Using Strings and tokens . . .

Question

Hello,
I was wondering if anyone could help me out with this problem(s). I'm designing a java program that (when a statement is typed in by a user) (1) tells you if it's a sentence, question, or exclamation, (2) it gives you the total amount of words in the statement, (3) tells you the longest word in the statement, (4)and also outputs the number of words that contain 1-3 characters. So far, i've been able to figure out how to do (1) and (2), but I'm really stuck on (3) and (4). Could someone please take a look at my program and tell me what I'm doing wrong. Thanks, Ana : )
// ProgramTwo.java Author: Ana
// Program Two. Demonstrates the use of strings and tokens.
import java.util.Scanner;
import java.io.*;
import java.util.StringTokenizer;
public class ProgramTwo
// Prints a string and various mutations of it.
public static void main (String[] args)
Scanner scan = new Scanner (System.in);
System.out.print("Enter a statement >");
String myString = scan.nextLine();
String oneWord;
if (myString.endsWith("!"))
System.out.println("Your statement ends with an exclamation.");
else
if (myString.endsWith("."))
System.out.println("Your statement is a sentence.");
else
System.out.println("Your statement is a question.");
StringTokenizer st = new StringTokenizer(myString);
System.out.println("There are " + st.countTokens() +
               " word(s) in your statement.");
st = new StringTokenizer(myString);
while (st.hasMoreTokens())
oneWord = st.nextToken();
if (oneWord.length() <= 3)
System.out.println(oneWord); //supposed to determine the number of words that contain up to three
//characters
String longestWord = "";
while (st.hasMoreTokens())
String w = st.nextToken();
if (w.length() > longestWord.length())
longestWord = w;
System.out.print(longestWord); // It's supposed to determine the longest word in the statement
}

Answer 1

Hey Guys,
I just wanted to thank all of you who responded to my message. With your help, I was able to figure out a bunch of other stuff. ChuckBing, I replaced some parts like you said and it worked like a charm! KPSeal, you brought up a good point, I doubled checked with my instructor and he said it was Ok for me to leave that part as is. Lutha, thanks for your input. I was just wondering, is Python similar to Java? I've never heard of it before, then again I've never heard of Java until a couple of months ago : ) Anyways, thanks again!! Ana : )
By the way, here's how my program came out.
// ProgramTwo.java Author: Ana
// Program Two. Demonstrates the use of strings and tokens.
import java.util.Scanner;
import java.io.*;
import java.util.StringTokenizer;
public class ProgramTwo
// Prints and groups various word types and amounts.
public static void main (String[] args)
Scanner scan = new Scanner (System.in);
System.out.print("Enter a statement >");
String myString = scan.nextLine();
String oneWord;
if (myString.endsWith("!"))
System.out.println("Your statement ends with an exclamation.");
else
if (myString.endsWith("."))
System.out.println("Your statement is a sentence.");
else
System.out.println("Your statement is a question.");
StringTokenizer st = new StringTokenizer(myString);
System.out.println("There are " + st.countTokens() +
               " word(s) in your statement.");
int shortWordCount = 0;
int medWordCount = 0;
int longWordCount = 0;
String longestWord = "";
String shortestWord = "";
while (st.hasMoreTokens())
oneWord = st.nextToken();
if (oneWord.length() <= 3)
shortWordCount++;
if (oneWord.length() >= 4 && (oneWord.length() <= 6))
medWordCount++;
if (oneWord.length() >= 7)
longWordCount++;
if (oneWord.length() > longestWord.length())
longestWord = oneWord;
if (oneWord.length() < shortestWord.length())
shortestWord = oneWord;
System.out.println("The shortest word is " + shortestWord + ".");
System.out.println("The longest word is " + longestWord + ".");
System.out.println("There are " + shortWordCount + " short words.");
System.out.println("There are " + medWordCount + " medium words.");
System.out.println("There are " + longWordCount + " long words.");