What do symbol ^ and stand for in the following script?
What do symbol *^* and *>>>* stand for in the following script?
Does *(int)* means that (temp ^ (temp >>> 32) return the int format?
long temp = Double.doubleToLongBits(salary);
result = PRIME * result + (int) (temp ^ (temp >>> 32));
return result;
Thank you very much
jetq wrote:
What do symbol *^* and *>>>* stand for in the following script?In Java, this is referred to as "code", script could be confused with Javascript, which is not Java at all.
The previous reply will help you find all you need to know.
Does *(int)* means that (temp ^ (temp >>> 32) return the int format?"format" refers to how a value is converted to text. (Sometimes how it is to be parsed as well)
"(int)" casts the long value to an int value (signed 32-bit)
long temp = Double.doubleToLongBits(salary);
result = PRIME * result + (int) (temp ^ (temp >>> 32));This will treat -0.0 as being different to 0.0. If this is undesirable, you can do something like...
long temp = aDouble != +0.0d ? Double.doubleToLongBits(aDouble) : 0L;
result = PRIME * result + (int) (temp ^ (temp >>> 32));
Similar Messages
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What do the symbol and stand for in the following script? not like displa
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Thank youjverd wrote:
BigDaddyLoveHandles wrote:
But the example, if it's correct, seems to be using >> to redirect stderr, not to append stdout. The OP should identify what OS and what shell they are using.In any unix shell I'm aware of, > is overwrite and >> is append.Which is why he said "seems to be using >> to redirect stderr". Which I read to mean that BDLH also found it to be incorrect but some "corner-product" shell may do this sort of thing (not that I know, or have heard, of any that do). ;-)
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