SQL - Decode for Other Dates Column

Question

This query returns 2 rows. Anyway I can use decode
(maybe nested decode, or some other method without union)
so I can return result set of 1 row with headings that
has correct counts for Total, 1999, 2000, 2001, Others.
Others represents all other years other than 1999, 2000,
or 2001. thank you.
select count(*) "Total",
sum(decode(to_char(o.order_date, 'YYYY'), 1999,1,0)) "1999",
sum(decode(to_char(o.order_date, 'YYYY'), 2000,1,0)) "2000",
sum(decode(to_char(o.order_date, 'YYYY'), 2001,1,0)) "2001",
0 "OTHER" from oe.orders o
union
select 0 "Total", 0 "1999", 0 "2000", 0 "2001", count (order_date) "OTHER" from oe.orders
where to_char (order_date, 'YYYY') not in ('1999', '2000', '2001');

Answer 1

I think something like that should also do it and is certainly faster then accesing twice your table:
select count(*) "Total",
sum(decode(to_char(o.order_date, 'YYYY'), 1999,1,0)) "1999",
sum(decode(to_char(o.order_date, 'YYYY'), 2000,1,0)) "2000",
sum(decode(to_char(o.order_date, 'YYYY'), 2001,1,0)) "2001",
sum(
decode(to_char(o.order_date, 'YYYY'), 1999, 0, 2000,0,2001,0,1)
) "OTHER" from oe.orders o
If you are using an Oracle 8i or 9i you could also have a look at the CASE function