Simple calculator for viewing in cmd

Question

i am taking my first programming class and have started to feel overwhelmed. this is my assignment:
To write a program that lets a user do simple math operations on two numbers
? To demonstrate using decision logic in a Java program.
? To become aware of error conditions when writing a program
? To continuing practicing working with two files in a Java program, one Java class
and a tester
Programming Requirements
1. Get user input for the users? name and two integer numbers.
2. Get the user input for a choice of math operation: addition, subtraction,
multiplication.
3. Output the user?s name and the result of the math operation on the two numbers
that were input by the user.
Output: The output should look similar to the following:
What is your name?
Java
Enter a number:
7
Enter another number:
3
Choose a math operation: (A) addition, (S) subtraction, (M)
multiplication
M
Hello Java! 7 * 3 = 21
all i have so far is:
* Calculator.java
* Modified on July 14, 2008
* This class has a method that accepts input from a user about their name, 2 integers, and mathematical
* operation. it then calculates answer and outputs information to screen
import java.util.Scanner; // This import is so that I can have access to the Scanner code.
* @author sandra
/** Creates a new instance of Calculator */
public Calculator() {
* @param args the command line arguments
public static void main(String[] args) {
//I am creating an object of type Scanner to help me get input from the user.
Scanner inputScanner = new Scanner(System.in);
     // value for variables are listed below
int firstNumber = 0; // initialize input to 0
int secondNumber = 0:
String inputName = "Doe"; //assigns an initial value for the string value inputName
System.out.println("What is your name?");
inputName = inputScanner.nextLine(); //Stores user input for later use
System.out.println("Enter a number");
int firstNumber = inputScanner.nextInt();
myScanner.nextLine(); // Reading the return character from the previous integer input to get around bug...
System.out.println("Enter another number");
int secondNumber = inputScanner.nextIt();
myScanner.nextLine(); // Reading the return character from the previous integer input to get around bug...
System.out.println("Choose a math operation:");
System.out.println("(1) Addition");
System.out.println("(2) Subtraction");
System.out.println("(3) Multiplication");
// Store the user's response as an integer
int operation = myScanner.nextInt();
myScanner.nextLine(); // Reading the return character from the previous integer input to get around bug...
if (operation == 1 )
i know i'm probably on the wrong track. the if/else statements are frying my brain. PLEASE help. thanks

Answer 1

Looks like you are on the right track to me. I give a little hint.
if(....) {
    // what should you do if user enters 1?
} else if(....) {
    // what should you do if user enters 2?
} else if(....) {
    // what should you do if user enters 3?
} else {
    // what should you do if user enters 42?
System.out.println(....);Just work out what the dots are.