5508 to join with 2 Wism's as backup
Dear Folks,
I have a facility, where all the access points almost 250 of them are connected to two WisM's (One in each core switch ) . They are running in 6.0.199 firmware . These two WisM's are managed by WCS , which is running 6.0.188.
As i need to add more access points and to make fully redundant , 5500 controller was ordered and it has with firmware 7.0 installed. Couple of queries related with it .
1. Can 5500 be added in the WLC group, so that existing Access Points can be configured to use primary controller as 5500 and secondary / tertiary controller as WISM ?
2. Will 5500 be able to be detected by WCS , as the version of 5500 is 7.0 and WCS version is 6.0.188 ?
3. As WCS was already deployed and live, is it possible to upgrade, if the client has support contract like SUSA ?
Appreciate your kind help and support .
Regards,
SID
Thanks Scott for your valuable reply .
Two more queries please,
1. I saw in 5500 controller with two images installed by default, one is 7.0 and other one is backup recovery image , which is 6.0.199 , can we boot the controller with that image , or we should directly downgrade it from 7.0 to 6.0.199
2. With an existing service contract, is it possible to reinstall WCS with an upgraded version, as i understand , license would be tagged with the Computer's hostname , right
Similar Messages
-
Problem with outer join with filter on join column
Hi,
In physical layer I have one dimension and two facts, and there's an outer join between the facts.
dim_DATE ,
fact_1 ,
fact_2
Joins:
dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
select fact1.X, fact2.Y
from
Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
and Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
The filter on Fact_2.DATE effectively replaces outer join with inner.
Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
Thanks in advance,
Alex
Edited by: AM_1 on Aug 11, 2009 8:20 AMIf you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
* create in your physical layer for each fact table the joins with the dimension
* create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
Cheers
Nico -
How Can We Tune the Joins with "OR" Caluse ?
Hi
We've identified one Query in one of Our PL/SQL Stored Procedure which is taking huge time to fetch the records. I have simulated the problem as shown below. The problem Is, How can i tune the Jions with "OR" Clause. i have tried replacing them with Exists Caluse, But the Performance was not much was expected.
CREATE TABLE TEST
(ID NUMBER VDATE DATE );
BEGIN
FOR i IN 1 .. 100000 LOOP
INSERT INTO TEST
VALUES
(i, TO_DATE(TRUNC(DBMS_RANDOM.VALUE(2452641, 2452641 + 364)), 'J'));
IF MOD(i, 1000) = 0 THEN
COMMIT;
END IF;
END LOOP;
END;
CREATE TABLE RTEST1 ( ID NUMBER, VMONTH NUMBER );
INSERT INTO RTEST1
SELECT ID, TO_NUMBER(TO_CHAR(VDATE,'MM'))
FROM TEST ;
CREATE TABLE RTEST2 ( ID NUMBER, VMONTH NUMBER );
INSERT INTO RTEST2
SELECT ID, TO_NUMBER(TO_CHAR(VDATE,'MM'))
FROM TEST;
CREATE INDEX RTEST1_IDX2 ON RTEST1(VMONTH)
CREATE INDEX RTEST2_IDX1 ON RTEST2(VMONTH)
ALTER TABLE RTEST1 ADD CONSTRAINT RTEST1_PK PRIMARY KEY (ID)
ALTER TABLE RTEST2 ADD CONSTRAINT RTEST2_PK PRIMARY KEY (ID)
SELECT A.ID, B.VMONTH
FROM RTEST1 A , RTEST2 B
WHERE A.ID = B.ID
AND ( (A.ID = B.VMONTH) OR ( B.ID = A.VMONTH ) )
BEGIN
DBMS_STATS.gather_table_stats(ownname => 'PHASE30DEV',tabname => 'RTEST1');
DBMS_STATS.gather_table_stats(ownname => 'PHASE30DEV',tabname => 'RTEST2');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST1_IDX1');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST2_IDX2');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST1_IDX2');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST2_IDX1');
END; Pls suggest !!!!!!! How can I tune the Joins with "OR" Clause.
