[(409)Conflict] on OCS10g File Upload

When I upload a large file(over 100MB) to workspace, it occurs with an error message [(409)Conflict].
And, When I upload the file by WebDAV, it also occurs an error.

This is probably because you are exceeding the quota on the Workspace Library. Please try uploading a file that is less than your library quota. If you require to request more library quota, please file a TAR on metalink to receive a patch to increase library quota.
Thanks
-Jason

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(409) Conflict. at System.Net.HttpWebRequest.GetResponse() at Microsoft.SharePoint.Client.SPWebRequestExecutor.Execute() at Microsoft.SharePoint.Client.File.SaveBinary(ClientContext context, String serverRelativeUrl,
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type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
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Hi All,
I solved this few minutes after I posted this question. Thought I should share with everybody, just in case some one else need it.
I copied these three files in the folder C:\Sun\AppServer\jdk\jre\lib\ext
1. servelet-api.jar
2. commons-io-1.2.jar
3. commons-fileupload-1.1.1.jar
No need to set any class path.
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Hi,
This is amit Joshi
I have uploaded content using input tag of type file and posted to jsp as multipart/form-data type
in that jsp i am using following code to display the content in browser but only first content is displayed How can i modify it to show all content in the file ..
<html>
<head>
<title>File Upload Display</title>
</head>
<body>
<%
//ServletOutputStream sout=response.getOutputStream();
StringBuilder strBuilder = new StringBuilder();
int count=0;
String f;
f=request.getParameter("filedb");
DBManager dbm = new DBManager();
//dbm.createTable("mms3");
//log.info("In JSP : "+ f);
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if (ServletFileUpload.isMultipartContent(request)){
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while (it.hasNext()){
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%>
Name-value Pair Info:
Field name: <%= fileItemTemp.getFieldName() %>
Field value: <%= fileItemTemp.getString() %>
<%
if (fileItemTemp.getFieldName().equals("filename"))
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if (fileItem!=null){
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%>
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Content type: <%= fileItem.getContentType() %>
Field name: <%= fileItem.getFieldName() %>
File name: <%= fileName %>
<%
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File : <%
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 outputStream=null;
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<%
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%>
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Edited by: Amit_Joshi on Nov 13, 2007 10:58 PM

Well Well Well..
That would not work...
What you have to do is save the uploaded file content on to a location and then pass the fileName as a request parameter to a deidicated which displays the contents of that file.
Just as an example
<html>
<head>
<title>File Upload Display</title>
</head>
<body>
<%
//ServletOutputStream sout=response.getOutputStream();
StringBuilder strBuilder = new StringBuilder();
int count=0;
String f;
f=request.getParameter("filedb");
DBManager dbm = new DBManager();
//dbm.createTable("mms3");
//log.info("In JSP : "+ f);
//dbm.insert_data(f,"mms3");
%>
<%
if (ServletFileUpload.isMultipartContent(request)){
ServletFileUpload servletFileUpload = new ServletFileUpload(new DiskFileItemFactory());
List fileItemsList = servletFileUpload.parseRequest(request);
strBuilder.append("<?xml version=\"1.0\" encoding=\"UTF-8\" ?>").append('\r').append('\n').append("<xpage version=\"1.0\">").append('\r').append('\n');
String optionalFileName = "";
FileItem fileItem = null;
Iterator it = fileItemsList.iterator();
ServletOutputStream outputStream=null;
while (it.hasNext()){
 FileItem fileItemTemp = (FileItem)it.next();
%>
Name-value Pair Info:
Field name: <%= fileItemTemp.getFieldName() %> 
Field value: <%= fileItemTemp.getString() %> 
<%
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%>
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Field name: <%= fileItem.getFieldName() %> 
File name: <%= fileName %> 
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<%
%>
</body>
</html>a sample code snippet for FileServlet.
String fileName = request.getParameter(fileName);
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However,this is not the recommended way of doing this make use of MVC pattern.Would be a better approach.
you might think of googling on this and can findout what is the best practise followed for problems of this sort
REGARDS,
RaHuL

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Hi,
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Re: File Upload Problem
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Dear friend,
i am also trying to upload using the common file upload.
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