Adding image on separate layer inserts it into slideshow below?

Hello all,
I'm trying to add an image to a rectangle on Layer 2 by selecting the rectangle and using the Place... command from the menu.
When I do this, the image is added as a Hero image to a slideshow on Layer 1 below the rectangle. This is not what I want; I'd like the image to be independent of the slide show as I play with parallax scrolling effects.
Can anyone tell me if it is possible to add an image to the same x,y area occupied by a slideshow without having the image automatically added to the slideshow?

Hi Mistfall,
Kindly lock the entire layer 1 or the slideshow, before you place the image.
Locking will ensure that you do not accidentally select and edit the objects.
Regards
Sonam

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Grayscaled image , posterised, each level onto separate layer

I am a photorealistic graphite artist and use photoshop to turn colour photos into b&w. Then I often posterize the drawing to get a better understanding of the facial shapes as expressed in their different tonal values. I would like to have each posterised value on a separate layer in the correct grayscale value.
How can I achieve that. My literature, and my searching the web, did not turn out the answer, hence my 'call for help here'. Thanks for taking an interest.

I can't think of an automatic way.
Here is what I would do:
Include a small Black to White gradient in each image before posterizing.
After posterizing, set your Magic Wand Tool to zero tolerance and uncheck Contiguous.
Now click on a tonal value in your B-W gradient with the Magic Wand and go Layer>Layer via Copy (Cmd+J shortcut).
Do the same process for each value in your gradient (remember to target your background layer each time before selecting with the Magic Wand Tool).

Reasons why can't move image on its separate layer or combined?

I am using Creative Suite 5.5 on my MacBook Pro...and today had issues demonstrating the simple process of dragging one person/image onto another, applying a quick mask to do some simple morphing.
But...one, I couldn't drag the image from the internet and drop onto the project, but had to go to Edit and copy, then create a new file and hit paste. Placing one image side by side to another...I was not able to drag the image of one person to drop onto the other. I either had to use the marquee tool, drag around the image, copy and paste or...found I could drag the image from its layer in the layer's palette and drop onto the project.
More frustrating was that once I had both images in the same project, I was not able to move the new person/image added to locate in right position over the background person/image. I would drag it to that new location, and it would snap back to the original location. Obviously the need to take any image added and move it around to orchestrate your image is important.
I have asked a number of artist friends, checked the mode (both images are RGB) and both images at 8 bits...
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Hi there
You posted your help request to the forum for photoshop.com, and online portal site (not a forum for Photoshop CS). I'll move this for you.

Background layer seizes added images.

I am trying to create a photo collage by scratch (not using "Collage"). First I create a new blank page for the background and save it. It is shown as "locked" with a padlock. Then I open an image file (.jpg) to add to the background layer, and I get a message that I need to unlock the background layer so I click to unlock it. However the added image locks onto the background layer and doesn't make a new layer. If I open another image file it locks on top of the others.

The Layers panel only shows the layer(s) belonging to the currently active file. You need to arrange your image windows so that you can see your composite image as well as the source. With the source image active the Layers panel will show the source - click and drag that layer to the composite.
So in the following, the violet image is the active image and I drag its layer to the white image I've created for my collage. In the composite image with the new layer selected I can position it where I want. Select each of the other images in turn and do the same. Refer to my previous note, you can also do this with Copy & Paste.
When finished, your composite image and its Layers panel will look like this:
Cheers,
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Insanity is hereditary, you get it from your children
If this post or another user's post resolves the original issue, please mark the posts as correct and/or helpful accordingly. This helps other users with similar trouble get answers to their questions quicker. Thanks.

How to insert data into newly added column

Hi all,
i am having a doubt how to insert entries into newly added column..
i created a table with two columns and inserted the data into them then i altered the table by adding additional column.now i want to insert data into that..plz tell me how to do that..??
thanks in advance..help me

Small example:
[email protected]> create table t(id int, id2 int);
Table created.
[email protected]> insert into t values (1,2);
1 row created.
[email protected]> insert into t values (2,2);
1 row created.
[email protected]> alter table t add id3 int;
Table altered.
[email protected]> select * from t;
ID ID2 ID3
1 2
2 2
[email protected]> update t
2 set id3 = 10
3 where id = 1;
1 row updated.
[email protected]> select * from t;
ID ID2 ID3
1 2 10
2 2
Best Regards
Krystian Zieja / mob

