Time_out - Time limit exceed - Error

Question

Hi,
The following code gives the Time_out run time error.
LOOP AT i_outtab.
    IF p_cust = 'X'.
     Select single kunnr from vbak into sales_cust
                 where kunnr =  i_outtab-kunnr
                 and  ERDAT GE date.
    IF sy-subrc NE 0.
    DELETE i_outtab INDEX sy-tabix.
    CONTINUE.
    ENDIF.
    ENDIF.
    i_outtab1-kunnr = i_outtab-kunnr.
    i_outtab1-name1 = i_outtab-name1.
    i_outtab1-land1 = i_outtab-land1.
    i_outtab1-ernam  = i_outtab-ernam.
    i_outtab1-vkorg  = i_outtab-vkorg.
    i_outtab1-vtweg  = i_outtab-vtweg.
    i_outtab1-spart   =  i_outtab-spart.
    APPEND i_outtab1.
    CLEAR i_outtab1.
  ENDLOOP.
However, if the select query is omitted when the condition fails, the performance of the program is fast. Only because of this select query, it goes to run time error.
What is the issue?
Thanks,
Ezhil

Answer 1

Hi Ezhilhrh,
Please see the code below.  I have removed the select query from the loop. 
IF p_cust = 'X'.
DATA: TEMP_ITAB LIKE TABLE OF I_OUTTAB OCCURS 0
      WITH HEADERLINE.
Select single kunnr from vbak into table temp_itab
for all entries in i_outtab
where kunnr = i_outtab-kunnr
  and ERDAT GE date.
IF sy-subrc EQ 0.
i_outtab[] = temp_itab[]
SORT I_OUTTAB BY KUNNR.
LOOP AT i_outtab.
READ TABLE TEMP_ITAB WITH KEY KUNNR = I_OUTTAB-KUNNR BINARY SEARCH.
IF SY-SUBRC EQ 0.
i_outtab1-kunnr = TEMP_ITAB -kunnr.
i_outtab1-name1 = i_outtab-name1.
i_outtab1-land1 = i_outtab-land1.
i_outtab1-ernam = i_outtab-ernam.
i_outtab1-vkorg = i_outtab-vkorg.
i_outtab1-vtweg = i_outtab-vtweg.
i_outtab1-spart = i_outtab-spart.
APPEND i_outtab1.
CLEAR i_outtab1.
ELSE.
DELETE i_outtab INDEX sy-tabix.
CONTINUE.
ENDIF.
ENDLOOP.
ENDIF.
This code will improve your performance as well.
Regards,
Md Ziauddin.