2 GB Limit – Please explain the concept

I have more than 35000 photos already uploaded into Revel.
In order to continue to remain a Free member, shall I have to delete all my photos and keep only within 2 GB limit?
Please explain the new concept... Thanks!

You may continue to use revel free of charge with the new model change, however, if you have stored more than 2 GB of files, then you will be unable to upload any additional photos/videos until you delete some files to take you below the limit or subscribe to get unlimited uploads.
Pattie

Similar Messages

  • Hi,  can any body explain the concept of UTILIZATION IN EXCISE

    hi,
    sap gurus,
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    part of that please.
    please explain me on this also
    in direct factory sales from direct factory to customer how utilisation works
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    customer then in this situation  how utilisation works in SAP.
    regards,
    balaji.t

    Dear balaji
    Export under Rebate is the procedure in which the exporters first pay the central excise duty before clearing the goods from the factory and subsequently get it back by applying for rebate after the goods are exported.  They have to apply to the Division or to the Maritime Commissioner (designated exclusively to look after all Export related issues) as the case may be, along with the required documents (usually the Export Promotion copy of the Shipping Bill and Bill of Lading) to prove that their goods had actually been exported.  
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    From SD side, you have to make settings in Logistics-General --> Tax on Goods Movements --> India --> Business Transactions --> Outgoing Excise Invoices --> Maintain Default Excise Groups and Series Groups.
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    thanks
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  • Can any one explain the concept of  Hash ( # ),

    Hi All,
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         #          199001     000.00
                   199002     000.00
                   199003     000.00
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    I have same problem in other Cubes with other Characteristics …
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    Regards,
    Shaik

    Shaik,
    since the thread in the Business Explorer forum has been marked as answered , I assume that this thread can also be closed as answered ... please assign points and close as answered..
    Arun
    other post
    How can I permanently Restrict Hash..in Query level  ( # )

  • Please explain the following terms in SRM

    Hi Forum,
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    Thanks,
    Vivek

    Vivek
    It would be great if you go through http://help.sap.com/saphelp_srm30/helpdata/en/8d/f6a93e08503614e10000000a114084/frameset.htm
    This will help you clear most of your queries.
    Regards,
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  • Please explain,  the job of the  "ASSIGN COMPONENT ".

    Please read this popular example appended below. I am newbie to ABAP.
    At the end of the execution the code is printing 33. Don't get it.
    Please explain,  the job of the  "ASSIGN COMPONENT ". How or why it is printing value 33.  What is the meaning of the statement, "ASSIGN COMPONENT <F2> OF STRUCTURE <F1> TO <F3>." ?
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    COL1 TYPE I VALUE '11',
    COL2 TYPE I VALUE '22',
    COL3 TYPE I VALUE '33',
    END OF LINE.
    DATA COMP(5) VALUE 'COL3'.
    FIELD-SYMBOLS: <F1>, <F2>, <F3>.
    ASSIGN LINE TO <F1>.
    ASSIGN COMP TO <F2>.
    DO 3 TIMES.
    ASSIGN COMPONENT SY-INDEX OF STRUCTURE <F1> TO <F3>.
    WRITE <F3>.
    ENDDO.
    ASSIGN COMPONENT <F2> OF STRUCTURE <F1> TO <F3>.
    WRITE / <F3>.
    11 22 33
    33

    DATA: BEGIN OF LINE,
    COL1 TYPE I VALUE '11',
    COL2 TYPE I VALUE '22',
    COL3 TYPE I VALUE '33',
    END OF LINE.
    DATA COMP(5) VALUE 'COL3'.
    FIELD-SYMBOLS: <F1>, <F2>, <F3>.
    ASSIGN LINE TO <F1>.
    ASSIGN COMP TO <F2>.      "here you are assigning the column name which is COL3 to <f2>.
    DO 3 TIMES.
    ASSIGN COMPONENT SY-INDEX OF STRUCTURE <F1> TO <F3>.
    WRITE <F3>.
    ENDDO.
    ASSIGN COMPONENT <F2> OF STRUCTURE <F1> TO <F3>.
    ASSIGN 'COL3' of structure <f1> to <f3>. "it is equal to above statement.
    WRITE / <F3>.
    11 22 33
    33
    ASSIGN COMPONENT <F2> OF STRUCTURE <F1> TO <F3>. means
    assigining  COL3  value of the structure <f1> to <f3>, so value is 33 , it will be assigned to <f3> .it prints 33.

