.AI files opening as text files in illustrator.

I created two pieces of work last night, 2/4/15, using Adobe Illustrator and once completed I saved the files and haven't moved them from their original destination. I attempted to open the files today, 2/5/15, and have a pop up saying that it is opening the files as a text document and upon proceeding am met with a blank new document in the size of the file I had saved. A majority of previous files open with no problem and all have the same .ai extension and show the preview. Any help would be greatly appreciated as I'm not sure what caused this issue and I haven't run into in previously. Thank you.
I have attached photos of the screen that appears upon opening the .ai files in illustrator.

Hardy,
You may see whether the file size seems right.
You have already tried to create a new document and File>Place the corrupted one to see how much may be rescued that way.
You may also try to open the document with Adobe Acrobat, if it was saved with PDF Compatible file ticked, then save it as PDF and try to open that.
Here are some websites where you can see whether it can rescue the file, and if it can, you may pay for a subscription to have it done,
http://www.recoverytoolbox.com/buy_illustrator.html
http://markzware.com/adobe-software/fix-illustrator-file-unknown-error-occurred-pdf2dtp-fi le-recovery/
http://www.illustrator.fixtoolbox.com/
As far as I remember, the first one is for Win and the one is for Mac, while the third one should be for both.
Here are a few pages about struggling with it yourself:
http://daxxter.wordpress.com/2009/04/16/how-to-recover-a-corrupted-illustrator-ai-file/
http://helpx.adobe.com/illustrator/kb/troubleshoot-damaged-illustrator-files.html
http://kb2.adobe.com/cps/500/cpsid_50032.html
http://kb2.adobe.com/cps/500/cpsid_50031.html
http://helpx.adobe.com/illustrator/kb/enable-content-recovery-mode-illustrator.html

Similar Messages

  • .AI files opening as Text Imports in Illustrator

    I created two pieces of work last night, 2/4/15, using Adobe Illustrator and once completed I saved the files and haven't moved them from their original destination. I attempted to open the files today, 2/5/15, and have a pop up saying that it is opening the files as a text document and upon proceeding am met with a blank new document in the size of the file I had saved. A majority of previous files open with no problem and all have the same .ai extension and show the preview. Any help would be greatly appreciated as I'm not sure what caused this issue and I haven't run into in previously. Thank you.
    I have attached photos of the screen that appears upon opening the .ai files in illustrator.

    I apologize but I'm not sure what a networked volume is. With that being
    said I'm pretty sure that I didn't save them to a networked volume. I
    created a new file, edited the file, saved the file onto my hard drive
    along with many other ai files then closed the program. Upon reopening the
    program and attempting to open file, open recent file, and creating a new
    document then placing my ai file with no resolution.
    On Thu, Feb 5, 2015 at 3:02 PM, Monika Gause <[email protected]>

  • Opening a text file in server from an applet running in the client

    Friends,
    I want to open a text file in the server(The server machine uses tomcat 4.1.12 server)from an applet running in the client machine;
    The applet invokes a servlet that opens the text file;this text file is opened in the server machine; but I want it to be opened in the client machine where the applet is running.
    Plese help me to get around this.

    You can open the textfile on the servlet and then send the information to the client (applet) as stirngs. The must then applet convert the stirngs into some object or simply display the information in someway. But then the text file that you are opening must be stored in some relevant tomcat directory e.g. on the server. If you want to open a file on the clients computer, you get into signed applets.

  • Opening a Text File?

    I am having no luck opening a text file that contains comma delimited data. I have tried some different ways and am having no luck at all. I can't even get a open file dialog to appear when I click a button.
    I did not see any example of this in the sdk sample plugins.
    Anyone able to help me out.
    The file I am trying to load is "D:\Test\TestFile.txt".

    If you did not escape the path's backslashes that may be part of the problem.
    Some example code:
    local LrDialogs = import 'LrDialogs'
    local LrFileUtils = import 'LrFileUtils'
    local LrPathUtils = import 'LrPathUtils'
    local file = 'C:\\temp\\Testfile1.txt'
    if not LrFileUtils.isReadable(file) then
    local dialogresult = LrDialogs.runOpenPanel {
      title = 'Select input text file',
      allowsMultipleSelection = false,
      initialDirectory = LrPathUtils.parent(file)
    file = dialogresult and dialogresult[1] or nil
    end
    if file and LrFileUtils.isReadable(file) then
    local collectedLines = {}
    for line in io.lines(file) do table.insert(collectedLines, line) end
    LrDialogs.message(table.concat(collectedLines, '\n'))
    end
    Herb

  • Recommended way to open a text file included in a jar?

