Using both CPU cores on Zynq?

Question

Hi,
Has anyone tried to use both cpu cores of zynq?
I did not find any example from Xilinx, only related information
in "Zynq-7000 EPP Technical Reference Manual UG585 (v1.2)".
It says that cpu0 must do these two things:
1. Write the address of the application for CPU1 to 0xFFFFFFF0.
2. Execute the SEV instruction to cause CPU1 to wake up and
jump to the application.
Found a "dual cpu demo" example on ARM web-site:
http://www.arm.com/files/pdf/ZC702_DS5_2.pdf
However, the attached source code doesn't do any of the
above two actions. How can the second cpu start then?
Regards,
Pramod Ranade
 

Answer 1

Thank you j, for the suggestions.
I was basically trying with baremetal/baremetal.
First I used "hello world" example for CPU0, it
works fine. Then I added another "hello world",
but now for CPU1. Then I edited it's main() and
removed the initialization part and also the
printf("hello world"). Instead, I simply declare
a pointer to some memory location. And in an
infinite loop, I keep incrementing the value
pointed by that pointer.
The "hello world0" on the other hand has been
modified to write start address of the "hello world1"
to location 0xFFFFFFF0 and then a simple "SEV".
Then the program reads the same memory
location (which is being incremented by CPU1)
and prints it's value to UART. I was expecting that
the value will be seen increasing...but I see it
constant.
For the shared memory location, I tried 0x00700000
which is in DDR RAM. I also tried 0xFFFFE000 which
is in OCM. Neither worked...
I suspect, CPU0 needs to something more than just
writing CPU1 start address to 0xFFFFFFF0 and then
issuing a SEV. But I could not find any more information.
Nor can I find any example that uses both CPU cores.
Regards,
Pramod Ranade