Update with Outer Join

Is it possible to do an update that involves an outer join on the table being updated?
Here's what I mean - currently, I have something like:
UPDATE table_1 t1
SET col_1 =
SELECT t2.col_2
FROM table_2 t2
WHERE t2.t1_key = t1.t1_key
WHERE EXISTS
SELECT t2.*
FROM table_2 t2
WHERE t2.t1_key = t1.t1_key
UPDATE table_1 t1
SET col_1 = 0
WHERE NOT EXISTS
SELECT t2.*
FROM table_2 t2
WHERE t2.t1_key = t1.t1_key
Yes, I could do set all of the table_1.col_1 values = 0 first, and then do the first update, but it is inefficient given the number of records in the table that would be updated twice.
Is there a way of combining these two updates into a single update statement?

You could simply use your first update and omit the WHERE EXISTS clause since you want to update all the rows in table_1 anyway.
If the subquery finds a match, it will update with the selected value. Normally, a non-match would set the column to a null but you can solve that with NVL:
SQL> select * from table_1;
              T1_KEY                COL_1
                   1                    1
                   2                    1
                   3                    1
                   4                    1
                   5                    1
                   6                    1
                   7                    1
                   8                    1
                   9                    1
9 rows selected.
SQL> select * from table_2;
              T2_KEY                COL_2
                   1                    9
                   3                    9
                   5                    9
SQL> UPDATE table_1 t1
  2  SET    col_1 = nvl (
  3                       (SELECT t2.col_2
  4                        FROM   table_2 t2
  5                        WHERE  t2.t2_key = t1.t1_key
  6                       ),0
  7                     )
  8  ;
9 rows updated.
SQL> select * from table_1;
              T1_KEY                COL_1
                   1                    9
                   2                    0
                   3                    9
                   4                    0
                   5                    9
                   6                    0
                   7                    0
                   8                    0
                   9                    0
9 rows selected.

Similar Messages

  • Update with Outer Join, round 2

    Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
    However, here is a new version of my problem:
    I have three tables.
    Table_1 has a column that needs to be updated based on values in Table_2 and Table_3.
    Both Table_1 and Table_2 have values used to determine which Table_3 row to use.
    However, not every Table_1 row has a corresponding Table_3 row, in which case the Table_3 value to use is assumed to be 1.
    The tables and corresponding columns are:
    TABLE_1
    value_1 - the value to be updated
    key_2 - a pointer to TABLE_2
    key_3a - a pointer to TABLE_3, or a dummy value if there is no corresponding TABLE_3 record
    TABLE_2
    key_2 - the primary key
    key_3b - a secondary pointer to TABLE_3
    value_2 - a value to be used in calculating TABLE_1.value_1
    TABLE_3
    key_3a - the first part of the unique key
    ley_3b - the second part of the unique key
    value_3 - a value to be used in calculating TABLE_1.value_1
    If there is a row in table_3 that matches the table_1.key_3a and table_2.key_3b values (where table_2.key_2 = table_1.key_2):
    set table_1.value_1 = table_2.value_2 * table_3.value_3
    If there is no such row in table_3:
    set table_1.value_1 = table_2.value_2
    I want to do something like this:
    UPDATE table_1 t1
    SET value_1 =
    SELECT t2.value_2 * NVL(t3.value_3, 1)
    FROM table_2 t2
    LEFT JOIN table_3 t3
    ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
    WHERE t2.key_2 = t1.key_2
    However, Oracle does not allow t1 to be referenced in the ON clause of the outer join.
    (Assume that every key_2 value in table_1 is in table_2 as well - it is only the key_3 value that can be a dummy.)
    If I move "t3.key_3 = t1.key_3" to the WHERE clause, then t1.value_1 is null for rows without the corresponding table_3 value.
    I can do it with a clone of table_1 using ROWIDs:
    UPDATE table_1 t1
    SET value_1 =
    SELECT t2.value_2 * NVL(t3.value_3, 1)
    FROM table_1 t1a
    JOIN table_2 t2
    ON t2.key_2 = t1a.key_2
    LEFT JOIN table_3 t3
    ON (t3.key_3b = t2.key_3b and t3.key_3a = t1a.key_3a)
    WHERE t1a.row_id = t1.row_id
    However, is there an easier way to do this using ANSI joins (i.e. without (+) syntax)?
    I have this feeling I am missing something reasonably obvious here.