Regards
RJI don't like it, but you could use a hint:
SQL>r
1 SELECT A.ID, B.VMONTH
2 FROM RTEST1 A , RTEST2 B
3 WHERE A.ID = B.ID
4* AND ( (A.ID = B.VMONTH) OR ( B.ID = A.VMONTH ) )
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=94 Card=2 Bytes=28)
1 0 TABLE ACCESS (BY INDEX ROWID) OF 'RTEST2' (Cost=94 Card=1 Bytes=7)
2 1 NESTED LOOPS (Cost=94 Card=2 Bytes=28)
3 2 TABLE ACCESS (FULL) OF 'RTEST1' (Cost=20 Card=100000 Bytes=700000)
4 2 BITMAP CONVERSION (TO ROWIDS)
5 4 BITMAP AND
6 5 BITMAP CONVERSION (FROM ROWIDS)
7 6 INDEX (RANGE SCAN) OF 'RTEST2_PK' (UNIQUE)
8 5 BITMAP OR
9 8 BITMAP CONVERSION (FROM ROWIDS)
10 9 INDEX (RANGE SCAN) OF 'RTEST2_IDX1' (NON-UNIQUE)
11 8 BITMAP CONVERSION (FROM ROWIDS)
12 11 INDEX (RANGE SCAN) OF 'RTEST2_PK' (UNIQUE)
Statistics
0 recursive calls
0 db block gets
300332 consistent gets
0 physical reads
0 redo size
252 bytes sent via SQL*Net to client
235 bytes received via SQL*Net from client
2 SQL*Net roundtrips to/from client
0 sorts (memory)
0 sorts (disk)
2 rows processed
SQL>SELECT /*+ ordered use_hash(b) */ A.ID, B.VMONTH
2 FROM RTEST1 A, RTEST2 B
3 WHERE A.ID = B.ID AND(A.ID = B.VMONTH OR B.ID = A.VMONTH)
4 ;
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=175 Card=2 Bytes=28)
1 0 HASH JOIN (Cost=175 Card=2 Bytes=28)
2 1 TABLE ACCESS (FULL) OF 'RTEST1' (Cost=20 Card=100000 Bytes=700000)
3 1 TABLE ACCESS (FULL) OF 'RTEST2' (Cost=20 Card=100000 Bytes=700000)
Statistics
9 recursive calls
0 db block gets
256 consistent gets
156 physical reads
0 redo size
252 bytes sent via SQL*Net to client
235 bytes received via SQL*Net from client
2 SQL*Net roundtrips to/from client
0 sorts (memory)
0 sorts (disk)
2 rows processed -
Outer Join with Where Clause in LTS
HI all,
I have a requirement like this in ANSI SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1 left outer join product_group p2 on p1.product_id = p2.product_id
and p2.product_group = 'NEW'
In Regular SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1, product_group p2
WHERE p1.product_id *= p2.product_id and p2.product_group = 'NEW'
In OBIEE, I am using a left outer join between these two in Logical table Source, and also, Gave
p2.product_group = 'NEW' in WHERE clause of LTS.
This doesn't seem to solve purpose.
Do you have any idea how to convert WHERE clause in physical query that OBIEE is generating to something like
product p1 left outer join product_group p2 on p1.product_id = p2.product_id AND p2.product_group = 'NEW'
I am using Version 10.1.3.4.1
Creating an Opaque view would be my last option though.Hello
I have read your post and the responses as well. and I understand that you have issues with the Outer Join with where Clause in LTS.
Try this solution which worked for me (using your example ) -
1. In the Physical Layer created a Complex join between PRODUCT and PRODUCT_GROUP tables and use this join relationship :
PRODUCT.PROD_ID = PRODUCT_GROUP.PROD_ID AND PRODUCT_GROUP.GROUP_NAME = 'MECHANICAL'
2. In the General Tab of PRODUCT table LTS add PRODUCT_GROUP table and select Join Type as Left Outer Join.
3. Check Consistency and make sure there are no errors .
when you run a request you should see the following query generated -
select distinct T26908.PROD_ID as c1,
T26908.PROD_NAME as c2,
T26912.GROUP_NAME as c3
from
PRODUCT T26908 left outer join PRODUCT_GROUP T26912 On T26908.PROD_ID = T26912.PROD_ID and T26912.GROUP_NAME = 'MECHANICAL'
order by c1, c2, c3
Hope this works for you. If it does please mark this response as 'Correct' .
