Adding a cloumn in a fact table which has pctfree 0

Hi,
I have a partitioned fact table with millions of rows and pctfree 0. Now I want to add a new column in this table (without any default value in the new column, so new column is a null). How will it affect (because of pctfree 0) the performance of old data retrieval for reports.
Thanks,
Ravi

Hello,
If this is Berkeley DB what is the platform and version? If not this is not the
right forum. You might try the SQL and PL/SQL forum at:
PL/SQL
Thank you,
Sandra

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Hi All,
I have to insert the data into a SQL SERVER 2005 Database table.
I am able to insert the data into a normal SQL Server table.
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Had anybody tried this??
There are some SRs on this issue, Oracle agreed that it is a bug. I am wondering if there is any workaround from any one of you (refer Insert in MS-SQL database table with IDENTITY COLUMN
Thanks
V Kumar

Even I had raised a SR on this in October 2008. But didn't get any solution for a long time, finally I had removed the identity column from the table. I can't to that now :).
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If you are running SQL Server as your database platform run this query:
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SQL> select *
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3 /
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Message was edited by:
guru paran
Changed the table name.

You probably want to help us out with all your ddl:
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v_type my_type := my_type();
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check this :
batch@DOLN1> create table "from" ("select" varchar2(10));
Table created.
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Name Null? Type
select VARCHAR2(10)
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ERROR at line 1:
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0 rows updated.
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Commit complete.
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1 row updated.
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select
World

Adding a cloumn in a partitioned table having pctfree 0

Hi,
I have a partitioned fact table with millions of rows and pctfree 0. Now I want to add a new column in this table (without any default value in the new column, so new column is a null). How will it affect (because of pctfree 0) the performance of old data retrieval for reports.
Thanks,
Ravi

Alter Table <tab_name> add <column_name> datatype;
The column will added @ last
Edited by: LPS on Jul 13, 2011 11:16 PM

Adding Dimension field ($) in measures (fact) table in logical layer

Hi,
I have a field (amount) in the dimension table. I would like to add this field in the fact table at the logical layer. Dimension table and fact table had physical joins. Can I add into fact table and still do aggregation on that field based on the other dimensions linked to fact table. I working on Siebel Analytics version 7.8. Any help would be greatly appreciated.
Thanks in advance,
RK

Check here : How to create a measure from data that is stored in a dimension table
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Problem while inserting into a table which has ManyToOne relation

Problem while inserting into a table *(Files)* which has ManyToOne relation with another table *(Folder)* involving a attribute both in primary key as well as in foreign key in JPA 1.0.
Relevent Code
Entities:
public class Files implements Serializable {
@EmbeddedId
protected FilesPK filesPK;
private String filename;
@JoinColumns({
@JoinColumn(name = "folder_id", referencedColumnName = "folder_id"),
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)})
@ManyToOne(optional = false)
private Folders folders;
public class FilesPK implements Serializable {
private int fileId;
private int uid;
public class Folders implements Serializable {
@EmbeddedId
protected FoldersPK foldersPK;
private String folderName;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "folders")
private Collection<Files> filesCollection;
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)
@ManyToOne(optional = false)
private Users users;
public class FoldersPK implements Serializable {
private int folderId;
private int uid;
public class Users implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer uid;
private String username;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "users")
private Collection<Folders> foldersCollection;
I left out @Basic & @Column annotations for sake of less code.
EJB method
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
FoldersPK folderPk = new FoldersPK(folderID, uid);
// My understanding that it should automatically handle folderId in files table,
// but it is not…
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
It is giving error:
Internal Exception: java.sql.SQLException: Field 'folderid' doesn't have a default value_
Error Code: 1364
Call: INSERT INTO files (filename, uid, fileid) VALUES (?, ?, ?)_
_ bind => [hello.txt, 1, 0]_
It is not even considering folderId while inserting into db.
However it works fine when I add folderId variable in Files entity and changed insertFile like this:
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
file.setFolderId(folderId) // added line
FoldersPK folderPk = new FoldersPK(folderID, uid);
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
My question is that is this behavior expected or it is a bug.
Is it required to add "column_name" variable separately even when an entity has reference to ManyToOne mapping foreign Entity ?
I used Mysql 5.1 for database, then generate entities using toplink, JPA 1.0, glassfish v2.1.
I've also tested this using eclipselink and got same error.
Please provide some pointers.
Thanks