    ddelgran wrote:
    Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
    I want to do something like this:
    UPDATE table_1 t1
    SET value_1 =
    SELECT t2.value_2 * NVL(t3.value_3, 1)
    FROM table_2 t2
    LEFT JOIN table_3 t3
    ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
    WHERE t2.key_2 = t1.key_2
    However, Oracle does not allow t1 to be referenced in the ON clause of the outer join.
    (Assume that every key_2 value in table_1 is in table_2 as well - it is only the key_3 value that can be a dummy.)
    If I move "t3.key_3 = t1.key_3" to the WHERE clause, then t1.value_1 is null for rows without the corresponding table_3 value.
    I can do it with a clone of table_1 using ROWIDs:
    UPDATE table_1 t1
    SET value_1 =
    SELECT t2.value_2 * NVL(t3.value_3, 1)
    FROM table_1 t1a
    JOIN table_2 t2
    ON t2.key_2 = t1a.key_2
    LEFT JOIN table_3 t3
    ON (t3.key_3b = t2.key_3b and t3.key_3a = t1a.key_3a)
    WHERE t1a.row_id = t1.row_id
    However, is there an easier way to do this using ANSI joins (i.e. without (+) syntax)?
    I have this feeling I am missing something reasonably obvious here.You might want to refer to my post in your original thread how to use join views in updates. You can use ANSI join syntax there, too:
    Re: Update with Outer Join
    You would end up with something like this (note: untested):
    UPDATE
      SELECT t1.value_1, t2.value_2 * NVL(t3.value_3, 1) as new_val
      FROM table_1 t1
      INNER JOIN table_2 t2 ON (t2.key_2 = t1.key_2)
      LEFT JOIN table_3 t3
      ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
    SET value_1 = new_val;And again the same restrictions regarding key-preserved tables apply as described in the post referred to.
    Regards,
    Randolf
    Oracle related stuff blog:
    http://oracle-randolf.blogspot.com/
    SQLTools++ for Oracle (Open source Oracle GUI for Windows):
    http://www.sqltools-plusplus.org:7676/
    http://sourceforge.net/projects/sqlt-pp/

  • How to poll a blob using db adapter, with outer joins condition

    Hi All,
    We are trying to poll tables which contain column types as long and blob, we are using relationships in adapter and kept outer joins. by this we got select distinct t1.document .....etc
    distinct keyword cannot be used for blobs.
    is there any way to poll these tables having blob column types with outer joins.
    thanks a lot in advance,
    RR

    Hi,
    Procedure will be an explicit Invoke not Polling. If you can alter you design such that your BPEL process instead of polling gets triggered by some external entity (Java, PL/SQL, Scheduler, another BPEL etc.), you can put the data fetching logic in the procedure and call this procedure from your BPEL process to get the data. And your BPEL process is called periodically at an interval by an external entity.
    Also see if you can restrict the duplicate records at the database level itself. Polling, AFAIK, is limited in terms of customization and wouldn't be easy to customize. However, would like to learn a way if someone has.
    Regards,
    Neeraj Sehgal

  • Help requried with outer joins

    Hi All,
    I neeed a query help can any one please help me getting this done,
    for the below query
    select trunc(assumed_time_sql) AS date1,sum(rp.rebate_due)as sum1 from mn_date_dim dd ,mn_rebate_payment rp,mn_prc_program prc,mn_structured_doc sd
    where trunc(assumed_time_sql) in (TO_DATE('01-JUL-10','dd-mon-yy'),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-3),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-6),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-9))----input parameter
    AND trunc(dd.assumed_time_sql)=TRUNC(rp.start_date)
    AND prc.prc_program_id=rp.tiered_rebate_id
    AND sd.struct_doc_id=prc.struct_doc_id
    AND sd.struct_doc_id_num='M0000763'----input parameter
    group by trunc(assumed_time_sql);
    I am getting output as
    date1      sum1
    01-JAN-10      10
    01-APR-10     15
    01-JUL-10     20
    But i want my output to be as
    date1      sum1
    01-JAN-10      10
    01-APR-10     15
    01-JUL-10     20
    01-OCT-09 NULL
    I have tried with outer joins but this didn't help me
    Can any one please give me help in getting this done
    Thanks

    Hi,
    As SB pointed out, you'd better provide tables and data in order to be helped more efficiently.
    Anyway, you may want to investigate the use of NVL and/or DECODE so that you can translate NULL into valid values so they are returned to your select statement.
    HTH,
    Thierry
    Handle:  p78   
    Status Level:  Newbie (10) 
    Registered:  Mar 9, 2009 
    Total Posts:  60 
    Total Questions:  35 (30 unresolved)  Be kind to share your helpful / correct threads with other with marking them as ANSWERED
    Edited by: Urgent-IT on Feb 13, 2011 11:00 AM