Good Luck. -
How do I join with the network that is in our apt? The iPod asks for a password and I do not have one. What to do?
You have to enter the correct password to connect.
Ask the person who setup the router for the password. -
Self join with fact table in Obie 10G
I am a newbie to obiee.I have a development requirement as follows-
I need to find supervisors designation with the existing star RPD design. explanation is below
DIM_Designation(Desig_Wid)
|(Row_wid)
|
DIM_EMPLOYEE--------WORKER_FACT------------DIM_Supervisor
(Row_Wid)-----------------(Employee_Wid)
(Supervisor_Wid)------------(Row_Wid)
3 dimension is joined to fact to get employee, his supervisor and designation of employee. now i want to get the supervisor's designation? how is it possible? already employee and supervisor dimension is same W_employee_d table joined with fact as alias DIM_EMPLOYEE and DIM_SUPERVISOR. how to do self join with fact to get supervisor's designation. i do not have any supervisor_desig_wid in fact table. any help is deeply appreciated.Yes,Duplicate the fact table create a primary key on the newly fact table alias dimension table.So you can ur data modelling as usual.
-
Maximum number of tables that can be outer joined with one table in a query
Hi All,
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
Thanks,
Srinisrinu2 wrote:
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
There is no limit to the number of tables you can outer join as long as you join them correctly.
SQL> with a as
2 (
3 select 1 id, 2 b_key, 3 c_key from dual union all
4 select 2 id, 1 b_key, 4 c_key from dual union all
5 select 3 id, 3 b_key, 1 c_key from dual union all
6 select 4 id, 4 b_key, 2 c_key from dual
7 ),
8 b as
9 (
10 select 1 id, 1 c_key2 from dual union all
11 select 2 id, 5 c_key2 from dual union all
12 select 3 id, 3 c_key2 from dual union all
13 select 4 id, 2 c_key2 from dual
14 ),
15 c as
16 (
17 select 1 key1, 1 key2, '1-1' dta from dual union all
18 select 1 key1, 2 key2, '1-2' dta from dual union all
19 select 1 key1, 3 key2, '1-3' dta from dual union all
20 select 1 key1, 4 key2, '1-4' dta from dual union all
21 select 2 key1, 1 key2, '2-1' dta from dual union all
22 select 2 key1, 2 key2, '2-2' dta from dual union all
23 select 2 key1, 3 key2, '2-3' dta from dual union all
24 select 2 key1, 4 key2, '2-4' dta from dual union all
25 select 3 key1, 1 key2, '3-1' dta from dual union all
26 select 3 key1, 2 key2, '3-2' dta from dual union all
27 select 3 key1, 3 key2, '3-3' dta from dual union all
28 select 3 key1, 4 key2, '3-4' dta from dual union all
29 select 4 key1, 1 key2, '4-1' dta from dual union all
30 select 4 key1, 2 key2, '4-2' dta from dual union all
31 select 4 key1, 3 key2, '4-3' dta from dual union all
32 select 4 key1, 4 key2, '4-4' dta from dual
33 )
34 select d.a_id, d.b_id, c.key1 as c_key1, c.key2 as c_key3, c.dta
35 from
36 c,
37 (
38 select
39 a.id as a_id, b.id as b_id, a.c_key, b.c_key2
40 from a, b
41 where a.b_key = b.id
42 ) d
43 where d.c_key = c.key1 (+)
44 and d.c_key2 = c.key2 (+);
A_ID B_ID C_KEY1 C_KEY3 DTA
3 3 1 3 1-3
4 4 2 2 2-2
2 1 4 1 4-1
1 2
SQL> -
Replacing a inner join with for all entries
Hi Team,
In a already developed program I am replacing a inner join with select query follow up with for-all-entris and passing the data to final internal table but in both the case the result should be same then only my replacement will be correct. But my no records in both cases differs. This happening because when i am selecting data from first data base table is 32 lines. then I am doing fo-all-entries moving all the duplicate entries then the no records are four. but in final internal table i am looping the first internal table. So in final internal table the no of records are 32. But in inner join query the records are 16.So please let me know how resolve this issue?
