SQ01 query - Drilldown total level larger than 0 and drilldown function

Hi everybody,
I have made a sq01 query and set the call up report at "Report assignment" function. The drilldown total level of my query is 1 and I found that this makes the report can't pass the selected data (with cursor) to the receiver report correctly. I can't change the drilldown total level as 0 due to the user requirement. May I ask is there any other way to solve this problem? Thank you.

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Please mark solved if I've answered your question, vote for it as helpful to help other users find a solution quicker
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My Blog | My Page
Dear Praveen Dsa
Thanks for your reply, but order_no and date are paired and related, cannot separate.
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Edit:
Here is a snippet of the tracefile on the client right after Executing the select-statement. Some data seems to be retrieved and than it ends with these lines:
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 2D 20 49 6E 74 72 61 6E |-.Intran|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 65 74 2D 47 72 75 6E 64 |et-Grund|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 6C 61 67 65 6E 02 C1 04 |lagen...|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 02 C1 03 02 C1 0B 02 C1 |........|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 51 00 02 C1 03 02 C1 2D |Q......-|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 05 48 4B 4F 50 50 01 80 |.HKOPP..|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 03 3E 64 66 01 80 07 78 |.>df...x|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 65 0B 0F 01 01 01 07 76 |e......v|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: C7 01 01 09 01 01 07 76 |.......v|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: C7 01 01 18 01 01 07 78 |.......x|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 65 0B 0F 01 01 01 07 76 |e......v|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: C7 01 01 09 01 01 07 76 |.......v|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: C7 01 01 18 01 01 02 C1 |........|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 3B 02 C1 02 01 80 00 00 |;.......|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 00 00 00 00 00 00 00 00 |........|
(1992) [20-AUG-2008 17:13:00:953] nsprecv: 00 00 01 80 15 0C 00 |....... |
(1992) [20-AUG-2008 17:13:00:953] nsprecv: normal exit
(1992) [20-AUG-2008 17:13:00:953] nsrdr: got NSPTDA packet
(1992) [20-AUG-2008 17:13:00:953] nsrdr: NSPTDA flags: 0x0
(1992) [20-AUG-2008 17:13:00:953] nsrdr: normal exit
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: acquired the bit
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] nsdo: what=1, bl=2001
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: acquired the bit
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] nsdo: nsctxrnk=0
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] nsdo: normal exit
(1992) [20-AUG-2008 17:13:00:953] nioqrc: exit
(1992) [20-AUG-2008 17:13:00:953] nioqrc: entry
(1992) [20-AUG-2008 17:13:00:953] nsdo: entry
(1992) [20-AUG-2008 17:13:00:953] nsdo: cid=0, opcode=85, bl=0, what=0, uflgs=0x0, cflgs=0x3
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: acquired the bit
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] nsdo: rank=64, nsctxrnk=0
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] nsdo: nsctx: state=8, flg=0x100400d, mvd=0
(1992) [20-AUG-2008 17:13:00:953] nsdo: gtn=127, gtc=127, ptn=10, ptc=2011
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: acquired the bit
(1992) [20-AUG-2008 17:13:00:953] snsbitts_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: entry
(1992) [20-AUG-2008 17:13:00:953] snsbitcl_ts: normal exit
(1992) [20-AUG-2008 17:13:00:953] nsdo: switching to application buffer
(1992) [20-AUG-2008 17:13:00:953] nsrdr: entry
(1992) [20-AUG-2008 17:13:00:953] nsrdr: recving a packet
(1992) [20-AUG-2008 17:13:00:953] nsprecv: entry
(1992) [20-AUG-2008 17:13:00:953] nsprecv: reading from transport...
(1992) [20-AUG-2008 17:13:00:968] nttrd: entry
Message was edited by:
vhbtech

Found nothing in the \bdump alert.log or \bdump trace files. I only have the DEFAULT profile and everything is set to UNLIMITED there.
But the \udump generates a trace file the moment i execute the query:
Dump file <path>\udump\<sid>ora4148.trc
Fri Aug 22 09:12:18 2008
ORACLE V10.1.0.5.0 - Production vsnsta=0
vsnsql=13 vsnxtr=3
Oracle Database 10g Release 10.1.0.5.0 - Production
With the OLAP and Data Mining options
Windows Server 2003 Version V5.2 Service Pack 2
CPU : 2 - type 586, 1 Physical Cores
Process Affinity : 0x00000000
Memory (Avail/Total): Ph:898M/3071M, Ph+PgF:2675M/4967M, VA:812M/2047M
Instance name: <SID>
Redo thread mounted by this instance: 1
Oracle process number: 33
Windows thread id: 4148, image: ORACLE.EXE (SHAD)
*** 2008-08-22 09:12:18.731
*** ACTION NAME:(SQL Window - select * from stude) 2008-08-22 09:12:18.731
*** MODULE NAME:(PL/SQL Developer) 2008-08-22 09:12:18.731
*** SERVICE NAME:(<service-name>) 2008-08-22 09:12:18.731
*** SESSION ID:(145.23131) 2008-08-22 09:12:18.731
opitsk: network error occurred while two-task session server trying to send break; error code = 12152
This trace is only generated if the query with a expected large resultset fails. If i narrow down the resultset no trace is written, well and the query then works of course.

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Edited by: JoelH on 10-Feb-2010 10:59
Edited by: JoelH on 10-Feb-2010 10:59

Hi Joel,
Now, when I add 4 secondary database indexes - on the 4 long values - I would expect to see approximately an additional 4 * 32 * 280k Bytes -> ~ 35MA secondary index consists of a regular JE database containing key-value pairs, where the key of the pair is the secondary key and the value of the pair is the primary key. Your primary key is 80 bytes, so this would be 4 * (4 + 80) * 280k Bytes -> ~ 91M.
The remaining space is taken by per-record overhead for every primary and secondary record, plus the index of keys itself. There are (280k * 5) records total. Duplicates do not take less space.
I assume this is an insert-only test, and therefore the log should contain little obsolete data. To be sure, please run the DbSpace utility.
Does this answer your question?
--mark

SQ01 query - Drilldown total level larger than 0 and drilldown function

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