  • Please explain the use of all the below movt types

    Hi friends,
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    901     GR Area for Production
    902     GR Area External Rcpts
    904     Returns
    910     GI Area General
    911     GI Area for Cost Center
    912     GI Area Customer Order
    913     GI Area - Fixed Assets
    914     GI Area Production Orders
    915     Fixed Bin Picking Area
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    917     Quality Assurance
    920     Stock Transfers (Plant)
    921     Stock Transfers (StLoc)
    922     Posting Change Area
    980     R/3 --> R/2 cumulative
    998     Init.entry of stock bal.
    999     Differences
    Regards,
    Balu R.V

    Hi,
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  • Please explain the magic! (Question)

    The ActionScript snippet below is from the BlaseDS chat sample app. Can someone please explain the magic that declares the chatMessage property of AsyncMessage.body (IMessage.body?) object? It's not in the docs anywhere so I'm guessing it is not built into AsyncMessage. And it's not defined in any of the sample app source files.
    Coming from a strongly-typed development world, seeing a property that apparently has no declaration and is not explicitly instantiated does not pass the sniff-test.
    Thanks.
    <mx:Script>
      <![CDATA[
       import mx.messaging.messages.AsyncMessage;
       import mx.messaging.messages.IMessage;
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        var message:IMessage = new AsyncMessage();
        message.body.chatMessage = msg.text;
        producer.send(message);
        msg.text = "";
       private function messageHandler(message:IMessage):void
        log.text += message.body.chatMessage + "\n";
      ]]>

    Hold your nose, because that is the dynamic "feature" of Actionscript.  Pretty much every class derives from Object (http://livedocs.adobe.com/flash/9.0/ActionScriptLangRefV3/Object.html) which is a dictionary of key-value property pairs.  The {"chatMessage", msg.text as Object} pair is created upon assignment.
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  • TS1503 In the iPhone, please explain the requirements in settings for Apple id, iPhone and iCloud

    In the iPhone, please explain the requirements in settings for Apple id, iPhone and iCloud

    You can use 1 unified Apple ID for iTunes so you don't have to repurchase apps.   That part is fine.
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  • Could someone please explain the difference between Projects Intelligence and Projects Analytics?

    Could someone please explain the difference between Projects Intelligence and Projects Analytics?
    Thanks,
    Adrien

    Older iPads got 3G service and were called Wi-Fi + 3G. Newer iPads can connect to faster cellular networks and those are given different names by the major carrier so to simplify things Apple calls the newer models Wi-Fi + Cellular.
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  • Can any please explain the integration business process between PS and CS

    Dear Guru's
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    Regards,
    Bhanu

    basic steps for such a process would be
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    2) Use CS functionality for warranty and service - set up the work as a functional location on customer site (PM/CS functionality)
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  • A consent for a new eula, please explain the ramification of these new terms

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    (g) You have or will obtain all rights necessary for you to grant Adobe the licenses granted in Section 16 (“Content”), below.
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    You (if you are a Site Owner) or your End Users (if you are a Partner), and/or each such party’s respective licensors, retain ownership of any information, content and/or materials that they submit in the course of using the Services (“Content”); however, Adobe needs certain rights to Content in order to provide the Services. Accordingly, you hereby grant to Adobe and its service providers and designees a worldwide, non-exclusive, transferable, sublicensable (through multiple tiers), royalty-free, perpetual, irrevocable right and license, without compensation to you: to use, reproduce, distribute, adapt (including without limitation edit, modify, translate, and reformat), create derivative works of, transmit, publicly display and publicly perform such Content, in any media now known or hereafter developed.
    please explain the ramification of these new terms
    Thank you,
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    Hi guys,
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    - http://forums.adobe.com/message/4353638
    Kind regards,
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  • Please explain the logic.

    select * from
    from cust b
         LEFT OUTER JOIN
         cust a
         ON
         (a.sales_date+1=b.sales_date)
         WHERE TRIM(TO_CHAR(b.sales_date,'DAY')) IN ('SUNDAY','MONDAY','TUESDAY','WEDNESDAY','THURSDAY','FRIDAY')
         AND b.sales_Date BETWEEN TO_DATE(V_START_DATE,'DD-MON-YY') AND to_date(V_END_DATE,'DD-MON-YY')
         AND a.sales_Date BETWEEN TO_DATE(V_START_DATE,'DD-MON-YY')-1 AND to_date(V_END_DATE,'DD-MON-YY')
    Could someone explain the logic behind the query above?
    Thanks,
    Bhagat

