To open a file where the filename is dynamic ......

Question

String logfile=request.getParameter("value");
out.println(logfile);
FileInputStream fs1 = new FileInputStream("/opt/Abhishek/software/tomcat/webapps/AMS/Backend/History/");
                                DataInputStream in1 = new DataInputStream(fs1);
                                while (in1.available() !=0)
                                String str=in1.readLine();
                                out.println(str+"<br>");
                                }I have to display the available number of logfiles in a directory in a JSP page and once the logfile is clicked i need to show its contents.Once the logfile is clicked the filename is passed as a parameter to another JSP page the code shown above.In the above code i have the filename .And the File is available in the History Directory.I dont know what to put after the History .How to open the file that is mentioned by the value which is dynamic ????????
Any one could Please Help???????????????

Answer 1

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String logfile=request.getParameter("value");
FileInputStream fs1 = new FileInputStream("/opt/Abhishek/software/tomcat/webapps/AMS/Backend/History/" + logfile);?