  • When I go to update and it gets to the backup part it gives me error -43 and says to complete it it will take all the stuff off my iPod how do I get it to update with out loosing everything on my 64 gb iPod touch

    When I go to update and it gets to the backup part it gives me error -43 and says to complete it it will take all the stuff off my iPod how do I get it to update with out loosing everything on my 64 gb iPod touch

    You have a 1st generation iPod Touch.
    It can be updated to 3.1.3 by purchase. See here Purchasing iOS 3.1 Software Update for iPod touch (1st generation)

  • Generate a where clause with outer join criteria condition: (+)=

    Hi,
    In my search page, I use Auto Customization Criteria mode, and I build where clause by using get Criteria():
    public void initSrpQuery(Dictionary[] dic, String userName) {
    int dicSize = dic.length;
    StringBuffer whereClause = new StringBuffer(100);
    Vector parameters = new Vector(5);
    int clauseCount = 0;
    int bindCount = 1;
    for(int i=0; i < dicSize; i++){
    String itemName = (String)(dic.get(OAViewObject.CRITERIA_ITEM_NAME));
    Object value = dic[i].get(OAViewObject.CRITERIA_VALUE);
    String joinCondition = (String)dic[i].get(OAViewObject.CRITERIA_JOIN_CONDITION);
    String criteriaCondition = (String)dic[i].get(OAViewObject.CRITERIA_CONDITION);
    String criteriaDataType = (String)dic[i].get(OAViewObject.CRITERIA_DATATYPE);
    String viewAttributename = (String)dic[i].get(OAViewObject.CRITERIA_VIEW_ATTRIBUTE_NAME);
    String columnName = findAttributeDef(viewAttributename).getColumnNameForQuery();
    if((value != null) /*&& (!("".equals((String).trim())))*/){
    if(clauseCount > 0){
    whereClause.append(" AND ");
    whereClause.append(columnName + " " + criteriaCondition + " :");
    whereClause.append(++bindCount);
    parameters.addElement(value);
    clauseCount++;
    If I want to generate following where clause:
    select
    ,emp.name
    ,emp.email
    ,emp.salesrep_number
    ,comp.name
    ,gs.srp_goal_header_id
    ,gs.status_code
    ,gs.start_date
    ,gs.end_date
    from g2c_goal_shr_emp_assignments_v emp
    ,jtf_rs_salesreps rs
    ,xxg2c_srp_goal_headers_all gs
    ,cn_comp_plans_all comp
    where 1 = 1
    and rs.salesrep_id = gs.salesrep_id (+)
    and gs.comp_plan_id = comp.comp_plan_id (+)
    and gs.period_year (+) = :1 -- :1 p_fiscal_year
    How can I generate a where clause with outer join : gs.period_year (+) = :1 ? Will I get '(+)=' from get(OAViewObject.CRITERIA_CONDITION)?
    thanks
    Lei

    If you are using SQL-Plus or Reports you can use lexical parameters like:
    SELECT * FROM emp &condition;
    When you run the query it will ask for value of condition and you can enter what every you want. Here is a really fun query:
    SELECT &columns FROM &tables &condition;
    But if you are using Forms. Then you have to change the condition by SET_BLOCK_PROPERTY.
    Best of luck!

  • Group by with outer join

    Group by sum doesn't work with outer join. Can anyone please help me to get it right?
    I've posted some sample data and queries below:
    CREATE TABLE COMPLAINT
      CNO     NUMBER,
      REASON  VARCHAR2(15 BYTE),
      TOTAL   NUMBER
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (1, 'edge', 250);
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (2, 'edge', 250);
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (3, 'brst', 300);
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (4, 'crea', 400);
    COMMIT;
    CREATE TABLE SCOTT.COMPLAINTROLL
      CNO   NUMBER,
      ROLL  VARCHAR2(15 BYTE)
    SET DEFINE OFF;
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (2, 'roll22');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll4');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll3');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll2');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll1');
    COMMIT;
    select * from complaint
    CNO     REASON     TOTAL
    1     edge     250
    2     edge     250
    3     brst     300
    4     crea     400
    select * from complaintroll
    CNO     ROLL
    1     roll1
    1     roll2
    1     roll3
    1     roll4
    2     roll22
    -- total of reason code edge is 500
    select reason,sum(total)
    from complaint c
    group by reason
    REASON     SUM(TOTAL)
    brst     300
    crea     400
    edge     500
    -- total of reason code edge after outer join is 1250
    select reason,sum(total)
    from complaint c,complaintroll cr
    where c.cno=cr.cno(+)
    group by reason
    REASON     SUM(TOTAL)
    brst     300
    crea     400
    edge     1250
    {\code}
    Thanks for reading this post.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

