Why do I get error -17500 when calling a batch file using the call executable step type?

I am calling a batch file using the call executable step type. If the path to the batch file contains a space I get error -17500 and a message stating there was an error in "Post". For example the path to the batch file is "c:\TestWin\Test Files\...\Program.bat" When I run this I get the above mentioned error, however if I change my directory structure so the path is now "c:\TestWin\TestFiles\...\Program.bat" it runs fine. I use the browse feature to find my batch file so it is not me typing in a path incorrectly. I have removed the batch file and I get a different error stating that it couldn't find the file so it appears that for my error it can find the file but can't run it. I am
sure that this has something to do with the fact that batch files are written in DOS but really don't want to resort to changing my directory structure on all my test stations. Is there any way to fix this problem so I can leave a space in my path?

It appears I have figured it out. This was on another computer so I was unaware of how they used their computer. I like you got it to work in the temp directory and in fact got the program.bat file to work as long as I put it under the temp directory, but when I switched out to my TestWin directory it wouldn't work, so I removed everything from the directory except the batch file it self and it work. What I found out after adding files in one at a time is that the person had a file called "Test" with no file extension in there "c:\TestWin\" directory. Removing this file made it work. Putting the file back broke it. So it appeares that when teststand was running it followed the path saw a space and attempted to grab the "Test" file instead of bro
wsing into the "Test Files" directory. If you create a file in your temp directory called "temp" with no file extension you will see the same problem. Thank you for your help.

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error.PNG ‏12 KB
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