Thanks and REgards
DeepaHi Thomas,
Thanks for ur suggestion.
The solved that in below.
In select query I did not change anything The way I had written the code was correct.
I think many of us know how to write that how to make the performance better in that way.
I made the change when I transfered the to final internal table.
The original Inner join code:
select a~field1 a~field2 a~field3 b~field2 b~field3 b~field4
from dbtab1 as a inner join dbtab2 as b
on a~field1 = b~field1 into it_final where
a~field1 in s_field1. [Field1 in both the table are key field]
Before code:
Sort itab1 by key-fields.
sort itab2 by keyfields.
loop at itab1 into wa1.
move: wa1-field1 to wa_final-field1,
wa1-field2 to wa_final-field2,
wa1-field3 to wa_final-field3.
read table itab2 into wa2 witk key field1 = wa1-field1 binary search.
if sy-subrc = 0.
move : wa2-field2 to wa_final-field4,
wa2-field3 to wa_final-field5,
wa2-field4 to wa_final-field6.
append wa_final to it_final.
endif.
Clear : wa1, wa2, wa_final.
endloop.
In this case if the one key fieild value is not present there in second internal table but its there in first internal table still it will read that row with 2nd internal values having zeroes. Normally what does not happen in inner join case if the key field value will same in both the case ,then that will fetch only those rows.
Changed Code
loop at itab1 into wa1.
read table itab2 into wa2 witk key field1 = wa1-field1 binary search.
if sy-subrc = 0.
move: wa1-field1 to wa_final-field1,
wa1-field2 to wa_final-field2,
wa1-field3 to wa_final-field3.
move : wa2-field2 to wa_final-field4,
wa2-field3 to wa_final-field5,
wa2-field4 to wa_final-field6.
append wa_final to it_final.
endif.
Clear : wa1, wa2, wa_final.
endloop.
In this case the values will read to final internal table if both key field matches.
With Regards
Deepa -
INNER JOIN with FOR ALL ENTRIES IN Performance ?
I am using following the following <b>Select using Inner join with For All Entries in.</b>
SELECT kebeln kebelp kvbeln kvbelp
FROM ekkn AS k INNER JOIN ekbe AS b ON kebeln = bebeln
AND kebelp = bebelp
INTO TABLE gi_purchase
FOR ALL ENTRIES
IN gi_sales
WHERE k~mandt EQ sy-mandt
AND k~vbeln EQ gi_sales-vbeln
AND k~vbelp EQ gi_sales-posnr
AND b~budat EQ p_date.
If i am not doing inner join then I will have to do 2 select with for all entries in on ekkn and ekbe tables and then compare them.
<b>I want to know which one has better performance
Inner join with for all entries in
or
2 Selects with for all entries in</b>the join is almost aways faster:
<a href="/people/rob.burbank/blog/2007/03/19/joins-vs-for-all-entries--which-performs-better">JOINS vs. FOR ALL ENTRIES - Which Performs Better?</a>
<a href="http://blogs.ittoolbox.com/sap/db2/archives/for-all-entries-vs-db2-join-8912">FOR ALL ENTRIES vs DB2 JOIN</a>
Rob -
Inner Join with For All Entries - Performance ?
I am using following the following <b>Select using Inner join with For All Entries in.</b>
SELECT kebeln kebelp kvbeln kvbelp
FROM ekkn AS k INNER JOIN ekbe AS b ON kebeln = bebeln
AND kebelp = bebelp
INTO TABLE gi_purchase
FOR ALL ENTRIES
IN gi_sales
WHERE k~mandt EQ sy-mandt
AND k~vbeln EQ gi_sales-vbeln
AND k~vbelp EQ gi_sales-posnr
AND b~budat EQ p_date.
If i am not doing inner join then I will have to do 2 select with for all entries in on ekkn and ekbe tables and then compare them.
<b>I want to know which one has better performance
Inner join with for all entries in
or
2 Selects with for all entries in</b><b></b>An Inner Join with for all entries should be done if you add this....
IF NOT gi_sales[] IS INITIAL.