    The problem that you described is simple. The outer join duplicates all the rows from the parent table (complaint). If you want to sum a column from the parent table, then this sum includes all the duplicated rows.
    There are several solutions for this problem.
    A) One had been shown already by Cenutil. Instead of doing an outer join, you can do a subquery in the select clause that delivers the additional information from the detail table.
    SQL> select reason,
       sum(total),
       sum((select count(*) from complaintroll cr where c.cno=cr.cno)) cnt_rolls
    from complaint c
    group by c.reason;
    REASON          SUM(TOTAL)  CNT_ROLLS
    crea                   400          0
    brst                   300          0
    edge                   500          5b) sum in two steps. First sum and count including the join criteria, then use this information to calculate the correct total sum.
    SQL> select reason, sum(stotal), sum(stotal/scount), sum(scount), sum(cnt_rolls)
      2  from (select reason, sum(total) stotal, count(*) scount, count(cr.cno) cnt_rolls
      3         from complaint c
      4         left join complaintroll cr on c.cno=cr.cno
      5         group by reason, c.cno
      6         )
      7   group by reason;
    REASON          SUM(STOTAL) SUM(STOTAL/SCOUNT) SUM(SCOUNT) SUM(CNT_ROLLS)
    crea                    400                400           1              0
    brst                    300                300           1              0
    edge                   1250                500           5              5
    sql> c) another option is to do the left join, but do the aggregation only one time for the parent table. Analytic functions are helpful for that. However since analytic fuinctions can't be used inside an aggregation function, we would again need an inline view.
    SQL> select reason, sum(case when rn = 1 then total end) sum_total, count(*), count(crcno)
      2  from (select row_number() over (partition by c.reason order by c.cno) rn,
      3                   c.*, cr.cno crcno
      4         from complaint c
      5         left join complaintroll cr on c.cno=cr.cno
      6         )
      7  group by reason;
    REASON           SUM_TOTAL   COUNT(*) COUNT(CRCNO)
    brst                   300          1            0
    crea                   400          1            0
    edge                   250          5            5
    SQL> Edited by: Sven W. on Feb 10, 2011 1:00 PM - formatting + column added to 2nd option

  • Trim With Outer Join in where

    Getting an error called Invalid relational Operator
    SELECT DISTINCT t1.recv_order_no, t2.reference_no
    FROM receiving_order t1, receiver_num t2
    WHERE TRIM(t2.reference_no) (+) = TRIM (t1.recv_order_no)
    ORDER BY t2.reference_no ASC
    What I am doing wrong here ?
    Can I use trim fun with outer join ?
    Thanks for help.
    Srini

    Hi Srini,
    I have done this with emp and dept
    Following is an example:
      1  select a.deptno, b.ename
      2     from dept a, emp b
      3*   where trim(a.deptno) = trim(b.deptno(+))
    scott>/
        DEPTNO ENAME
            10 CLARK
            10 KING
            10 GHULAM
            10 MILLER
            20 SMITH
            20 ADAMS
            20 FORD
            20 SCOTT
            20 JONES
            30 ALLEN
            30 BLAKE
            30 MARTIN
            30 JAMES
            30 TURNER
            30 WARD
            40Hope this helps
    Ghulam

  • How to use common object from two tables with out join.

    HI,
    I have two tables called A & B In A table i have the following objects
    1.weekend
    2.S1(measure)
    3.S2(measure)
    4.S3(measure)
    5.S4(measure)
    And In B table i have followning columns
    1.week end
    2.p1(measure)
    3.p2(measure)
    4.p3(measure)
    5.p4(measure)
    Now in universe i created all the measure objects i.e.s1,s2,s3,s4,p1,p2,p3,p4 A.weekend,B.weekend.
    instead of using week end two times i wnt to use only once because this is common in both table.
    if i use join between these tables i am getting values fine
    But With out join is there any thing to do in universe level to create common objects to use from both the tables..I tried using aggregate awareness but while reporting it is taking as two SQL.which is not synchronized.
    Please help me on this ...

    hi,
    Although  Weekend column is present in both tables, by creating a single Object in Universe, Universe can identify relationship with only table referenced in Object Creation.
    So, there will be no identification of relationship with other table measures.
    Obviously, you need to create 2 Weekend objects in Universe (in two classes).
    Case 1: You need not join these two tables in Universe. When you create 2 Queries in WEBI, automatcially Weekend objects are synchronized (if both are of same datatype)
    Case 2: If you join these two tables in Universe, Obviously,
    your SQL may contain Weekend from Table1, measures from Table 2
    or
    your SQL may contain Weekend from Table2, measures from Table 1
    Finally, You need to create 2 objects in Universe. But your query may contain a single Object based on Case 2.
    Regards,
    Vamsee

  • Tabular form from query with outer join destroys the universe!