    Bugs wrote:
    select * from
    from cust b
         LEFT OUTER JOIN
         cust a
         ON
         (a.sales_date+1=b.sales_date)
         WHERE TRIM(TO_CHAR(b.sales_date,'DAY')) IN ('SUNDAY','MONDAY','TUESDAY','WEDNESDAY','THURSDAY','FRIDAY')
         AND b.sales_Date BETWEEN TO_DATE(V_START_DATE,'DD-MON-YY') AND to_date(V_END_DATE,'DD-MON-YY')
         AND a.sales_Date BETWEEN TO_DATE(V_START_DATE,'DD-MON-YY')-1 AND to_date(V_END_DATE,'DD-MON-YY')
    Could someone explain the logic behind the query above?
    Thanks,
    BhagatDoes this query even run? It has syntax error. You have lot of post under your name. So by now you must be knowing the usage of {noformat}{noformat} tag. So please use them to format the code.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                           

  • Please explain the following displayed properties

    Hi,
    I tried to change the format of displayname under search result rendering setting. I found the following string for displaying display name:
    <b>rnd:displayname(contentLink/[1;2-3]/alignTop/space-right=30</b>
    please explain how this setting works? for example how that contentLink/[1;2-3] works? is there other setting I can use? like contentLink/1?
    Thanks!
    T.J.

    Hi T.J.
    First read this:
    http://help.sap.com/saphelp_nw04/helpdata/en/79/a1d23e6b2c3d67e10000000a114084/frameset.htm
    There are multiple property renderers available for some properties. Simply using the property name
    instead of the property name with rnd: namespace will typically display the property value in a
    more primitive way than the formatted rnd: version. For instance, the rnd: version for description
    will truncate the text whereas the raw version will not.
    The bracket syntax is used to postion the properties in grid renders like the search results layout sets.
    Regards,
    Darin

  • Please explain the query?

    hello all,
    please explain below query used in solution below, thanks in advance!
    ELECT MAX(P1.ET) AS ST, P2.ST AS ET
    FROM XYZ AS P1
    INNER JOIN XYZ AS P2 ON (P1.ST < P2.ST)
    GROUP BY P2.ST
    HAVING MAX(P1.ET) < P2.ST
    IF OBJECT_ID('XYZ') IS NOT NULL
    DROP TABLE XYZ
    GO
    CREATE TABLE XYZ
    id int identity(1,1),
    ST smalldatetime NOT NULL,
    ET smalldatetime NOT NULL
    GO
    INSERT INTO XYZ (ST, ET)
    VALUES ('2010-01-01 9:00AM', '2010-01-01 10:00AM')
    INSERT INTO XYZ (ST, ET)
    VALUES ('2010-01-01 9:00AM', '2010-01-01 12:00PM')
    INSERT INTO XYZ (ST, ET)
    VALUES ('2010-01-01 1:00PM', '2010-01-01 2:00PM')
    INSERT INTO XYZ (ST, ET)
    VALUES ('2010-01-01 3:00PM', '2010-01-01 5:00PM')
    INSERT INTO XYZ (ST, ET)
    VALUES ('2010-01-01 11:00AM', '2010-01-01 12:00PM')
    GO
    WITH Gaps(Gap) AS
    SELECT COALESCE(SUM(DATEDIFF(MINUTE,ST,ET)), 0)
    FROM (
    SELECT MAX(P1.ET) AS ST, P2.ST AS ET
    FROM XYZ AS P1
    INNER JOIN XYZ AS P2 ON (P1.ST < P2.ST)
    GROUP BY P2.ST
    HAVING MAX(P1.ET) < P2.ST
    ) gaps
    SELECT (
    COALESCE(DATEDIFF(MINUTE, MIN(ST), MAX(ET)), 0)
    - (SELECT Gap FROM Gaps)
    ) / 60.0 TotalHrs
    FROM XYZ