    Forgive me if this seems like an ignorant question, but I keep reading two different things about loading resources in the javadocs and forums, and can't seem to connect them...
    Say you want to open a text file and read the contents into a String or a List. Apparently, the preferred way to do this is something like:
    fileName = "myFile.txt";
    BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
    String line;
    while ((line = reader.readLine()) != null) {...}
    Now say you want to distribute your app in a jar file, with the text file included in the jar file. The above method won't work, because a FileReader operates on a File, and as I understand it, once myFile.txt is packed into the jar file, it's no longer a "file".
    So what do you do? I keep reading that the best way to open the jarred text file is to use something like this:
    InputStream is = getClass().getResourceAsStream(fileName);
    Here's where I get confused: InputStream, and all of its subclasses, are now supposedly dispreferred for reading character data (in preference to Reader, as above). But no subclass of Reader can wrap around an InputStream, which would facilitate the reading of character data greatly, with methods like readLine().
    So my question is: What's the best way to read a text file from within a .jar?
    Thanks,
    Gregory

    great! glad it's working
    here is a statement from the javadoc
    http://java.sun.com/j2se/1.4.2/docs/api/java/io/InputStreamReader.html
    For top efficiency, consider wrapping an InputStreamReader within a BufferedReader. For example:
    BufferedReader in
    = new BufferedReader(new InputStreamReader(System.in));
    kind regards
    Waken16

  • Opening a text file in a bundle with C++

    Hi folks! I'm working with bundles for the first time, and I'd like to know how to open a text file inside one with C++. What I have now is this:
    ifstream file = new ifstream(fileName.c_str());
    if (!file->is_open())
    return false;
    Where fileName is a std::string. This is the way I'm accustomed to opening files (I'm from a Windows development background -- don't hate me! ). Unfortunately, the is_open() test always fails.
    I know how to get the path of the bundle. Once I add on my data subdirectory and file name, the fileName variable ends up as this:
    /Users/sb/...project location.../Debug/MyProg.app/data/Dev Options.ini
    Should the path be different somehow? Thanks for any help!

    Your data folder most likely isn't directly inside the .app bundle. The first directory inside an .app bundle is named Contents. The article at the following URL should help you:
    http://www.meandmark.com/bundlespart1.html
    If you're going to use C++ streams to open files, you'll want to ignore the section on opening the file in Part 3 of the article. You'll want to read up on the Core Foundation CFURL functions. You'll want to use one of the functions that gives you a path to the text file that you can pass to a C++ file stream.

  • How to open a text file using button click event

    hi, How can i open a text file in a textpad or notepad on the click event of a button.?
    Thanks
    Jay

    Pnt,
    this will not work LV 8.0.1 and LV 8.6 will give back error 193.
    Attached is a VI to use the ShellExecute WinAPI. The VI is LV 7.1.1.
    Message Edited by waldemar.hersacher on 10-09-2008 10:48 PM
    Waldemar
    Using 7.1.1, 8.5.1, 8.6.1, 2009 on XP and RT
    Don't forget to give Kudos to good answers and/or questions
    Attachments:
    ShellExecute.zip ‏27 KB

  • How do I open a text file to sort using bubble sort?

    Hi,
    I have a text file, which is a list of #'s.. ex)
    0.001121
    0.313313
    0.001334
    how do you open a text file and read a list? I have the bubble sort code which sorts.. thanks

    I wrote this, but am getting a couple errors:
    import java.util.*;
    import java.io.*;
    public class sort
         public static void main(String[] args)
              String fileName = "numsRandom1024.txt";
              Scanner fromFile = null;
              int index = 0;
              double[] a = new double[1024];Don't use double. You should use something that implements Comparable, like java.lang.Double.
              try
                   fromFile = new Scanner(new File(fileName));
              catch (FileNotFoundException e)
    System.out.println("Error opening the file " +
    " + fileName);
                   System.exit(0);
              while (fromFile.hasNextLine())
                   String line = fromFile.nextLine();
                   a[index] = Double.parseDouble(line);Don't parse to a double, create a java.lang.Double instead.
                   System.out.println(a[index]);
                   index++;
              fromFile.close();
              bubbleSort( a, 0, a.length-1 );No. Don't use a.length-1: from index to a.length-1 all values will be null (if you use Double's). Call it like this:bubbleSort(a, 0, index);
    public static <T extends Comparable<? super T>> void
    d bubbleSort( T[] a, int first, int last )
              for(int counter = 0 ; counter < 1024 ; counter++)
    for(int counter2 = 1 ; counter2 < (1024-counter) ;
    ) ; counter2++)Don't let those counter loop to 1024. The max should be last .
                        if(a[counter2-1] > a[counter2])No. Use the compareTo(...) method:if(a[counter2-1].compareTo(a[counter2]) > 0) {
                             double temp = a[counter2];No, your array contains Comparable's of type T, use that type then:T temp = a[counter2];
    // ...Good luck.

  • How to open a text file

    hello
    if so have an idea on how to open a text file
    thanks

    File file=new File("[path to the text file]");
    String encoding="[encoding of the file]";
    BufferedReader reader=new BufferedReader(new InputStreamReader(new FileInputStream(file), encoding));
    // Do whatever you like with the reader
    // For example write the text file to the output
    String line;
    while ((line=reader.readLine())!=null)
    System.out.println(line);
    reader.close();Hope it helps,
    Marcin
    PS. This is not the write forum category to post this question.

  • Can Muse open existing text files authored in GoLive?

    Can Muse open existing text files authored in GoLive and or Dreamweaver?