    Well, maybe just my app...
    At any rate, what I have is a query that pulls RISKS for a project and does a reasonable outer join which joins the latest value from a RISK_HISTORY table. Values for RISK are updated and the value for RISK_HISTORY is changed and a new entry added to the RISK_HISTORY table.
    At least that's how it's supposed to be.
    I was able to do this with a report-with-a-form region by adding an extra update process to do a new insert into RISK_HISTORY but it seems that the tabular form is a bit more work.
    Here's the query I'm using:
    select * from(
    select
    r.RISK_SEQ RISK_SEQ_DISPLAY,
    r.RISK_PRIORITY,
    r.RISK_INFO,
    r.RISK_MITIGATION,
    r.ONGOING_FLAG,
    r.RISK_DATE,
    r.WEEK_GROUP_SEQ,
    r.CREATED_ON,
    r.CREATED_BY,
    r.LAST_MODIFIED_ON,
    r.LAST_MODIFIED_BY,
    rh.STATUS,
    row_number() over (partition by rh.risk_seq order by rh.last_modified_on desc) rn
    from RISK r, WEEK_GROUP w, RISK_HISTORY rh
    where w.PROJECT_SEQ=43
    and r.week_group_seq= w.week_group_seq
    and w.week_index=0
    and rh.RISK_SEQ = r.RISK_SEQ
    ) where rn = 1
    Clicking "Add Row" gets me this:
    Error in mru internal routine: ORA-20001: no data found in tabular form
    Running debug doesn't seem to expose much for me either. Is there a better tact for me to take here?
    Thanks,
    Jon

    Hi Prazy,
    using nvl also didn't solve my problem.Actually my problem is I am having a table a in which I have a column called satus, status has the values like A or I .I have one lookup called MTH_BUYSINESS_FUNCTION in which for lookup_code A I have menaing as Active and for lookup_code I meaning is Inactive.Now in table a for sttaus I have two values one A and one null Now I want to write sql which displayes the meaning for column staus.Result should be Active and null .If I am uisng 1 query which I gave u I am not able to get the 2nd row in my output.If I use 2nd query then I get duplicate rows.
    Thanks ,
    Amrit

  • Error with Outer Join

    So, I have a complex VO that includes two updatable entities. One of these is an outer join. It's an adjustment table which has a 0-1 relation with travel Request table that has an estimated amount.
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    So, how do I keep ADF from inserting a row into the outer join but still update the other entity?
    I'm using JDev 11.1.1.3.0
    Thanks,
    Jet

    Thanks for the feedback. I had to remember to go back and add it to the App Module and juggle the bindings a bit, but I got it sorted out so it doesn't error
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    if I already put a row in then it displays properly and I can change it.
    How do I make it give me a field so I can insert a row when required?

  • Problem with outer join/insert

    I created a test case in scott schema that describes my problem. I use emp table, and I want to have one more table - emp_info - that will store some additional info about employees. Not every employee will have additional info. I can't add a field to emp table - this has to be in an additional table.
    I want to display all the emp's in a swing table, and an info if it exists - of course, using outer join. Further more, I want users to be able to enter info in this same table. If info already exists in the emp_info it will be updated, if not a new record is created.
    I hope you get the picture.
    So, emp_info table is:
    create table emp_info(empno number(4), info varchar2(10))
    ALTER TABLE "SCOTT"."EMP_INFO"
    ADD (CONSTRAINT "PK_EMP_INFO" PRIMARY KEY("EMPNO"))
    ALTER TABLE "SCOTT"."EMP_INFO"
    ADD (CONSTRAINT "FK_EMP_INFO_EMP" FOREIGN KEY("EMPNO")
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    SELECT Emp.EMPNO, Emp.ENAME, Emp.JOB, Emp.MGR, Emp.HIREDATE,
    Emp.SAL, Emp.COMM, Emp.DEPTNO, EmpInfo.EMPNO AS EMPNO1,
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