Error while adding Image: ORA-00001: unique constraint

Dear all,
I have an error while adding images to MDM I can´t explain. I want to add 7231 images. About 6983 run fine. The rest throws this error.
Error: Service 'SRM_MDM_CATALOG', Schema 'SRMMDMCATALOG2_m000', ERROR CODE=1 ||| ORA-00001: unique constraint (SRMMDMCATALOG2_M000.IDATA_6_DATAID) violated
Last CMD: INSERT INTO A2i_Data_6 (PermanentId, DataId, DataGroupId, Description_L3, CodeName, Name_L3) VALUES (:1, :2, :3, :4, :5, :6)
Name=PermanentId; Type=9; Value=1641157; ArraySize=0; NullInd=0;
Name=DataId; Type=5; Value=426458; ArraySize=0; NullInd=0;
Name=DataGroupId; Type=4; Value=9; ArraySize=0; NullInd=0;
Name=Description_L3; Type=2; Value=; ArraySize=0; NullInd=0;
Name=CodeName; Type=2; Value=207603_Img8078_gif; ArraySize=0; NullInd=0;
Name=Name_L3; Type=2; Value=207603_Img8078.gif; ArraySize=0; NullInd=0;
Error: Service 'SRM_MDM_CATALOG', Schema 'SRMMDMCATALOG2_m000', ERROR CODE=1 ||| ORA-00001: unique constraint (SRMMDMCATALOG2_M000.IDATA_6_DATAID) violated
Last CMD: INSERT INTO A2i_Data_6 (PermanentId, DataId, DataGroupId, Description_L3, CodeName, Name_L3) VALUES (:1, :2, :3, :4, :5, :6)
Name=PermanentId; Type=9; Value=1641157; ArraySize=0; NullInd=0;
Name=DataId; Type=5; Value=426458; ArraySize=0; NullInd=0;
Name=DataGroupId; Type=4; Value=9; ArraySize=0; NullInd=0;
Name=Description_L3; Type=2; Value=; ArraySize=0; NullInd=0;
Name=CodeName; Type=2; Value=207603_Img8085_gif; ArraySize=0; NullInd=0;
Name=Name_L3; Type=2; Value=207603_Img8085.gif; ArraySize=0; NullInd=0;
I checked all data. There is no such dataset in the database. Can anybody give me a hint how to avoid this error.
One thing I wonder: The PermanentId is allways the same but I can´t do anything here.
BR
Roman
Edited by: Roman Becker on Jan 13, 2009 12:59 AM

Hi Ritam,
For such issues, can you please create a new thread or directly email the author rather than dragging back up a very old thread, it is unlikely that the resolution would be the same as the database/application/etc releases would most probably be very different.
For now I will close this thread as unanswered.
SAP SRM Moderators.

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Hi,
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I am using Dreamweaver 8. I have taken my camcorder video and uploaded it to youtube and copied the mp4 file to my hard drive.
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I want to have the video open on the same page in the same location as the screenshot. Click on the image and it just starts playing.
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The help docs tell you how:
http://help.adobe.com/en_US/Dreamweaver/10.0_Using/WSc78c5058ca073340dcda9110b1f693f21-7c9 fa.html
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Using Crystal 2008 to insert records into a table

Hi,
We have a unique need to use Crystal to insert records into a table. We have managed to test a report that can write into a temporary table. This is done by using sql command object and uses the following code :
INSERT INTO TEMP_TABLE (ORDERID)
VALUES ({?orderid}) (-- where orderid a parameter).
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Regards,
Mohit.
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Hmmm... I don't use Oracle but the syntax looks good...
You've already tested it and I assume that you are using the same driver in the production report as you used in the test, so that shouldn't be an issue...
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If it's all in 1 command (as it should be), a bad parameter would fail in the final SELECT causing an error.
Also... are rows null or empty string values being added to table when the report executes? This would be an indication that the command is being executed but isn't getting the parameter value.
Jason

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Hello forum members!
Just got the trial today and I am trying to insert text into a document. I press "T" and drag a box for a textbox. I then double-click inside that box to type something, and whatever I type absolutely NOTHING appears. It just blinks and nothing is actually typed inside the box.
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Could you elaborate on that a little? I have taken a screenshot of my screen to show you how everything is. I have not touched any settings and have literally downloaded the trial about an hour ago.
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Welcome to the forum.
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Can not insert null into foreign key issue

Hi ,
I am having parent-child relationship table.
In the child table when I am adding a new record , data is getting inserted with foreign key.
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Hi ,
I am having parent-child relationship table.
In the child table when I am adding a new record , data is getting inserted with foreign key.
After insert if I immediately update the same record. Its giving error that can not insert null into foreign key.
If i click on rollback button I am able to update that record properly.

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Is there any way to insert comments into the template, in the same way as is possible for e.g. in SQL? I tried to insert a Word Comment, but that generates errors.
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Hi,
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How to insert data into datagrid dynamically and also programatically with data and column names being retrived from a xml file..

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A DataGrid is row-based rather than cell-based with each row
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Adding image on separate layer inserts it into slideshow below?

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