Hello,
What version of EclipseLink did you try? This looks like bug https://bugs.eclipse.org/bugs/show_bug.cgi?id=280436 that was fixed in EclipseLink 2.0, so please try a later version.
You can also try working around the problem by making both fields writable through the reference mapping.
Best Regards,
Chris

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Hi Everyone,
I am trying to update a grade column in table called enrolled which has 6 composite primary key column including SID, TERMYEAR, FACCODE, DEPCODE, COURSENO, SECNO and 2 extra column including GRADE, IDD all of them are of type VARCHAR2 as describe below:
To update this table I used the command below:
UPDATE enrolled
SET grade = :COURSE_BLOCK.GRADE_TEXT
WHERE IID = :GLOBAL.logUserid
AND SID = :COURSE_BLOCK.SID_TEXT
AND FACCODE = :COURSE_BLOCK.FACULTY_TEXT
AND DEPCODE = :COURSE_BLOCK.DEPARTMENT_TEXT
AND COURSENO = :COURSE_BLOCK.COURSE_TEXT
AND SECNO = :COURSE_BLOCK.SECTION_TEXT;
Note: the :GLOBAL.logUserid is a global variable that I assigned the user id when the user log on to the application.
When I run the application and fill out the form in order to update the table this doesn't update the table and if I use SQL*PLUS as well with the values that I use for the form to update the table I get message: o rows updated
Can Someone help please?

Here is the solution.
The problem:
The problem was that the enrolled table was designed in a way that a student can enrolled in the lecture(LEC type column) and Laboratory(LAB type column). When a student is given a grade, it is given a grade for the course 100 (eg: 03-60-100) this course has a lecture and lab. this course belong to the faculty code 03(science) department 60 (computer Science) so when a student register to a course, will register to a lecture and a lab but he will receive a grade for the course 100 lec in this case Oracle couldn't update the table because there was two column with course 100 for that particular student Id
The solution:
There are many solution I believe but my quickest solution is when a student register to the course by default is given a grade 'I' means Incomplete then when the instructor add the grade, he can just update a grade from incomplete to the final grade (eg A) now the code will be to get only the course 100 that has grade and discard that doesn't have grade this means that I need only to make sure that the WHERE Clause grade is not null shown below.
UPDATE enrolled
SET grade = BLOCK_NAME.FIELD_NAME
WHERE grade IS NOY NULL
AND IID = BLOCK_NAME.FIELD
AND faccode = BLOCK_NAME.FIELD
AND depcode = BLOCK_NAME.FIELD
AND courseno= BLOCK_NAME.FIELD_NAME
NAD secno = BLOCK_NAME.FIELD_NAME
AND SID = BLOCK_NAME.FIELD_NAME

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Hi Friends,
I have one issue.
How to get the specific Tcode again for the table to which i have used table maintenance .
I have generated table maintenance for many tables inside my package.
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Thanks in advance.
Regards
kishore

Hi Gautham,
I am still having problem... If i give Z* it shows all the Tcodes created with Z.
For that i will click Display object list and get my Tcodes inside my package..
But that is not my issue...
I am sorry if i didn get you properly
But still i didn find any way for that.
Will give one sample table which is Ztest. Ihave tcode ztest1.
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kishore

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Hi All
I need to create a table which is table driven i.e., the columns of that table need to be inserted from another table in a different schema...Can any one help me with this??

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How to write a cursor to check every row of a table which has millions of rows

