2 SD cards with the same file numbers

How do I burn 2 SD cards with the same file numbers. Always says do I want to replace photo with the same number.

Welcome to the Apple Discussions. Rename one set of photos by renaming them in iPhoto with the Photos ➙ Batch Change ➙ Title to Text menu option and then export to the Desktop with the option to use the Title as the new file name.
Or, put one each set of photos in their own folder and put the two folders on the memory card.
Happy Holidays

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    Misio wrote:
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    lol... have to say that macs don't "just work" as they want everyone to believe. plus, if there is any kind of problem you can't try to fix it yourself unlike a PC... but anyway I digress
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    Celtic Mom
    Welcome to the Apple user to user discussion forums
    While I was organizing my photos, I realized there are about 30 or so photos that have the same exact file name as another photo. Example: There are two IMG_1243.jpg, but they are different pictures. They were taken at different times, even different years. I have used more than one camera to import photos. I have changed the name of one of the photos in the Title area in the information section of iPhoto. When I try to put the newly named photo into a folder that has the other IMG_1243, I get a message that says" An older item named "IMG_1243" already exists. Do you want to replace it with the newer one you are moving?"
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    It looks like a finder bug. To replicate, I surf to any website, I right-click on a jpg image, select "Save Image As" and in the window that pops up I type in the filename "000.jpg", I select the folder Pictures, and click on Save.
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    Misio wrote:
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    When I did it a couple of times, always saving image as "000.jpg" from various sources, I ended up with two distinct files named "000" and both in the same folder Pictures.
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    it sounds to me like you saved one file as 000.jpg and the other and 000.jpg.jpg.
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    Message was edited by: trying to fix the table formating sorry it's so unreadable
    Luke22

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    SQL> with t as (select 1 emp_num, 'A' bank, date '2007-08-01' dt from dual union all
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      6             select 3 emp_num, 'A' bank, date '2007-08-07' dt from dual union all
      7             select 3 emp_num, 'C' bank, date '2007-08-08' dt from dual)
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             1 B    02.08.2007
             1 C    03.08.2007
             3 A    07.08.2007
             2 A    05.08.2007
             2 B    04.08.2007
             3 C    08.08.2007
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    SQL> with t as (select 1 emp_num, 'A' bank, date '2007-08-01' dt from dual union all
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      3             select 1 emp_num, 'C' bank, date '2007-08-03' dt from dual union all
      4             select 2 emp_num, 'A' bank, date '2007-08-05' dt from dual union all
      5             select 2 emp_num, 'B' bank, date '2007-08-04' dt from dual union all
      6             select 3 emp_num, 'A' bank, date '2007-08-07' dt from dual union all
      7             select 3 emp_num, 'C' bank, date '2007-08-08' dt from dual)
      8  --
      9             select emp_num, max(bank) keep (dense_rank last order by dt) bank, max(dt) from t
    10             group by emp_num
    11  /
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             2 A    05.08.2007
             3 C    08.08.2007

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