SQL that provides direct and Indirect reports

Question

SELECT DISTINCT J.EMPLID ,J.EMPL_RCD ,A.NAME ,J.BUSINESS_UNIT ,J.JOBCODE ,JC.DESCR ,J.DEPTID ,D.DESCR
,J.SUPERVISOR_ID ,J.REPORTS_TO ,J.LOCATION ,J.COMPANY ,J.PAYGROUP ,J.GP_PAYGROUP ,ED.WORKGROUP ,ED.TASKGROUP
,J.POSITION_NBR ,L.BUILDING, WG.INCL_ML_BRK_FLG
FROM PS_JOBCODE_TBL JC , PS_JOB J , PS_TL_EMPL_DATA ED, PS_TL_GROUP_DTL F ,PS_TL_GRP_SECURITY S
,PS_PERSON_NAME A , PS_DEPT_TBL D, PS_LOCATION_TBL L, PS_TL_WRKGRP_TBL WG
WHERE S.GROUP_ID = F.GROUP_ID
AND F.EMPLID = J.EMPLID
AND F.EMPL_RCD = J.EMPL_RCD
AND F.EMPLID = A.EMPLID
AND F.EMPLID = ED.EMPLID
AND F.EMPL_RCD = ED.EMPL_RCD
AND S.ROWSECCLASS = 'DPALL'
AND J.EFFDT = ( SELECT MAX(J1.EFFDT) FROM PS_JOB J1
WHERE J1.EMPLID = J.EMPLID
AND J1.EMPL_RCD = J.EMPL_RCD
AND J1.EFFDT <= '22-MAY-2012')
AND J.EFFSEQ = ( SELECT MAX(J2.EFFSEQ) FROM PS_JOB J2
WHERE J2.EMPLID = J.EMPLID
AND J2.EMPL_RCD = J.EMPL_RCD
AND J2.EFFDT = J.EFFDT )
AND ED.EFFDT = ( SELECT MAX(ED1.EFFDT) FROM PS_TL_EMPL_DATA ED1
WHERE ED1.EMPLID = ED.EMPLID
AND ED1.EMPL_RCD = ED.EMPL_RCD
AND ED1.EFFDT <= '22-MAY-2012')
AND JC.SETID = J.SETID_JOBCODE
AND JC.JOBCODE = J.JOBCODE
AND JC.EFFDT = ( SELECT MAX(JC1.EFFDT) FROM PS_JOBCODE_TBL JC1
WHERE JC1.SETID = J.SETID_JOBCODE
AND JC1.JOBCODE = J.JOBCODE
AND JC1.EFFDT <= '22-MAY-2012')
AND D.SETID = J.SETID_DEPT
AND D.DEPTID = J.DEPTID
AND D.EFFDT = ( SELECT MAX(D1.EFFDT) FROM PS_DEPT_TBL D1
WHERE D1.SETID = J.SETID_DEPT
AND D1.DEPTID = J.DEPTID
AND D1.EFFDT <= '22-MAY-2012')
AND L.SETID = J.SETID_LOCATION
AND L.LOCATION = J.LOCATION
AND L.EFFDT = ( SELECT MAX(EFFDT) FROM PS_LOCATION_TBL
WHERE SETID = L.SETID
AND LOCATION = L.LOCATION
AND EFFDT <= '22-MAY-2012')
AND J.SUPERVISOR_ID LIKE '76634%'
AND A.EMPLID <> '76634'
AND ED.WORKGROUP = WG.WORKGROUP
AND WG.EFFDT = (SELECT MAX(WG1.EFFDT) FROM PS_TL_WRKGRP_TBL WG1
WHERE WG.WORKGROUP = WG1.WORKGROUP
AND WG1.EFFDT <= '22-MAY-2012'
AND J.EMPL_STATUS IN ('A','L','P','S')
AND J.EFFDT <= '20-MAY-2012');
Above SQL provides me the list of employees (only direct reports) who report to EMPLID 76634. Now I want to modify this SQL so that It will also provide me the list of employees from a lower level (indirect reports).
For example, if employees 1, 2 report to 76634. And 3,4 report to 1. And 5,6 report to 2. I want to modify the above SQL such that it will retrieve both direct and indirect reports for 76634 i.e 1,2,3,4,5 and 6.
As of now above SQL will retrieve only 1,2. Any thoughts?

Answer 1

SQLServer uses a recursive query for this.
Just typing "SQLServer recursive query" in a search engine will provide you with tons of examples, but I will redirect you to the source MSDN,
http://msdn.microsoft.com/en-us/library/ms175972%28SQL.90%29.aspx
Look for the following example
D. Using a recursive common table expression to display multiple levels of recursion
The following example shows the hierarchical list of managers and the employees who report to them.
USE AdventureWorks;
GO
WITH DirectReports(ManagerID, EmployeeID, EmployeeLevel) AS
SELECT ManagerID, EmployeeID, 0 AS EmployeeLevel
FROM HumanResources.Employee
WHERE ManagerID IS NULL
UNION ALL
SELECT e.ManagerID, e.EmployeeID, EmployeeLevel + 1
FROM HumanResources.Employee e
INNER JOIN DirectReports d
ON e.ManagerID = d.EmployeeID
SELECT ManagerID, EmployeeID, EmployeeLevel
FROM DirectReports ;
GO