Hello every one.
I need help. please... Below is the script (sample data), You can run directly on sql server management studio.
Here we need to update PPTA_Status column in Donation table. There WILL BE 3 statuses, A1, A2 and Q.
Here we need to update PPTA_status of January month donations only. We need to write a cursor. Here as this is a sample data we have only some donations (rows), but in the real table we have millions of rows. Need to check every row.
If i run the cursor for January, cursor should take every row, row by row all the rows of January.
we have donations in don_sample table, i need to check the test_results in the result_sample table for that donations and needs to update PPTA_status COLUMN.
We need to check all the donations of January month one by one. For every donation, we need to check for the 2 previous donations. For the previous donations, we need to in the following way. check
If we want to find previous donations of a donation, first look for the donor of that donation, then we can find previous donations of that donor. Like this we need to check for 2 previous donations.
If there are 2 previous donations and if they have test results, we need to update PPTA_STATUS column of this donatioh as 'Q'.
If 2 previous donation_numbers has test_code column in result_sample table as (9,10,11) values, then it means those donations has result.
BWX72 donor in the sample data I gave is example of above scenario
For the donation we are checking, if it has only 1 previous donation and it has a result in result_sample table, then set this donation Status as A2, after checking the result of this donation also.
ZBW24 donor in the sample data I gave is example of above scenario
For the donation we are checking, if it has only 1 previous donation and it DO NOT have a result in result_sample table, then set this donation Status as A1. after checking the result of this donation also.
PGH56 donor in the sample data I gave is example of above scenario
like this we need to check all the donations in don_sample table, it has millions of rows per every month.
we need to join don_sample and result_sample by donation_number. And we need to check for test_code column for result.
-- creating table
CREATE TABLE [dbo].[DON_SAMPLE](
[donation_number] [varchar](15) NOT NULL,
[donation_date] [datetime] NULL,
[donor_number] [varchar](12) NULL,
[ppta_status] [varchar](5) NULL,
[first_time_donation] [bit] NULL,
[days_since_last_donation] [int] NULL
) ON [PRIMARY]
--inserting values
Insert into [dbo].[DON_SAMPLE] ([donation_number],[donation_date],[donor_number],[ppta_status],[first_time_donation],[days_since_last_donation])
Select '27567167','2013-12-11 00:00:00.000','BWX72','A',1,0
Union ALL
Select '36543897','2014-12-26 00:00:00.000','BWX72','A',0,32
Union ALL
Select '47536542','2014-01-07 00:00:00.000','BWX72','A',0,120
Union ALL
Select '54312654','2014-12-09 00:00:00.000','JPZ41','A',1,0
Union ALL
Select '73276321','2014-12-17 00:00:00.000','JPZ41','A',0,64
Union ALL
Select '83642176','2014-01-15 00:00:00.000','JPZ41','A',0,45
Union ALL
Select '94527541','2014-12-11 00:00:00.000','ZBW24','A',0,120
Union ALL
Select '63497874','2014-01-13 00:00:00.000','ZBW24','A',1,0
Union ALL
Select '95786348','2014-12-17 00:00:00.000','PGH56','A',1,0
Union ALL
Select '87234156','2014-01-27 00:00:00.000','PGH56','A',1,0
--- creating table
CREATE TABLE [dbo].[RESULT_SAMPLE](
[test_result_id] [int] IDENTITY(1,1) NOT NULL,
[donation_number] [varchar](15) NOT NULL,
[donation_date] [datetime] NULL,
[test_code] [varchar](5) NULL,
[test_result_date] [datetime] NULL,
[test_result] [varchar](50) NULL,
[donor_number] [varchar](12) NULL
) ON [PRIMARY]
---SET IDENTITY_INSERT dbo.[RESULT_SAMPLE] ON
---- inserting values
Insert into [dbo].RESULT_SAMPLE( [test_result_id], [donation_number], [donation_date], [test_code], [test_result_date], [test_result], [donor_number])
Select 278453,'27567167','2013-12-11 00:00:00.000','0009','2014-01-20 00:00:00.000','N','BWX72'
Union ALL
Select 278454,'27567167','2013-12-11 00:00:00.000','0010','2014-01-20 00:00:00.000','NEG','BWX72'
Union ALL
Select 278455,'27567167','2013-12-11 00:00:00.000','0011','2014-01-20 00:00:00.000','N','BWX72'
Union ALL
Select 387653,'36543897','2014-12-26 00:00:00.000','0009','2014-01-24 00:00:00.000','N','BWX72'
Union ALL
Select 387654,'36543897','2014-12-26 00:00:00.000','0081','2014-01-24 00:00:00.000','NEG','BWX72'
Union ALL
Select 387655,'36543897','2014-12-26 00:00:00.000','0082','2014-01-24 00:00:00.000','N','BWX72'
UNION ALL
Select 378245,'73276321','2014-12-17 00:00:00.000','0009','2014-01-30 00:00:00.000','N','JPZ41'
Union ALL
Select 378246,'73276321','2014-12-17 00:00:00.000','0010','2014-01-30 00:00:00.000','NEG','JPZ41'
Union ALL
Select 378247,'73276321','2014-12-17 00:00:00.000','0011','2014-01-30 00:00:00.000','NEG','JPZ41'
UNION ALL
Select 561234,'83642176','2014-01-15 00:00:00.000','0081','2014-01-19 00:00:00.000','N','JPZ41'
Union ALL
Select 561235,'83642176','2014-01-15 00:00:00.000','0082','2014-01-19 00:00:00.000','NEG','JPZ41'
Union ALL
Select 561236,'83642176','2014-01-15 00:00:00.000','0083','2014-01-19 00:00:00.000','NEG','JPZ41'
Union ALL
Select 457834,'94527541','2014-12-11 00:00:00.000','0009','2014-01-30 00:00:00.000','N','ZBW24'
Union ALL
Select 457835,'94527541','2014-12-11 00:00:00.000','0010','2014-01-30 00:00:00.000','NEG','ZBW24'
Union ALL
Select 457836,'94527541','2014-12-11 00:00:00.000','0011','2014-01-30 00:00:00.000','NEG','ZBW24'
Union ALL
Select 587345,'63497874','2014-01-13 00:00:00.000','0009','2014-01-29 00:00:00.000','N','ZBW24'
Union ALL
Select 587346,'63497874','2014-01-13 00:00:00.000','0010','2014-01-29 00:00:00.000','NEG','ZBW24'
Union ALL
Select 587347,'63497874','2014-01-13 00:00:00.000','0011','2014-01-29 00:00:00.000','NEG','ZBW24'
Union ALL
Select 524876,'87234156','2014-01-27 00:00:00.000','0081','2014-02-03 00:00:00.000','N','PGH56'
Union ALL
Select 524877,'87234156','2014-01-27 00:00:00.000','0082','2014-02-03 00:00:00.000','N','PGH56'
Union ALL
Select 524878,'87234156','2014-01-27 00:00:00.000','0083','2014-02-03 00:00:00.000','N','PGH56'
select * from DON_SAMPLE
order by donor_number
select * from RESULT_SAMPLE
order by donor_number