    Unfortunately not, for now, Muse can only open .muse extension files, created within Muse.

  • Can Quickword open a text file 10K?

    I have a couple of simple, notepad text files.
    6K opens (after about 5 seconds)
    90K, well, it doesn't
    480K, neither does this.
    I can open the files using notepad, direct from the phone.
    Can anyone else open simple text files of this range of size.
    ...Lyall

    Well, I have a Tab Separated variable file (output from Excel) with about 20 columns.
    I edited it down from 5000 lines to 1000, 500 and 250 lines.
    I then copied all 4 files to the E90.
    QuickWord will open the 250 line file after about 5-10 seconds.
    It does NOT open (at least within my lifetime) the 500+ line files.
    So, how do I look at text files on the E90?
    ...Lyall

  • Copy one text file to another text file and delete last line

    Hi all wonder if someone can help, i want to be able to copy one text file to another text file and remove the last line of the first text file. So currently i have this method:
    Writer output = null;
             File file = new File("playerData.xml");
             try {
                   output = new BufferedWriter(new FileWriter(file, true));
                   output.write("\t" + "<player>" + "\n");
                   output.write("\t" + "\t" + "<playerName>" + playerName + "</playerName>" + "\n");
                   output.write("\t" + "\t" + "<playerScore>" + pointCount + "</playerScore>" + "\n");
                   output.write("\t" + "\t" + "<playerTime>" + minutes + " minutes " + seconds + " seconds" + "</playerTime>" + "\n");
                   output.write("\t" + "</player>" + "\n");
                   output.write("</indianaTuxPlayer>" + "\n");
                  output.close();
                  System.out.println("Player data saved!");
             catch (IOException e) {
                   e.printStackTrace();
              }However each time the method is run i get the "</indianaTuxPlayer>" line repeated, now when i come to read this in as a java file i get errors becuase its not well formed. So my idea is to copy the original file, remove the last line of that file, so the </indianaTuxPlayer> line and then add this to a new file with the next data saved in it. So i would end up with something like this:
    <?xml version="1.0" encoding="UTF-8"?>
    <indianaTuxPlayers>
         <player>
              <playerName>Default Player</playerName>
              <playerScore>0</playerScore>
              <playerTime>null minutes null seconds</playerTime>
         </player>
         <player>
              <playerName>Default Player</playerName>
              <playerScore>0</playerScore>
              <playerTime>null minutes null seconds</playerTime>
         </player>
         <player>
              <playerName>Default Player</playerName>
              <playerScore>0</playerScore>
              <playerTime>null minutes null seconds</playerTime>
         </player>
    </indianaTuxPlayers>
    However after all day searching the internet and trying ways, i have been unable to get anything working, could anyone give me a hand please?

    I would go the XML route too, but for fun, open a file as a BufferedWriter and do this:
    void copyAllButLastLine(File src, BufferedWriter tgt) throws IOException {
        BufferedReader in = new BufferedReader(new FileReader(src));
        try {
            String previous= in.readLine();
            for (String current = null; (current = in.readLine()) != null; previous=current) {
                tgt.write(previous);
                tgt.newLine();
        } finally {
            in.close();
    }

  • How do I convert an audio mp3 file to a text file?

    How do I convert an audio mp3 file to a text file?

    StephenInAZ wrote:
    I keep responding to posters here but my responses dissapear.
    there were reasons for that, see:
    https://discussions.apple.com/static/apple/tutorial/tou.html

  • How to save the contents of a file(not a text file)

    Hi all, I want to save the contents of a file(,png file, not a text file) as a field in a class. Shall I have it as a string or byte array or something?
    I have tried saving a file in a string but there were some problems with loading the file from a different platform. Following is my code.
            String string;
            try {
                StringBuffer sb = new StringBuffer(1024);
                char[] characterArray = new char[1024];
                BufferedReader br = new BufferedReader(new FileReader(file));
                while(br.read(characterArray) != -1){
                    sb.append(String.valueOf(characterArray));
                br.close();
                string= sb.toString();
            } catch (IOException ex) {
                ex.printStackTrace();
            }and I use the following code to recover the string back to a stream, and save that stream back to a time later.
        ByteArrayInputStream bais = new ByteArrayInputStream(map.getBytes());I realized that because this file is not a text file, the string could cause some problems. But anyone could tell me if I should use a byte array or someting? and how?
    Any help would be appreciated!
    Cheers,
    Jing

    You should use a byte array, and the binary streams (InputStream a& OutputStream). Never use Strings and Reader/Writer if you have binary data.
    Kaj

  • How to convert a HTML files into a text file using Java

    Hi guys...!
    I was wondering if there is a way to convert a HTML file into a text file using java programing language. Likewise I would also like to know if there is a way to convert any type of file (excel, power point, and word) into text using java.
    By the way, I really appreciated the help that you guys gave me on my previous topic on how to extract tests from a pdf file.
    Thank you....

    HTML files are already text files. What do you mean you want to convert them?
    I think if you search the web, you can find things for converting those MS Office files to text (or extracting text from them, as I assume you mean).

Maybe you are looking for