Unable To Use Regular Expression To Find Function Names

Hi,
I am trying to create a regular expression to find function and procedure names without the static designation and the parameter list. Sample source document:
static function test
static function test(i,j)
function test
function test(i,j)
static procedure test
static procedure test(i,j)
procedure test
procedure test(i,j)
For each of the above samples, I would like only the word "test" to be found.
Thanks

I suggest starting with this expression:
^\s*(static\s+)?(function|procedure)\s+(?<NAME>\w+)
Programmatically, the name can be extracted from the group called “NAME”.
The expression can be improved.

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Using regular expressions to find and replace code.

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Using Regular Expressions to Find Quoted Text

I have run into a couple problems with the following code.
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YATArchivist was right about the regular expressions.
I think I've got it but somebody test it if you want. Let me know what you find.
I've included a barebones Position class as well...
import java.util.regex.*;
import java.io.*;
import java.util.*;
@author Joshua A. Logan, Jr.
public class RegexTest
   private static final String SLASH_SLASH = "(//.*)";
   private static final String SLASH_STAR =
                           "(/\\*(?:[^\\*]|(?:\\*(?!/)))+(\\*/)?)";
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                     Pattern.compile( SLASH_SLASH + "|" + SLASH_STAR );
   private static final Pattern QUOTED_STRING_PATTERN =
                  Pattern.compile( "\" ( (?:(\\\\.) | [^\\\"])*+ )     \"",
                                   Pattern.COMMENTS );
   // Breaking the above regular expression down, you'd have:
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   //   ^          ^     ^     ^       ^      ^
   //   |          |     |     |       |      |
   //   1          2     3     4       5      6
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   // 1) The starting quote...
   // Followed by something that is either:
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   //                    any found text at the end.
   //        Note: the text found would be in group(1)
   // 6) Finally, find the ending quote!!
   public static Position [] getQuotedStringPosition( final String text )
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              qm = QUOTED_STRING_PATTERN.matcher( text );
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      int startPos = 0;
      List positions = new ArrayList();
      while ( startPos < len )
         if ( cm.find(startPos) )
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                commEnd   = cm.end();
            // are we starting @ a comment?
            if ( commStart == startPos )
               startPos = commEnd;
            else if ( qm.find(startPos) )
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                   stringEnd   = qm.end(1);
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               if ( stringStart > commStart )
                  startPos = commEnd; // restart search after comment end...
               else if ( (stringEnd > commEnd) ||
                         (stringEnd < commStart) )
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                                              stringEnd) );
                  int quoteEnd = qm.end();
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                  throw new IllegalStateException( "illegal case" );
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                                           qm.start(1),
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How to use regular expression to find string

hi,
who know how to get all digits from the string "Alerts 4520 ( 227550 ) ( 98 Available )" by regular expression, thanks
br, Andrew

Liu,
You can use RegEx as
d+
Whether you are using CL_ABAP_REGEX class then
report zars.
data: regex   type ref to cl_abap_regex,
      matcher type ref to cl_abap_matcher,
      match   type c length 1.
create object regex exporting pattern = 'd+'
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matcher = regex->create_matcher( text = 'Test123tes456' ).
match = matcher->match( ).
write match
You can find more details regarding REGEX and POSIX examples here
http://www.regular-expressions.info/tutorial.html
a®

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Can someone help me with this...I am using Regular expressions to
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REPLACE:
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"Please visit this site <a href='http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747'>http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747</a>. Thank you"
I am using regular expression (http|https)://.+?\\s which marks the end of the url with a white space character.This pattern doesn't work if the URL is located at the end of the string since there will be no space at the end.
For example if the string is "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747" the regex will fail.
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* using String index
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The end of the input is '$' as a regex.
import java.util.regex.*;
public class Prasanna{
public static void main(String[] args){
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Find text using regular expression and add highlight annotation

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Using regular expressions for validating time fields

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Date and time fields are tricky because you have to consider the formattedValue versus the rawValue. If I am going to use regular expressions to do validation I find it easier to make them text fields and ignore the time patterns (formattedValue). Something like this works (as far as my very brief testing goes) for 24 hour time where time format is HH:MM.
// form1.page1.subform1.time_::exit - (JavaScript, client)
var error = false;
form1.page1.subform1.errorMsg.rawValue = "";
if (!(this.isNull)) {
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else {
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form1.page1.subform1.errorMsg.rawValue = "The time must be in the format HH:MM where HH is 00-23 and MM is 00-59.";
form1.page1.subform1.errorMsg.presence = "visible";
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How to write regular expression to find desired string piece *duplicate*