SELECT k~ebeln k~ebelp k~vbeln k~vbelp
FROM ekkn AS k INNER JOIN ekbe AS b ON k~ebeln = b~ebeln
AND k~ebelp = b~ebelp
INTO TABLE gi_purchase
FOR ALL ENTRIES
IN gi_sales
WHERE k~mandt EQ sy-mandt
AND k~vbeln EQ gi_sales-vbeln
AND k~vbelp EQ gi_sales-posnr
AND b~budat EQ p_date.
ENDIF.
Also, while you use an index or the complete key for the SELECT, your not going to suffer from lack of performance -;)
Greetings,
Blag. -
Oracle 8i, left join with conditional
Coming from the MySQL world, I'm trying to do a left join with a
condition:
select c.givenname,c.surname,c.userid,r.letternr
from cand c,responses r
where (c.userid=r.username(+))
and
c.activeprofile=1
No problem whatsoever.
If there is no corresponding "response" in R for a given
candidate, I get a NULL return for R.letternr.
However, there is a flag in R, called "VISIBLE" that I wish to
use to mean "Don't count this entry in R". R.VISIBLE=0 means
that the response is not active/present/visible/valid.
Am I making any sense? :-)If you don't want to display a row with a null value for
r.letternr when r.visible = 0, then:
SELECT c.givenname,
c.surname,
c.userid,
r.letternr
FROM cand c,
responses r
WHERE c.userid = r.username (+)
AND c.activeprofile = 1
AND r.visible != 0
Or, if you do want to display a row with a null value for
r.letternr when r.visible = 0, then:
SELECT c.givenname,
c.surname,
c.userid,
r.letternr
FROM cand c,
responses r
WHERE c.userid = r.username (+)
AND c.activeprofile = 1
AND r.visible (+) != 0 -
SQL JOIN with BPM sql component
Hello friends.
How to use SQL JOIN with BPM sql component?
The tables objects are created but the joined tables belong to different sql components .
I tried something like that, but a error "table doesn't exist" occours.
Ex:
for each element in
SELECT imuImovelCd
FROM IMOVEIS_URBANOS,
Integracao.FGLP.IMOVEIS_PRE_EDITAIS
WHERE IMOVEIS_URBANOS.imuImovelCd = Integracao.FGLP.IMOVEIS_PRE_EDITAIS.ipeImuCd
AND Integracao.FGLP.IMOVEIS_PRE_EDITAIS.ipePedNr = 1
AND Integracao.FGLP.IMOVEIS_PRE_EDITAIS.ipePedAa = 2008
do
extend this.imoveis using cdImovel = element.imuimovelcd,
nrImovel = call(DEC_ENDERECO, codimovel : element.imuimovelcd, tipoimovel : 1)
end
Edited by: user9008295 on 26/01/2010 05:19ok, ok you are right.
When I try use SQL Statement to make a JOIN with 2 tables on different sql objects, BPM returns "table dosn't exists".
So.... I change my code. I dont know if this is the best way to do, but... i hope u, or everyone, can help me to do a best work.
This code works fine.
for each element in
SELECT ipeImuCd
FROM Integracao.FGLP.IMOVEIS_PRE_EDITAIS
WHERE Integracao.FGLP.IMOVEIS_PRE_EDITAIS.ipePedNr = 1
AND Integracao.FGLP.IMOVEIS_PRE_EDITAIS.ipePedAa = 2008
do
for each element2 in
SELECT imuImovelDv
FROM IMOVEIS_URBANOS
WHERE imuImovelCd = element.ipeImuCd
do
extend this.imoveis using cdDvImovel = String(element2.imuImovelDv),
cdImovel = Decimal(element.ipeImuCd),
endereco = call(DEC_ENDERECO, codimovel : element.ipeImuCd, tipoimovel : 1)
end
end
Thx a lot!!! -
Outer join With a constant value
Hi all,
In one of query i have found out that the outer join with a constant value like
to_currency(+)='USD'
to_currency is a column name in a table.can any one please explain this outer join condtn.
