    output like this 101 1/2/3
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    Thanks

    864470 wrote:
    However, I am not getting any distinct values for that.Are you sying there are multiple records for same emp_id, dept_id combination? If so:
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      4             select 101,2 from dual union all
      5             select 101,3 from dual
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      3             select 101,2 from dual union all
      4             select 101,2 from dual union all
      5             select 101,3 from dual
      6            )
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      8  select  emp_id,
      9          rtrim(xmlagg(xmlelement(d,dept_id,'/').extract('//text()') order by dept_id),'/') dept_list
    10    from  (
    11           select  emp_id,
    12                   dept_id
    13             from  t
    14             group by emp_id,
    15                      dept_id
    16          )
    17    group by emp_id
    18  /
        EMP_ID DEPT_LIST
           101 1/2/3
    SQL> SY.

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    Post Author: sdgroves
    CA Forum: General
    I am trying to pull data from a Student Management System. I specifically need the data from the SMS to show up like this:
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    Jones, Rick       123456       Johnson            Landers          Jones
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    Student Name  Student ID   English Class   History Class  Math Class
    Jones, Rick       123456       Johnson           
    Jones, Rick       123456                              Landers         
    Jones, Rick       123456                                                       Jones
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    Post Author: sdgroves
    CA Forum: General
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    Irha10 wrote:
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    Irha10 wrote:
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  • Compare column data of two rows

    Hi there,
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    COMP_ID      PROD      COLOR       COMPAREFLAG  ORDER_NUMBER
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    2              sun      blue          Y                         2
    3           horse      black         -                          1
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    Message was edited by:
    ben512

    I hope that I well understand.
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      3   select 2 comp_id, 'sun'   prod, 'blue'  color, 'Y'  compareflag, 2 order_number from dual union all
      4   select 3 comp_id, 'horse' prod, 'black' color, null compareflag, 1 order_number from dual union all
      5   select 4 comp_id, 'horse' prod, 'white' color, 'Y'  compareflag, 1 order_number from dual union all
      6   select 5 comp_id, 'chair' prod, 'black' color, null compareflag, 3 order_number from dual union all
      7   select 6 comp_id, 'chair' prod, 'black' color, 'Y'  compareflag, 3 order_number from dual )
      8  select comp_id, prod, color, compareflag, order_number
      9  from  (select comp_id,
    10                prod,
    11                decode(first_value(prod) over (partition by order_number order by comp_id range between unbounded preceding and unbounded following),
    12                       last_value(prod) over (partition by order_number order by comp_id  range between unbounded preceding and unbounded following),null,prod) prod_d,
    13                color,
    14                decode(first_value(color) over (partition by order_number order by comp_id range between unbounded preceding and unbounded following),
    15                       last_value(color) over (partition by order_number order by comp_id  range between unbounded preceding and unbounded following),null,color) color_d,
    16                 compareflag,
    17                 order_number
    18         from   tbl
    19         where  order_number=&order_number)
    20  where  (prod_d is not null or color_d is not null)
    21  order by 1;
    Enter value for order_number: 1
    old  19:        where  order_number=&order_number)
    new  19:        where  order_number=1)
       COMP_ID PROD  COLOR C ORDER_NUMBER
             3 horse black              1
             4 horse white Y            1
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    old  19:        where  order_number=&order_number)
    new  19:        where  order_number=2)
       COMP_ID PROD  COLOR C ORDER_NUMBER
             1 sun   red                2
             2 sun   blue  Y            2
    SQL> /
    Enter value for order_number: 3
    old  19:        where  order_number=&order_number)
    new  19:        where  order_number=3)
    no rows selected
    SQL> Nicolas.

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