A difficult problem with php code and sql code

Question

it's good place to visit(Paged Result Sets with PHP and Oracle)
http://www.oracle.com/technology/pub/articles/oracle_php_cookbook/fuecks_paged.html
maybe below part php code could not be used in above address's php code.
if((isset($l_company) and $l_company != $rows['COMPANY']) or empty($stmt) and empty($total_pages) ) {
echo "<tr bgcolor='#CCFFCC'>";
echo "<td colspan= 3 align='center'>".$l_company."</td>";
echo "<td >".$totalcomany." </td>";
$totalcomany = 0;
echo "<td > </td>";
echo "</tr>";
$l_company = $rows['COMPANY'];
because the same company in one page could calculate sum while if
the same company in two pages could not do that.
and what do you think of ?
thanks !

Answer 1

Hi,
this is because your sql-statement selects only the rows, you need to build this one page.
Neither php nor the given result from your query knows about data wich will be part of the result of another page.
Greetings from Hamburg
Thorsten Körner