You didn't mention the version of SQL Server. It's important, because SQL Server 2012 makes the job much easier (and will also run much faster, by dodging a self join). (As Kalman said, the OVER clause contributes to this answer).
Both approaches below avoid needing the cursor at all. (There was part of your explanation I didn't understand fully, but I think these suggestions work regardless)
Here's a SQL 2012 answer, using LAG() to lookup the previous 1 and 2 donation codes by Donor: (EDIT: I overlooked a couple things in this post: please refer to my follow-up post for the final/fixed answer. I'm leaving this post with my overlooked
items, for posterity).
With Results_Interim as
Select *
, count('x') over(partition by donor_number) as Ct_Donations
, Lag(test_code, 1) over(partition by donor_number order by donation_date ) as PrevDon1
, Lag(test_code, 2) over(partition by donor_number order by donation_date ) as PrevDon2
from RESULT_SAMPLE
Select *
, case when PrevDon1 in (9, 10, 11) and PrevDon2 in (9, 10, 11) then 'Q'
when PrevDon1 in (9, 10, 11) then 'A2'
when PrevDon1 is not null then 'A1'
End as NEWSTATUS
from Results_Interim
Where Test_result_Date >= '2014-01' and Test_result_Date < '2014-02'
Order by Donor_Number, donation_date
And a SQL 2005 or greater version, not using SQL 2012 new features
With Results_Temp as
Select *
, count('x') over(partition by donor_number) as Ct_Donations
, Row_Number() over(partition by donor_number order by donation_date ) as RN_Donor
from RESULT_SAMPLE
, Results_Interim as
Select R1.*, P1.test_code as PrevDon1, P2.Test_Code as PrevDon2
From Results_Temp R1
left join Results_Temp P1 on P1.Donor_Number = R1.Donor_Number and P1.Rn_Donor = R1.RN_Donor - 1
left join Results_Temp P2 on P2.Donor_Number = R1.Donor_Number and P2.Rn_Donor = R1.RN_Donor - 2
Select *
, case when PrevDon1 in (9, 10, 11) and PrevDon2 in (9, 10, 11) then 'Q'
when PrevDon1 in (9, 10, 11) then 'A2'
when PrevDon1 is not null then 'A1'
End as NEWSTATUS
from Results_Interim
Where Test_result_Date >= '2014-01' and Test_result_Date < '2014-02'
Order by Donor_Number, donation_date

Adding a summary column in a table which contains the start and end dates in the week

Hi,
I've got a DIMENSION DATE table and want to add in another column which shows the start and end date of the week.
See below, the new column is WEEKOFYEARTEXT.
Does anybody know how i may generate this column using SQL and using the existing columns?
Umar Javed

See: http://www.sqlusa.com/bestpractices/datetimeconversion/
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1 2015-01-01 2015-01-03
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Kalman Toth Database & OLAP Architect
SQL Server 2014 Database Design
New Book / Kindle: Beginner Database Design & SQL Programming Using Microsoft SQL Server 2014

Adding a cloumn in a fact table which has pctfree 0

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