Type 'Microsoft.SharePoint.WebControls.EmbeddedFormField' does not have a public property named 'div' - SharePoint 2013

I was changing my Home page's Master Page, so I went to the advanced mode via SharePoint designer and changed the Master Page line, then that happened! I tried to export and Import the Home.aspx but same?!

Hi,
According to your post, my understanding is that you got errors when you changed the master page.
Based on the earlier threads, If you forget the <zone template> tags, this issue may happen.
You can wrap your whole code in a <div> tag, then check whether it works.
There are some similar threads for your reference.
http://mysharepointwork.blogspot.com/2011/07/type-microsoftsharepointwebcontrolsscri.html
http://www.sharepointboris.net/2009/02/type-microsoftsharepointwebcontrolsformfield-does-not-have-a-public-property-named-xmlnssharepoint-error/
http://social.technet.microsoft.com/Forums/en-US/89e99b85-5af3-45c1-a39e-677711329aba/error-systemwebuiwebcontrolscontentplaceholder-does-not-have-a-public-property-named?forum=sharepointadminprevious
Thanks & Regards,
Jason
Jason Guo
TechNet Community Support

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Wscompile + xmlbeans: class does not have a public accessible empty constru

Hi
I have some schema files from 3gpp.org and created java files with xmlbeans.
Now I try to use them but wscompile complains:
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that class is generated by xmlbeans and I can't modify it...
The class is an innner class of an interface, and looks like this:
* Enumeration value class for provider.VersionType.
* These enum values can be used as follows:
* <pre>
* enum.toString(); // returns the string value of the enum
* enum.intValue(); // returns an int value, useful for switches
* // e.g., case Enum.INT_X_5_3_0
* Enum.forString(s); // returns the enum value for a string
* Enum.forInt(i); // returns the enum value for an int
* </pre>
* Enumeration objects are immutable singleton objects that
* can be compared using == object equality. They have no
* public constructor. See the constants defined within this
* class for all the valid values.
static final class Enum extends org.apache.xmlbeans.StringEnumAbstractBase
* Returns the enum value for a string, or null if none.
public static Enum forString(java.lang.String s)
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* Returns the enum value corresponding to an int, or null if none.
public static Enum forInt(int i)
{ return (Enum)table.forInt(i); }
private Enum(java.lang.String s, int i)
{ super(s, i); }
static final int INT_X_5_3_0 = 1;
public static final org.apache.xmlbeans.StringEnumAbstractBase.Table table =
new org.apache.xmlbeans.StringEnumAbstractBase.Table
new Enum[]
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private static final long serialVersionUID = 1L;
private java.lang.Object readResolve() { return forInt(intValue()); }
Can anyybody help me ?
thanks
Gabor

Sorry, I think you are out-of-luck on this one. The JAXRPC spec mandates that an acceptable value type have a public empty constructor. The only work-around I can suggest is to write a wrapper bean around this one that has such a constructor and use that in you interface instead.

Applet - JavaPurse does not have a public constructor

Hello,
I'm starting playing with Javacard and I tried to compile a demo of Java purse Applet.
I can compile it withou problem but once I try to start it with JBuilder 2006 I get the following error :
The applet com.sun.javacard.samples.JavaPurse.JavaPurse does not have a public constructor com.sun.javacard.samples.JavaPurse.JavaPurse()
Here is a part of my code
public class JavaPurse extends javacard.framework.Applet {
protected JavaPurse(byte[] bArray, short bOffset, byte bLength) {
public static void install(byte[] bArray, short bOffset, byte bLength) {
new JavaPurse(bArray, bOffset, bLength);
Does anyone of you know why JBuilder is displaying this error message?
Thanks in advance fo you reply.
Alain.

I don't think that's the error message; there is no class "java.awt.Applet". Are you sure it doesn't say "java.applet.Applet"?
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GetCodeBase() generates "does not have a public constructor"

I've been searching the net for days, and I seem to be the only guy with this problem. Here's the simple code:
public class testapplet extends JApplet {
public testapplet() {
URL url = getCodeBase();
I get the error message:
The applet testapplet does not have a public constructor testapplet()
I once had the same error message, but it was an entirely different problem. At that time, I made an JMenu[2] and somewhere in the code addressed JMenu[3];
As I said, this has nothing to do with my current problem, but I get VERY frustrated when I get such an error.
I'm running JBuilder6 on Win XP. Please help! desperate cry

Damn, it helped. O_O Thanks a lot! As you can tell, I'm new to this. I was surprised since in my other program, I wrote a lot of stuff without that init procedure and it worked...
Thanks again!