    SELECT MAX(P1.ET) AS ST, P2.ST AS ET
    FROM XYZ AS P1
    INNER JOIN XYZ AS P2 ON (P1.ST < P2.ST)
    GROUP BY P2.ST
    HAVING MAX(P1.ET) < P2.ST
    Finds all of the gaps (that is time that is not in any interval in your original data.  To see how it works, let's look at an example.  I'm going to use data that is a little different than your original data because your data has no gaps. 
    The query still works if you have no gaps, but it is easier to see what it is doing if the data has some gaps.  Also, I'm going to explicitly set the id column instead of making it an identity.  This will make it a little easier to identify each
    row in the following explanation. So the data I'm going to work with is
    CREATE TABLE XYZ
    id int,
    ST smalldatetime NOT NULL,
    ET smalldatetime NOT NULL
    GO
    INSERT INTO XYZ (id, ST, ET)
    VALUES (1, '2010-01-01 9:00AM', '2010-01-01 10:00AM')
    INSERT INTO XYZ (id, ST, ET)
    VALUES (2, '2010-01-01 9:00AM', '2010-01-01 12:00PM')
    INSERT INTO XYZ (id, ST, ET)
    VALUES (3, '2010-01-02 1:00PM', '2010-01-02 2:00PM')
    INSERT INTO XYZ (id, ST, ET)
    VALUES (4, '2010-01-03 3:00PM', '2010-01-03 5:00PM')
    INSERT INTO XYZ (id, ST, ET)
    VALUES (5, '2010-01-03 7:00PM', '2010-01-03 9:00PM')
    Notice that the gaps here are from row 2 to row 3 (12PM on the 1st to 1PM on the 2nd) and row 3 to row 4 (2PM on the 2nd to 3PM on the 3rd) and row 4 to row 5 (5PM on the 3rd to 7PM on the 3rd).  So that's what the above subquery should be finding for
    us.
    To see what a query you don't understand is doing, simplify it to the smallest part you can and see what it returns and then build it up to the final query.  So the simplest thing we can do is just the from clause.  That gives us
    SELECT *
    FROM XYZ AS P1
    INNER JOIN XYZ AS P2 ON (P1.ST < P2.ST)
    /* That gives us the result
    1 2010-01-01 09:00:00 2010-01-01 10:00:00 3 2010-01-02 13:00:00 2010-01-02 14:00:00
    2 2010-01-01 09:00:00 2010-01-01 12:00:00 3 2010-01-02 13:00:00 2010-01-02 14:00:00
    1 2010-01-01 09:00:00 2010-01-01 10:00:00 4 2010-01-03 15:00:00 2010-01-03 17:00:00
    2 2010-01-01 09:00:00 2010-01-01 12:00:00 4 2010-01-03 15:00:00 2010-01-03 17:00:00
    3 2010-01-02 13:00:00 2010-01-02 14:00:00 4 2010-01-03 15:00:00 2010-01-03 17:00:00
    1 2010-01-01 09:00:00 2010-01-01 10:00:00 5 2010-01-03 19:00:00 2010-01-03 21:00:00
    2 2010-01-01 09:00:00 2010-01-01 12:00:00 5 2010-01-03 19:00:00 2010-01-03 21:00:00
    3 2010-01-02 13:00:00 2010-01-02 14:00:00 5 2010-01-03 19:00:00 2010-01-03 21:00:00
    4 2010-01-03 15:00:00 2010-01-03 17:00:00 5 2010-01-03 19:00:00 2010-01-03 21:00:00
    Now we want to Group by P2.ST and get the MAX(P1.ET) and P2.ST, so that gives us
    SELECT MAX(P1.ET) AS ST, P2.ST AS ET
    FROM XYZ AS P1
    INNER JOIN XYZ AS P2 ON (P1.ST < P2.ST)
    GROUP BY P2.ST
    /* Result is
    2010-01-01 12:00:00 2010-01-02 13:00:00
    2010-01-02 14:00:00 2010-01-03 15:00:00
    2010-01-03 17:00:00 2010-01-03 19:00:00
    Now with this sample data there are no rows in the output with MAX(P1.ET) > P2.ST.  But if there was one, you would not want that row because it is not a real gap (obviously, a gap can't start today and end yesterday).  (If you want to see how
    you could get a case like that, add a row 6 to the sample data with a ST of 2010-01-01 7:00PM and an ET of 2010-01-03 9:00PM.)
    So we add a HAVING MAX(P1.ET) < P2.ST to remove those cases.
    That leaves us with all of the gaps.  So then with
    SELECT COALESCE(SUM(DATEDIFF(MINUTE,ST,ET)), 0)
    FROM (
    SELECT MAX(P1.ET) AS ST, P2.ST AS ET
    FROM XYZ AS P1
    INNER JOIN XYZ AS P2 ON (P1.ST < P2.ST)
    GROUP BY P2.ST
    HAVING MAX(P1.ET) < P2.ST
    ) gaps
    we get the total amount of time in all gaps.  Then the final result is just the time from the earliest ST to the latest ET minus the total time from the gap.
    Tom

  • Please explain the scenario

    Experts
    Please explain below scenario
    1.Create a Formula variable with processing by replacement path
    2.Assign it to the key figure associated with the characteristic
    3.Create a new key figure based on the formula variable
    4. Set the exception threshold for this new key figure.
    Thanks In Advance
    Ravi

    Hi,
    <i>2.Assign it to the key figure associated with the characteristic
    3.Create a new key figure based on the formula variable
    4. Set the exception threshold for this new key figure.</i>
    For your second question, i think you are restricting the One characterstic with a keyfigure.
    Go to Rows> right click>New selection--> in this select the characterstic you want, and right click --> restrict with the key figure ,with which you want to.
    3.Go to Rows>right click>New selection--> select the key figure,and restrict with the Formula variable.
    Hope you understand it.
    Assign points if it helps..........

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