3d view C2W and CO values

I'm trying to set a 3d view to make my 3d model fit to the view's borders. To accomplish that I set the C2W - the translation part of it) and the CO parameters to values I calculate from my model.
As I learned that the camera model in adobe has an initial fixed value for the view angle of 30 degrees I have to calculate the above mentioned values accordingly.
But setting the values to what I calculate does not give me an initial view so that my model fits the viewing window.
So I attach a generated pdf file with an embedded u3d model of a block of 100 mm in a pdf page of 100mmx100mm.
I calculate the CO distance value as:
CO = L/2 / tan(alpha)  with L = 50mm = 0.05 model units and alpha as 15° (= half of view angle) which gives me:
CO = 0.05 / tan(15°)
CO = 0.05 / 0.268 = 0.186
In adobe reader this value is used but the object is display too big.
Using the zoom tool I can fit the model and get a distance value (leaving the viewing angle at 30°) of 0.24.
Can somebody explain if I don't understand the adobe camera model or if my calculation is wrong?
Thanks a lot in advance!

Ok, my answer wasn't quite complete and I am only familiar with the perspective view.
/C2W determines the camera postion within the world coordinate system. The translational component of the C2W matrix must be adjusted in a way that the distance between the camera (30° opening angle) and the cube centre is
0.05 / tan(15°) + 0.05=0.236602540378
as I stated in my previous message. Now, If  the cube's centre is located at (0,0,0) in the world coordinate system, as in your case, then it is easy. Just take the above value and use it as one of the components of the translational vector in C2W. For a front view this would be:
/C2W [-1 0 0 0 0 1 0 1 0 0 -0.236602540378 0]
This will make the cube fit exactly into the viewport. Note, that if the object centre is not located at the origin, the positional vector of the object must be added to the translational vector in the C2W matrix.
Now, /CO needs to be set such that the centre of the camera orbit is in the cube centre to make it revolve around the cube at a fixed distance. Again, use the above value:
/CO 0.236602540378
For parallel projection, the camera may need to be moved onto the cube's surface (/C2W [-1 0 0 0 0 1 0 1 0 0 -0.05 0], /CO 0.05), but I am not sure about this.
Alexander

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