ERROR:The applet Tennisball does not have a public constructor Tennisball()

hi all...sorry...i encountered this java error msg with the following code.....n the error msg tat was generated is that i do not have a public constructor which i already have...can some1 please enlighten me..??
import java.applet.*;
import java.awt.*;
public class Tennisball
     double x, y, oldx, oldy, xinc, yinc, v=2.0;
     int i,e,west,north,east,south,ry,rs,score,rx;
     int choice, zone;
     AudioClip ballout;
     boolean running,toggle,enough;
        Color ballcolor;
     Tennis t;
     Color bgColor = Color.black;
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                west=w;
          east=e;
          south=s;
          north=n;
          ballout = bo;
          //this.t = t;
          xinc=1.7*v;
          yinc=0.7*v;
     public void getRacketPosition(int racket_y)
          ry=racket_y;
          rs=ry;
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          ballcolor=Color.yellow;
          x=20;
          y=(int)(Math.random()*100+50);
          int angle=(int)(Math.random()*8+1);
          if(angle==1)yinc=-0.7*v;
          if(angle==2)yinc=-0.5*v;
          if(angle==3)yinc=-0.4*v;
          if(angle==4)yinc=-0.3*v;
          if(angle==5)yinc=0.3*v;
          if(angle==6)yinc=0.4*v;
          if(angle==7)yinc=0.5*v;
          if(angle==8)yinc=0.7*v;
          toggle=false;
          running=true;
          enough=false;
          e=0;
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          if(running)
               if(!toggle)
                    oldx=x;
                    oldy=y;
                    x+=xinc*v;
                    y+=yinc*v;
               if(x<west && xinc<0)
                    int angle=(int)(Math.random()*8+1);
                    if(angle==1)yinc=-0.7*v;
                    if(angle==2)yinc=-0.5*v;
                    if(angle==3)yinc=-0.4*v;
                    if(angle==4)yinc=-0.3*v;
                    if(angle==5)yinc=0.3*v;
                    if(angle==6)yinc=0.4*v;
                    if(angle==7)yinc=0.5*v;
                    if(angle==8)yinc=0.7*v;
                   xinc=-xinc;
                    t.playClick();
               else if(x>east-10)
                    x=east-10;
                    toggle=true;
                    running=false;
                    score++;
                    t.playBallout();
               else if(y<north || y>south)
                   if(y<north&&yinc<0)
                         yinc=-yinc;
                    if(y>south&&yinc>0)
                         yinc=-yinc;
                    t.playClick();
               else if(x>425 && xinc>0 && y>ry && y<rs+25)
                    if(y<ry+3)zone=1;
                    else if(y>=ry+3&&y<ry+6)zone=2;
                    else if(y>=ry+6&&y<ry+9)zone=3;
                    else if(y>=ry+9&&y<ry+12)zone=4;
                    else if(y>=ry+12&&y<ry+15)zone=5;
                    else if(y>=ry+15&&y<ry+18)zone=6;
                    else if(y>=ry+18&&y<ry+21)zone=7;
                    else if(y>=ry+21)zone=8;
                    if(zone==1)yinc=-0.7*v;
                    if(zone==2)yinc=-0.5*v;
                    if(zone==3)yinc=-0.4*v;
                    if(zone==4)yinc=-0.3*v;
                    if(zone==5)yinc=0.3*v;
                    if(zone==6)yinc=0.4*v;
                    if(zone==7)yinc=0.5*v;
                    if(zone==8)yinc=0.7*v;
                    xinc=-xinc;
                    t.playClick();
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                    int i=t.j;
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                         if(i>10&&i<20){ballcolor=bgColor;e++;}
                    if (e>35){ballcolor=bgColor;enough=true;}
     public void paint(Graphics g)
          if(toggle)toggle();
          g.setColor(ballcolor);
          g.fillOval((int)x,(int)y,10,10);
}

I thought I should point out a few things
The rule is that every class should have a no
argument constructor that you need to specify
explicitly if you have overloaded the default one.
One of the reaons for that is the following:This is not true, there are many classes that do not have a no argument constructor (For example Integer). Integer is a perfect example of why you would not want a no argument constructor, having an Integer with no value is pointless (theres nothing you can do with it).
public class A {
private final int a ;
public A(int b) {
this.a = b ;
}Now you realize that the variable
n
is getting initialized in the constructor. I see no variable n in the constructor but I take it you mean a
Now if you
refer to
n
somewhere else in you code you get a compile error because
n
might not have been initialized.This is not true, only local variables can cause a
variable (a variable) might not have been initialized
this is because all member fields are initialised with their default valuse. For example all pointers are intitialised to null, ints are intitialised to 0, booleans to false and so on.
>
So you need this:
public class A {
private final int a ;
public A(int b) {
this.a = b ;
public A() {
this(0) ; /* Calls the above constructor with some
default parameter. */
/* You can add some more code below but not above
this(0) */
Of course you know you are never calling the default
constructor but it's still there so you need to
ensure that the variables get initialized if some one
calls it!
As above classes can have no argument constructors
Just add this to your code for example:
public Tennisball() {
this(0, 0, 0, 0, null) ;
} Hope that helped you out!
Thanks,
Nikolas.
PS any duke dollars would be much appreciated as i'm
very poor at the moment :-)I dont mean to be offensive just thought I should clarify these points
Michael