Hi All,
Suppose that i have following string piece:
name:ali#lastname:kemal#name:mehmet#lastname:cemalI need
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SQL> select lst, regexp_replace(lst,'(name:)(.*)(lastname)(.*)','\2',1,1) nm from (
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name:ali#lastname:kemal#name:mehmet#lastname:cemal ali#lastname:kemal#name:mehmet#
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Edited by: mennan on Jul 4, 2010 9:53 PM
thread was posted twice due to chrome refresfment. Please ignore the thread and reply to How to write regular expression to find desired string piece

The approach is to do cartesian join to a 'number' table returning number of records equal to number of names in the string.I have hardcoded 2 but you can use regexp_count to get the number of occurrences of the pattern in the string and then use level <=regexp_count(..... .
See below for the approach
with cte as(
select
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Hello Everybody,
I am using VS 2013 professional, SQL Server 2012.
I am writing database application in c#. I have a table which stores starttime and endtime of operator
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I'm not sure what exactly you're referring to, but I think you may be able to accomplish some of what you want by using triggers, constraints, and column defaults. These are database objects that are defined by using DDL, so have a look at the DDL reference
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In addition you can write SQLCLR objects (e.g. triggers and functions) that can use the .NET regular expression library, which is an implementation of the well-known regular expression library. There are a number of examples of SQLCLR/regular expressions
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How to use regular expressions to generate test data ?

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One for the Tekkies: How to get this output using REGULAR EXPRESSIONS?

How to get the below output using REGULAR EXPRESSIONS??
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FULL_ADDRESS
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Hi,
user12240205 wrote:
... Frank, ʃʃp's method, I understand. But your method, although correct, I find it difficult to understand.
Could you explain how you did this?? What does '.*(\d{5})\D*' and '\1' mean???
Your method is better because it uses only ONE reg expression function. ʃʃp's uses 2.In Oracle 10.2 (I believe) and higher, '\d' is equivalent to '[[:digit:]]', and '\D' is equivalent to '[^[:digit:]]'. I find '\d' and '\D' easier to type, but there's nothing wrong with using '[[:digit:]]' and '[^[:digit:]]'.
'.*' means "0 or more of any character".
'\D*' means "0 or more non-digits".
The whole expression, '.*(\d{5})\D*' means:
a. 0 or more characters (any characters)
b. 5 digits
c. 0 or more non-digits.
'\1' is a Backreference . It means the sub-string that matched the pattern after the 1st '(', up to (but not including) its matching ')'. In this case, that means the sub-string that matched '\d{5}', or b. using the explanation immediately above.
So the entire REGEXP_REPLACE call means "When you see a sub-string consisting of a., follwed immediately by b., followed immedately by c., replace that sub-string with b. alone."

Use regular expressions to extract .llb filename from path

I am trying to be clever (always a dangerous thing) and use a regular expression to extract the name of a library from a filepath converted to a string. Whilst I appreciate there are other ways to do this, regex would appear to be a very powerful neat way, should I be able to get it to work.
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Solved!
Go to Solution.

Hi Matt,
attached you'll find two other options.
Mike
Message Edited by MikeS81 on 04-13-2010 01:30 PM
Attachments:
Path.PNG ‏7 KB

Regular expression in FIND statement

Hi All,
I am writing the regular expressions.
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Hi,
What do you mean by FIND?
If I got it right, you can use a READ statement with KEY f1 f2 etc BINARY SEARCH.Mention all the fields you want in the KEY fields.
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Thanks
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Using Regular Expressions in Numbers 09?

Is there any way to use regular expressions in Numbers 09 in Find & Replace?

kilowattradio wrote:
Is there any way to use regular expressions in Numbers 09 in Find & Replace?
NO !
_Go to "Provide Numbers Feedback" in the "Numbers" menu_, describe what you wish.
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Yvan KOENIG (VALLAURIS, France) vendredi 25 septembre 2009 14:49:49

Unable To Use Regular Expression To Find Function Names

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