Thanks in advance
SenthilHallo,
if you write var (+) = constant
var can be equal constant, and also can be null
Compare these 2 queries
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno(+) = 10EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7369 SMITH CLERK 7902 17-Dez-1980 800 20
7499 ALLEN SALESMAN 7698 20-Feb-1981 1600 300 30
7521 WARD SALESMAN 7698 22-Feb-1981 1250 500 30
7566 JONES MANAGER 7839 2-Apr-1981 2975 20
7654 MARTIN SALESMAN 7698 28-Sep-1981 1250 1400 30
7698 BLAKE MANAGER 7839 1-Mai-1981 2850 30
7782 CLARK MANAGER 7839 9-Jun-1981 2450 10
7788 SCOTT ANALYST 7566 19-Apr-1987 3000 20
7839 KING PRESIDENT 17-Nov-1981 5000 10
7844 TURNER SALESMAN 7698 8-Sep-1981 1500 0 30
7876 ADAMS CLERK 7788 23-Mai-1987 1100 20
7900 JAMES CLERK 7698 3-Dez-1981 950 30
7902 FORD ANALYST 7566 3-Dez-1981 3000 20
7934 MILLER CLERK 7782 23-Jan-1982 1300 10
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno = 10 EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7782 CLARK MANAGER 7839 9-Jun-1981 2450 10
7839 KING PRESIDENT 17-Nov-1981 5000 10
7934 MILLER CLERK 7782 23-Jan-1982 1300 10
As you can see, this (+) is very important
Regards
Dmytro -
I have a very complicated query to construct that requires the use of 'AND', 'OR', and Outer Joins. Oracle's 9i documentation says you can't use an outer join with an 'OR'.
Can you suggest how I may return the correct records under the following conditions. There are 3 tables to join. Table A, Table B, and Table C. Tables A & B join with an = to common fields. The problem is with Table C.
The way the application was designed, it has to track a parent and child relationship. As such, the field to relate may exist in 1 of 2 fields. Let's see if I can draw it out for you.
Table A - Record 1
(ID = 1)
Table B - Record 1
(ID =1 [this relates to Table A.ID]
PID = 12345
CID = 67899
Site = A)
Table C - Record 1
(PID = 12345 [this relates to Table B.PID]
CID = 67899
Site = A)
Table C - Record 2
(PID = 67899 [This relates to Table B.CID]
CID = 12345
Site = A)
Now, I need to relate Table A to Table B where A.ID = B.ID AND
((B.PID = C.PID AND B.CID = C.CID)
OR
(B.CID = C.PID AND B.PID = C.CID))
AND
B.SITE = C.SITE
There may or may NOT be related records in Table C. That's the problem. This is where I need the outer join to get the all the records of the 1st two joins and only those that apply from the last join.
Your help will be greatly appreciated.I'd create two queries, a join from b to c in each of those manners and then UNION ALL the results together.
drop table junk_a;
create table junk_a (
id number );
drop table junk_b;
create table junk_b (
id number,
pid number,
cid number,
site varchar2(80) );
drop table junk_c;
create table junk_c (
pid number,
cid number,
site varchar2(80) );
insert into junk_a values (1);
insert into junk_b values (1, 12345, 67899, 'A');
insert into junk_c values (12345, 67899, 'A');
insert into junk_c values (67899, 12345, 'A');
commit;
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.pid(+) = b.pid
AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.cid(+) = b.pid
AND c.pid(+) = b.cid;
SELECT a.id,
bc.pid,
bc.cid,
bc.site,
bc.site_c
FROM junk_a a,
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.pid(+) = b.pid
AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.cid(+) = b.pid
AND c.pid(+) = b.cid
) bc
WHERE bc.id(+) = a.id; -
I have written the below query, our requirement is, Some employees have "Transport Allowance" but not "Project Allowance". For this, I tried to use OUTER JOIN with this query. But this query takes long time and failed. The following query works fine if the employee has both "Transport Allowance" and "Project Allowance" (without outer join) Now, I also need to retrieve the employees who have "Transport Allowance" but not "Project Allowance". How can I retrieve it?
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_types_x petf2
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entries_f peef2
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_element_entry_values_x peev2
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
,apps.pay_input_values_x pivf2
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance.I am using sames tables with alias to retrieve the columns values from the same table.
Here is my query.
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance.
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