The applet FtpExample does not have a public constructor FtpExample()

Hi
Get this from my Jbuilder, but I got an constructor. What's the problem ?
import ftp.*;
import java.io.*;
import java.applet.*;
class FtpExample implements FtpObserver, Runnable
Thread thread;
FtpBean ftp;
long num_of_bytes = 0;
public FtpExample()
// Create a new FtpBean object.
ftp = new FtpBean();
try {
jbInit();
} catch (Exception ex) {
ex.printStackTrace();
// Connect to a ftp server.
public void connect()
try
ftp.ftpConnect("xxxxxxxxxxxx", "xxxxxxx", "xxxxxxx");
} catch(Exception e)
System.out.println(e);
and more...
.

I thought I should point out a few things
The rule is that every class should have a no
argument constructor that you need to specify
explicitly if you have overloaded the default one.
One of the reaons for that is the following:This is not true, there are many classes that do not have a no argument constructor (For example Integer). Integer is a perfect example of why you would not want a no argument constructor, having an Integer with no value is pointless (theres nothing you can do with it).
public class A {
private final int a ;
public A(int b) {
this.a = b ;
}Now you realize that the variable
n
is getting initialized in the constructor. I see no variable n in the constructor but I take it you mean a
Now if you
refer to
n
somewhere else in you code you get a compile error because
n
might not have been initialized.This is not true, only local variables can cause a
variable (a variable) might not have been initialized
this is because all member fields are initialised with their default valuse. For example all pointers are intitialised to null, ints are intitialised to 0, booleans to false and so on.
>
So you need this:
public class A {
private final int a ;
public A(int b) {
this.a = b ;
public A() {
this(0) ; /* Calls the above constructor with some
default parameter. */
/* You can add some more code below but not above
this(0) */
Of course you know you are never calling the default
constructor but it's still there so you need to
ensure that the variables get initialized if some one
calls it!
As above classes can have no argument constructors
Just add this to your code for example:
public Tennisball() {
this(0, 0, 0, 0, null) ;
} Hope that helped you out!
Thanks,
Nikolas.
PS any duke dollars would be much appreciated as i'm
very poor at the moment :-)I dont mean to be offensive just thought I should clarify these points
Michael

My school does not have a Public iTunes U site...

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Hello drummerbloke,
The following website is where K-12 school districts, universities, and colleges can enroll in iTunes U to distribute courses and collections of education content that anyone can access:
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Best Regards,
DevImran.

Hi Devlmran,
For a more sufficient suggestion for Fackbook control, I would suggest you ask question at FaceBook forum.
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--James
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HERE to participate the survey.

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Hi,
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Thanks
Madani

I already found the solution:
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The type or namespace name 'BusinessData' does not exist in the namespace 'Microsoft.SharePoint' (are you missing an assembly reference?)

I am trying to compile my SharePoint 2010 solution(VS2010) in VS2013 to deploy in SP2013, i have removed all old 14 ref and added 15 ref for microsoft.SharePoint, office.server and other assemblies.
still i am getting "The type or namespace name 'BusinessData' does not exist in the namespace 'Microsoft.SharePoint'
(are you missing an assembly reference?)"
did i miss any step here or any version issue?
any suggestions to resolve
Thanks
S.Venkata Appaji

Hi,
Just confirm that Target Frame work has been changed to 4.5 or not, if not changed it to 4.5 and give it a try. Then also it gives error then check the SP reference, dll properties and check its version(it should be 15.0.).
PS:-You can fine target framework under project properties->Application-> Target Framework.
Regards,
MS

Visual Studio 2012 SharePoint Project Error : The partial project item type does not have a value for this property

Hi,
I am getting this error from visual studio 2012 whenever i try to create the following project types:
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- Web parts
The error is as mentioned below
"The partial project item type does not have a value for this property"
Due to this the when I add above type of items in my project, they show a red cross icon against them.
Please let me know If have you any solution?

Hi
I had same issue. Below is the solution
Installing
"Visual Studio 2012 Update 3" usually solves this problem. (You can download it through microsoft's official site at
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Hansraj Rathva

SP 2010 upgrade fails Error C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\config\WEBCONFIG.ACCSRV.XML, does not have element "configuration/configSections/sectionGroup[@name='SharePoint']"

I was upgrading my SP 2010 server to SP1 but at step 8 i get this error. I cleared configuration cache, moved the file out of the folder, got the same file from other farm where upgrade went smooth, but no success yet. I am at loss.
So i have another farm in SP1. As a fall back option i was thinking to move content database on that server and start hosting site there but now i find out pre sp1 content databse cannot be moved to sp1 farm just through content database migration.
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Adit

Hi ,
How many SharePoint servers do you have? If you have more than one SharePoint server, you need to install SP1 on all servers in the farm.
Make sure you run SharePoint 2010 configuration wizard using “Run As administrator”.
Please check the log to find more information about this issue.
In addition, here is a similar post, please take a look at:
http://sharepointnomad.wordpress.com/2014/02/23/fixing-sharepoint-2010-configuration-wizard-error-webconfig-accsrv-xml-does-not-have-element-configurationconfigsectionssectiongroupnamesharepoint-or-it-is-invalid/
Best Regards,
Wendy
Wendy Li
TechNet Community Support

'Uninstall app for SharePoint': Could not load type 'Microsoft.SharePoint.Administration.SPAppInstanceErrorDetails' from assembly 'Microsoft.SharePoint

Hi there,
I am new to developing with SharePoint and would like to create my first app for SP13 with VS12.
To run SP13 and VS12 on the same virtual machine. The SP Tools Developer I have also installed.
My problem:
I select the Project Wizard from VS12 to create a new app SP13 using provider hosted option. After the project is created I want to directly deploy (F5), and yet I always get the following error:
Error 1
Error occurred in deployment step 'Uninstall app for SharePoint': Could not load type 'Microsoft.SharePoint.Administration.SPAppInstanceErrorDetails' from assembly 'Microsoft.SharePoint, Version=15.0.0.0, Culture=neutral, PublicKeyToken=71e9bce111e9429c'.
0 0
SharePointApp20132106
Does anybody advice?

Please have a look at the below thread
http://social.msdn.microsoft.com/Forums/en-US/7b8a50ed-651d-4aa5-95f0-a551edb95550/sharepoint-hosted-app-deployment-error-in-sharepoint-2013-preview?forum=appsforsharepoint
My Blog- http://www.sharepoint-journey.com|
If a post answers your question, please click Mark As Answer on that post and Vote as Helpful

The type or namespace name 'VisualStudio' does not exist in the namespace 'Microsoft' (are you missing an assembly reference?)

we are using VS 2013. i have created new build definition and run that created build its getting failed and showing error message as "The type or namespace name 'VisualStudio' does not exist in the namespace 'Microsoft' (are you missing an assembly
reference?)" and "The type or namespace name 'WinComboBox, UITestControl, WinTitleBar.....etc' could not be found (are you missing a using directive or an assembly reference?)". in the error log is showing the error number are "error CS0234
& error CS0246".
Actually i have created build for automation execution from MTM lab environment. i have to assign the build to the test plan. once the build is passed , i will assign to the test plan and run with automation options.
if i build the solution its getting successfully build. but when i run the created build definition it show the error message's.
Could you guide me how to resolve the above error's ?
Thanks in Advance...

Hello Divakar Ponnada,
I have checked the error CS0234 from here:
http://msdn.microsoft.com/en-us/library/0e92xd7b.aspx
It means your project cannot find the proper reference to your type "Visual Studio" from the namespace Microsoft.
May I ask this question, does your build definition means something like the following blog described?
http://www.asp.net/web-forms/overview/deployment/configuring-team-foundation-server-for-web-deployment/creating-a-build-definition-that-supports-deployment
"A build definition is the mechanism that controls how and when builds occur for team projects in TFS. "
If that is the problem, may I ask whether your build agent is in the same machine where you build your application?
The build agent will first search for the reference from its local GAC and if it cannot find it, the error like you said will reports. Please manually build your project from your build agent machine to see the result, or install Visual Studio to your build
agent machine. In that way I think your problem may fixed.
Best regards,
Barry
We are trying to better understand customer views on social support experience, so your participation in this interview project would be greatly appreciated if you have time. Thanks for helping make community forums a great place.
Click
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HT1338 My keyboard does not have the number sign: # . How do I get my keyboard to type this?

My keyboard does not have the number sign: # . How do I get my keyboard to type this?

It depends on your keyboard layout.
From the menu bar, select
 ▹ System Preferences... ▹ Keyboard ▹ Keyboard ▹ Show Keyboard & Character Viewers in menu bar
Now select
Show Keyboard Viewer
from the menu with a keyboard icon in the menu bar, towards the right. By pressing modifier keys, you can see what characters correspond to any key combination. You can also produce a character by clicking it in the viewer.

Type 'Microsoft.SharePoint.WebControls.EmbeddedFormField' does not have a public property named 'div' - SharePoint 2013

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